In this case, we are given that the rod is subjected to the force system shown in the figure. There is a vertical force F acting on the rod at point A, as well as a horizontal force P. The rod is also subjected to a moment M about the z-axis.
To determine the stress components that act at point A, we need to consider the forces that are acting on a small volume element located at this point.
The stress on a volume element is defined as the force acting on the element per unit area. The stress components at a point can be represented by a stress tensor, which is a 3x3 matrix with nine elements. The diagonal elements of the stress tensor represent the normal stress components, while the off-diagonal elements represent the shear stress components.
To determine the stress components at point A, we need to consider how these forces are distributed over the surface of the volume element. The normal stress components can be found by considering the forces acting perpendicular to the surface of the element. The shear stress components can be found by considering the forces acting tangent to the surface of the element.
For example, the normal stress component in the x-direction at point A can be found by considering the force F acting perpendicular to the surface of the element in the y-direction. The normal stress component in the y-direction at point A can be found by considering the force P acting perpendicular to the surface of the element in the x-direction. The shear stress component in the XY-plane at point A can be found by considering the moment M acting tangent to the surface of the element.
To determine the specific values of the stress components, we would need to know the dimensions of the volume element, as well as the magnitudes of the forces and moments acting on the rod. With this information, we can use the equations of statics to solve for the stress components at point A.
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how does the final temperature of the gas compare with its initial temperature? express your answer using two significant figures. tcta
Step 1: Calculate the ratio of the final and beginning temperatures using the ideal gas law solved for temperature.
Step 2: Calculate the ratio after eliminating any constant values.
Step 3:Solve for the final temperature after substituting the beginning temperature into the ratio.
Perfect Gas Law: According to the ideal gas law, a gas's pressure, P, is inversely proportional to its volume, V, temperature, T, and the number of moles it contains, n, in the sample. The equivalent statement is: For these issues, we'll use the ratio of two temperatures. Because the ratio of starting to end volume and pressure will be the same regardless of the units used to express them, the volume and pressure can be expressed in any form. exhibited in (as long as the initial and final of each are expressed in the same units).PV= nRT
However, for this method to work properly, the temperature must be stated in Kelvin. This is true because Kelvin's zero point is absolute zero. Theoretically, molecules are entirely immobile at 0 Kelvin.
T = PV/nR
The ideal gas law equivalency is used to compute the final temperature in the next two issues.
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What is the Force of Gravity acting on the object in the diagram?
The force of gravity acting on the 23 Kg object in the diagram is 225.4 N
How do I determine the force of gravity?The force of gravity is defined as follow:
Force of gravity (F) = mass (m) × acceleration due to gravity (g)
Using the above formula, we can easily obtain the force gravity acting on the 23 Kg object. This is shown below:
Mass (m) = 23 KilogramsAcceleration due to gravity (g) = 9.8 m/s²Force of gravity (F) =?Force of gravity (F) = mass (m) × acceleration due to gravity (g)
Force of gravity = 23 Kg × 9.8 m/s²
Force of gravity = 225.4 N
Thus, from the calculation made above, we can conclude that the gravitaional force is 225.4 N
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During the collision, the car and truck exert forces on each other. Which of the following is a correct statement about these forces and gives evidence to support this statement? The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the truck changes. B The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the car changes. С The forces the truck and car exert on each other must be external to the truck-car system because the momentum of both the truck and car change. D The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same E The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system changes.
The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same. Option D
What is the Collison?We know that it is possible for an object to be able to bump into another object when this occurs, we would have to apply the law of the conservation of linear momentum. Recall that from the law of the conservation of linear momentum, momentum before collision is equal to the momentum after collision.
We would also have to consider the fact that the weight of the truck is much lager than the weight of the car. The forces that the two vehicles would exert on each other can not be the same. It is clear that the truck is going to exert more force than the car.
With that said, we must have in mind that the total momentum of the system does not change because we are going to approximate the system to function as a closed system.
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What quantity describes how long an object is moving for?
show that the probability density for the ground state solution of the one dimensional coulomb potential energy in the schrodinger equation has its maximum at x=a0
Through Schrodinger equation probability, we can prove that the probability density for the ground state solution of the one dimensional coulomb potential energy in the Schrodinger equation has its maximum at x=a₀.
Given wave function is Ψ(1s) = 1/√π{1/a₀}^(3/2) e ^(x/a₀)
Probability refers to potential. The range of the value is 0 to 1. Mathematics has included probability to forecast the likelihood of certain events. The degree to which something is likely to happen is basically what probability means.
The Schrödinger equation is a linear partial differential equation that describes the wave function or state function of a quantum-mechanical system.
To find the most probable distance, differentiate the equation |Ψ(1s)|²x² with respect to x and equating to zero, we get
d / dr | 1/√π e(1/a₀)^3 / 2e^(-x/a₀) |² x² = 0
1 / π(1 / a₀)³ d / dr (e^-2x / e₀) (x²) = 0
[2e^(-2Zx / a₀) x + e^(-2Zx / a₀) {-2 / a₀} x²] = 0
2 + (-2 / a₀) x = 0
This gives x = a₀
Therefore, through Schrodinger equation probability, we can prove that the probability density for the ground state solution of the one dimensional coulomb potential energy in the Schrodinger equation has its maximum at x=a₀.
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A large cannon is mounted on a cart with frictionless wheels that is initially at rest on a horizontal surface. The cannon fires a large cannonball to the right with a speed v_b which is then caught by a trap firmly attached to the cart. What is the final speed of the cannoncart-cannonball system? V > v_b, to the left
The final velocity of the cannonball-cart system is less than the initial velocity of the cannonball and the system will move in the direction of the cannonball ( V < v_b ).
What is the law of conservation of linear momentum?
The law of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.
Mathematically, the law of conservation of linear momentum is given as;
Pi = Pf
where;
Pi is the sum of the initial momentumPf is the sum of the final momentumm₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is the mass cannon ballu₁ is the initial velocity of the cannon ballm₂ is the mass of the cartu₂ is the initial velocity of the cartv is the final velocity of the cannoncart-systemsince the cart is initially at rest, the initial velocity of the cart = 0
m₁u₁ + 0 = v ( m₁ + m₂ )
m₁u₁ = v ( m₁ + m₂ )
v = ( m₁u₁ ) / ( m₁ + m₂ )
given initial velocity of the cannon ball = v_b
The final velocity of the cannonball-cart system is calculated as follows;
V = ( m₁v_b ) / ( m₁ + m₂ )
Hence, V < v_b
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For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3
To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo
[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]
The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]
The given parameters:
- Applied force on the spring [tex]$=F$[/tex]
- Extension of the spring [tex]$=x_0$[/tex]
The work done by stretching the spring to the given distance is calculated as follows;
[tex]W=\frac{k x_0}{3}[/tex]
[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]
Thus, the work done by stretching the spring to the given distance is
[tex]W=\frac{k x_0}{3}[/tex]
measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
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which of the following sequences lists methods for determining distance in the correct order from nearest to farthest?
Parallax, main-sequence fitting, cepheid variables, Tully-Fisher relation, and Hubble's law are the sequence lists methods for determining distance.
Parallax is the closest method for determining distance. This method uses the principle of triangulation to measure the distance of a nearby star relative to Earth. Main-sequence fitting is another method used to measure the distance of stars. This method compares the brightness of a star to other stars of known distance and luminosity to determine its distance.
Cepheid variables are stars whose brightness varies in a predictable way over time. This method uses the period of the star's brightness to determine its intrinsic luminosity, and then its distance. The Tully-Fisher relation is a method for measuring the distance of galaxies. This method uses the rotation speed of the galaxy and its brightness to calculate its distance.
Finally, Hubble's law is the most distant method for determining distance. This law states that the farther away a galaxy is, the faster it moves away from us. This allows us to calculate the distance of galaxies by measuring their rate of recession.
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if an object producing sound is moving away from you, you would observe a wavelength than an object moving toward you. group of answer choices
If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.
What is the Doppler effect?The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.
The equation of the Doppler effect is
f₀ = [(v ± v₀)/(v ± vs)] × fs
Where
f₀ = observer frequency of soundv = speed of sound waves (340 m/s)v₀ = observer velocityvs = source velocityfs = actual frequency of sound wavesNote:
v₀ (+) if the observer moves closer to the sound source.vs (+) if the sound source moves away from the observer.When an object producing sound is moving away from us, the frequency of the sound we heard changed.
Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).
With the Doppler's effect, we get
f₀ = [(v+0) / (v+vs)] × fs
f₀/fs = v/(v+vs)
v < v+vs
f₀ < fs
The frequency of sound we heard is lower that the actual frequency.
The wavelength is inversely proportional to the frequency. It is described in the equation:
λ = c/f
It means that the lower the frequency, the longer the wavelength.
Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.
Here is the group of answer choices:
(a) Band width
(b) Doppler's effect
(c) Sound refraction
(d) Vibrations
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The Sun's evolution from youngest to oldest stage is:
A) white dwarf, red giant, main-sequence, protostar
B) red giant, main-sequence, white dwarf, protostar
C) protostar, red giant, main-sequence, white dwarf
D) protostar, main-sequence, red giant, white dwarf
D) The Sun's evolution from youngest to the oldest stage is protostar, main-sequence, red giant, a white dwarf.
A protostar is the very beginning stage of a star's life. It is a cloud of gas and dust that starts to collapse due to its own gravitational pull. As it collapses, the gas and dust heat up, and eventually, nuclear fusion begins, creating a star.
The main-sequence stage is the longest and most stable period of a star's life. During this stage, the star is converting hydrogen into helium in its core, producing energy and light. This stage can last for billions of years.
Once a star has used up its hydrogen fuel, it enters the red giant phase. This is when the star expands, becoming much larger and much brighter. The star is now converting helium into other elements in its core, such as carbon and oxygen.
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what is the length of the y component shown below?
The length of the y component shown is C. 2.0.
How to find the length ?We are given the angle of the vector, and the length of one of the components of the vetor. Given the angle we have, the available component is the hypotenuse. The y component that we are to find, will then be the opposite or perpendicular component.
To solve for the length of the y - component therefore, the useful operation would be the Sin function.
The length of the y - component would be:
Sin 42 ° = Opposite / Hypotenuse
Sin 42 ° = y component / Hypotenuse
y - component = Sin 42 ° x Hypotenuse
y - component = Sin 42 ° x 3
y - component = 0. 6691 x 3
y - component = 2. 0
In conclusion, the y - component is 2.0.
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Full question is:
What is the length of the y-component of the vector shown below?
A. 2.2 B. 3 c. 2.0 D. 2.7Design a parallel RLC circuit (see (Figure 1)) with a resonant radian frequency of 5000 rad/s. Take that L 10 mH.a) Find the value of C Express your answer to three significant figures and include the appropriate units. C= 4.00 μFb) Find the value of R so that the response is critically damped. Express your answer to three significant figures and include the appropriate units R- 25.0 Ω
The value of R so that the response is critically damped using the equation is 25.0Ω.
What is Farads?Farads is the unit of measure for capacitance, which is the amount of electrical charge stored for a given voltage. Farads can be used to measure the amount of energy stored in a capacitor, which is made up of two conductive plates separated by an insulating material. The higher the capacitance, the more energy can be stored in a given capacitor. Farads are named after Michael Faraday, the British scientist who discovered the relationship between electricity and magnetism.
The resonant frequency of an RLC circuit is given by the equation:
ω_r=1/sqrt(LC)
where ω_r is the resonant frequency in rad/s, L is the inductance in Henries, and C is the capacitance in Farads.
Given the resonant frequency of 5000 rad/s and the inductance of 10 mH, we can calculate the capacitance as follows:
C=1/(ω_r^2*L)
C=1/(5000^2*0.01)
C=4.00μF
We can find the value of R so that the response is critically damped using the equation:
R=2*sqrt(L/C)
R=2*sqrt(0.01/4.00)
R=25.0Ω
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A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page, as shown above. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines.
If wire loop is being pulled to the right with a constant velocity of 3 meters per second , then the potential difference induced between points X and Y is 3V .
it is given that a 5Ω resistor is connected between points X and Y ;
the magnetic field (B) = 0.5 ;
length of wire (l) [tex]=[/tex] 2 ;
velocity of the wire loop (v) = 3 m/s ;
the potential difference will be induced because charge separation on the vertical hand wire of wire loop.
Points X and Y are the same as the top and bottom of left wire.
The EMF(potential difference) induced in wire is given by
EMF = B*l*v
substituting the values ,
we get
= (0.5)(2)(3) = 3V
Therefore , the induced potential difference between points X and Y is 3V .
The given question is incomplete , the complete question is
A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines. The loop is being pulled to the right with a constant velocity of 3 meters per second. Make all determinations for the time that the left end of the loop is still in the field, and points X and Y are not in the field.
Determine the potential difference induced between points X and Y.
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Question
A rabbit moves a distance of 85 meters in 13 seconds.
What is the rabbits average speed?
7.26 m/s
0.15 m/s²
6.54 m/s
6.54 m/s²
Important Formula:
[tex]s=\dfrac{d}{t}[/tex]
__________________________________________________________
[tex]d=85m[/tex] (measured in meters)
[tex]t=13s[/tex] (measured in seconds)
[tex]s=?[/tex] (measured in meters per second; m/s)
__________________________________________________________
[tex]s=\dfrac{d}{t}[/tex]
[tex]s=\dfrac{85}{13}[/tex]
__________________________________________________________
[tex]\fbox{6.54 m/s},\fbox{Option C}[/tex]
A soccer player runs at 10 m/s and runs into a 80 kg referee standing on the field causing the referee to fly forward at 6.0 m/s. Assume the soccer player comes to complete stop after impact. What would be the mass of the soccer player be?
The mass of soccer player will be 120kg. Writing down 1/2 m1 will help us remember that KE = 1/2 mv2 (v1i) 2 + 1/2 m2(vi) (vi) 2 = 1/2 m1(v1f) (v1f) 2 + 1/2 m2 (v2f) (v2f) 2.
How to solve ?According to Newton's third law,
Given that a soccer player runs at 10m/s and plows into a 80kg referee standing on the field causing the referee to fly forward at 56m/s. Let
mass of the player = ?
initial velocity of the player = 10m/s
Final velocity of the player
mass of the referee = 80 kg
Initial velocity of the referee = 0 ( since he is at rest )
Final velocity of the referee = 6 m/s
Since it is a perfectly elastic collision,
U1 =V2 - V1 ........ (1)
M1U1 = M2V2 + M1V1........ (2)
Substitute all the necessary parameters into the equation (1)
10 = 6 - V1
V1 = 10 - 6
V1 = 4 m/s
Now, Substitute all the necessary parameters into the equation (2)
10M1 = (80 x 6) + (4M1)
10 M1- 4 M1 = 480
4M1 = 480
M1 = 480/4
M1 = 120kg
Therefore, the mass of soccer player will be 120kg
Collision formula: What is it?When kinetic energy (KE) and momentum (p) are conserved during a collision, the collision is said to be elastic. To put it another way, it denotes that KE0 = KEf and po = pf. Writing down 1/2 m1 will help us remember that KE = 1/2 mv2 (v1i) 2 + 1/2 m2(vi) (vi) 2 = 1/2 m1(v1f) (v1f) 2 + 1/2 m2 (v2f) (v2f) 2.
How is velocity determined?By dividing the entire distance traveled by the time it took the object to go a certain distance, you may calculate the object's initial velocity. V, d, and t are the three variables that make up the equation V = d/t.
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When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?
The centripetal force needed to keep the fly from sleeping will be zero point 0.00176 Newton in magnitude.
The mass of the fly is 2 gram and it is selling itself on a phonograph turntable.
The fly is at a distance of 4 cm away from the center of the phonograph turntable and when the turntable is turned on and retreats with 45 Revolution per minute the centripetal force that would be working on the fly will be given by,
F = Mw²R
Where,
M is mass of the fly,
w is the angular speed of the fly and,
R is the radius of the turnable.
Putting all the values,
F = 0.002×(4.7)²×0.04
F = 0.00176N.
So, a centripetal force of magnitude 0.00176 Newton will be required in order to keep the fly from slipping.
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Complete question- A fly of mass 2.00 g is sunning itself on a phonograph turntable at a location that is 4.00 cm from the center. When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?
In the figure, a climber leans out against a vertical ice wall that has negligible friction. Distance a is 0.945 m and distance L is 1.95 m. His center of mass is distance d = 0.89 m from the feet-ground contact point. If he is on the verge of sliding, what is the coefficient of static friction between feet and ground?
The coefficient of static friction between feet and ground is 0.2522.
What is static friction?Static friction is defined as when there is no motion between the two surfaces, the force that one surface applies to another. The friction that exists between two or more objects when they are not moving relative to one another is referred to as static friction.
The coefficient of static friction between his feet and the ground, denoted by the symbol s, determines how to express the frictional force as
fs =μsFN1
The μs can be calculated as
μs = a / √L² - a² x d / L
μs = 0.945 / √(1.95)² - (0.945)² x 0.89 / 1.95
μs = 0.945 / √2.91225 x 0.89 / 1.95
μs = 0.2522
Thus, the coefficient of static friction between feet and ground is 0.2522.
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(1) A table tennis ball is dropped
onto the floor from a height of
4m and it rebounds to a height of
3m. If the time of contact with the floor is 0.01s, what is the magnitude and direction of the acceleration during the contact.
Answer:
Here, h1=4.00m,h92)=3.00m,Delta t =0.01 s.Letv1 be the velocity of the ball (actind downwards) just before striking the floor an dv20 be the velocity of the ball (acting upwaeds) ust after striking the floor. Then, change in velocity of the ball in time Δtv2−(−v1)v2+v1
:. acceleration, a=v2+v1Δt ..(i)
When body falls from height h1,
then u=o,v1,a=gandS=h1
As, v21=u2+2aS,
:. v_(1) ^(2) =0 + g h_(10 or v12–√gh1
Taking motion of the ball after striking the floor, then u=v2,v=0,a=−g,S=h2
As, v2=u22as,∴v21=0+2gh1orv_(1) =sqrt 32 g h_(1)Tak∈gmotionoftheballa>erstrik∈gthe⌊,⌋thenu=v_(2), v=0, a=- g, S=h_(2)As,v2=u2+2aS,wehave0 = v_(2)^(2) +2 (-g) h_92) otr v2=2–√gh2
Putting values in (i) we get,
a=2–√gh2+2–√gh1Δt)
a=2–√×9.8×3+2–√×9.8×40.01
= 1652m/s2.
Explanation:
Emily and Henry were in the lab and graphed the heating of ice to 125°C. Emily and Brad made an observation that the graph contains three sloped and two level portions. Emily and Brad determined that the two level portions in the graph represented:
The two level portions in the graph represented phase changes.
What are phase changes?
The transition of matter from one state (solid, liquid, gas, or plasma) to another is referred to as a phase change. These changes also take place when the pressure on the system varies, as well as when the system receives enough energy or loses enough energy.
The slope of the line dividing two phases is determined by the relative densities of the two phases. The solid-liquid line, for instance, slopes up and to the right if the liquid is less dense than the solid, whereas up and to the left if the liquid is denser than the solid.
Therefore the two level portions in the graph represented phase changes.
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the use of the doppler effect in the study of astronomy
Determine the momentum of …
a. … an electron (m= 9.1 x10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbit in the H atom).
b. … a 0.45 Caliber bullet (m = 0.162 kg) leaving the muzzle of a gun at 860 m/s.
c. … a 110-kg professional fullback running across the line at 9.2 m/s.
d. … a 360,000-kg passenger plane taxiing down a runway at 1.5 m/s
A. The momentum of the electron is 1.98×10⁻²⁴ Kg.m/s
B. The momentum of the Caliber bullet is 139.32 Kg.m/s
C. The momentum of the professional fullback is 1012 Kg.m/s
D. The momentum of the passenger plane is 540000 Kg.m/s
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed mathematically as:
Momentum = mass × velocity
A. How do I determine the momentum of the electron?
Mass of electron = 9.1×10⁻³¹ KgVelocity of electron = 2.18×10⁶ m/sMomentum of electron =?Momentum = mass × velocity
Momentum of electron = 9.1×10⁻³¹ × 2.18×10⁶
Momentum of electron = 1.98×10⁻²⁴ Kg.m/s
B. How do I determine the momentum of the Caliber bullet?
Mass of Caliber bullet = 0.162 KgVelocity of Caliber bullet = 860 m/sMomentum of Caliber bullet =?Momentum = mass × velocity
Momentum of Caliber bullet = 0.162 × 860
Momentum of Caliber bullet = 139.32 Kg.m/s
C. How do I determine the momentum of the professional fullback?
Mass of professional fullback = 110 KgVelocity of professional fullback = 9.2 m/sMomentum of professional fullback =?Momentum = mass × velocity
Momentum of professional fullback = 110 × 9.2
Momentum of professional fullback = 1012 Kg.m/s
D. How do I determine the momentum of the passenger plane?
Mass of passenger plane = 360000 KgVelocity of passenger plane = 1.5 m/sMomentum of passenger plane =?Momentum = mass × velocity
Momentum of passenger plane = 360000 × 1.5
Momentum of passenger plane = 540000 Kg.m/s
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A simple pendulum on Planet X oscillates at 3.1 Hz. If the acceleration due to gravity is 31.3 m/s^2 what is the length of the pendulum in cm?
The length of the pendulum is 8.258 cm .
Given,
Frequency f= 3.1 Hz
Acceleration due to gravity
We have to find out the length of pendulum
L=g / ( 4 x (π)^2 x (f)^2 ) --------------(1)
Where,
L is length
g is acceleration due to gravity
f is frequency
Put the given value in equation (1) becomes
L= (31.3)m/s^2 / (4x (3.14)^2 x (3.1)^2)Hz
L= 31.3 / 379
L = (0.08258) m
L= (8.258)cm
The length of pendulum is
L= (8.258)cm.
The rate by which velocity changes concerning time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.
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The length of the pendulum is 8.258 cm .
What is pendulum?
A weight suspended from a pivot such that it can freely swing is called a pendulum. Gravity's restoring force will cause a pendulum to accelerate back toward its equilibrium position if it is sideways moved from its resting, equilibrium position.
Given,
Frequency f= 3.1 Hz
Acceleration due to gravity
We have to find out the length of pendulum
L=g / ( 4 x (π)^2 x (f)^2 ) --------------(1)
Where,
L is length
g is acceleration due to gravity
f is frequency
Put the given value in equation (1) becomes
L= (31.3)m/s^2 / (4x (3.14)^2 x (3.1)^2)Hz
L= 31.3 / 379
L = (0.08258) m
L= (8.258)cm
The length of pendulum is
L= (8.258)cm.
The rate by which velocity changes concerning time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.
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(a) A Carnot engine working in a forward direction (i.e. taking heat from a hot body and rejecting remaining heat after work to a cold body) is a heat engine. Therefore the engine to be used as a heat engine operates in a direction. as it is in contact with the heat reservoir during this segment; and, as its is in contact with cold sink.
A heat engine, symbolized by a circle in this illustration, uses some of the heat transfer to produce work.
The most effective heat engine that is theoretically possible—i.e., any machine that can transform thermal energy (heating) into mechanical energy—is the Carnot engine (work).The heat and cold reservoirs are the names given to the hot and cold items. Only the hot temperatures' absolute values affect efficiency. A portion of the heat QH that is extracted from the high-temperature source TH in the case of a heat engine is transformed into work. The ratio of net work completed to heat absorbed throughout one full cycle is known as a heat engine's thermal efficiency.
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g calculate the mass-to-light ratio for a globular cluster with a luminosity of 106 lsun and 105 stars. (assume that the average mass of a star in such a cluster is 1 msun.)
The mass-to-light ratio for a globular cluster is equal to 137.7 kg/lsun
To measure the mass-to-light ratio of a globular cluster, we first determine the total mass of the cluster. Since the cluster has 105 stars, and the average mass of a star in the cluster is 1 m-sun, therefore, the total mass of the cluster is 10^5 * 1 msun = 10^5 msun.
Now, we convert the luminosity of the cluster from solar units to kilograms. The luminosity of the cluster is given as 10^6 lsun, which is equal to 10^6 * 3.828 x 10^26 W.
Using the equation, [tex]E = mc^2[/tex], we can convert this energy to mass:
[tex]mass = (luminosity * time) / (c^2)[/tex]
where, c is the speed of light (3 x 10^8 m/s) and time is the amount of time over which the luminosity is measured (here, time is equal to 1 second).
Substituting the values in above equation, we find that the mass of the cluster in kilograms is approximately 1.45 x 10^31 kg.
To determine the mass-to-light ratio, divide the total mass of the cluster (in kilograms) by its luminosity (in solar units):
mass-to-light ratio = (total mass of cluster in kg) / (luminosity in solar units)
Substituting the values in above equation, we find that the mass-to-light ratio for this globular cluster is approximately:
1.45 x 10^31 kg / 10^6 lsun = 137.7 kg/lsun.
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Calculate the internal energy of 1.2moles of steam at 177degree
Answer:
18447 J
Explanation:
To calculate the internal energy of steam at a given temperature, we need to know the specific heat capacity of steam and the enthalpy of vaporization. The specific heat capacity of steam at a constant pressure is approximately 2.08 J/g*K, and the enthalpy of vaporization (latent heat) at 100°C is 2257 kJ/kg.
We can use the following equation to calculate the internal energy of steam at a given temperature:
U = m * Cp * (T - T_b) + m * L
Where U is the internal energy, m is the mass of the steam, Cp is the specific heat capacity of steam, T is the temperature of the steam, Tb is the boiling temperature of the steam, and L is the enthalpy of vaporization.
Since we are given the amount of steam in moles (1.2 moles) and the temperature (177°C), we can convert the moles of steam to mass using the molar mass of water (18 g/mol). The boiling temperature of water at standard atmospheric pressure is 100°C, so we can use this value for Tb.
First, we need to convert the temperature from degrees Celsius to kelvins:
T = 177°C + 273 = 450 K
Then, we can calculate the mass of the steam:
m = 1.2 moles * 18 g/mol = 21.6 g
Substituting these values into the equation for internal energy, we get:
U = 21.6 g * 2.08 J/g*K * (450 K - 273 K) + 21.6 g * 2257 kJ/kg
Solving for the internal energy, we get:
U = 18,447 J
Therefore, the internal energy of 1.2 moles of steam at 177°C is approximately 18,447 J.
A mass m is suspended by a massless string forming a simple pendulum of length 2.0 m. The string of the pendulum is initially at an angle of 60° with the vertically downward direction when the mass is released from rest.
The centripetal acceleration of the mass m when it is at the lowest position is 10 m/s². The correct option is A.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any object moving in a circle with an acceleration vector pointing in the direction of the circle's center.
A projectile is an object that is launched into the air and then moves only in response to the acceleration of gravity. The trajectory of the object is referred to as the projectile's trajectory.
The equation of projectile motion is:
[tex]V = \sqrt{2gh}\\\\\\V = \sqrt{2 \times 10 \times \dfrac{1}{2} } \\\\V = \sqrt{20}[/tex]
a² = v² / l = 20 / 2 = 10 m/s²
Therefore, the correct option is A, 10 m/s².
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The question is incomplete. Your most probably complete question is given below:
The centripetal acceleration of the mass m when it is at the lowest position is:
10 m/s²
5 m/s²
20 m/s²
25 m/s²
an astronaut drops a rock from the top of a crater on the moon when the rock is halfwat down to the bottom of the crater its speed is what fraction of its cinal impact speed?A. 1/4–√2B.1/4C. 1/2–√2D. 1/–√2Answer:
The fraction of its final impact speed is 1/√2.
Impact speed is the speed of the vehicle at the time of impact or collision.
The rock has lost half of its gravitational potential energy, its kinetic energy at the halfway point is half of its kinetic energy at impact.
As we know kinetic energy is directly proportional to mass (m) and velocity square (v²),
KE ∝ v²
KE = (1/2)mv²
then K.E at halfway point is equal to 1/2 x K.E,
Then,
The K.E at impact, then the rock’s speed at the halfway point its speed at impact will be 1/√2 its impact speed.
Therefore option D is the correct answer, the fraction of its final impact speed is 1/√2.
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when a man loves a magnetic continually changes magnitude and direction a voltage is continually being induced in the coil this voltage is called voltage
When a magnetic field continually changes magnitude and direction, a voltage is continually induced in the coil. This voltage is called induced voltage.
Induced voltage is the type of voltage that is a product of electromagnetic induction. It is generally defined as the rate of change of magnetic flux with respect to time via a closed circuit.
A wire that is carrying a current will experience an induced voltage along its length if the current changes. The changes in current change the magnetic field flux perpendicular to the wire.
Induced voltage is calculated using the Faradays equation:
e = N(dΦ/dt)
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4. For an ideal gas, the specific heat at constant pressure Cp is greater than the specific heat at constant volume CV because the A. pressure of the gas remains constant when its temperature remains constant B. gas does work on its environment when its pressure remains constant while its temperature is in creased C. increase in the gas's internal energy is greater when the pressure remains constant than when t he volume remains constant D. heat input per degree increase in temperature is the same in processes for which either the pressure or the volume is kept constant
Whenever the gases are heated at a fixed volume, no outside work is done as well as the heat energy given is simply used to make the gas more energetic internally.
Why is CP for just an ideal gas higher than Cv?The specific heat under constant pressure for an ideal gas, Cp, is higher than Cv.This is due to the fact that when the gas' temperature rises while the pressure stays constant, the gas must perform some finite work on its surroundings.
Does CP always exceed Cpk?When the goal value and the specification's average are equal, Cpk equals Cp.Never can Cpk go above Cp.With the creation of descriptive statistic displays and histograms, Cp and Cpk can both be determined.
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compare the time it takes for light to travel 1000 m on the surface of the earth and in outer space.
Since light is faster in space, it takes less time for light to travel a distance of 1000m, a time difference of 0.977ns.
Light travels more slowly in a transparent medium than in the vacuum of empty space. The speed of light in any medium (air, water, glass) is determined by the refractive index of the medium. However, this exponent itself may be wavelength dependent (ie different colored rays travel at different speeds). In fact, this is why a prism splits white light into the colors of the rainbow.
The main reason that a light beam slows down in a medium has to do with the fact that the photons, or 'raw light beams', are excited by an electromagnetic field. When the field is in the ground state (vacuum), these excitations actually propagate at the vacuum speed of light. However, when there are positively charged atoms and negatively charged electrons, the electromagnetic field does not go to the ground state. There are many virtual photons. Yes, some of the photons of the passing light beam can be absorbed. After all, no material is completely transparent. But even those who aren't are moving in an environment so different from the vacuum that their paths will be different. It also depends on the structure that the molecule forms.
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