The graph of a function f(x) is shown below:


What is the domain of f(x)? (1 point)
integers from - 1< x <2
integers from -3 < y < 3
integers from -3 < y <3
integers from -1 < x < 2

Answer:

5, 12, 19, 26, 33

Step-by-step explanation:

Using the recursive rule and a₁ = 5 , then

a₂ = a₁ + 7 = 5 + 7 = 12

a₃ = a₂ + 7 = 12 + 7 = 19

a₄ = a₃ + 7 = 19 + 7 = 26

a₅ = a₄ + 7 = 26 + 7 = 33

The first 5 terms are 5, 12, 19, 26, 33

Answer:

a(y_2)_b(y_2) =a_b)(y_2(

Answer:rrrrrrrr

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Step-by-step explanation:

rrrrrrrrrrrrrrr

The equation for the scenario is x + x+1 + x+2 = 117 and largest number is 40.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

Let x be the first number:

The other numbers are:

x+1, x+2

The sum of three consecutive numbers is 117:

x + x+1 + x+2 = 117

3x + 3 = 117

3x = 114

x = 38

x+ 1 = 38+1 = 39

x+2 = 38+2 = 40

Thus, the equation for the scenario is x + x+1 + x+2 = 117 and largest number is 40.

Learn more about the linear equation here:

brainly.com/question/11897796

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Answer:

7920

Step-by-step explanation:

you can use the binomial theorem obviously but you can also use symbolabs or wolframalpha and just solve it like that.

Answer:

Its either 2(A+7=5) or 2(A+7) =5

Answer:

[tex]{ \tt{ {x}^{2} - \frac{1}{ {x}^{2} } }} \\ = { \tt{ {(2 + \sqrt{5} )}^{2} - \frac{1}{ {(2 + \sqrt{5}) }^{2} } }} \\ = { \tt{ \frac{(2 + \sqrt{5} ) {}^{4} - 1}{ {(2 + \sqrt{5} )}^{2} } }} \\ = { \tt{ \frac{(9 + 4 \sqrt{5}) {}^{2} }{ {(9 + 4\sqrt{5}) }}}} \\ = { \tt{9 + 4 \sqrt{5} }}[/tex]

Answer:

[tex]8\sqrt{5}[/tex]

Step-by-step explanation:

[tex]x = 2 + \sqrt{5}\\\\ x^{2} = (2+ \sqrt{5})^{2} \\\\ \ \ \ \ = 2^{2}+2* \sqrt{5}*2+( \sqrt{5})^{2}\\\\[/tex]

 [tex]= 4 + 4 \sqrt{5}+5\\\\= 9+4 \sqrt{5}[/tex]

[tex]\frac{1}{x^{2}}=\frac{1}{9+4\sqrt{5}}\\\\=\frac{1*(9-4\sqrt{5}}{(9+4\sqrt{5})(9-4\sqrt{5})}\\\\=\frac{9-4\sqrt{5}}{9^{2}-(4\sqrt{5})^{2}}\\\\=\frac{9-4\sqrt{5}}{81-4^{2}(\sqrt{5})^{2}}\\\\=\frac{9-4\sqrt{5}}{81-16*5}\\\\=\frac{9-4\sqrt{5}}{81-80}\\\\=\frac{9-4\sqrt{5}}{1}\\\\=9-4\sqrt{5}[/tex]

[tex]x^{2}-\frac{1}{x^{2}}= 9 + 4\sqrt{5} -(9 - 4\sqrt{5})\\\\[/tex]

            [tex]= 9 + 4\sqrt{5} - 9 + 4\sqrt{5}\\\\= 9 - 9 + 4\sqrt{5} + 4\sqrt{5}\\\\= 8\sqrt{5}[/tex]

Answer:

-3/5

Step-by-step explanation:

Pythagorean formula :

x^2 + y^2 = r^2

(-8)^2 + (-6)^2 = r^2

64 + 36 = 100

r^2 = 100

r= 10

sin is the y coordinate over the radius :

-6/10

-3/5

Answer:

Choice C.

[tex]y + 1 = - 2(x - 2)[/tex]

Step-by-step explanation:

When converting to

[tex]y = mx + b[/tex]

We are left with:

[tex]y = - 2x + 3[/tex]

Which fits both the x-intercept and y-intercept.

Answer:

m∠DAB+m∠ADC=180

115+ 29 + m∠ADB=180

m∠ADB=180 - 115 -29

= 36°

Answer:

D. Subtract 9y from both sides of the equation.

Step-by-step explanation:

A. Divide both sides of the equation by 36.

B. Multiply both sides of the equation by 6.

C. Add 9y to both sides of the equation.

D. Subtract 9y from both sides of the equation.

Given:

9y - 6x = 36

To solve for x

Step 1: subtract 9y from both sides

9y - 6x - 9y = 36 - 9y

- 6x = 36 - 9y

Step 2: Divide both sides by -6

- 6x / -6 = (36 - 9y) / - 6

x = (36 - 9y) / - 6

The answer is

x = (36 - 9y) / - 6

Answer:

d

Step-by-step explanation:

Answer:

p = 1

Step-by-step explanation:

7 = 8 - p

7 + p = 8

p = 8-7

p = 1

Answered by Gauthmath

Answer:

7 slices

Step-by-step explanation:

1/3 of the bread would be seven slices (21/3), and he would be left with 2/3, half of which is 1/3; another seven slices were eaten. On Wednesday, he will have 7 slices left over.

Answer:

19: 5

Step-by-step explanation:

Total fruit  is 5+10+4 = 19

fruit: pears

19: 5

Answer:

19:5

Step-by-step explanation:

5+10+4= 19

Pears= 5

Answer:

(x+2)(2x+2) = 130

x=6.58m

Step-by-step explanation:

The shape of the whole figure is a triangle. Hence the area of the whole figure is expressed as:

Area = Length * Width

Given

Length = 2 + x + x = 2+2x

Width = 2 + x

Area = 130m²

Substitute the resultng values into the formula;

(2+2x)(2+x)= 130

(x+2)(2x+2) = 130

Expand the bracket:

[tex]2x^2+2x+4x+4=130\\2x^2+6x+4=130\\[/tex]

Divide through by 2

[tex]x^2+3x+2=65\\x^2+3x=65-2\\x^2+3x = 63[/tex]

Complete the square by adding the square of the half of the coefficient of x to both sides:

[tex](x^2+3x+(\frac{3}{2} )^2)=63+(\frac{3}{2} )^2[/tex]

[tex](x+\frac{3}{2} )^2=63 + \frac{9}{4} \\(x+\frac{3}{2} )^2=\frac{252+9}{4} \\(x+\frac{3}{2} )^2=\frac{261}{4}\\(x+\frac{3}{2} )^2=65.25[/tex]

Take the square root of both sides

[tex]\sqrt{(x+(\frac{3}{2} ))^2} = \sqrt{65.25}\\x+\frac{3}{2}= 8.078\\x=8.078-1.5\\x=6.58m[/tex]

Hence the value of x is 6.58m

Answer:

range{-5,4)

Step-by-step explanation:

3(-1)-2= -5

3(2)-2=4

Answer:

259 ft.

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are isosceles. scalene, equilateral, acute, obtuse and right angled triangle.

A right angled triangle is a triangle in which one of the angles is 90 degrees. Trigonometric ratios show the relationship between the angles of a right angle triangle and its sides.

Let h represent the height of the house above water, hence using trigonometric ratios:

tan(26) = h / 531

h = 531 * tan(26)

h = 259 ft.

Answer:

80%

Step-by-step explanation:

Change is (45-25)/25*100=(20/25)*100=80%

Answer:

B) To the left five units, down three units

Answer:

( B ) To the left five units, down three units.

Answer:

write question in short form

Step-by-step explanation:

Step-by-step explanation:

1/5=1/5×1000=200

1/2 of 200

1/2×200=100

Hi!

x² + 7x + 9 = 3

x² + 7x + 9 - 3 = 0

x² + 7x + 6 = 0

Answer:

x^2+7x+ 6 = 0

Step-by-step explanation:

x^2+7x+ 9 = 3

Subtract 3 from each side

x^2+7x+ 9-3 = 3-3

x^2+7x+ 6 = 0

Answer:

(-2, -7) or (3, 18)

Step-by-step explanation:

Start with your 2 equations

y = x^2 + 4x - 3

y = 5x + 3

Because both equal y, we substitute:

x^2 +4x -3 = 5x+ 3

x^2 - x - 6 = 0

Factor:

(x + 2) (x - 3) = 0

Solutions for x: -2 or 3 since if either of the numbers in parentheses is 0, the equation is 0 (0* anything = 0).

Then plug -2 in for x in either equation:

y = 5* -2 + 3

y = -7

So ( -2, -7) is a solution.

Plug 3 in for x in either equation:

y = 5*3 + 3

y = 18

So ( 3 , 18) is a solution.

Hope that helps, let me know if I did anything wrong!

Answer:

(- 2, - 7 ) and (3, 18 )

Step-by-step explanation:

Given the 2 equations

y = x² + 4x - 3 → (1)

y = 5x + 3 → (2)

Substitute y = x² + 4x - 3 into (2)

x² + 4x - 3 = 5x + 3 ( subtract 5x + 3 from both sides )

x² - x - 6 = 0 ← in standard form

(x - 3)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 3 = 0 ⇒ x = 3

Substitute these values into (2) for corresponding values of y

x = - 2 : y = 5(- 2) + 3 = - 10 + 3 = - 7 ⇒ (- 2, - 7 )

x = 3 : y = 5(3) + 3 = 15 + 3 = 18 ⇒ (3, 18 )

Answer:

42.78⁹, 137.22⁹.

Step-by-step explanation:

sine Ф=0.6792

Angle Ф in the first quadrant = 42.78 degrees.

The sine is also positive in the second quadrant so the second solutio is

180 - 42.78

= 137.33 degres.

Answer:

(-2,-2)

Step-by-step explanation:

x^2 + y^2 = 9

A circle has an equation of the form

(x-h)^2 + (y-k)^2 = r^2

where the center is at ( h,k) and the radius is r

The circle is centered at (0,0) and has a radius 3

The only point entirely within the circle must have points less than 3

(-2,-2)

Answer:

-6

Step-by-step explanation:

A parabola is vertex form is written as

y = a(x-h)^2 +k  where (h,k) is the vertex

Substituting in the vertex

y = a(x-5)^2 +5

We know a point on the parabola so we can find a

-1 = a( 6-5)^2 +5

-1 =a(1)^2+5

-1 = a +5

Subtract 5 from each side

-1-5 = a

-6 =a

Answer:

CAUTION HERE !!!!!

if you suggested edits are accurate the solution would be...

[tex]\frac{3p^2 - 5p+9}{6p^2}[/tex]

that is not one of your choices, but is is almost identical to choice "D"

which is different by [tex]6px^2[/tex]  vs   [tex]6p^2[/tex]

which i think is your comment ????  

Step-by-step explanation:

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]

First Mistake : Line 2

[tex]a = x \\ b = 6 \\ c = 10[/tex]

Second Mistake : Line 4

[tex]136 = {x}^{2} \\ not \\ 136 = x[/tex]

Correct Solution :

[tex] {x}^{2} + {6}^{2} = {10}^{2} \\ {x}^{2} = {10}^{2} - {6}^{2} \\ {x}^{2} = 100 - 36 \\ [/tex]

[tex] {x}^{2} = 64 \\ \sqrt{ {x}^{2} } = \sqrt{64} \\ x = 6[/tex]