The mathematical model that represents the general price movement of mortgages is: ΔPM = f(Δk, ΔPrin, ΔC)
Where ΔPM is the change in the price of the mortgage, Δk is the change in the required rate of return, ΔPrin is the change in the principal payment, and ΔC is the change in the interest payment.
This means that the change in the price of a mortgage is a function of the change in the required rate of return, the change in the principal payment, and the change in the interest payment.
The securities that are issued to financial institutions to increase liquidity in the secondary mortgage market by financing the origination of mortgages are:
Government National Mortgage Association (Ginnie Mae) mortgage-backed securitiesFederal Home Loan Mortgage Association (Freddie Mac) participation certificatesFederal National Mortgage Association (Fannie Mae) mortgage-backed securitiesFinancial institutions may also receive private-label pass-through securities, although these are not guaranteed by government entities like Ginnie Mae, Freddie Mac, or Fannie Mae.
They are not backed by the government, but by private institutions, which can make them riskier.
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Construct a 99% confidence interval of the population proportion using the given information.
x = 75, n = 250
The 99% confidence interval for the population proportion p is :lower bound= 0.225, upper bound 0.375
What does a confidence interval actually mean?
Your estimate's mean is added to and subtracted from by the estimate's range to create a confidence interval. If you repeat your test, within a specific level of confidence, this is the range of values you anticipate your estimate to fall within.
Given that,
n = 250
x = 75
Point estimate = sample proportion = p = x / n = 75/250=0.3
1 - p =1 - 0.3=0.7
At 99% confidence level the z is ,
α = 1 - 99% = 1 - 0.99 = 0.0
α / 2 = 0.01 / 2 = 0.005
Z /2 = Z0.005 = 2.576 ( Using z table )
Margin of error = E = Zα / 2 * √(( p * (1 - p)) / n)
= 2.576 (√((0.3*0.7) /250 )
E = 0.075
A 99% confidence interval for population proportion p is ,
p - E < p < p + E
0.3 -0.075 < p < 0.3 + 0.075
0.225< p < 0.375
The 99% confidence interval for the population proportion p is :lower bound= 0.225, upper bound 0.375.
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What value of Y and Z will make DEF correspond to JKI?
[tex]\bold{Solution:}[/tex]
[tex]\Delta[/tex][tex]DE[/tex][tex]F[/tex] congruent to [tex]\Delta[/tex][tex]JKI[/tex]
[tex]\bold{FD=JI} \text{(corresponding angles of congruent triangles)}[/tex]
[tex]z + 22 = 3z[/tex]
[tex]\text{or,} \ z-3 z= -22[/tex]
[tex]\text{or,} \ -2z = -22[/tex]
[tex]\text{or,} \ z = \bold{11}[/tex]
[tex]\bold{EF=KI} \text{(corresponding angles of congruent triangles)}[/tex]
[tex]5y+13=6y[/tex]
[tex]\bold{y=13}[/tex]
write an algebraic expression to represent the phrase twelve dollars less than the original price. let p represent the unknown.
Answer:
p=O-12
Step-by-step explanation:
original price:O
12 less than O is "O-12"
therefore p=O-12
Find the definite integral of f(x)=
fraction numerator 1 over denominator x squared plus 10x plus 25 end fraction for x∈[5,7]
the definite integral of f(x) over the interval [5, 7] is (-5 / 600).
How to find?
The given function is:
f(x) = 1 / (x² + 10x + 25)
To find the definite integral of this function over the interval [5, 7], we can use the following steps:
Rewrite the function using partial fraction decomposition:
f(x) = 1 / (x² + 10x + 25)
= 1 / [(x + 5)²]
Using partial fraction decomposition, we can write this as:
f(x) = A / (x + 5) + B / (x + 5)²
where A and B are constants to be determined. Multiplying both sides by the common denominator (x + 5)², we get:
1 = A(x + 5) + B
Setting x = -5, we get:
1 = B
Setting x = 0, we get:
1 = 5A + B
= 5A + 1
Solving for A, we get:
A = 0
Therefore, the partial fraction decomposition is:
f(x) = 1 / [(x + 5)²]
= 0 / (x + 5) + 1 / (x + 5)²
Use the formula for the definite integral of a power function:
∫ xⁿ dx = (1 / (n + 1))× x²(n + 1) + C
where C is the constant of integration.
Using this formula, we can find the antiderivative of the function 1 / (x + 5)²:
∫ 1 / (x + 5)² dx = -1 / (x + 5) + C
Evaluate the definite integral over the interval [5, 7]:
∫[5,7] 1 / (x + 5)² dx
= [-1 / (x + 5)] [from 5 to 7]
= (-1 / 12) - (-1 / 10)
= (-5 / 600)
Therefore, the definite integral of f(x) over the interval [5, 7] is (-5 / 600).
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4. A pet store has eight dogs and cats. Three are dogs. What fraction represents the number of cats?
A. 1/4
B. 3/8
C. 1/2
D.5/8
Answer:
Step-by-step explanation:
Number of cats = 8 - 3 = 5
Fraction that are cats [tex]=\frac{5}{8}[/tex]
Find the standard normal area for each of the following (LAB)Round answers to 4 decimals
The answer of the standard normal area for each of the following questions are given below respectively.
What is standard normal area?Standard normal area refers to the area under the standard normal distribution curve, which is a normal distribution with a mean of 0 and a standard deviation of 1.
a. P(1.24<Z<2.14) = 0.0912
b. P(2.03 <Z<3.03) = 0.0484
c. P(-2.03 <Z<2.03) = 0.9542
d. P(Z > 0.53) = 0.2977
Note: The standard normal distribution is a continuous probability distribution with mean 0 and standard deviation 1. The area under the curve represents probabilities and can be calculated using a standard normal distribution table or a calculator with a normal distribution function.
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Given the coefficient of correlation in the relationship to be - 0.73 , what percentage of the variation in hours of sleep cannot be explained by the time spent on social media?
In the inequality, x (< with line underneath) 8, represents the number of books on a shelf.
How do you know if 8 is a possible value of x?
Answer:
The numbers 8 and lower are possible values of x.
Step-by-step explanation:
The inequality [tex]x\leq 8[/tex] means x is less than or equal to 8. Therefore, 8 is a possible value of x.
A salesperson earns 4% commission on furnace sales.
What is the commission that the salesperson earns on the sale of $33,000 worth of furnaces.
The commission earned 4 percentage on the salesperson on the sale of furnaces is $1320.
What is percentage?In mathematics, a percentage is a number or ratio that can be expressed as a fraction of 100. If we need to calculate a percentage of a number, we should divide it by its entirety and then multiply it by 100. The percentage therefore refers to a part per hundred. The word per cent means per 100. The letter "%" stands for it. The term "percentage" was adapted from the Latin word "per centum", which means "by the hundred". Percentages are fractions with 100 as the denominator.
by the question.
the commission that the salesperson earns on the sale of $33,000 worth of furnaces= 4% of 33,000 = 4× 330 = $1320
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Does the expression 56x+40y-48z=8(7x+5y-6z)
For all values of x, y, and z, the expression 56x + 40y - 48z = 8(7x + 5y - 6z) holds true.
Explain expression using an example.As an illustration, the phrase x + y is one where x and y are terms with an addition operator in between. There are two sorts of expressions in mathematics: numerical expressions, which only contain numbers, and algebraic expressions, which also include variables.
Indeed, for all values of x, y, and z, the expression 56x + 40y - 48z = 8(7x + 5y - 6z) holds true.
We can simplify both sides of the equation to understand why:
56x + 40y - 48z = 8(7x + 5y - 6z)
56x + 40y - 48z = 56x + 40y - 48z
As we can see, the equation is true for all values of x, y, and z because both sides are identical.
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Which operation do you use to simplify a ratio after finding the greatest common factor (GCF)?
division
addition
multiplication
subtraction
Answer:
hey baby
Step-by-step explanation:
hi thwrw honey i love you lol
The operation we use to simplify a ratio after finding the greatest common factor (GCF) is division.
Option A is the correct answer.
What is an expression?An expression contains one or more terms with addition, subtraction, multiplication, and division.
We always combine the like terms in an expression when we simplify.
We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.
Example:
1 + 3x + 4y = 7 is an expression.
3 + 4 is an expression.
2 x 4 + 6 x 7 – 9 is an expression.
33 + 77 – 88 is an expression.
We have,
To simplify a ratio after finding the greatest common factor (GCF), we use division.
We divide both terms of the ratio by the GCF.
This reduces the ratio to its simplest form.
Thus,
The operation we use to simplify a ratio after finding the greatest common factor (GCF) is division.
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Management estimates that 5% of credit sales are eventually uncollectible. Of the collectible credit sales, 65% are likely to be collected in the month of sale and the remainder in the month following the month of sale. The company desires to begin each month with an inventory equal to 70% of the sales projected for the month. All purchases of inventory are on open account; 30% will be paid in the month of purchase, and the remainder paid in the month following the month of purchase. Purchase costs are approximately 60% of the selling prices. Budgeted January cash payments for December inventory purchases by Collection Corporation are:
Answer:
Step-by-step explanation:
Unfortunately, there is no information provided about the sales projections for the month of January or the selling prices of the inventory. Without this information, it is not possible to calculate the budgeted January cash payments for December inventory purchases.
Mrs. Young has p goats and q cows on his farm. He has 23 fewer cows than goats.
What are the missing values in the table?
PLSSSS QUICK
Step-by-step explanation:
35:12
40:17
45:22
50:27
55:32
Use the gradient to find the directional derivative of the function at P in the direction of PQ. f(x, y) = 3x2 - y2 + 4, P(1, 5), 2(4,2)
The directional derivative of f(x,y) at point P(1,5) in the direction of PQ is -2√2.
Find the directional derivative of the function f(x,y) = 3x² - y² + 4 at point P(1,5) in the direction of PQ, where P(1,5) as well as Q(4,2), we need to first calculate the gradient of f(x,y) at point P.
The gradient of f(x,y) at P is:
∇f(x,y) = [∂f/∂x, ∂f/∂y] = [6x, -2y]
Evaluating this at point P(1,5), we get:
∇f(1,5) = [6(1), -2(5)] = [6, -10]
Now, we need to find the unit vector in the direction of PQ. This can be calculated as follows:
u = PQ/|PQ|
where PQ = Q - P = [4 - 1, 2 - 5] = [3, -3] and |PQ| = √(3² + (-3)²) = √18 = 3√2
So, u = PQ/|PQ| = [3/3√2, -3/3√2] = [1/√2, -1/√2]
The directional derivative of f(x,y) at P in the direction of PQ is then given by:
D_u f(P) = ∇f(P) · u
where · represents the dot product.
Substituting the values we obtained earlier, wehave:
D_u f(P) = [6, -10] · [1/√2, -1/√2]
D_u f(P) = (6/√2) + (-10/√2)
D_u f(P) = -2√2
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Part A
Use GeoGebra to graph points A, B, and C to the locations shown by the ordered pairs in the table. Then join each pair of
points using the segment tool. Record the length of each side and the measure of each angle for the resulting triangle.
Location
A(3,4), B(1,1).
C(5.1)
A(4.5), B(2.1).
C(7.3)
—————-
AB=
BC=
AC=
Answer:
Step-by-step explanation:
Answer:
[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12}\sf Location&AB&BC&AC\\\cline{1-4}\vphantom{\dfrac12} A(3,4),\;B(1,1),\;C(5,1)&3.61&4&3.61\\\cline{1-4}\vphantom{\dfrac12} A(4,5),\;B(2,1),\;C(7,3)&4.47&5.39&3.61\\\cline{1-4}\end{array}[/tex]
[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12}\sf Location&m \angle A&m \angle B&m \angle C\\\cline{1-4}\vphantom{\dfrac12} A(3,4),\;B(1,1),\;C(5,1)&67.38^{\circ}&56.31^{\circ}&56.31^{\circ}\\\cline{1-4}\vphantom{\dfrac12} A(4,5),\;B(2,1),\;C(7,3)&82.87^{\circ}&41.63^{\circ}&55.49^{\circ}\\\cline{1-4}\end{array}[/tex]
Step-by-step explanation:
Step 1Place points A, B and C on the coordinate grid.
Alternatively, type the following into the input field as 3 separate inputs:
Triangle 1
A = (3, 4)B = (1, 1)C = (5, 1)Triangle 2
A = (4, 5)B = (2, 1)C = (7, 3)Step 2Use the Segment tool to join each pair of points.
Alternatively, type Segment( <Point>, <Point> ) into the input field (replacing <Point> with the letter name of the point) to create a segment between two points.
Record the length of each side.
[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12}\sf Location&AB&BC&AC\\\cline{1-4}\vphantom{\dfrac12} A(3,4),\;B(1,1),\;C(5,1)&3.61&4&3.61\\\cline{1-4}\vphantom{\dfrac12} A(4,5),\;B(2,1),\;C(7,3)&4.47&5.39&3.61\\\cline{1-4}\end{array}[/tex]
Step 3Use the Angle tool to measure each angle in the resulting triangle.
Alternatively, type Angle(Polygon(A, B, C)) into the input field to create all interior angles.
Record the measure of each angle.
[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12}\sf Location&m \angle A&m \angle B&m \angle C\\\cline{1-4}\vphantom{\dfrac12} A(3,4),\;B(1,1),\;C(5,1)&67.38^{\circ}&56.31^{\circ}&56.31^{\circ}\\\cline{1-4}\vphantom{\dfrac12} A(4,5),\;B(2,1),\;C(7,3)&82.87^{\circ}&41.63^{\circ}&55.49^{\circ}\\\cline{1-4}\end{array}[/tex]
Note: All measurements have been given to the nearest hundredth (2 decimal places).
for autonomous equations, find the equilibria, sketch a phase portrait, state the stability of the equilibria.
Understanding the equilibria, sketching a phase portrait, and determining the stability of equilibria for autonomous equations are important tools for analyzing and understanding the behavior of systems over time.
Autonomous equations are differential equations that do not depend explicitly on time. To find the equilibria of an autonomous equation, we set the derivative of the function to zero and solve for the values of the independent variable that satisfy the equation. These values represent points at which the function does not change over time and are known as equilibrium points.
To sketch a phase portrait for an autonomous equation, we plot the slope field of the function and then draw solutions through each equilibrium point. The resulting graph shows the behavior of the function over time and helps us understand how the solutions behave near each equilibrium point.
The stability of an equilibrium point is determined by examining the behavior of nearby solutions. If nearby solutions move toward the equilibrium point over time, the equilibrium point is stable. If nearby solutions move away from the equilibrium point over time, the equilibrium point is unstable. Finally, if the behavior of nearby solutions is inconclusive, further analysis is needed.
Here is the sketch for [tex]dx/dt = x - x^3[/tex]
/ <--- (-∞) x=-1 (+∞) ---> \
/ \
<--0--> x=-1 x=1 0-->
\ /
\ <--- (-∞) x=1 (+∞) ---> /
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Pls help !! I will mark brainilest
Answer:
m = -1
Step-by-step explanation:
may not be accurate, I haven't done this in a while
Answer:
-1y−y1=m(x−x1)
y−6=−1(x+5)
y−6=−1x+(−1×5)
y−6=−1x+−5
y−6=−1x−5
y=−1x−5+6
y=−1x+1
y=−x+1
m=−1
b=1
Step-by-step explanation: Hope this helps!! Mark me brainliest!
Cant figure out the surface area
Answer:
[tex]96 \: {m}^{2} [/tex]
The correct answer is B
Step-by-step explanation:
First, we have to find the area of one side of the cube:
[tex]a(side) = 4 \times 4 = 16[/tex]
Now multiply this number by 6 (since the cube has 6 sides in total):
[tex]a(surface) = 16 \times 6 = 96[/tex]
Answer: B - 96 sq m
Step-by-step explanation:
The surface area is the area of all the squares added up. To find the area of one square, you multiply 4 x 4, which equals 16. Then, count the number of sides on the cube. There are 6 sides on this cube. So, you multiply 16 x 6. 96 is your total. And you can eliminate C because it says meters instead of square meters.
Find dz/dt in two ways: by using the Chain Rule, and by first substituting the expressions for x and y to write z as a function of t. Do your answers agree?z= x^2y+xy^2, x = 3t y = t^2
The derivative of the function z= x^2y+xy^2, x = 3t y = t^2 using the chain rule is given by dz/dt = 36t^3 + 15t^4.
Expressions are equals to,
z= x^2y+xy^2
x = 3t
y = t^2
Using the chain rule calculate dz/dt,
which states that if z is a function of x and y,
And x and y are both functions of t, then,
dz/dt = (dz/dx)(dx/dt) + (dz/dy)(dy/dt)
Using these expressions, calculate the value of dz/dt using the chain rule,
z= x^2y+xy^2
This implies,
dz/dx = 2xy + y^2
dz/dy = x^2 + 2xy
x = 3t
⇒ dx/dt = 3
y = t^2
⇒ dy/dt = 2t
Substituting these values into the chain rule formula, we get,
dz/dt = (2xy + y^2)(3) + (x^2 + 2xy)(2t)
= [2(3t)(t^2 ) + (t^2)^2 ]3 + [(3t)^2 + 2(3t)(t^2)](2t )
= [ 6t^3 + t^4 ]3 + [ 9t^2 + 6t^3 ]2t
= 18t^3 + 3t^4 + 18t^3 + 12t^4
= 36t^3 + 15t^4
Substituting the given expressions for x and y into z, we get,
z = (3t)^2(t^2) + (3t)(t^2)^2
= 9t^4 + 3t^5
here also,
dz/dt = 36t^3 + 15t^4
Therefore, the value of the function using the chain rule dz/dt is equals to 36t^3 + 15t^4.
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If r and s are constants and r² +rx + 12 is equivalent to (x+3)(x + 5), what is the value of r?
F.:3
H. 7
J. 12
K. Cannot be determined from the given information
Answer:
H. 7
Step-by-step explanation:
Given x² + rx + 12 is equivalent to (x + 3)(x + s), equate the two expressions and expand the right side of the equation:
[tex]\begin{aligned}x^2+rx+12&=(x + 3)(x + s)\\ x^2+rx+12&=x^2 + sx + 3x + 3s\\x^2+rx+12&=x^2 + (s+3)x + 3s\end{aligned}[/tex]
To find the value of r, first find the value of s.
The constant term of the right-hand side must be equal to the constant term of the left-hand side. Therefore:
[tex]\implies 3s = 12[/tex]
Solve for s by dividing both sides of the equation by 3:
[tex]\implies s = 4[/tex]
Compare the coefficients of the terms in x:
[tex]\implies r = s + 3[/tex]
Substitute the value of s into the equation and solve for r:
[tex]\begin{aligned} \implies r &= s + 3\\&= 4 + 3\\&= 7\end{aligned}[/tex]
Therefore, the value of r is 7.
Answer:
[tex]\large\boxed{\sf r = 7 }[/tex]
Step-by-step explanation:
Correct question:- If r and s are constants and r² +rx + 12 is equivalent to (x+3)(x + s), what is the value of r?
Here we are given that , the expression (x+3)(x+s) is equal to r² + rx + 12 .
Firstly, expand the expression (x+3)(x+s) as ,
[tex]\implies (x+3)(x+s) \\[/tex]
[tex]\implies x(x+s)+3(x+s) \\[/tex]
[tex]\implies x^2 + xs + 3x + 3s \\[/tex]
Take out x as common,
[tex]\implies x^2 + (3+s)x + 3s \\[/tex]
Now according to the question,
[tex]\implies x^2 + (3+s)x + 3s = r^2 + rx + 12\\[/tex]
On comparing the respective terms , we get,
[tex]\implies r = 3 + s \\[/tex]
[tex]\implies 3s = 12 \\[/tex]
Solve the second equation to find out the value of s , so that we can substitute that in equation 1 to find "r" .
[tex]\implies 3s = 12 \\[/tex]
[tex]\implies s =\dfrac{12}{3}=\boxed{4} \\[/tex]
Now substitute this value in equation (1) as ,
[tex]\implies r = 3 + s \\[/tex]
[tex]\implies r = 3 + 4 \\[/tex]
[tex]\implies \underline{\underline{ \red{ r = 7 }}} \\[/tex]
and we are done!
Really Need help asap!
Step-by-step explanation:
h(-2) = 25
h(-1) = 5
h(0) = 1
h(1) = 1/5
h(2) = 1/25
please help me with 4 math questions
Using linear negative association, According to the all four parts correct options are D ;A ;D ;D respectively
What is linear negative association?The slope of a line expresses a great deal about the linear relationship between two variables. If the slope is negative, there is a negative linear relationship, which means that as one variable increases, the other variable decreases. If the slope is zero, one increases while the other remains constant.
The first answer to the question is option D
The second answer to the question must be option A
Option D must be chosen for the third question.
Option D must be selected for Question 4.
Solution:
1.
square of 3 is 9
3 to the power of negative 2 is 1/ 9
cube of 3 is 27
3 to the negative power 3 is 1/27
2.
cylinder volume =πr²h
Given value
pi =3.14
r=5
h=10
Volume=3.14×5²×10
cylinder volume =785m³
3.
When a point is rotated 90 degrees anticlockwise about the origin, it becomes the point (x,y) (-y,x).
The coordinates of Point N are (4, 3)
N' will be the new coordinates (-3, 4)
As a result, the y-coordinate of N' is 4.
4.
Option D must be selected for Question 4.
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The expression 1.05x calculates what change to the value of x?
With comparison to the initial value of x, this signifies an increase of 5%.
What is an illustration of an initial value?If, for instance, we have the mathematical problem y′=2x y ′ = 2 x, then y(3)=7 y (3) = 7 is an initial value, so when these equations are combined, they create an initial-value problem.
The calculation of a 5% increase in the value of x is done by the phrase 1.05x.
We may modify the phrase as follows to understand why:
1.05x = x + 0.05x
Thus, 1.05x is the same as increasing x by 5% from its initial value.
For example, if x = 100, then:
1.05x = 1.05 × 100 = 105
The initial value of x has increased by 5% as a result of this.
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With comparison to the initial value of x, this signifies an increase of 5%. Thus, option A is correct.
What is an illustration of an initial value?If, for instance, we have the mathematical problem y′=2x y ′ = 2 x, then y(3)=7 y (3) = 7 is an initial value, so when these equations are combined, they create an initial-value problem.
The calculation of a 5% increase in the value of x is done by the phrase 1.05x.
We may modify the phrase as follows to understand why:
1.05x = x + 0.05x
Thus, 1.05x is the same as increasing x by 5% from its initial value.
For example, if x = 100, then:
1.05x = 1.05 × 100 = 105
The initial value of x has increased by 5% as a result of this.
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Complete question:
The expression 1.05x calculates what change to the value of x?
a. increase of 5%
b. Power of 5
c. decrease of 5%
d. fraction of 5
Find the distance from Link to the Octorok so Link can attack
The distance from Link to the Octorok is 10.63 units.
How to find the distance?We know that the distance between two points (x₁, y₁) and (x₂, y₂) is given by the formula below:
distance = √( (x₂ - x₁)² + (y₂ - y₁)²)
Here we want to find the distance from Link to the Octorok so Link can attack, so we need to get the distance between the points (-4, -5) and (3, 3).
The distance will be:
distance = √( (3 + 4)² + (3 + 5)²)
distance = √( (7)² + (8)²)
distance = √113
distance = 10.63
The distance is 10.63 units.
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Let A and B be events with P(A) = 0.3, P(B) = 0.6, and P(A and B) = 0.03. Are A and B mutually exclusive? Explain why or why not.
Answer:
A and B are not mutually exclusive
Step-by-step explanation:
A and B are not mutually exclusive because P(A and B) > 0. If A and B were mutually exclusive, then they would have no outcomes in common and the probability of their intersection would be zero. However, in this case, they do share some outcomes, since P(A and B) is greater than zero.
5 Mrs. Newsome bought a piece of fabric 142 centimeters long to make a quilt for her son's bedroom. She bought a piece of fabric 2 meters long for curtains. How could Mrs. Newsome find the total length, in centimeters, of both pieces of fabric? Multiply 2 by 2,000, then add 142. Add 2 and 142, then multiply by 100. Divide 142 by 100, then add 2,000. O Multiply 2 by 100, then add 142. B C
Answer:
Step-by-step explanation:
To find the total length of both pieces of fabric in centimeters, we need to add the length of the first piece of fabric (142 cm) and the length of the second piece of fabric (2 meters).
However, we need to make sure that the units are consistent before we add the lengths. We can convert the length of the second piece of fabric from meters to centimeters by multiplying by 100. Therefore, the total length in centimeters is:
142 cm + 2 meters * 100 cm/meter = 142 cm + 200 cm = 342 cm
The option that correctly gives the answer is "Multiply 2 by 100, then add 142" (Option C).
can you help me to solve this question?
The asymptotes of the function f(x) = (2x² - 5x + 3)/(x - 2) are given as follows:
Vertical asymptote at x = 2.Oblique asymptote at: y = 2x - 3/2.How to obtain the asymptotes of the function?The function for this problem is defined as follows:
f(x) = (2x² - 5x + 3)/(x - 2)
The vertical asymptote is the value of x for which the function is not defined, hence it is at the zero of the denominator, and thus it is given as follows:
x - 2 = 0
x = 2.
The oblique asymptote is at the quotient of the two functions, hence:
(mx + b)(x - 2) = 2x² - 5x + 3
mx² + (b - 2m) - 2b = 2x² - 5x + 3.
Hence the values of m and b are given as follows:
m = 2.-2b = 3 -> b = -3/2.More can be learned about the asymptotes of a function at https://brainly.com/question/1851758
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performed 100 trials of a simulation to see what difference in proportions would occur due to chance variation
Performing a simulation with 100 trials is a common technique used to assess the impact of chance variation on the results of an experiment or study. The simulation can help you understand how likely it is to see certain results due to chance variation alone, rather than any underlying difference in proportions.
To perform this simulation, you would first need to define the two proportions that you want to compare. For example, you might want to compare the proportion of people who prefer brand A to brand B in a survey.
Next, you would randomly assign each trial to either brand A or brand B based on the defined proportions. For example, if the proportion of people who prefer brand A is 0.6, you would assign 60 out of the 100 trials to brand A and 40 trials to brand B.
After assigning each trial, you would then calculate the difference in proportions between the two groups. This would give you a distribution of differences that you would expect to see due to chance variation alone.
If the observed difference falls within the range of differences expected due to chance variation, you can conclude that the difference in proportions you observed is not statistically significant and may be due to chance.
However, if the observed difference is larger than what you would expect to see due to chance variation, you can conclude that the difference is statistically significant and likely due to an underlying difference in proportions.
To know more about chance variation:
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HELP Whats the Answer to this Stand Deviation Question?
Answer: he would be 2 standard deviations above the
Step-by-step explanation:
please help !! Given l, m, n, find the value of x.
(7x-2)° (5x+14)°
Answer:
Step-by-step explanation:
7x - 2 = 5x + 14
2x - 2 = 14
2x = 16
x = 8
