Answer:
$4.60
Step-by-step explanation:
1 lb ---> 80 cents
5 3/4 lb ---> 5 3/4 * 80 cents
[tex] 5 \dfrac{3}{4} \times 80 = [/tex]
[tex] = \dfrac{23}{4} \times \dfrac{80}{1} [/tex]
[tex] = \dfrac{23 \times 80}{4 \times 1} [/tex]
[tex] = \dfrac{1840}{4} [/tex]
[tex] = 460 [/tex]
460 cents = $4.60
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle and label its height and width.4x+y^2=12, x=yThen find the area S of the region.
Answer:
The Area of the Enclosed Region Is 64/3.
Step-by-step explanation:
As Given in Question
We have, Curve 4x+[tex]Y^{2}[/tex]=12
& X=Y
Solution.
4Y+[tex]Y^{2}[/tex]=12 (X=Y)
[tex]Y^{2}[/tex]+4Y-12=0
[tex]Y^{2}[/tex]+6Y-2Y-12=0
Y(Y+6)-2(Y+6)=0
(Y-2)*(Y+6)=0
Y=2 & -6 (X=Y)
Now at (2,2) & (-6,-6) both curves intersect each other.
The Area Of Enclosed Region is [tex]\int\limits^2_{-6} [(3-Y^{2}/4 )-Y] \, dy[/tex]
by Solving This Equation we get Area of Region = 64/3 .
this equation Solution & Curve Diagram please see In Attachment .
HELP!!!! NUMBER 2
2. Find the distance between these two points.
First Point
Second Point
Distance
(5, - 2)
(8,6)
(5,6)
(-3,6)
(-3,6)
(5,-2)
Answer:
1. 8
2 . 11
[tex]3 . \sqrt{128} \ or \ 8 \sqrt2[/tex]
Step-by-step explanation:
[tex]Distance = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2 }[/tex]
1 . ( 5 , - 2 ) and ( 5 , 6 )
[tex]Distance = \sqrt{(5 -5)^2 + ( 6-(-2))^2} = \sqrt{ 0 + 8^2 } = \sqrt{64} = 8[/tex]
2 . ( 8 , 6 ) and ( - 3 , 6 )
[tex]Distance = \sqrt{( -3 -8)^2 + ( 6 - 6)^2 } = \sqrt{ (-11)^2 + 0 } = \sqrt { 121 } = 11[/tex]
3. ( 5 , - 2 ) and ( -3 , 6 )
[tex]Distance = \sqrt{(-3 - 5)^2 + ( 6 --2)^2} = \sqrt{(-8)^2 + ( 8)^2} = \sqrt{ 64 + 64 } = \sqrt{128}[/tex]
[tex][ \ \sqrt{128} = \sqrt{ 2 \times 64} = \sqrt{ 2 \times 8^2 } = 8 \sqrt{2} \ ][/tex]
Use the distributive property to write the next step in simplifying th
numerical expression
7(2 + 7)
A. 7• 2+7•7
B. 7• 2+7
C. (7+2) • (7 + 7)
D. 7+2 • 7+ 7
Answer:
A)
Step-by-step explanation:
If using the method of completing the square to solve the quadratic equation x^2+15x+21=0, which number would have to be added to "complete the square"?
Step-by-step explanation:
the answer is in the above image
Answer:
my answer is 225/5 sorry comments for wrong
Identify the 3D shape shown below
Answer:
square pyramid...........
Answer:
SQUARE PYRAMID
Step-by-step explanation:
Find the fifth term and the nth term of the geometric sequence whose initial term, a, and common ratio, r, are given.
a = 8; r = -5
Answer:
[tex]a_n = 8(-5)^{n-1}[/tex]
The fifth term of the sequence is 5000.
Step-by-step explanation:
Geometric sequence:
In a geometric sequence, the quotient between consecutive terms is always the same, called common ratio. The nth term of a geometric sequence is:
[tex]a_n = a_1(r)^{n-1}[/tex]
a = 8; r = -5
Thus:
[tex]a_n = a_1(r)^{n-1}[/tex]
[tex]a_n = 8(-5)^{n-1}[/tex]
Fifth term:
This is [tex]a_5[/tex]. So
[tex]a_5 = 8(-5)^{5-1} = 5000[/tex]
The fifth term of the sequence is 5000.
What number must be added to both the numerator and denominator of the fraction 2/5 to get 7/8?
a) 13
b) 15
c) 17
d) 19
What is the midpoint of the line segment connecting the points (-4, 5) and (4,7)?
Answer:
(0,6)
Step-by-step explanation:
Answer:
(0,6)
Step-by-step explanation:
We need to find the midpoint of the line segment having end points (-4,5) and (4,7). So, here we can use the Midpoint Formula :-
Points :- (-4,5) and (4,7).
Using Midpoint Formula ,
[tex]\rm\implies Midpoint =\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)[/tex]
Substitute the respective values ,
[tex]\rm\implies Midpoint =\bigg(\dfrac{-4+4}{2},\dfrac{7+5}{2}\bigg)[/tex]
Simplify the numbers ,
[tex]\rm\implies Midpoint =\bigg(\dfrac{0}{2},\dfrac{12}{2}\bigg)[/tex]
This equals to ,
[tex]\rm\implies \boxed{\blue{\rm Midpoint =\bigg( 0,6\bigg)}}[/tex]
Hence the midpoint is (0,6) .
please solve fast please
Answer:
3/6 =1/25/6pls give me brainliest plzzzzz
find slope from the pair of points (-5,-4) (5,-1)
Answer:
3/10
Step-by-step explanation:
If we have two points on a line, we can find the slope using the slope formula
m= ( y2-y1)/(x2-x1)
= ( -1 - -4)/( 5 - -5)
= ( -1 +4)/ ( 5 + 5)
= 3/10
find the area of the following figures:
Answer:
Area = 156 square cm
Step-by-step explanation:
Write in standard form 4.91E-2
Answer:
4.91e-2 in decimal form is 0.0491
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,000 and $50,000. Assume that a 95% confidence interval estimate of the population mean annual starting salary is desired. Determine the planning value for the population standard deviation.
1. Determine how large a sample should be taken if the desired margin of error is:
a. $500
b. $200
c. $100
2. Would you recommend trying to obtain the $100 margin of error? Explain
Answer:
1) the planning value for the population standard deviation is 10,000
2)
a) Margin of error E = 500, n = 1536.64 ≈ 1537
b) Margin of error E = 200, n = 9604
c) Margin of error E = 100, n = 38416
3)
As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.
Hence, I will not recommend trying to obtain the $100 margin of error in the present case.
Step-by-step explanation:
Given the data in the question;
1) Planning Value for the population standard deviation will be;
⇒ ( 50,000 - 10,000 ) / 4
= 40,000 / 4
σ = 10,000
Hence, the planning value for the population standard deviation is 10,000
2) how large a sample should be taken if the desired margin of error is;
we know that, n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²
given that confidence level = 95%, so [tex]z_{\alpha /2[/tex] = 1.96
Now,
a) Margin of error E = 500
n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 500 ]²
n = [ 19600 / 500 ]²
n = 1536.64 ≈ 1537
b) Margin of error E = 200
n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 200 ]²
n = [ 19600 / 200 ]²
n = 9604
c) Margin of error E = 100
n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 100 ]²
n = [ 19600 / 100 ]²
n = 38416
3) Would you recommend trying to obtain the $100 margin of error?
As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.
Hence, I will not recommend trying to obtain the $100 margin of error in the present case.
Anne invested $1000 in an account with a 3% annual interest rate. She made no deposits or
withdrawals on the account for 2 years. If interest was compounded annually, which equation
represents the balance in the account after the 2 years?
Hi, could someone help me solve this. so the question says to find the area of the shaded part (in black) , in terms of pie (π). the length of the square is 12 cm. the radius of the circle is 6cm. i came with the answer of (144-36π)/4. is this ok? below is the picture of the question.
Answer:
yes but can be simplified
Step-by-step explanation:
area of shaded part = ( area of square - area of circle ) / 4
= [tex]\frac{12^2-\pi (6)^2}{4}[/tex]
= [tex]\frac{144-36\pi }{4}[/tex]
= [tex]\frac{144}{4}[/tex] - [tex]\frac{36\pi }{4}[/tex]
= 36 - 9π
Graph the equation. Let x3, 2, 1, 0, 1, 2, and 3. y=3x-1
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The attachment shows the table of point values and the graph.
PLS HELP ! THANK YOU
Will mark Brainliest
Answer:
I think. . . sphere? SO SORRY IF IM WRONG!!
Step-by-step explanation:
ASAP there are three marbles in a bag. One is red and two are black. What is the probability of picking a black marble first, putting it back in the bag and then picking a black marble? Use the following probability to find the answer.
Answer:
[tex] \frac{4}{9} [/tex]
Step-by-step explanation:
[tex]p = \frac{favorable \: outcomes}{total \: outcomes} = \frac{4}{9} [/tex]
=============================================================
Explanation:
The probability you get a black marble on the first selection is 2/3 since we have 2 black marbles out of 2+1 = 3 total.
We put the marble back and then we have 2/3 as the probability of selecting another black marble on the second try. Nothing has changed because we put the marble back. That means the events are independent.
So we get (2/3)*(2/3) = 4/9 as the probability of selecting 2 black marbles in a row (with replacement).
Chung has 6 trucks and 5 cars in his toy box. Brian has 4 trucks and 5 cars in his toy box.
Which is the correct comparison of their ratios of trucks to cars?
StartFraction 6 Over 4 EndFraction less-than StartFraction 5 Over 5 EndFraction
StartFraction 6 Over 4 EndFraction greater-than StartFraction 5 Over 5 EndFraction
StartFraction 6 Over 5 EndFraction less-than StartFraction 4 Over 5 EndFraction
StartFraction 6 Over 5 EndFraction greater-than StartFraction 4 Over 5 EndFraction
Given:
Chung has 6 trucks and 5 cars in his toy box.
Brian has 4 trucks and 5 cars in his toy box.
To find:
The correct comparison of their ratios of trucks to cars.
Solution:
The ratio of trucks to cars is defined as:
[tex]\text{Ratio}=\dfrac{\text{Number of trucks}}{\text{Number of cars}}[/tex]
Chung has 6 trucks and 5 cars in his toy box. So, the ratio of trucks to cars is:
[tex]\text{Ratio}=\dfrac{6}{5}[/tex]
Brian has 4 trucks and 5 cars in his toy box.
[tex]\text{Ratio}=\dfrac{4}{5}[/tex]
We know that,
[tex]6>4[/tex]
[tex]\dfrac{6}{5}>\dfrac{4}{5}[/tex]
Therefore, the correct option is D.
Answer:
what the guy above me said
Step-by-step explanation:
so yeah he is right points
1.4 meters is the same as
Answer:
Step-by-step explanation:
1.4 m = 1.4 * 100 = 140.0 = 140 cm
The ice cream man just ended his shift for the day. Let 1/2x^2 6/11x + 8 represent the amount of chocolate ice cream bars he sold. Let 5/9x^2 + 2/3 represent the amount of vanilla ice cream bars he sold. Finally let 1/3x^2 + 4x + 4/3 represent the amount of strawberry ice cream bars he sold. Select all the statements that are true
a. The total amount of ice cream bars sold can be represented by the expression 25/18x^2+ 50/11x +10
b. The total amount of ice cream bars sold can be represented by the expression 25/18x^2 + 172/33x +28/3
c. He sold 1/6x^2 + 50/11x + 28/3 more chocolate than strawberry ice cream bars.
d. He sold 1/6x^2 - 38/11x + 20/3 more chocolate than strawberry ice cream bars.
Answer:
A and D
Step-by-step explanation:
Total ice cream bars sold = sum of chocolate sold , vanilla and strawberry ice-creams sold.
=(1/2)x2 + (6/11)x + 8 + (5/9)x2 + (2/3) +(1/3)x2 + 4x +(4/3) (Given in the question)
=(25/18)x2 + (50/11)x + 10 (Adding terms corresponding to x2,x ,constant respectively)
Difference in chocolate and strawberry bars =[ (1/2)x2 + (6/11)x + 8] - [(1/3)x2 + 4x +(4/3)]
= (1/6)x2 - (38/11)x +(20/3)
So, the correct options are A and D
Un ganadero está reparando una mezcla de avena y harina de maíz para ganado. Cada onza de avena proporciona 4 gramos de proteína y 18 gramos de carbohidrato; una onza de harina de maíz proporciona 3 gramos de proteína y 24 gramos de carbohidratos.
¿Cuántas onzas de cada uno se pueden usar para satisfacer las metas nutricionales de 200 gramos de proteína y 1320 gramos de carbohidrato por ración?
Answer:i love you
Step-by-step explanation:
The formula for the surface area of a cylinder is:
SA = 2π r 2 + 2πrh note: that π= 3.14
a. Solve for h showing all work.
b. If the height of a can of soup is 5 inches and the radius is 1.5 inches, what is the surface area?
Answer:
Below in bold.
Step-by-step explanation:
a. SA = 2π r^2 + 2πrh
2πrh = SA - 2π r^2
h = (SA - 2πr^2)/2πr
When π = 3.14 we have
h = (SA - 6.28r^2)/ 6.28r
b. SA = 6.28*1.5^2 + 6.28*1.5* 5
= 61.23 in^2
what does $42,690e(0.03)×(20) equal
Answer:
77,786.251
Step-by-step explanation:
Answer:
77,786.251 is the answer that equals $42,690e(0.03)×(20)
Step-by-step explanation:
hey mate hope this help you...!
(Right angle Trigonometry) Please help me solve and explain!
Answer:
31.3
Step-by-step explanation:
Reference angle given = 56.1°
Hypotenuse = 56.1
Adjacent side = x = ?
We would apply CAH, which is:
Cos 56.1° = Adj/Hyp
Cos 56.1° = x/56.1
56.1 × Cos 56.1° = x
31.2895006 = x
x = 31.3 (approximated to the nearest tenth)
474 ( ) 548 42. - 8 how do I arrive at this answer.
9514 1404 393
Answer:
(64x^28)/(5y^22)
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)^c = a^(bc)
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
__
First, eliminate the outside exponent on the left factor. Then use the above rules to combine factors with the same base.
[tex]\displaystyle\left(\frac{4x^4}{5y^6}\right)^5\cdot\left(\frac{5^4y^8}{4^2x^{-8}}\right)=\frac{(4^5x^{20})(5^4y^8)}{(5^5y^{30})(4^2x^{-8})}=4^{5-2}5^{4-5}x^{20-(-8)}y^{8-30}\\\\=4^35^{-1}x^{28}y^{-22}=\boxed{\frac{64x^{28}}{5y^{22}}}[/tex]
Triangle ABC is the pre-image and triangle DFE is the image.
What is the scale factor of the dilation?
Please helppp!!!!!
Answer:
Scale factor = ½
Step-by-step explanation:
The original image is the preimage = ∆ACB
The new image is the image = ∆DFE
The scale of factor of dilation = image/preimage = DF/AC
DF = 6 cm (given)
AC = 12 cm (given)
Plug in the values into the equation to find the scale factor of dilation:
Scale factor = 6/12
Scale factor = ½
PLEASE ANSWER ASAP - I WILL MARK BRAINLIEST!!!!!!!!
Answer:
2/3
Step-by-step explanation:
P ( 8 or more) = number that are 8 or more) / total
= (6+4) / ( 2+3+6+4)
= 10/15
=2/3
Which matrix represents the solution to the system of equations below?
2a+b+c=2
-a+ - =-4
a-25+2c=6
1
0
0
2
1
0
-2.
0
0
1
0
1
0
0
1
0
1
0
- 2
0
0
1
0
2
1
1
2.
-4
Answer:
The one that's include a rows 2 1 1 2
Answer:
A
Step-by-step explanation:
they wanted the reduced echelon form.
On Edge. btw
The National Highway Traffic Safety Administration reported the percentage of traffic accidents occurring each day of the week. Assume that a sample of accidents provided the following data. Sunday= 64, Monday=53, Tuesday=55, Wednesday=49, Thursday=55, Friday=68, Saturday=76. Conduct a hypothesis test to determine if the proportion of traffic accidents is the same for each day of the week. What is the -value? Compute the value of the test statistic (to 3 decimals).
Answer:
Hence,
a)
Test statistic [tex]X^{2}[/tex] = 9.269.
p value = 0.148
b)
Sunday= 15.23%, Monday= 12.62%, Tuesday= 13.10%, Wednesday=11.67%,
Thursday= 13.10%, Friday= 16.19%, Saturday= 18.09%.
Step-by-step explanation:
a)
relative observed Expected Chi square
Category frequency(p) [tex]O_{i}[/tex] Ei=total*p [tex](O-E)^{2}[/tex] [tex]R^{2}_{i} =(O_{i} -E_{i} )^{2} /E_{i}[/tex]
1 0.142857143 64.0 60.00 16.00 0.267
2 0.142857143 53.0 60.00 49.00 0.817
3 0.142857143 55.0 60.00 25.00 0.417
4 0.142857143 49.0 60.00 121.00 2.017
5 0.142857143 55.0 60.00 25.00 0.417
6 0.142857143 68.0 60.00 64.00 1.067
7 0.142857143 76.0 60.00 256.00 4.267
Total 1.000 420 420 556 9.269
Test statistic [tex]X^{2}[/tex] = 9.269.
p value = 0.148 from excel: chidist(9.269,6)
b)
Percentage %= Frequency of traffic occur on category x 100 / Total number of frequency given.
Category Percentage%
Sunday 15.23%
Monday 12.62%
Tuesday 13.10%
Wednesday 11.67%
Thursday 13.10%
Friday 16.19%
Saturday 18.09%
