Answer:
h(x)=\sqrt(x+6)
Step-by-step explanation:
I just did the test for a p e x
A system of equations is shown below.
y = 3x + 9
y = x^2 - 1
What is the largest value of y in the solution set of the system?
A. -2
B. 24
C. 3
D. 5
Answer:
it should be 3 so letter c
Step-by-step explanation:
I hope this help
Find the volume
Help me please
Answer:
1372/3 π
that's the volume
Please help!!
Take a factor out of the square root:
Answer:
2a times the sq root of 2a or 2a (2a)**1/2
Step-by-step explanation:
(8a**3)**1/2 =
((2**2 * 2) (a**2) (a))**1/2 then take out and squares
2a (2a)**1/2
or 2a times the sq root of 2a
How many distinguishable permutations for the letters in the word "statistical" are there?
You can use the same reasoning as I provided on your other question (URL 24277817).
"statistical" has 11 total characters, thus 11! total permutations.
• s, a, and i each appear 2 times
• t appears 3 times
Then the number of distinguishable permutations is
11! / (2! × 2! × 2! × 3!) = 831,600
f(x) = x2 What is g(x)?
O A. g(x) = 25x2
O B. g(x) =1/5x2
O C. g(x) = 5x2
O D. g(x) = (5x)2
Answer:
C
Step-by-step explanation:
The graph is 5x^2. Hence the option C is correct
The required function g(x) is 5x² for the given graph, which is the correct option (C).
What are the functions?The function is defined as a mathematical expression that defines a relationship between one variable and another variable.
The given function is as follows:
f(x) = x²
Substitute the value of x = 1 in the above equation,
f(1) = 1
As per the given graph, we have
g(1) = 5
Now, we can write the proportion as:
f(x)/g(x) = f(1)/g(1)
Substitute the known values in the above proportion, and solve for g(x):
x²/g(x) = 1/5
Cross-multiplying and we get:
g(x) = 5x²
Therefore, the required function g(x) is 5x².
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Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Answer:
c
Step-by-step explanation:
First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.
[tex]\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right][/tex]
Next, we can define a reduced row echelon form matrix as follows:
With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.
Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form
[tex]\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right][/tex] for the first three rows and columns. This would make the equation translate to
x= something
y= something
z = something, making it easy to solve for x, y, and z.
Going back to our matrix,
[tex]\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right][/tex] ,
we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in
[tex]\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right][/tex]
as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in
[tex]\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right][/tex]
After that, to reach the desired second column, we can divide the second row by 14, resulting in
[tex]\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right][/tex]
Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in
[tex]\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right][/tex]
We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix
[tex]\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right][/tex]
Therefore,
x=-5
y=-6
z=-3
* we could also switch the second and third rows here to make the process a little simpler
Answer:
C
Step-by-step explanation:
EDGE BOY (or girl)
If you car was going 60mph and you increased your speed by 5mph every minute for seven consecutive minutes how fast would you be going at the end
Please help!!! I'll give 25 points plus brainliest.
The half-life of Palladium-100 is 4 days. In an experiment, there are 10 milligrams of Palladium-100 sample to start with.
Write the exponential function for this situation. (3 points)
Use your answer in part a to find the amount of Palladium-100 two weeks after the experiment starts. (4 points)
How long will it take for the amount of Palladium to drop below 1 mg?
Show your work or attach a sketch/screenshot if you used technology. (4 points)
Answer:
(b) 26.6 days
Step-by-step explanation:
Half life, T = 4 days
initial amount, No = 100 mg
(a) The exponential function is given by
[tex]N = No e^{-\lambda t}\\\\N = No e^{\frac{-0.693t}{T}}\\\\N = No e^{\frac{-0.693t}{4}}\\\\N = No e^{\frac{-0.17325t}{T}}\\\\[/tex]
where, N is the amount left.
(b) N = 1 mg
[tex]N = No e^{\frac{-0.17325t}{4}}\\\\1 = 100 e^{\frac{-0.17325t}{4}}\\\\4.605 = 0.17325 t \\\\t=26.6 days[/tex]
Question 6 of 25
In APQR, m P= 60°, m_ Q = 30°, and m2 R = 90°. Which of the following
statements about APQR are true?
Check all that apply.
Answer:
A, E, F
Step-by-step explanation:
From the angles given, we can infer that ΔPQR is a 30-60-90 special triangle. In a 30-60-90 triangle, the leg opposite the 30 degree angle is 1/2 the hypotenuse and the leg opposite the 60 degree angle is √3 times the one opposite the 30. Using this, we can say:
PR = 1/2 PQ which is just 2 PR = PQ(E)
PR √3 = QR (A)
We can substitute in PR from the first equation to the second to get:
√3/2 PQ = QR(F)
Would this be 20? I'm confused on what the problem is asking here.
Answer:
This would not be 20
Step-by-step explanation:
This question can be thought as a Pythagoras question.
By subtracting 2cm from both the left side ZW, and the right side YX, you will have a right angled triangle WYX (or ZYX, since after subtracting 2cm Z and W are essentially the same point)
I have attached a crude drawing of what the triangle is looking like, we are looking for the unknown value marked with the ?
Pythagoras states that [tex]a^{2} +b^{2} =c^{2}[/tex]
We are given the lengths 2cm and 20cm, which can be thought of as a (or b) and c. Substitute in the values 2 and 20 and solve for the unknown
1 point (1) Three times a number minus two times a number* Your answer
Answer:
Three times a number minus two times a number
3x-2x
=x
Simplify the expression below 5x(2x - 5)
Solve log6 + log6 (x-1) = 1
Answer:
[tex]\boxed{\sf x = 7 }[/tex]
Step-by-step explanation:
We are here given a logarithmic equation and we need to solve it out and then find the value of x. The given equation is ,
[tex]\sf\longrightarrow log_6 + log_6 ( x -1) = 1 [/tex]
Here I am assuming that the base of the logarithm is 6 . The equation can be written as ,
[tex]\sf\longrightarrow log_6 1+ log_6 ( x -1) = 1 [/tex]
Recall the property of log as , [tex]\sf log_x a + log_x b = log_x(ab) [/tex] , on using this property we have ,
[tex]\sf\longrightarrow log_6 \{ 1 ( x -1)\} = 1 [/tex]
Simplify ,
[tex]\sf\longrightarrow log_6 ( x -1) = 1 [/tex]
We know that , if [tex]\sf log_a b = c [/tex] then in expotential form it can be expressed as [tex]\sf a^c = b [/tex] . Using this we have ,
[tex]\sf\longrightarrow 6^1 = x - 1[/tex]
Simplify ,
[tex]\sf\longrightarrow 6 = x - 1[/tex]
Add 1 both sides ,
[tex]\sf\longrightarrow x = 6 + 1[/tex]
Therefore ,
[tex]\sf\longrightarrow \boxed{\blue{\sf \quad x = 7\quad }} [/tex]
Hence the value of x is 7 .
Answer:
x=7
Step-by-step explanation:
log6(1) + log6 (x-1) = 1
We know that log (a) * log (b) = log (ab)
log6 (1*(x-1)) = 1
log6 (x-1) = 1
Raising each side to the base of 6
6 ^log6 (x-1) = 6^1
x-1 = 6
Add 1 to each sdie
x-1+1 = 6+1
x=7
complete the equation: x^2-14x + __ = (__)^2
a. -14; x+14
b. -14; x-14
c. 49; x-7
d. 49; x+7
Answer:
C. 49, x-7
Step-by-step explanation:
(A+B)^2 = A^2 + 2AB + B^2
-14x = 2*A*B
where A=x
Therefore B=-7
and (x-7)^2=x^2-14x+49
Can someone help me with this math homework please!
Answer:
2+4/6=1
y-2/x-6=1
y-2=x-6
y=x-4
or y+4=x
Answer:
3rd option
y + 4 = x
Step-by-step explanation:
look,
point A (0, -4) forms the y intercept
(remember the condition for y intercept? the coordinates for which value of x is 0)
so in the equation
[tex]\boxed{ y= mx+c}[/tex]
c being the y intercept is equal to (-4)
finding the slope :-
[tex]m = \frac{ 2 + 4 }{6 - 0} \\ = \frac{6}{6} = 1[/tex]
plugging all these values into the equation
y = 1x - 4
y= x - 4
taking 4 to the other side
y+ 4 = x
Find the value of X (plz answer quick)
Answer:
let:
4x-9=2x+3
4x-2x=3+9
2x=12
x=12/2
x=6 Ans
Lyon walked 3/4 mile from school to the soccer field.
He then walked 1/6 mile home.
About how many miles did Lyon walk?
Answer:
11/12 miles Lyon walk.
Step-by-step explanation:
3/4 -> 9/12
1/6 -> 2/12
9 + 2 = 11
The solution is :about 11/12 miles Lyon walk.
What is addition?Addition is a way of combining things and counting them together as one large group. ... Addition in math is a process of combining two or more numbers.
here, we have,
given that,
Lyon walked 3/4 mile from school to the soccer field.
He then walked 1/6 mile home.
now, we have to find that,
About how many miles did Lyon walk
so, we need to add the both distance
i.e. 3/4 + 1/6
so, we have,
3/4 -> 9/12
1/6 -> 2/12
so, we get,
9 + 2 = 11
i.e. 3/4 + 1/6
= 9/12 + 2/12
=11/12
Hence, about 11/12 miles Lyon walk.
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A tin of paint covers a surface area of 50m2. Each tin costs £5.60. The entire surface of a solid cylindrical rod with diameter 8m and height 12m needs to be painted. Find the minimum cost of painting the rod. (NO NEED FOR EXLENATION)
the answer is in the picture
Express 2x^2-12x-7 in the form a(x+b)^2+c
Answer:
2(x - 3)^2 - 25.
Step-by-step explanation:
2x^2-12x-7
= 2(x^2 - 6x) - 7
= 2[(x - 3)^2 - 9] - 7
= 2(x - 3)^2 - 18 - 7
= 2(x - 3)^2 - 25.
Y=3/4x - 6 find the x-intercept of the line
Answer:
The x intercept is (8,0)
Step-by-step explanation:
To find the x intercept set y = 0 and solve for x
Y=3/4x - 6
0 =3/4x - 6
6 = 3/4x
4/3 *6 = 4/3*3/4x
8 =x
The x intercept is (8,0)
Answer:
8
Step-by-step explanation:
0 =3/4x - 6
6 = 3/4x
24 = 3x
x = 24/3 = 8
Which equation represents the line that passes through the points (–3, 7) and (9, –1)?
y = negative two-thirds x + 5
y = negative two-thirds x minus 7
y = two-thirds x minus 7
y = two-thirds x + 5
Answer:
1st option
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 3, 7) and (x₂, y₂ ) = (9, - 1)
m = [tex]\frac{-1-7}{9-(-3)}[/tex] = [tex]\frac{-8}{9+3}[/tex] = [tex]\frac{-8}{12}[/tex] = - [tex]\frac{2}{3}[/tex] , then
y = - [tex]\frac{2}{3}[/tex] x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (9, - 1 ) , then
- 1 = - 6 + c ⇒ c = - 1 + 6 = 5
y = - [tex]\frac{2}{3}[/tex] x + 5 ← equation of line
I need help understanding this
Answer:
the first choice
Step-by-step explanation:
Events A and B are independent if the equation P(A∩B) = P(A) · P(B) holds true.
then it means if the events are independent then the probability is multiplying the probability of each event.
?
What single decimal multiplier would you use to decrease by 1% followed by a 3% decrease?
Answer:
0.9797
Step-by-step explanation:
100*101% = 101
101*0.97% = 97.97% = 0.9797
wat iz dis bul crup
i was literally THE hardest math problem EVER
Answer: 289,952,278
Step-by-step explanation: Big brain
Please can someone help me with this question?
9514 1404 393
Answer:
C. f^-1(x) = (x +4)^2; x ≥ -4
Step-by-step explanation:
The range of the given function f(x) is -4 ≤ f(x). This will be the domain of the inverse function.
We find the inverse function by solving ...
x = f(y)
x = √y -4
x +4 = √y
(x +4)^2 = y
The inverse function is ...
f^-1(x) = (x +4)^2 . . . for x ≥ -4
10. A linear line with a positive slope will always cross which of the following once?
A. X-axis
B. y-axis
C. both x and y-axis D. nothing
ANSWER ASAP ILL MARK BRAINLIEST!!!!
find all the real zeros of the quadratic function.
f(x)=2x²-6x-1
Answer:
[tex]2 {x}^{2} - 6x - 1 = 0 \\ a = 2 \: \: \: b = - 6 \: \: \: c = - 1 \\ \\ x = \frac{6\binom{ + }{ - } \ \sqrt{ {6}^{2} - 4(2)( - 1)} }{2 \times 2} \\ \\ x = \frac{6 \binom{ + }{ - } \sqrt{44} }{4} \\ x = \frac{6 + \sqrt{44} }{4} \\ \\ or x = \frac{6 - \sqrt{44} }{4} [/tex]
I hope that is useful for you :)
Triangle SKY with vertices S(-7, 2), K(-1,8), and Y(-2,1) undegoes a reflection with new corrdinates S'(-7,-2), K'(-1, -8), and Y'(-2,-1). Name the line of reflection.
Step-by-step explanation:
reflection under
x-axis
hope this will help you
The line of reflection is given as x-axis.
How to transform a graph of the function?The graph of a function can be transformed by either shifting it in the right, left, up or down.
When the transformation is rightwards, the function becomes as f(x - a).
For left shifting it is f(x + a).
The coordinates of the triangle SKY before and after reflection are given as below,
S(-7, 2) → S'(-7, -2)
K(-1, 8) → K'(-1, -8)
Y(-2, 1) → Y'(-2, -1)
It is clear from the transformed coordinates that the x coordinates are the same but y-coordinate changes.
Thus, the reflection is about x-axis.
Hence, the line of reflection is x-axis.
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Solve for b. Round your answer to the nearest whole degree.
5.1
bº
3.6
100
Answer:
b =44
Step-by-step explanation:
We need to use the law of sines to determine b
sin b sin 100
---------------- = ----------------
3.6 5.1
Using cross products
5.1 sin b = 3.6 sin 100
sin b = 3.6 sin 100 / 5.1
Taking the inverse sin of each side
b = arcsin ( 3.6 sin 100 / 5.1)
b = 44.03984209
To the nearest degree
n = 44
Graph the following inequality 6x-2y>8
Please help me and show me how to graph it.
Answer:
6x - 2y > 8
First, solve the inequality (Isolate the y-variable & put it in function format):
[tex]6x - 2y > 8\\-2y > 8 - 6x\\(-1)(-2y) > (-1)(8-6x)\\2y < 6x-8\\y < \frac{6x-8}{2} \\y < 3x - 4[/tex]
Second, graph the function y = 3x - 4 on the graph.
It should be linear.Because the inequality is < and not ≤, the values on the line aren't included in the solution, so your line should be dotted, not solid.Third, shade in the area below the line(where y-values are smaller).
Since the inequality is <, that means the solutions are smaller than the solutions of the function 3x - 4.