The mass flow rate through a centrifugal compressor is 1 kg/s. If air enters at 1 bar and 288k and leaves at 200 kN/m² and 370k, determine the power of the compressor. Take Cp = 1.103 kJ (kg.K), R = 287 kJ (kg.k)​

Answer:

0.75

Explanation:

From this question above we have the following information

A = probability of investment in mutual fund= 0.6

B = probability of investment in government fund = 0.3

C = probability of investing in both the mutual fund and the government= 0.15

Where to find the probability of this investor investing in either of these two

= Prob(a) + prob(b) - prob(c)

= 0.6 + 0.3 - 0.15

= 0.9 - 0.15

= 0.75

Answer:

The new length of the rod is 182 cm.

Explanation:

Given that a rod that was originally 100-cm-long experiences a strain of 82%, to determine what is the new length of the rod, the following calculation must be performed:

100 x 1.82 = X

182 = X

Therefore, the new length of the rod is 182 cm.

Explanation:

print() has a variable number of parameters. this is the answer.

hope this helps you

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Answer:

. 1. Type of building

2. Location of emergency

3. Extent of emergency

Explanation:

1. The kind of building in which people find themselves could be a factor that can be used to make this decision. a lot of buildings can be easily affected by disasters such as explosions or tornadoes the extent of the effect is dependent on how the building is constructed. in some situations it is better to shelter in, while in others it is best to evacuate.

2. Another factor to be considered is the location or area where this is happening it is good to consider this so that people can be safely moved given that help can be easily accessed or if best to stay in.

3. The last is the extent of what is happening. The risk involved is one way of making the choice to evacuate or to stay.

The factors that affect the decision on whether to evacuate or shelter in place include:

It should be noted that the building where an individual lives play a vital role during emergencies. Buildings that have poor foundations can easily be affected during emergencies.

Another factor that should be considered is the location where the emergency is taking place. Lastly, the extent of the emergency can determine if the person should stay or not.

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Answer:

Following are the solution to the given question:

Explanation:

Line voltage:

[tex]V_L=\sqrt{3}V_{ph}=\sqrt{3}(120) \ v[/tex]

Power supplied to the load:

[tex]P_{L}=\sqrt{3}V_{L}I_{L} \cos \phi[/tex]

[tex]10\times 10^3=\sqrt{3}(120 \sqrt{3}) I_{L}\ (0.85)\\\\I_{L}= 32.68\ A[/tex]

Check wye-connection, for the phase current:

[tex]I_{ph}=I_L= 32.68\ A[/tex]

Therefore,

Phasor currents: [tex]32.68 \angle 0^{\circ} \ A \ ,\ 32.68 \angle 120^{\circ} \ A\ ,\ and\ 32.68 -\angle 120^{\circ} \ A[/tex]  

Magnitude of the per-phase load impedance:

[tex]Z_{ph}=\frac{V_{ph}}{I_{ph}}=\frac{120}{32.68}=3.672 \ \Omega[/tex]

Phase angle:

[tex]\phi = \cos^{-1} \ (0.85) =31.79^{\circ}[/tex]

Please find the phasor diagram in the attached file.

Answer:

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Explanation:

209781

Answer:

a) 1.918 kw

b) 86.23%

c) 0.26 kw

Explanation:

Given data:

T1 = -30°C = 243 k  , T0 = 27°C

using steam tables

h1 = 232.19 KJ/kg

s1 = 0.9559 Kj/Kgk

T2 = 55°C   P2 = 900 kPa

Psat = 1492 kPa,  h2 = 289.95 Kj/Kg, s2 = 0.9819 Kj/kgk , m = 0.0332 kg/s

a) Determine the power input to the compressor

power input = 1.918 kw

b) Determine isentropic efficiency of compressor

Isentropic efficiency = 86.23%

c) Determine rate of exergy destruction

rate = 0.26 kw

Attached below is the detailed solution of the given problems

Answer:

Technician B only.

Explanation:

It is not necessary that all electric motors will use Direct current, some may also use Alternative current. Some electric motors that use DC may use brushes. There are two types of brushless motors that use alternative current.

Answer:

The correct answer is "99.9%".

Explanation:

According to the information given in the question,

[tex]P(1 \ fail) = 0.1[/tex]

The probability of all fail will be:

[tex]P(all \ fail) = (0.1)^3[/tex]

                  [tex]=0.001[/tex]

hence,

[tex]P(not \ all \ fail)= 1-P(all \ fail)[/tex]

                        [tex]=0.999[/tex]

                        [tex]=99.9[/tex] (%)

Thus the above is the right answer.

Answer:

attached below

Explanation:

a) G(s) = 1 / s( s+2)(s + 4 )

Bode asymptotic magnitude and asymptotic phase plots

attached below

b) G(s) = (s+5)/(s+2)(s+4)

phase angles = tan^-1 w/s , -tan^-1 w/s , tan^-1 w/4

attached below

c) G(s)= (s+3)(s+5)/s(s+2)(s+4)

solution attached below

Answer:

very good thx

Explanation:

Answer:

The answer of these questions is

Explanation:

b) NO

Answer:

a)[tex]V_1=4.88m^2/s[/tex]

  [tex]V_2=4.88m^2/s[/tex]

b)[tex]P=-119.18kW[/tex]

Explanation:

From the question we are told that:

Steady State Saturated vapor [tex]T_1= -20C=>253k[/tex]

Mass Flow rate [tex]M=1.2kg/s[/tex]

Exit Pressure [tex]P_2=7bar[/tex]

Exit Temperature [tex]T_2=70C=>373k[/tex]

From Refrigerant 134a Properties

[tex]T_1= -20C =>P_1=1.399 bar[/tex]

Generally the equation for Volumetric Flow rate is mathematically given by

For Inlet

[tex]V_1=m\frac{RT_1}{P_1}[/tex]

[tex]V_1=m\frac{8314*253}{1.399*10^3}[/tex]

[tex]V_1=18.97m^2/s[/tex]

For outlet

[tex]V_2=m\frac{RT_2}{P_2}[/tex]

[tex]V_2=1.2*\frac{8314*343}{7*10^3}[/tex]

[tex]V_2=4.88m^2/s[/tex]

b)

Generally the equation for Steady state mass and energy equation  is mathematically given by

[tex]P=m(h_1-h_2)[/tex]

From Refrigerant 134a Properties

[tex]T_1= -20C =>h_1=24.76kJ/kg[/tex]

[tex]T_2= 70C =>h_2=124.08kJ/kg[/tex]

Therefore

[tex]P=1.2(12.76-124.08)[/tex]

[tex]P=-119.18kW[/tex]

Therefore

Power input into the compressor is

[tex]P=-119.18kW[/tex]

Answer:

[tex]V_{pp}=2V[/tex]

Explanation:

Source Voltage [tex]V= 120V[/tex]

Frequency [tex]f=60Hz[/tex]

Peak output voltage [tex]Vp=15V[/tex]

Peak Output Voltage with filter [tex]V_p'=14V[/tex]

Generally the equation for Peak to peak voltage is mathematically given by

[tex]V_p'=V_p-\frac{V_{pp}}{2}[/tex]

Therefore

[tex]V_{pp}=2(V_p-v_p')[/tex]

[tex]V_{pp}=2(15-14)[/tex]

[tex]V_{pp}=2V[/tex]

Answer:

[tex]l=24mm[/tex]

Explanation:

From the question we are told that:

Plane strain fracture toughness of [tex]T=55 MPa-m1/2[/tex]

Y value [tex]Y=1.0[/tex]

Stress level of[tex]\sigma =200 MPa[/tex]

Generally the equation for length of a surface crack is mathematically given by

[tex]l=\frac{1}{\pi}(\frac{T}{Y*\sigma})^2[/tex]

[tex]l=\frac{1}{3.142}(\frac{55}{1*200})^2[/tex]

[tex]l=0.024m[/tex]

Therefore

in mm

[tex]l=24mm[/tex]

Answer: (b)

Explanation:

Given

Original length of the rod is [tex]L=100\ cm[/tex]

Strain experienced is [tex]\epsilon=82\%=0.82[/tex]

Strain is the ratio of the change in length to the original length

[tex]\Rightarrow \epsilon =\dfrac{\Delta L}{L}\\\\\Rightarrow 0.82=\dfrac{\Delta L}{100}\\\\\Rightarrow \Delta L=82\ cm[/tex]

Therefore, new length is given by (Considering the load is tensile in nature)

[tex]\Rightarrow L'=\Delta L+L\\\Rightarrow L'=82+100=182\ cm[/tex]

Thus, option (b) is correct.

Answer:

[tex]U=\pm 0.382N[/tex]

Explanation:

From the question we are told that:

Resolution: 0.25 N

Range: 0 to 100 N

Linearity error: within 0.20 N over range

Hysteresis error: within 0.30 N over range

Generally the equation for Stage Uncertainty is mathematically given by

[tex]U=\sqrt{u_0^2+u_T^2}[/tex]

Where

[tex]u_0=Zero\ order\ uncertainty[/tex]

[tex]u_0=\pm 0.5*0.25[/tex]

[tex]u_0=\pm=0.125[/tex]

And

u_T=Total instrumental Uncertainty

[tex]u_T=\sqrt{l_e^2+h_e^2}[/tex]

Where

l_e=Error of linearity

h_e=Error due to hysteresis

Hence

[tex]u_T=\sqrt{0.20^2+0.30^2}[/tex]

[tex]u_T=\pm 0.36[/tex]

Therefore

[tex]U=\sqrt{(0.125)^2+0.36^2}[/tex]

[tex]U=\pm 0.382N[/tex]

Answer:

The answer is below.

Explanation:

Some of the ways, how I think elliptic cryptography is more advanced than RSA are the following:

1. ECC - Elliptic Curve Cryptography uses smaller keys for the same level of security, particularly at greater levels of security.

2. ECC can work well and at a faster rate on a small-capacity device compared to RSA

3. It uses offer speedier SSL handshakes that enhance security

4. It offers fast signatures

5. It allows signatures to be computed in two stages, which enables lower latency than inverse throughput.

6. Relatively quick encryption and decryption

i have made notes and saved it as a pdf u can take it to answer question and make ur concept good

The minimum length of vertical curve that will provide 220 m stopping sight distance is; 458.8 m

Stopping sight distance; S = 220 m

Design Speed; V = 110 km/h

Intersection grade 1; G1 = +2.7

Intersection Grade 2; G2 = -3.5

From the table, at S = 220 m and V = 110 km/h, we can see that;

Radius of vertical curvature; K = 74

A = G1 - G2

A = 2.7 - (-3.5)

A = 2.7 + 3.5

A = 6.2

L = KA

Thus;

L = 74 × 6.2

L = 458.8 m

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Answer:

Explanation:

To obtain 240 V from 12 V batteries they must be connected in series. The number needed is ...

  240/12 = 20 . . . batteries needed

__

The current draw will be ...

  (3000 W)/(240 V) = 12.5 A

Then the time available from the battery stack is ...

  (120 Ah)/(12.5 A) = 9.6 h

The motor can run 9.6 hours from the series connection.

In heavy traffic areas, you should wave pedestrians across the street if there is no crosswalk: False.

A crosswalk can be defined as the marked or specially paved part of a road that is characterized by heavy traffic, so as to enable pedestrians have right of way to cross the street because drivers are required by traffic law to stop for them.

However, a driver or other road users in heavy traffic areas shouldn't wave pedestrians across the street if there is no crosswalk

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Answer:

320 m

Explanation:

To find the side length of the current park, x, we solve the quadratic equation for the area of the park

x² + 200x = 166400

x² + 200x - 166400 = 0

We multiply -166400 by x² to get -166400x². We now find the factors of 166400x² that will add up to 200x. These factors are -320x and 520x

So, we re-write the expression as

x² + 200x - 166400 = 0

x² + 520x - 320x - 166400 = 0

We write out the factors of the expression,

x² + 520x - 320x - 320 × 520 = 0

Factorizing the expression, we have

x(x + 520) - 320(x + 520) = 0

(x + 520)(x - 320) = 0

x + 520 = 0 or x - 320 = 0

x = -520 or x = 320

Since x is not negative, we take the positive answer.

So, x = 320 m

Answer:

a) [tex]\mu=3.3[/tex]

b)  [tex]Q=1440.7KJ/Kmol[/tex]

c)  [tex]W=1872.9KJ/Kmol[/tex]

Explanation:

From the question we are told that:

Initial Temperature [tex]T_1=325k[/tex]

initial Pressure [tex]P_1=2 bar[/tex]

Final Pressure [tex]P_2=4 bar[/tex]

iso-thermal expansion [tex]T_2=250k[/tex]

a)

Generally the equation for Coefficient of performance is mathematically given by

[tex]\mu=\frac{T_2}{T_1-T_2}[/tex]

[tex]\mu=\frac{250}{325-250}[/tex]

[tex]\mu=3.3[/tex]

b)

Generally the equation for Heat Expansion is mathematically given by

[tex]Q=RT_2 In(\frac{P_2}{P_1})[/tex]

Where

R=Gas constant

[tex]R=8.314462618[/tex]

Therefore

[tex]Q=8.314462618*250 In(\frac{4}{2})[/tex]

[tex]Q=1440.7KJ/Kmol[/tex]

c)

Generally the equation for work input is mathematically given by

[tex]W=RT_1 In(\frac{P_2}{P_1})[/tex]

[tex]W=8.314462618*250 In(\frac{4}{2})[/tex]

[tex]W=1872.9KJ/Kmol[/tex]

The coefficient of performance is 3.33, the heat transfer in the isothermal expansion is 1440.71kJ/K.mol and the work input is calculated as 1872.92kJ/K.mol

Given Data:

Isothermal expansion occurs at 250K.

This is calculated as

COP =[tex]\frac{T_2}{T_1-T_2}=\frac{250}{325-250} =3.33[/tex]

[tex]Q = RT_2In(\frac{p_2}{p_1})[/tex]

Therefore; In isothermal process du = 0

R = 8.314 AkJ/K.mol

Q = 8.314 * 250 In(4/2)

Q = 1440.71kJ/K.mol

W[tex]_i_n[/tex]=[tex]RT_1In(\frac{p_2}{p_1})\\W_i_n=8.314*325In(4/2)\\W_i_n=1872.92kJ/K.mol[/tex]

The work input is 1872.92kJ/K.mol

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Answer:

Explanation:

Using the kinematics equation [tex]v = v_o + a_ct[/tex] to determine the velocity of car B.

where;

[tex]v_o =[/tex] initial velocity

[tex]a_c[/tex] = constant deceleration

Assuming the constant deceleration is = -12 ft/s^2

Also, the kinematic equation that relates to the distance with the time is:

[tex]S = d + v_ot + \dfrac{1}{2}at^2[/tex]

Then:

[tex]v_B = 60-12t[/tex]

The distance traveled by car B in the given time (t) is expressed as:

[tex]S_B = d + 60 t - \dfrac{1}{2}(12t^2)[/tex]

For car A, the needed time (t) to come to rest is:

[tex]v_A = 60 - 18(t-0.75)[/tex]

Also, the distance traveled by car A in the given time (t) is expressed as:

[tex]S_A = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2[/tex]

Relating both velocities:

[tex]v_B = v_A[/tex]

[tex]60-12t = 60 - 18(t-0.75)[/tex]

[tex]60-12t =73.5 - 18t[/tex]

[tex]60- 73.5 = - 18t+ 12t[/tex]

[tex]-13.5 =-6t[/tex]

t = 2.25 s

At t = 2.25s, the required minimum distance can be estimated by equating both distances traveled by both cars

i.e.

[tex]S_B = S_A[/tex]

[tex]d + 60 t - \dfrac{1}{2}(12t^2) = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2[/tex]

[tex]d + 60 (2.25) - \dfrac{1}{2}(12*(2.25)^2) = 60 * 0.75 +60((2.25)-0.75) -\dfrac{1}{2}*18*((2.25)-0.750)^2[/tex]

d + 104.625 = 114.75

d = 114.75 - 104.625

d = 10.125 ft

Answer:

ROLAP  is a branch of OLAP that is used to contain Relational database ( RDB ). which is a very fast database ( quick process of queries )

Explanation:

ROLAP ( Relational On-line Analytical processing ) is a branch of OLAP that is used to contain Relational database ( RDB ).

Advantages of ROLAP ( reasons for the use of ROLAP )

Answer:

Digestion functions become more active

Explanation:

I just took the text!

Answer:

I think ( MOV Metal oxide varistors )

Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more MOV Metal oxide varistors than bypass and absorb the energy of the transient.