The mean volume for a bottle of cologne is 4 ounces and the standard deviation is 0.22 ounces. A random sample of 121 bottles is taken. What is the probability of obtaining a sample mean within 0.04 ounces of the population mean?

a. 0.9545
b. 0.0363
c. 0.3085
d. 0.5000

Answers

Answer 1

Answer:

The standard error of the mean is 0.02

Step-by-step explanation:

Here, we want to calculate the standard error of the mean.

Mathematically;

standard error of mean = SD/ √n

where SD is the standard deviation and n is the number of samples

From the question, SD = 0.22 and n = 121

Inserting this into the equation

Standard error of the mean = 0.22/√121

= 0.22/11 = 0.02

Answer 2

The probability of obtaining a sample mean is "0.9545".

According to the question,

Mean,

[tex]\mu = 4[/tex]

Standard deviation,

[tex]\sigma = 0.22[/tex]

Random sample,

[tex]n = 121[/tex]

By Central limit theorem,

→ [tex]\bar {x} \sim (4, \frac{0.22}{\sqrt{121} } )[/tex]

     [tex]= 0.2[/tex]

Now,

→ [tex]P(|\bar{x} - \mu| \ \alpha \ 0.04) = P(-0.04 \ \alpha \ \bar{x} - \mu \ \alpha \ 0.04)[/tex]

                               [tex]= P(\frac{-0.04}{0.02} \ \alpha \ z \ \alpha \ \frac{0.04}{0.02} )[/tex]

                               [tex]= P(-2 \ \alpha \ z \ \alpha \ 2)[/tex]

                               [tex]= 0.9545[/tex]

Thus the above response i.e., "option a" is appropriate.

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https://brainly.com/question/16943601


Related Questions

A farmer with 5000 feet of fencing wants to enclose a rectangular field and then divide it into two plots by adding a fence in the middle parallel to one of the sides. Using the function A(x) , analytically find the WIDTH of the field that would maximize its area. (Round your answer to the nearest whole number)

Answers

Answer:

The required width of the field that would maximize the area is = 1250  feet

Step-by-step explanation:

Given that:

The total fencing length = 5000 ft

Let consider w to be the width and L to be the length.

Then; the perimeter of the rectangular field by assuming a parallel direction is:

P = 3L + 2w

⇒ 3L + 2w = 5000

3L = 5000 - 2w

[tex]L = \dfrac{5000}{3} - \dfrac{2w}{3}[/tex]

Recall that:

The area of the rectangle = L×w

[tex]A(w) = ( \dfrac{5000}{3}-\dfrac{2}{3} ) w[/tex]

[tex]A(w) = \dfrac{5000}{3}w-\dfrac{2}{3} w^2[/tex]

Taking the differentiation of both sides with respect to t; we have:

[tex]A' (w) = \dfrac{5000}{3} - \dfrac{2}{3} ( 2 w)[/tex]

[tex]A' (w) = \dfrac{5000}{3} - \dfrac{4w}{3}[/tex]

Then; we set A'(w) to be equal to zero;

So; [tex]\dfrac{5000}{3} - \dfrac{4w}{3}=0[/tex]

5000  = 4w

w = 5000/4

w = 1250

Thus; the required width of the field that would maximize the area is = 1250  feet

Also, the length [tex]L = \dfrac{5000}{3} - \dfrac{2w}{3}[/tex] can now be :

[tex]L = \dfrac{5000}{3} - \dfrac{2(1250)}{3}[/tex]

L = (5000 -2500)/3

L = 2500/3 feet

Suppose, the farmer divides the plot parallel to the width; Then  2500/3 feet = 833.33 feet and the length L = 1250 feet.

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Step-by-step explanation:

Given parameters:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

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