the moment of inertia of an object of mass m(a)m(a) is an intrinsic property of the object, (b) depends on the choice of axis of rotation, (c)(c) is proportional to mm regardless of the choice of axis, (d)(d) both (b)(b) and (c)(c) are correct.

If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.

How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.

Horizontal force acting on the cart, F = 11 N

Mass of the cart, m = 35 kg

To find,

Distance covered by the cart in 3.5 seconds if it starts from rest.

Solution,

Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :

s = 1.925 meters

In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."

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Refer to the photo taken.

The relation between the time-period of the transverse wave for the third harmonic and the time between the maximum displacement and minimum displacement is [tex]=16.3 \mathrm{~g}[/tex]

[tex]$$T_3=2 t$$Substitute$8.40 \mathrm{~ms}$[/tex]

for t in the above expression.

[tex]$$T_3=2(8.4 \mathrm{~ms})\left(\frac{10^{-3} \mathrm{~s}}{1 \mathrm{~ms}}\right)$$[/tex]

The wave velocity can be given by the following expression [tex]=0.0168 \mathrm{~s}[/tex]

[tex]v=\frac{\lambda_3}{T_3}[/tex]

Here,

[tex]$$\lambda_3$$[/tex]

is the frequency of third harmonics and

[tex]$$T_3$$[/tex]

is the time-period of third harmonics.

Substitute [tex]$0.1296 \mathrm{~m}$[/tex] for

[tex]$$\lambda_3$$[/tex]

and

[tex]$0.0168 \mathrm{~s}$ for$T_3$[/tex]

[tex]\begin{aligned}& v=\frac{0.1296 \mathrm{~m}}{0.0168 \mathrm{~m}} \\& =7.714 \mathrm{~m} / \mathrm{s}\end{aligned}[/tex]

The expression of the wave velocity is given by the following expression.

[tex]v=\sqrt{\frac{T}{m / L}}[/tex]

Rearrange the above expression for

[tex]$$m$$[/tex]

[tex]\text { Substitute } 5.00 \mathrm{~N} \text { for } T, 0.1944 \mathrm{~m} \text { for } L \text {, and } 7.714 \mathrm{~m} / \mathrm{s} \text { for } v \text { in the above expression. }[/tex]

[tex]\begin{gathered}m=\frac{(5.00 \mathrm{~N})(0.1944 \mathrm{~m})}{(7.714 \mathrm{~m} / \mathrm{s})^2} \\=(0.0163345 \mathrm{~kg})\left(\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}}\right) \\=16.3 \mathrm{~g}\end{gathered}[/tex]

The anti-nodes in the standing waves are at a distance half a wavelength. The time-period is twice the time from maximum displacement to minimum displacement of the anti-node.

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The volume of the toy is 80 ml.

To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.

In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.

The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.

It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.

Answer:

Volume of the toy: [tex]80\; {\rm mL}[/tex].

Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)

Explanation:

The graduated cylinder initially measures the volume of water in this cylinder:

[tex]V(\text{water}) = 70\; {\rm mL}[/tex].

Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:

[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].

Rearrange to find the volume of the toy:

[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].

To find the average density of this toy, divide mass by volume:

[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].

All galaxies outside the Local Group are moving away from us, and the farther away they are, the faster they're going.

We may learn a lot about the nature of the cosmos from Hubble's rule, which states essentially that a known universe velocity (or, as it is commonly displayed, its redshift) is precisely proportionate to its distance. The relationship between distance and speed should not exist if the cosmos is constant and unchanging.

The Hubble-Lemaître law, commonly referred to as Hubble's law, is the finding in astrophysics that planets are eloping from Earth at rates proportionate to their separation. In other words, they are travelling away from Earth more quickly the more away they are.

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Answer:

None of the choices you provided are correct. When a gas burns, it releases energy in the form of heat and light. Some of this energy is transferred to the pot of water, increasing its temperature, but some of the energy is also released as light. However, the rest of the energy is not transformed into chemical, electrical, or nuclear energy. Instead, it is lost to the environment in the form of waste heat. This is why gas stoves can become hot to the touch - they are releasing excess energy in the form of heat that is not being used to heat the pot of water.

Explanation:

To keep the car from slipping, the road and tires need to have a minimum coefficient of friction of 0.188.

The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, but it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible. Yes. Because the adhesive forces between molecules are stronger when the contact surface is substantially polished, frictional force increases. In this situation, the friction coefficient will be higher than one.

Here m= 1402 kg

r=53

v= 9.9 m/s

g=9.8

coefficient = (v^2) / rg

coefficient = (9.9^2) / (53*9.8)

coefficient = 98.01/519.4

coefficient = 0.188

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A tension of 3.5 to 4.5 is advised when sewing tough fabric, such denim or leather. This allows you to effortlessly maintain neatness across the fabric when sewing through it. Before starting to sew any thick material, check the attachments on your sewing machine and adjust the tension.

Depending on the thickness of the denim, I use a straight-stitch length between 3.0 mm and 4.0 mm. I also increase the tension on my machine to 4.6 (up from 4.0 for lightweight woven fabrics). If my denim has spandex in it, I use a stretch stitch, such as a narrow zigzag.

Linen, cotton and denim: These fabrics hold wrinkles well, so they require the highest heat, from 150 to 200 degrees. If needed, you may also use steam or spray water from a bottle or your iron.

The longer the stitch length, the easier and faster it will be to pull the fabric along the gathering threads. However, the shorter the stitch length, the easier it will be to achieve even gathers. We find a 4.5 mm setting to be a good compromise, but it's always a good idea to test and see what you prefer.

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The final temperature of the piece of iron with the mass of 9.8 grams on the absorption of 365J of energy is 113.56°C.

The specific heat capacity of a material can be defined as the quantity of heat energy (J) which is absorbed per unit mass (kg) of the material when its temperature is increased by 1 K (or 1 °C). The SI unit of specific heat capacity is J/(kg K) or J/(kg °C).

The specific heat capacity of a material can be calculated by the formula:

Q = m × c × ΔT

where, Q = heat energy,

m = mass of the material,

c = specific heat capacity,

ΔT = change in temperature

The final temperature of the piece of iron can be calculated by the formula:

Q = m × c × ΔT

ΔT = (Final temperature - initial temperature)

365J = 9.8 × 0.46 × ΔT

365J = 4.508 × ΔT

ΔT = 80.96

ΔT = Final temperature = initial temperature

ΔT = (T - 32.6)

80.96 = (T - 32.6)

T = 80.96 + 32.6

T = 113.56°C

Therefore, the final temperature of the piece of iron is 113.56°C.

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Three helium-4 nuclei (alpha particles) are turned into carbon by a series of nuclear fusion processes known as the triple-alpha process.

What results from the triple-alpha procedure as the finished product?

The triple-alpha process and the alpha process are two classes of nuclear fusion reactions that stars use to change helium into heavier elements. The alpha process is also referred to as the alpha ladder. [1] Only helium is used in the triple-alpha process, which also yields carbon.

Which statement concerning alpha particles in an atom is accurate?

Two protons and two neutrons make up alpha particles, which are identical to helium nuclei and have a positive charge.

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Answer:

(A)   9.2 Newtons

(B)   200.8 Newtons

Explanation:

Attached is the free body diagram I drew along with some of the work/formulas I used. Please ask me any questions you have in the comments about my diagram/work. I'd be happy to walk you through it.

Explanation:

If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.

The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:

Mass flow rate = Density * Flow rate

= Density * (Area * Velocity)

Where:

Density is the density of the fluid

Flow rate is the volume flow rate, or the rate at which volume flows through the pipe

Area is the cross-sectional area of the pipe

Velocity is the velocity of the fluid

The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.

The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:

A = pi * r^2

Where:

A is the cross-sectional area of the pipe

r is the radius of the pipe

The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:

A = pi * (1.5 cm)^2

= 7.07 cm^2

The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:

A = pi * (3 cm)^2

= 28.27 cm^2

Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:

(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)

Solving for v, the velocity on the narrow side, you get:

v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)

= 11.6 m/s

The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

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Answer:

x = A cos ω t          at t = zero, x displacement equals amplitude

x = .088 m cos ω t             describes the motion

We need yet to find ω in terms of P which is given

ω = √(k / m)        

P = 1 / f      and f = ω / (2 π)

Thus ω = 2 π f = 2 π / P       since 1 / f = P

This gives us

x = .088 m cos 2 π / .66 * t    

Answer:

Here is answer

Explanation:

a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.

b) The characteristics of the weight of solid 'S' are:

It acts in the downward direction.

It is a gravitational force that is exerted by the Earth on the solid 'S'.

It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).

c) The weight of solid 'S' can be represented by a vector as shown below:

[asy]

unitsize(1cm);

draw((0,0)--(0,15),Arrow(6));

label("$W$", (0,7.5), W);

[/asy]

a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.

b) These forces can be represented by vectors as shown below:

[asy]

unitsize(1cm);

draw((0,0)--(0,15),Arrow(6));

label("$W$", (0,7.5), W);

draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));

label("$N$", (7.5sqrt(2),7.5), NE);

draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));

label("$F_f$", (-7.5sqrt(2),-7.5), SW);

[/asy]

c) The characteristics of these forces are:

The normal force acts perpendicular to the surface of the inclined plane.

The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.

The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.

The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.

a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.

b) The characteristics of the gravitational force are:

It acts in the downward direction.

It is a force that is exerted by the Earth on the solid 'S'.

Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):

[asy]

unitsize(1cm);

draw((0,0)--(0,-1.3),Arrow(6));

label("$W$", (0,-0.65), S);

[/asy]

Answer:

5 m

Explanation:

Displacement is the straight-line distance from the starting point to the end point.  Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).  

d² = 3² + 4² = 25

d = [tex]\sqrt{25}[/tex] = 5 m

Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)

The force due to gravity will be 0.0272 Newtons.

The force between two mass-containing objects that are drawn toward one another is referred to as the gravitational pull. There is gravity everywhere around us. For instance, it maintains the planets in our solar system in orbit around the Sun. Additionally, because to gravity, the Moon maintains its orbit around the Earth.

Despite being weak and appealing, gravitational forces exist.

Given, mass of one object= 2300 kg

mass of another object= 4000 kg

distance between the two objects= 0.150 m

value of G is universal, [tex]G= 6.67[/tex]×[tex]10^{-11}[/tex] [tex]N m^{2} / kg^{2}[/tex]

the equation is, [tex]F=G\frac{M1 . M2}{d^{2} }[/tex]

                       [tex]F=0.0272 N[/tex]

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The new gravitational force between the object will be 1/20.25 times of the original force.

The gravitational force between any two object is defined as the product of the masses of the object and it is inversely proportional to the square of the distance between them which is given by,

F = GMm/R²

Here,

G is the universal gravitational constant, M and m are the mass of the body and R is the distance between them.

As per the given question the distance between the object is increased 4.5 times the original separation.

R' = 4.5R.

The new force of attraction between the object will be,

F' = GMm/(R')²

F' = GMm/(4.5R)²

F' = GMm/20.25R²

F' = F/20.25

So, the new force of attraction between the two objects will become 1/20.25 times of original force.

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The kinetic energy is 939.87 J.

Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. The object will be moving at a new, constant speed once the work is done because energy has been transferred to it.

A particle, an object, or a collection of particles can move because of kinetic energy, which is the force that drives motion. Kinetic energy is used by objects in motion like a person walking, a baseball being thrown, food falling from a table, and charged particles in an electric field.

Kinetic energy = 1/2mv²

Kinetic energy =  1/2×0.06×177²

Kinetic energy = 939.87 J.

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(a) The normal force is 267.7 N and frictional force is 980 N.

(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.

(c) The direction of the contact force is 1016 N.

∈(t) = 0

N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )

N₂ = 267.7 N

(a) Normal force F(d) = N₂ = 267.7 N

Frictional force N = 800 + 180

                         N = 980 N

(b) The minimum coefficient of static friction,

F(d) = μ N₁

μ = F / N₁

μ = 267.7 / 980

μ = 0.27

(c) The direction of the contact force,

R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]

R = 1016 N

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The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.

To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.

Now, we know that momentum =mass × velocity

So, initial momentum of first object=6.2×3=18.6Kg-m/sec

Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec

Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg

Now, both objects are moving with common velocity, so assume both have velocity v

=>So, final momentum of both objects is =14.2×v

according to law of conservation of momentum

=>18.6+25=14.2v

=>43.6=14.2v

=>v=43.6/14.2

=>v=3.07m/sec

Hence, final velocity of objects are 3.07m/sec.

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The pattern gets bigger as the light wave length gets longer. other maxima are further from the central one and are wider.

A wavelength is the distance between two identical locations (adjacent crests) in successive cycles in a waveform signals that is transmitted by a wire or in space. Typically, this length is expressed in feet (m), millimeters (cm), or millimeters (mm) in wireless systems (mm).

The distance that separates two wave crests is known as the wavelength, and it also applies to troughs. The number of vibrations that pass across a certain area in a second, or 60hz (Hz), is the unit of measurement for frequency (Hertz).

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We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.

acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.

An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.

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The required values are a) T = 2.3 seconds, b)  f = 0.434 Hz, c) ω = 2.7 rd/s.

Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.

Given,

Time = 11.5 seconds to five complete vibrations.

a) Time period is time taken to complete one vibration,

So T = 11.5/5 = 2.3 seconds

b) Frequency(f) = 1/T

f = 1/2.3 = 0.434 second inverse.

c) By using formula of angular frequency ω = 2π/T

ω = 2π/2.3 = 2.7 hz

Thus, final values are a) T = 2.3 seconds, b)  f = 0.434 second inverse, c) ω = 2.7 rd/s.

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Let us find first the forces at 1, 2 & 3 points.

We know that ke= 8.99 * 109N.m2 / C2

The forces are: -

F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2

F1 = 359.6 N

F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2

F2 = 29.96 N

F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2

F3 = 269.7 N

Now,

The net force on q1 is F1 – F2,

i.e. F1 + F2 = 359.6 + 29.96

F(q1) = 389.56 N to the left

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So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.

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Answer:

Below

Explanation:

Normal force will be   mg cos 15° = 1.5*9.81 cos 15°   Newtons

Downplane force will be  mg sin 15° = 1.5 * 9.81  sin 15°    N

Acceleration

F = ma

F/m = a

1.5 ( 9.81) sin 15° / 1.5   m/s^2  = a

The system that is more energy efficient is system A because it makes use of electricity to produce more results.

Energy efficiency is the use of less energy to perform the same task or produce the same result.

Energy-efficient homes and buildings use less energy to heat, cool, and run appliances and electronics, and energy-efficient manufacturing facilities use less energy to produce goods.

Energy efficiency has the following benefits:

According to this question, the following applies:

Based on the above explanation, it can be observed that system A is more energy efficient because it uses the same electricity to achieve more.

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The maximum height an object will reach if it is thrown vertically upwards at 24.0 m/s will be equal to 29.35 meters.

Kinetic energy is the term used in physics to describe the force that a moving item has.

It is described as the amount of effort necessary to accelerate anybody with a particular mass from rest to a given velocity. Except for variations in speed, the body retains the kinetic energy it gains during acceleration.

As per the given information in the question,

The formula of kinetic energy is,

K.E = 1/2 mv²   (i)

The formula of gravitational potential energy is,

u = mg     (ii)

Equate equations (i) and (ii)

1/2 mv² = mgh

h = 1/2 v²/g

h = 1/2 (24)²/9.81

= 576/19.62

h = 29.35 meters.

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During a game of bowling the ball's motion:

The correct options are A,B and E.

Bowling ball motion is commonly divided into sequential skid, hook, and roll phases. When the ball moves down the lane in the skid and hook phases, frictional contact with the lane causes the ball's forward (translational) speed to continually decrease, but to continually increase its revolution rate (rotational speed).

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