The first day of the snowstorm, there were 9.2 centimeters of snow. During the second day of the storm, another 18.2 centimeters fell. If the total snowfall for the three-day snowstorm was 39.1 centimeters, how much snow fell on the third day?​

A. (0.6, -2.8)

Hope this helps! :)

Answer:

[tex]3\sqrt{5}i[/tex]

Step-by-step explanation:

[tex]\sqrt{-45}[/tex]

[tex]\sqrt{-9*5}[/tex]

[tex]\sqrt{-9}\sqrt{5}[/tex]

[tex]3i\sqrt{5}[/tex]

[tex]3\sqrt{5}i[/tex]

Answer:

its x^4

Step-by-step explanation:

its x^4

[tex]\longrightarrow{\blue{B.\:94\:cm²}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]2 \: (3 \: cm \times 4 \: cm) + 2 \: (3 \: cm \times 5 \: cm) + 2 \: (4 \: cm \times 5 \: cm) \\ \\ = 2 \: (12 \: {cm}^{2} ) + 2 \: ( 15 \: {cm}^{2} ) + 2 \: (20 \: {cm}^{2} ) \\ \\ = 24 \: {cm}^{2} + 30 \: {cm}^{2} + 4 0\: {cm}^{2} \\ \\ = 94 \: {cm}^{2} [/tex]

[tex]\purple{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}[/tex]

Answer:

see below

Step-by-step explanation:   6  13  8  09

area = π r²    is the equation to calculate the area of the pool   r = radius

I don't no if the 1.11 ft is the diameter of the radius, so I will use the 1.11 ft as the diameter

diameter = 2×radius

diameter / 2 = radius

area = π (d/2)²   = T (d/2)²              d = diameter      π  = T      

        = 3.14(1.11 / 2)²              

        = 3.14 × (0.555)²

        = 0.9677 ft²    which seems like a small pool!

Answer:

108 cm

Step-by-step explanation:

You can cut off the piece sticking out and "attach" it to the other side to make a complete rectangle. From there, multiply 4.5 * 24. You should end up with 108 cm².

Answer:

D

Step-by-step explanation:

Given

(x + 2)² + 5(x + 2) - 6 = 0

Using the substitution u = x + 2 , then the equation can be expressed as

u² + 5u - 6 = 0 → D

Answer:

74

Step-by-step explanation:

84+84=168

316-168=148

148/2=74

Answer:

$577

Step-by-step explanation:

Let y = amount of money in the account.

Let x = number of months.

The withdrawals are always the same amount and occur every month, so this is a linear relation.

We are given two points of the relation: (5, 442) and (13, 226).

y = mx + b

m = (442 - 226)/(5 - 13) = 216/(-8) = -27

The slope, -27, represents the amount she withdraws each month.

y = -27x + b

442 = -27(5) + b

442 = -135 + b

b = 577

y = -27x + 577

b = y-intercept = initial amount

Answer: The input was $577.

Answer: B, B, and C

Step-by-step explanation: yo mama

Answer:

- 7 × i²⁹

Step-by-step explanation:

- 7 × i²⁹

Answer: -7 i

i kinda used g o o ogle but this is what it said, hope th is helps.

Answer:

340

Step-by-step explanation:

To find the cost of 4 liters of juices, take the cost of 1 liter and multiply by 4

4 *85 = 340

Answer: It's $340

Step-by-step explanation:

4 liters of juice - 3 liters = 1 liter

Multiply 1 liter by 4 = 340 (4 x 85)

Answer: $340

Answer: 25.8°

Step-by-step explanation:

We use CAH = Adjacent/Hypotenuse

Cos x = 27/30

Cos x = 25.8°

Answer:

Step-by-step explanation:

(-3,-2)

Answer:

0

Step-by-step explanation:

f(x)=2•3x

f(x)=6x+0

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

7 a)

Step 1 :

Make the denominators the same

           [tex]-\frac{1}{7} \ and \ \frac{2}{9}[/tex]

[tex]-\frac{1}{7} \times \frac{9}{9} = -\frac{9}{63}\\\\\frac{2}{9} \times \frac{7}{7} = \frac{14}{63}\\[/tex]

Step 2 :

Now find rational between (-9/63) and (14/63).

Just change the number in the numerator. Write any numbers between -9 and 14 in the numerator.

                            [tex]\frac{ -8}{63}, \ \frac{-7}{63},\ \frac{3}{63},\ \frac{6}{63},\ \frac{8}{63}[/tex]

7 b )

       [tex]x = 3 + 2\sqrt2\\\\x + \frac{1}{x} = (3 + 2\sqrt2) + \frac{1}{3+2\sqrt2}[/tex]

[tex][ Rationalize \ the \ denominator : \frac{1}{3 + \sqrt2} \times \frac{3 - 2\sqrt2}{3-2\sqrt 2} = \frac{3 - 2 \sqrt2}{3^2 - (2 \sqrt2)^2 } = \frac{3 - 2\sqrt2}{9 - 8} = 3 - 2\sqrt 2 \ ][/tex]

       [tex]therefore , x + \frac{1}{x} = 3 + 2\sqrt 2 + 3 - 2 \sqrt 2 = 6 + 0 = 6[/tex]

Answer:

it is quite difficult

Step-by-step explanation:

hope you understand

Answer:

As shown in the figure.

Step-by-step explanation:

At the bottom is the answer.

Answer:

Step-by-step explanation:

V = L * W * H

L = 4

W = 3

H = 2

V = 4 * 3 * 2

V = 24

Density = mass / Volume

density = 11.34

volume = 24

mass = ?

11.34 = mass / 24                   Multiply both sides by 24

11.34 * 24 = 24 * mass /24

mass = 272.16 grams

Answer:

220 yards in one minute

Step-by-step explanation:

15 miles in 120 minutes equals 26,400 (15 · 1760) yards in 120 minutes

26,400 yards in 120 minutes equals 220 yards in 1 minute (after dividing both 26400 and 120 by 120)

Answer:

220

Step-by-step explanation:

The first guy explained it, look above. I was about to say something similair

Answer:

F

E or C (depending on the actual angles - see below in the details)

Step-by-step explanation:

two triangles are congruent, when after some rotation or mirroring they can cover each other exactly.

that means they must both have the same angles and side lengths.

these are the possible conditions to determine that 2 triangles are congruent (without knowing ALL of the sides and angles) :

SSS (Side-Side-Side) - all 3 sides of triangle 1 are exactly of the same length as the 3 sides of triangle 2.

SAS (Side-Angle-Side) - 2 sides and one angle are the same

ASA (Angle-Side-Angle) - 2 angles and the side between these 2 angles are the same

AAS (Angle-Angle-Side) - 2 angles and any not-included side are the same

RHS (Right angle-Hypotenuse-Side) - both triangles are right-angled (one angle is 90 degrees), and the Hypotenuse (the side opposite to the 90 degree angle) and another side are the same.

so, now look at a).

we only know the angles. but we could use a zoom lens of a camera and make them bigger and smaller, while their angles remain actually the same.

therefore, we cannot say, if they are actually congruent (only if their side lengths are the same too).

but we can say that they could be congruent.

and therefore also none of the congruent conditions apply, because for all of them we always need at least one side length. and we don't have that.

now looking at b)

I am not sure I can read one of the given angles correctly.

case one: I read the angles in triangle 2 as 66 and 58 degrees. that would make the third angle

180 - 66 - 58 = 56

but triangle 1 has the angles of 68, 54 and

180 - 68 - 54 = 58

=> the three angles are not the same, so the triangles are definitely not congruent

case two: I could read the angles in triangle 2 also as 68 and 58. that would make the third angle

180 - 68 - 58 = 54

and the side connecting the 68 and 58 angles has the same length, so the ASA criteria are fulfilled, and the triangles are congruent. C

Answer:

I'm like positive it's C...

Step-by-step explanation:

Answer:

45/28

Step-by-step explanation:

take angle R as reference angle

tan R=opposite/adjacent

=45/28

Answer:

Step-by-step explanation:

Given that:

[tex]P = \left[\begin{array}{ccc}0.22&0.20&0.65\\0.62&0.60&0.15\\0.16&0.20&0.20\end{array}\right][/tex]

For a steady-state of a given matrix [tex]\bar X[/tex]

[tex]\bar X = \left[\begin{array}{c}a\\b\\c\end{array}\right][/tex]

As a result P[tex]\bar X[/tex] = [tex]\bar X[/tex] and a+b+c must be equal to 1

So, if P[tex]\bar X[/tex] = [tex]\bar X[/tex]

Then;

[tex]P = \left[\begin{array}{ccc}0.22&0.20&0.65\\0.62&0.60&0.15\\0.16&0.20&0.20\end{array}\right]\left[\begin{array}{c}a\\b\\c\end{array}\right] =\left[\begin{array}{c}a\\b\\c\end{array}\right][/tex]

[tex]\implies \left\begin{array}{ccc}0.22a+&0.20b+&0.65c\\0.62a+&0.60b+&0.15c\\0.16a+&0.20b+&0.20c\end{array} \right = \left \begin{array}{c}a ---(1)\\b---(2)\\c---(3)\end{array}\right[/tex]

Equating both equation (1) and (3)

(0.22a+ 0.2b + 0.65c) - (0.16a + 0.2b + 0.2c) = a - c

0.06a + 0.45c = a - c

collect like terms

0.06a - a = -c - 0.45c

-0.94 a = -1.45 c

0.94 a = 1.45 c

[tex]c =\dfrac{ 0.94}{1.45}a[/tex]

[tex]c =\dfrac{ 94}{145}a --- (4)[/tex]

Using equation (2)

0.62a + 0.60b + 0.15c = b

where;

c = 94/145 a

[tex]0.62a + 0.60b + 0.15(\dfrac{94}{145}) a= b[/tex]

[tex]0.62a + 0.15(\dfrac{94}{145}) a= -0.60b+b[/tex]

[tex]0.62a + (\dfrac{141}{1450}) a= 0.40b[/tex]

[tex](0.62+\dfrac{141}{1450}) a= 0.40b[/tex]

[tex](\dfrac{62}{100}+\dfrac{141}{1450}) a= 0.40b[/tex]

[tex](\dfrac{1043}{1450})a= 0.40b[/tex]

[tex](\dfrac{1043}{1450})a= \dfrac{4}{10} b[/tex]

[tex](\dfrac{1043 \times 10}{1450 \times 4})a = \dfrac{4}{10} \times \dfrac{10}{4}[/tex]

[tex]b = (\dfrac{1043}{580}) a --- (5)[/tex]

From a + b + c = 1

[tex]a + \dfrac{1043}{580}a + \dfrac{94}{145} a = 1[/tex]

[tex]a + \dfrac{1043}{580}a + \dfrac{94*4}{145*4} a = 1[/tex]

[tex]a + \dfrac{1043}{580}a + \dfrac{376}{580} a = 1[/tex]

[tex]\dfrac{580+ 1043+376 }{580} a= 1[/tex]

[tex]\dfrac{1999}{580} a= 1[/tex]

[tex]a = \dfrac{580}{1999}[/tex]

∴

[tex]b = \dfrac{1043}{580} \times \dfrac{580}{1999}[/tex]

[tex]b = \dfrac{1043}{1999}[/tex]

[tex]c = \dfrac{94}{145} \times \dfrac{580}{1999}[/tex]

[tex]c= \dfrac{376}{1999}[/tex]

∴

The steady matrix of [tex]\bar X[/tex] is:

[tex]\bar X = \left[\begin{array}{c}\dfrac{580}{1999} \\ \\ \dfrac{1043}{1999}\\ \\ \dfrac{376}{1999}\end{array}\right][/tex]

Answer:

Cost of one doughnut = $1.25

Step-by-step explanation:

Doughnut           Cost

  3                       3.75

   1                         x

[tex]\frac{3}{1} = \frac{3.75}{x}\\\\3 \times x = 3.75 \times 1\\\\x = \frac{3.75}{3} = \$ 1.25[/tex]

Answer:

$1.25

Step-by-step explanation:

We need to find the cost of one doughnut.

the total price is $3.75

3.75/3 = 1.25

each doughnut costs $1.25

Answers:

=============================================

Explanation:

The formula we use for "or" cases is

P(A or B) = P(A) + P(B) - P(A and B)

If events A and B are mutually exclusive, then we ignore the P(A and B) part since that is 0. Mutually exclusive events cannot occur simultaneously, which is why we have that 0.

-----------

For "and" cases, we have two basic flavors

P(A and B) = P(A)*P(B | A)

P(A and B) = P(B)*P(A | B)

We go with the first case for problem 2. These formulas apply if A and B are not independent.

If they are independent, then

P(A and B) = P(A)*P(B)

-----------

Start with the equation P(A and B) = P(B)*P(A | B) and divide both sides by P(B).

You'll end up with

P(A | B) = P(A and B)/P(B)

which is a conditional probability.

Answer:

true

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

The applicable relation in each case is ...

  s = rθ

where s is arc length, r is radius, and θ is rotation angle in radians. Of course the relation between degrees and radians is that π radians = 180°.

__

1. s = (1.5 m)(302.2/180π) ≈ 7.91 m

About 7.91 meters of wire will be wound on the drum.

__

2. The area of a sector is found by a formula that is similar to that for the area of a triangle. For a triangle, the area is A=1/2bh, where b is the base length and h is the height of the triangle. For a sector, the area is A=1/2sr, where s is the arc length and r is the radius. Usually, this is put in the form ...

  A = 1/2sr = 1/2(rθ)r

  A = 1/2r²θ

The angle through which the pendulum sweeps is ...

  (9°/s)(4 s) = 36° = (36°/180°)π radians = π/5 radians

Then the swept area is ...

  A = 1/2(14 cm)²(π/5) = 19.6π cm² ≈ 61.58 cm²

Each complete right to left swing sweeps an area of about 61.58 cm².

__

3. Each rotation is 2π radians of angle, so the angular speed is ...

  angle/time = (2π radians/revolution)(17 revolutions)/(32 s) = 17/16π radians/s

  ≈ 3.34 radians/s

The distance covered per unit time is found using the arc length formula above.

 (arc length)/time = (rθ)/time = (25 cm)(17/16π rad/s)

 = (426/16)π cm/s ≈ 83.45 cm/s . . . . . pulley rim speed

Answer:

using the formula is 87°F but without it is near 140°F

Answer:

Three of your next six donuts sold will be cake donuts.

Step-by-step explanation:

14:7 simplified to a unit ratio is 2:1. Using this information, we know that 6:3 is the ratio for the next 6 donuts.

Answer:

The function is increasing for all real values of x where

–6 < x < –2.

Answer:

4 weeks = 105

16 weeks = 42

24 weeks = 0

Step-by-step explanation:

the function is missing the 'w'

it should be : C(w) = 126 - 5.25w

'w' is the number of weeks

Substitute number of weeks in the 'w' spot

first one is 4 weeks, so

C(w) = 126 - 5.25(4)

= 126 - 21

= 105