Complete Question:
The length, breadth and height of an object are 20 cm, 15 cm and 25 cm respectively. Its mass is 7 kg. Find its volume and density
Answer:
a. Volume of cuboid = 7500 cm³
b. Density = 0.000933 Kg/cm³
Explanation:
Given the following data;
Length = 20 cmBreadth = 15 cmHeight = 25 cmMass = 7 kga. To find the volume of the object.
An object that has a length, breadth and height is a cuboid.
Mathematically, the volume of a cuboid is given by the formula;
Volume of cuboid = length * breadth * height
Substituting into the formula, we have;
Volume of cuboid = 20 * 15 * 25
Volume of cuboid = 7500 cm³
b. To find the density of the object;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the formula;
[tex] Density = \frac {mass}{volume} [/tex]
Substituting into the formula, we have;
[tex] Density = \frac {7}{7500} [/tex]
Density = 0.000933 Kg/cm³
1. Which pair of physical quantities consists of two vectors?
a. Electric charge and momentum
b. Displacement and distance
c. Velocity and force
d. Temperature and kinetic energy
Answer:
Velocity and force consists of two vectors as they both have magnitude and direction
Pair of physical quantities consists of two vectors are velocity and force.
What are physical quantities ?"The seven elemental physical quantities are mass, time, temperature, mole, length, luminosity, and electrical charge. "Some derived physical quantities are velocity, heat, density, pressure, and momentum. Extensive physical quantities depend on the amount of substance or the size of the object.
What is velocity ?"Velocity is the speed at which something moves in a particular direction. For example as the speed of a car travelling north on a highway, or the speed a rocket travels after launching. "The scalar means the absolute value magnitude of the velocity vector is always be the speed of the motion.
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Which activity is best described as a scientific endeavor?
A. Designing devices astronauts can use to help them stay healthy
while in space
B. Developing a procedure for testing how extended stays in space
affect the human body
C. Performing tests on devices used by astronauts to ensure they
can be used safely
D. Creating a process for improving the design of equipment used to
monitor astronauts' health
Answer:
B
Explanation:
BECAUSE TO DO THE TESTS YOU NEED TO DO THE SCIENTIFIC METHOD.
FOR EXAMPLE: OBSERVATIONS AND EXPERIMENTS TO OBTAIN RESULTS.
ANYWAY I LEAVE YOU THE LINK:
https://gscourses.thinkific.com
Answer pls. This is for People like me with this Question . Help!!! Question 3 of 20 What happens to the electric force between two particles if the distance between them is reduced by half? O A. It decreases to half the original force. OB. It increases to twice the original force. O C. It increases to 4 times the original force. O D. It decreases to 1/4 of the original force.
Answer:
It increases twice the original
which is part of the convection cycle in earths atmosphere?
a. hot, denser air rises
b. cold, denser air rises
c. hot, less-dense air rises
d. cold, less-dense air falls
A thunderclap sends a sound wave through the air and the ocean below. The
thunderclap sound wave has a constant frequency of 100 Hz. What is the
wavelength of the sound wave in water? (The equation for the speed of a
wave is v= f x 1.)
Water
Diamond
Glass
Air
1,493
12,000
5,640
346
Speed of
sound
(m/s)
A. 11.00 m
B. 12.00 m
C. 14.93 m
D. 3.46 m
Answer:
C. 14.93 m
Explanation:
The given frequency of the wave, f = 100 Hz
The given equation for the wave speed, v, is presented as follows;
v = f × λ
The speed of sound in water, v = 1,493 m/s
Therefore, we get;
The wavelength, λ = v/f
∴ λ = 1,493 m/s/(100 Hz) = 14.93 m
The wavelength, λ = 14.93 m.
A pendulum of mass 18 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 17 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that a=98 m/s2
By the work-energy theorem, the total work done on the mass as it swings is
W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J
No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.
If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.
Now, if w is the amount of work done by friction/air resistance, then
(176.4 N) h - w = 153 J
If you know the starting height h, then you can solve for w.
Which statement describes why energy is released in a nuclear fission reaction based on mass-energy equivalence?
A. For large nuclei, the mass of the original nucleus is greater than the mass of the products.
B. For large nuclei, the mass of the original nucleus is less than the mass of the products.
C. For small nuclei, the binding energy of the lighter nuclei is greater than the binding energy of the heavier nucleus.
D. For small nuclei, the binding energy of the lighter nuclei is less than the binding energy of the heavier nucleus.
Answer:
A is the answer!
Explanation:
Edge 2021
Answer:
A
Explanation:
Edge
A frictionless pulley used to lift 8000N of concrete. What is the minimum effort required to raise the block
Answer: 8000N
Explanation: since it is frictionless that means it has 100% efficiency therefore the mechanical advantage is 1 meaning the load equals to the effort
Convertir 25 km/h a m/s
Answer:
6.9 m/s
Explanation:
1000m = 1km
3600s = 1hr
25000m/3600s
6.9m/s
if the pelican in item 3 was traveling at the same speed but was only 2.7m above the water, how far would the fish travel horizontally before hitting the water?
Answer:
5.66 m
Explanation:
From online sources, the speed in item 3 being referred to was discovered to be 7.62 m/s
Now, let's get the time of flight from one of Newton's equation of motion;
S = ut + ½gt²
Considering the vertical component, we have u = 0 m/s.
Thus;.
S = ½gt²
Plugging in the relevant values;
2.7 = ½ × 9.8 × t²
t² = 2.7/4.9
t = √(2.7/4.9)
t = 0.7423 s
Now, when we consider the horizontal component of the motion, we have;
S = vt
Where;
S is the distance the fish will travel horizontally before hitting the water.
v = 7.62 m/s
t = 0.7423
Thus
s = 7.62 × 0.7423
s ≈ 5.66 m
Can someone help me with this Physics question please?
Q. The half-life of tritium (hydrogen-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a mishap, what mass of the sample will remain after 49.2 years?
Answer:
Explanation:
The formula for this, the easy one, is
[tex]N=N_0(\frac{1}{2})^{\frac{t}{H}[/tex] where No is the initial amount of the element, t is the time in years, and H is the half life. Filling in:
[tex]N=48.0(\frac{1}{2})^{\frac{49.2}{12.3}[/tex] and simplifying a bit:
[tex]N=48.0(.5)^4[/tex] and
N = 48.0(.0625) so
N = 3 mg left after 12.3 years
How many half-lifes is 49.2 years ?
(49.2 years) / (12.3 years per half-life) = 4 half-lifes.
In 4 half-lifes, (1/2) · (1/2) · (1/2) · (1/2) of the original sample remains.
That's (1/2⁴) or (1/16) of the original.
(1/16) of 48.0 mg = 3 mg .
=======================
Step-by-step:
== Start with 48 mg .
== After one half-life, 24 mg remains.
== Then, after the second half-life, 12 mg remains.
== Then, after the third half-life, 6 mg remains.
== Then, after the fourth half-life, 3 mg remains.
For saving lives, what is the most important safety feature on a car? A. Air bag B. Safety Belt C. Anti-lock brakes
For saving lives the most important safety feature on a car is B. Safety Belt
What are safety features of a car ?Safety features of a car is a feature of a product designed to ensure or increase safety.
Air bag and Anti-lock brakes are the supplemental protection and designed to work best with combination with seat bells.
Air bag reduce the chance that upper body or head will strike the vehicle's interior during a crash alongside with belt that will also hold your upper body
so, the primary safety feature is seat belt and Air bag and Anti-lock brakes comes in secondary safety feature as they increases the safety and risk of getting an injury during any accident
correct answer is B. Safety Belt
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write the relation of m² with its a multiple
Explanation:
The square meter is the SI-derived unit of area. It has a symbol m² (33A1 in Unicode). It is defined as the area of a square whose sides measure exactly one metre.
Why is a flower not a good blackbody radiator?
Answer:
A flower emits only visible light
A flower reflects much of the light that hits it
Help me please!!!!!!!!!
Answer:
// EDU HACK REDDIT EDITON //
if (running == null) {
var running = null; console.log("Program Loading...");
var iframe = document.getElementById("stageFrame");
for (i = 0; i < 1; i++) {
setInterval(function() {
if (running == null) { running = true; console.log('Program Loaded! Enjoy!') }
if (iframe.contentWindow.document.getElementsByClassName('FrameRight') != null) { iframe.contentWindow.document.getElementsByClassName('FrameRight')[0].onclick(); }
if (iframe.contentWindow.document.getElementById("invis-o-div") != null) { iframe.contentWindow.document.getElementById("invis-o-div").remove(); }
},1000);
}
} else {kgg
console.log("Program already running!")
}
Explanation:
what is projectile motion
[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]
[tex]\sf{\qquad{\qquad{\underline{\underline{ Projectile~motion }}}}}[/tex]
If an object is given an initial velocity in any direction and then allowed to travel freely under gravity only, it is called a projectile motion.
It is basically 3 types
horizontally projectile motion oblique projectile motion included plane projectile motionThe path followed by a projectile is called its trajectory.
Projectile motion is when an object moves in a bilaterally symmetrical, parabolic path.
The path that the object follows is called its trajectory.
Projectile motion only occurs when there is one force applied at the beginning, after which the only influence on the trajectory is that of gravity
Photosynthesis is a process in which plants prepare food using carbon dioxide, chlorophyll, and water in the presence of sunlight.
A parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is connected in series to a 4.89 μF capacitor. This three‑capacitor combination is connected to a 15.5 V battery. Determine the charge on each capacitor.
Answer:
a. i. 35.96 μC b. i. 11.98 μC ii. 24.04 μC
Explanation:
We need to find the total capacitance of the system C.
The total capacitance of the parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is C' = 1.47 μF + 2.95 μF = 4.42 μF.
C' = 4.42 μF is in series with the 4.89 μF capacitor and for a series combination of capacitors, we have the total capacitance, C from
1/C = 1/4.42 μF + 1/4.89 μF
1/C = (4.42 μF + 4.89 μF)/(4.42 μF × 4.89 μF)
1/C = 9.31 μF/21.6138 μF²
C = 21.6138/9.31 μF
C = 2.32 μF
So, the total charge in the circuit Q = CV where C = total capacitance = 2.32 μF and v = voltage = 15.5 V
So, Q = CV
Q = 2.32 μF × 15.5 V
Q = 35.96 μC
i. The charge on the 4.89 μF capacitor
Since the 4.89 μF is in series with C', the total charge flowing i the circuit is the total charge in the 4.89 μF capacitor. So, its charge Q = 35.96 μC
b. The charge in the 1.47 μF and 2.95 μF capacitors.
To find the charge in the 4.89 μF and 2.95 μF capacitors, we need to find the voltage across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor. The voltage, V' across the 4.89 μF capacitor, since Q = CV', V' = Q/C = 35.96 μC/4.89 μF = 7.35 V
So, the voltage V" across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor, C' is V" = 15.5 V - V' (since V' + V" = 15.5 V).
So, V" = 15.5 V - V'
V" = 15.5 V - 7.35 V
V" = 8.15 V
i. The charge on the 1.47 μF capacitor
Using Q' = CV" where Q' = charge across capacitor, C = 1.47 μF and V" = 8.15 V.
So, Q' = CV"
Q' = 1.47 μF × 8.15 V
Q' = 11.98 μC
ii. The charge on the 2.95 μF capacitor
Using Q" = CV" where Q' = charge across capacitor, C = 2.95 μF and V" = 8.15 V.
So, Q" = CV"
Q" = 2.95 μF × 8.15 V
Q" = 24.04 μC
Different nutrients play different roles in our bodies. Which is the energy-storing nutrient?
O carbohydrates
O minerals
O proteins
O fats
Answer:
D. Fats
Explanation:
they are the long term energy storing nutrient carbohydrates are a quick way for energy minerals dont contain any energy and neither do proteins
fats
Explanation:
it is nutrient kept in the body
Cuánto demorará un cuerpo en alcanzar su máxima altura, sabiendo que fue lanzado, verticalmente hacia arriba, con una velocidad cuyo valor fue de 90 m/s?
Answer:
The maximum height reached is 413.27 m.
Explanation:
How long will it take for a body to reach its maximum height, knowing that it was thrown, vertically upwards, with a velocity whose value was 90 m / s?
initial velocity , u = 90 m/s
gravity, g = 9.8 m/s^2
Let the maximum height is h.
At maximum height the velocity v = 0
Use third equation of motion
[tex]v^2 = u^2 - 2 gh\\\\0 = 90\times 90 - 2 \times 9.8 \times h\\\\h = 413.27 m[/tex]
Pls help asap!!
A bucket contains hot water at 95°c. A man wants to bath with water at 40°c. What is the ratio of the mass of hot water to the mass of cold water that he needs.
Answer:
55
Explanation:95-40=55
i hope i did the math right if i didnt please tell me
What is the relationship between electric field lines and equipotential lines that you observed in doing the lab
Answer:
Explained below
Explanation:
Generally speaking, we know in physics that Electric field lines are lines which usually start at positive charges and deflect away from them to terminate at the negative charges. Meanwhile Equipotential lines are lines that are used to connect points located on the same electric potential.
Finally, in conclusion, electric field lines are usually lines that go through in a perpendicular manner across every equipotential lines.
A rectangular coil of wire, 22.0 cm by 35.0 cm and carrying a current of 1.40 A, is oriented with the plane of its loop perpendicular to a uniform 1.50-T magnetic field pointing into the plane of the loop. Let the loop be in x-y Cartesian plane so that the long and short sides of the loop are parallel to x- and y-axis, respectively. The loop center is at the origin of x-y Cartesian plane. Note that the magnetic field is in the direction of the negative z-axis.a. Calculate: (i) the net force that the magnetic field exerts on the coil; (ii) the torque about the z-axis that the magnetic field exerts on the coil.b. The plane of the coil is now rotated through +30º from its initial orientation (the x-y plane of the Cartesian coordinate system that remains the same). Calculate: (i) the net force that the magnetic field exerts on the coil; (ii) the torque about the rotation axis that the magnetic field exerts on the coil.
Answer:
a) [tex]F_{net}=0[/tex]
b) [tex]T=0[/tex]
Explanation:
From the question we are told that:
Dimensions:
[tex]L*B=22.0*35.0cm[/tex]
Current [tex]I=1.40A[/tex]
Magnetic field [tex]B=1.40[/tex]
Therefore
[tex]Area=L*B[/tex]
[tex]A=22.0*35.0cm[/tex]
[tex]A=770cm=>770*0^{-4}[/tex]
a)
Generally Force on Looping gives
[tex]F_1-F_2[/tex]
[tex]F_3=F_4[/tex]
Therefore
[tex]F_{net}=0[/tex]
b)
Generally the equation for Torque is mathematically given by
[tex]T=i*Asin \theta[/tex]
Since A and B are on opposite direction
[tex]\theta=180[/tex]
Therefore
[tex]T=1.40*770*10^{-4}sin 180[/tex]
[tex]T=0[/tex]
Which of the following is evidence for continental drift?
một vật m=1kg có động lượng bằng 10kg.m/s. động năng của vật là
What is the final step in the fourth stage of technological design, after a product has been improved abs approved
Answer:
Evaluate the solution.
Explanation:
A technological design is designed as the design and study of a solution that can be provided from the solution by identifying the root cause or problem and trying to solve by various means.
A good technological design requires the minimum effort and resources while meeting the requirement of the problem.
The steps involved in the technological design are :
1. search and identify the problem or need.
2. design a solution
3. Implement a solution.
4. Evaluate the solution.
Therefore, the final step or the fourth step in the process of a technological design is " evaluating or communicating the final design solution".
HELP ASAP
A. 1.09 A
B. 1.20 A
C.0.910 A
D. 0.830 A
Answer:
The answer should be: 1.20 A
Explanation:
A toy airplane is flying at a speed of 3 m/s with an acceleration of 1.1 m/s squared how fast is it flying after five seconds
Answer:
[tex]8.5\frac{m}{s}[/tex]
Explanation:
Use Kinematics:
[tex]v = v_0 + at[/tex]
[tex]v = 3 + 1.1 * 5[/tex]
[tex]v = 8.5 \frac{m}{s}[/tex]
While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.
After the police car passes, its frequency is 460Hz. What is the speed of the police car? (speed of
sound = 340 m/s)
Answer:
v = 17.68 m/s
Explanation:
Given that,
While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.
After the police car passes, its frequency is 460Hz.
We need to find the speed of the police car.
The formula is as follows :
[tex]v=\dfrac{v_o(f-f')}{f+f'}[/tex]
Put all the values,
[tex]v=\dfrac{343(510-460)}{510+460}\\\\=17.68\ m/s[/tex]
So, the speed of the police car is 17.68 m/s.
Use the information below the answer the following 3 questions.
A 50 kg crate is being dragged across a floor by a force of 225 N at an angle of 40o from the horizontal. The crate is dragged a distance of 5.0 m and the frictional force is 60 N.
Question 2 (2 points)
Question 2 options:
The work done on the crate by the applied force is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 3 (2 points)
Question 3 options:
The work done on the crate by the frictional force is -___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 4 (2 points)
Question 4 options:
The net work done on the crate is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Hint: Do not use rounded answers in subsequent calculations
Answer:
2. 8.62×10² Nm
3. 2.30×10² Nm
4. 6.32×10² Nm
Explanation:
2. Determination of the work done by the applied force.
Force (F) = 225 N
Distance (d) = 5 m
Angle (θ) = 40°
Workdone (Wd) =?
Wd = Fd × Cos θ
Wd = 225 × 5 × Cos 40
Wd = 8.62×10² Nm
3. Determination of the work done by the frictional force.
Frictional Force (Fբ) = 60 N
Distance (d) = 5 m
Angle (θ) = 40°
Workdone (Wd) =?
Wd = Fբd × Cos θ
Wd = 60 × 5 × Cos 40
Wd = 2.30×10² Nm
4. Determination of the net work done.
We'll begin by calculating the net force acting on the crate
Force applied (F) = 225 N
Frictional Force (Fբ) = 60 N
Net force (Fₙ) =?
Fₙ = F – Fբ
Fₙ = 225 – 60
Fₙ = 165 N
Finally, we shall determine the net Workdone. This can be obtained as follow:
Net force (Fₙ) = 165 N
Distance (d) = 5 m
Angle (θ) = 40°
Workdone (Wd) =?
Wd = Fₙd × Cos θ
Wd = 165 × 5 × Cos 40
Wd = 6.32×10² Nm
