The gravitational force acting on various masses is measured on different planets. Measured values for the forces acting on the corresponding masses are shown in the data table. Analyze the data and develop a method for comparing the gravitational field strengths on the different planets. Use your method to compare the gravitational field strengths, and report your conclusions.

Answers

Answer 1

we Know that gravitational field strength(g) at a point on a planet is equal to gravitational force exerted per unit mass placed at that point.
It Means,
g=F/m
Here,
g=gravitational field strength
F=Gravitational force
m=Mass
Case A
planet force =10 and mass= .5
g1=F/m
g1=10/.5
=100/5
g1=20m/s
case B
F=30 and m=2
therefore g2=30/2
g2=15m/s^2
case C
F=45 and m=3
g3=45/3
=15m/s^2
case D
g4=60/6
g4=10m/s^2
from above results it is clear that the gravitational field strength of planet D is minimum which is 10m/s^2 and gravitational field strength of planet A is maximum which is 20m/s^2

Related Questions

define Neutons 3rd law .

Answers

Answer:

that when two object interact, they apply forces to one another that are equal in magnitude and opposite in direction.

Explanation:

Newton's third law: the law of action and reaction

What kind of circuit is the one shown below?
A. Series
B. Parallel
C. Open
D. Combination

Answers

That's a parallel circuit. (B)

When current from Point-A reaches the 3-way intersection just to the right of Point-B, it has to make a choice: Either turn left, go through B, and light the lower bulb, or go straight and light the upper bulb.

A circuit that has any "decision" points in it is a parallel circuit. What happens in the real world is: The current splits up. Some of the current that reaches the intersection turns left toward Point-B, and the rest of it goes straight up.

A series circuit is one in which there's only one possible path all the way around. There are no intersections of more than 2 roads, and no electron ever has to decide which way to flow.

An open circuit is one in which there's a break somewhere along the line and electrons can't jump across it. It's like a railroad where a big piece is cut out of the track somewhere. So no trains can travel on that route, and there's no current flowing anywhere in the circuit.

I'm not so sure about a "combination" circuit. I guess you could give that name to a complicated circuit that has some series parts and some parallel-parts. Personally, I'd call that a "series-parallel" circuit. But it really doesn't matter right now. Whatever the word means, the circuit in the picture is definitely not a "combination" circuit.

Answer:

B. Parallel Circuits

Explanation:

A parallel circuit is constructed by connecting the terminals of all the individual load devices so that the same value of voltage appears across each component. In a parallel circuit, charge divides up into separate branches such that there can be more current in one branch than there is in another.

hope i helped

derive an expression for resistivity of conductor of length l and area of cross section A

Answers

Answer

Resistivity R = K * L / A where resistivity is constant for material, L the length of the material and A the area of the material

K = R * A / L where R is the resistance of the material

Saul is testing an installation and discovers a short circuit what’s causing this
A.high current

B.high voltage

C.low resistance

D.low voltage

Answers

Answer:
C. Low resistance

Answer:

im pretty sure that it's (A.) High current

Explanation:

not 100% sure, tho

What do is mean by environment friendly behaviour?

Answers

Answer:
Being environmentally friendly means having a lifestyle that is better for the environment

A converging lens of focal length 20cm, forms a real image twice the size of the object. Calculate:
i) the power of the lens;
ii) the position of the image.

Answers

Answer:

Solition given:

focal length(f)=20cm

size of image(v)=2x

size of object(u)=x

we have

power of lens= reciprocal to focal length=1/20=0.05/cm

ii.

the position of the image is beyond C.

Explanation:

See the attachment !!!!!!!

1. How much heat energy ( Q ) is required to heat 2.0 kg of copper from 30.0 oC to 80.0 oC?

Answers

Answer:

38500

Explanation:

I looked it up so it may be wrong

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