Which of the following represents the graph of f(x) = 4X – 2?

Answer:

the slopes are different, and the y-intercepts are also different

Step-by-step explanation:

We can rewrite the equations given in slope-intercept to easily determine the slope (m) and the y-intercept (b). Slope-intercept equation is y = mx + b

Let's rewrite each equation:

✔️5x + 2y = 2

Subtract 5x from each side

2y = -5x + 2

Divide both sides by 2

y = -5x/2 + 2/2

y = -⁵/2(x) + 1

The slope (m) = -⁵/2

y-intercept (b) = 1

✔️3x - 3y = 18

Subtract 3x from each side

-3y = -3x + 18

Divide both sides by -3

y = -3x/-3 + 18/-3

y = x - 6

Slope (m) = 1

y-intercept (b) = -6

✅Therefore, the slopes are different and the y-intercepts are also different

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the right trianglea are not given. The general explanation is as follows.

Using Pythagoras Theorem, we have:

a² = b² + c²

Where:

a => hypotenuse

Assume that the opposite and the adjacent sides are given as 3 and 4, respectively.

The hypotension becomes

a² = 3² + 4²

a² = 9 + 16.

a² = 25

Take square roots.

a = 5

If any of the other side lengths is missing; you make that side the subject and then solve.

Answer:

$0.25

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Given:

The piecewise function is:

[tex]f(x)=\begin{cases}9x & \text{ if } x<-1 \\ x-4 & \text{ if } x\geq -1 \end{cases}[/tex]

To find:

The values of [tex]f(-3),f(0), f(-1)[/tex].

Solution:

In the given piecewise function,

[tex]f(x)=9x[/tex] for [tex]x<-1[/tex] and [tex]f(x)=x-4[/tex] for [tex]x\geq -1[/tex].

Putting [tex]x=-3[/tex] in [tex]f(x)=9x[/tex], we get

[tex]f(-3)=9(-3)[/tex]

[tex]f(-3)=27[/tex]

Putting [tex]x=0[/tex] in [tex]f(x)=x-4[/tex], we get

[tex]f(0)=0-4[/tex]

[tex]f(0)=-4[/tex]

Putting [tex]x=-1[/tex] in [tex]f(x)=x-4[/tex], we get

[tex]f(-1)=-1-4[/tex]

[tex]f(-1)=-5[/tex]

The required values are [tex]f(-3)=27,f(0)=-4,f(-1)=-5[/tex].

Therefore, the correct option is D.

Answer:

$30.21

Step-by-step explanation:

100% -25%= 75%

Discounted price of the book

= 75% ×$38

= $28.50

Since the customer must pay an additional 6% of the discounted price,

percentage of discounted price paid

= 100% +6%

= 106%

Total amount paid

= 106% × $28.50

= $30.21

_________________________________

Alternative working:

Original selling price= $38

Since the book is discounted 25%,

100% ----- $38

1% ----- $0.38

75% ----- 75 ×$0.38= $28.50

Since the sales tax is based on the discounted price, we let the discounted price be 100%.

100% ----- $28.50

1% ----- $0.285

106% ----- 106 ×$0.285= $30.21

∴ The total amount the customer pays for the discounted book is $30.21.

Answer:

30 hour

Step-by-step explanation:

girls time

12 20 hour

8 x(let)

now,

12/8=x/20

12×20=8×x

240=8x

x=240/8

x=30,,

Answer:

Buses - 43 people

Vans - 12 people

Answer:

6.27

Step-by-step explanation:

We are to obtain the standard deviation of the given values :

{24, 18, 31,25, 34}

The standard deviation = √(Σ(x - mean)²/ n)

The mean = (ΣX) /n

Using calculator to save computation time :

The standard deviation, s = 6.27 (2 decimal places)

Answer:

[tex]{ \bf{r(t) = 7e {}^{0.6t} }} \\ { \tt{r(2) = 7 {e}^{0.6 \times 2} }} \\ = { \tt{7 {e}^{1.2} }} \\ = 23.241 \: thiusand bacteria \: per \: hour[/tex]

Answer:

answer is

74....................

Answer:

D

Step-by-step explanation:

We want to find the difference between the two polynomials:

[tex](5x^3+4x^2)-(6x^2-2x-9)[/tex]

Distribute the negative:

[tex]=(5x^3+4x^2)+(-6x^2+2x+9)[/tex]

Rearrange the terms:

[tex]=(5x^3)+(4x^2-6x^2)+(2x)+(9)[/tex]

Combine like terms. Hence:

[tex]=5x^3-2x^2+2x+9[/tex]

Our answer is D.

Answer:

A (-1,-10) ; A (-1,14)

Step-by-step explanation:

[tex]\sqrt{(-1-4)^2 + (y-2)^2} = 13 \\ 25 + y^2 + 4 -4y = 169[/tex]

y^2 -4y - 140 = 0

Δ/4 = 4 + 140 = 144

y1 = 2 + 12 = 14

y2 = 2 -12= -10

Answe

SI Si olla amigo lel just spammin here

Step-by-step explanation:

Answer:

I'd use A = πr^2

The area is 28.3 if we're using 3.14 as pi (rounded to the nearest tenth)

Answer:

That is Arithmetic

Step-by-step explanation:

Arithmetic Sequence is described as a list of numbers, in which each new term differs from a preceding term by a constant quantity. Which is -5 in this case.

Hope this helps

Answer:

a) the work done in propelling a five-ton satellite to a height of 100 miles above Earth is 487.8 mile-tons  

b) the work done in propelling a five-ton satellite to a height of 300 miles above Earth is 1395.3 mile-tons

Step-by-step explanation:

Given the data in the question;

We know that the weight of a body varies inversely as the square of its distance from the center of the earth.

⇒F(x) = c / x²

given that; F(x) = five-ton = 5 tons

we know that the radius of earth is approximately 4000 miles

so we substitute

5 = c / (4000)²

c = 5 × ( 4000 )²

c = 8 × 10⁷

∴ Increment of work is;

Δw =  [ ( 8 × 10⁷ ) / x² ] Δx

a) For 100 miles above Earth;

W = ₄₀₀₀∫⁴¹⁰⁰ [ ( 8 × 10⁷ ) / x² ] Δx

= (8 × 10⁷) [tex][[/tex] [tex]-\frac{1}{x}[/tex] [tex]]^{4100}_{4000[/tex]

= (8 × 10⁷) [tex][[/tex] [tex]-\frac{1}{4100}[/tex] [tex]+\frac{1}{4000}[/tex] [tex]][/tex]

= (8 × 10⁷ ) [ 6.09756 × 10⁻⁶ ]

= 487.8 mile-tons  

Therefore, the work done in propelling a five-ton satellite to a height of 100 miles above Earth is 487.8 mile-tons  

b) For 300 miles above Earth.

W = ₄₀₀₀∫⁴³⁰⁰ [ ( 8 × 10⁷ ) / x² ] Δx

= (8 × 10⁷) [tex][[/tex] [tex]-\frac{1}{x}[/tex] [tex]]^{4300}_{4000[/tex]

= (8 × 10⁷) [tex][[/tex] [tex]-\frac{1}{4300}[/tex] [tex]+\frac{1}{4000}[/tex] [tex]][/tex]

= (8 × 10⁷ ) [ 1.744186 × 10⁻⁵ ]

= 1395.3 mile-tons

Therefore, the work done in propelling a five-ton satellite to a height of 300 miles above Earth is 1395.3 mile-tons

Answer:

90 kilometers

Step-by-step explanation:

https://www.bing.com/search?q=kilometers+are+there+in+9000000cm

Answer:

14

Step-by-step explanation:

Simply take the square root of 196.

Hope that this helps!

Answer:

The side length is 14 m

Step-by-step explanation:

The formula for the area of a square is A = s^2, where s represents the length of one side.

If A = s^2  =  196m^2, we find the side length by taking the square root of both sides:  

s = √(196 m^2) = 14 m

The side length is 14 m

Answer:

A = πx² - 2πx + π

Step-by-step explanation:

The area of the new cup opening :

We are given the area formula to use :

Area, A = πr²

r = Radius = x-1

Area = π(x - 1)²

A = π(x - 1)(x - 1)

A = π(x² - x - x + 1)

A =π(x² - 2x + 1)

A = πx² - 2πx + π

Answer:

The answer is below

Step-by-step explanation:

a) the volume of the pit = length * width * depth = 9 dm * 6 dm * 7 dm = 378 dm³

Hence to fil the pit, 378 dm³ of sand is needed.

b) Volume of the room = length * width * height = 2.3 m * 0.59 m * 3.74 m = 5.08 m³

The cabinet would occupy 5.08 m³ of space.

c) volume = length * width * height

210 dm³ = 3.5 dm * 6 dm * width

width = 210 dm³ / (3.5 dm * 6 dm) = 10 dm

d) Volume of the room = length * width * height = 15 m * 15 m * 15 m = 3375 m³

The stockroom has a space of 3375 m³

e) volume = length * width * height = 5 dm * 5 dm * 5 dm = 125 dm³

The container has a space of 125 dm³

f) volume = length * width * height = 41 cm * 13 cm * 24 cm = 12792  cm³

The box has a space of 12792  cm³

g) volume of prism = length * width * height

72 m³ = 4 m * 3 m * length

length = 72 m³ / (4 m * 3 m) = 6 m

h) volume = length * width * height = 8 cm * 8 cm * 8 cm = 512 cm³

The figure has a volume of 512 cm³

i) volume = length * width * height = 5 ft * 2 ft * 3 ft = 30 ft³

The cabinet has a space of 30 ft³

Answer:

[tex]cos \theta = \frac{11}{12}[/tex]

Step-by-step explanation:

[tex]sin \theta = \frac{\sqrt{23}}{12} \ , \ tan \theta = \frac{\sqrt{23}}{11}\\\\tan \theta = \frac{sin \theta }{cos \theta }\\\\ \frac{\sqrt{23}}{11} = \frac{\frac{\sqrt{23}}{12} }{cos \theta}\\\\cos \theta = \frac{\frac{\sqrt{23}}{12} }{\frac{\sqrt{23}}{11} }\\\\cos \theta = \frac{\sqrt{23}}{12 } \times \frac{11}{\sqrt{23}}\\\\cos \theta = \frac{11}{12}[/tex]

Answer:

The first equation, sorry can’t explain.

Answer:

g(x)=3f(2x)

I think

the answer is b. insurance

Answer:

Your options are not clear

Step-by-step explanation:

[tex]\sqrt[3]{-1000 \times p^{12} \times q^3} \\\\(-1 \times 10^3 \times p^{12} \times q^3)^{\frac{1}{3} }\\\\(-1^3)^{\frac{1}{3} }\times 10^{3 \times \frac{1}{3} } \times p^{12 \times \frac{1}{3}} \times q^{3 \times \frac{1}{3}} \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ (-1)^3 = - 1 \ ] \\\\- 1 \times 10 \times p^4 \times q\\\\-10p^4q[/tex]