The gravitational force does change believe it or not, but the explaination for this is because the earths orbit is an oval (or a not circle) the closer it nears its self to the sun.
The hull of a sunken boat, laying on the seabed, is 9 m below the surface of the sea, where the sea water has an average density of 1,025 kg/m3. The hull’s surface area is 12 m2. What is the total force exerted by seawater on the hull?Required to answer. Single line text.
Answer:
1084860 N
Explanation:
Applying,
P = ρgh................ Equation 1
Where P = pressure, ρ = density, h = height, g = acceleration due to gravity.
From the question,
Given: ρ = 1025 kg/m³, h = 9 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
P = (1025)(9)(9.8)
P = 90405 N/m²
Also,
P = F/A.............. Equation 2
Where, F = Force, A = Area.
Make F the subject of the equation
F = PA............... Equation 2
Given: A = 12m²
F = 12(90405)
F = 1084860 N
Express 0.00005 s in µs
Answer:
0.00005 second =
50 microseconds
Time
0.00005
Second
50
Microsecond
A 62.0 kg water skier at rest jumps from the dock into a 775 kg boat at rest on the east side of the dock. If the velocity of the skier is 4.50 m/s as she leaves the dock, what is the final velocity of the skier and boat?
2.78 m/s to the east
2.78 m/s to the west
0.360 to the west
0.360 to the east
Answer:
The final velocity of the skier and boat is 0.33 m/s to the east.
Explanation:
We can find the final velocity of the skier by conservation of linear momentum:
[tex] m_{s}v_{s_{i}} + m_{b}v_{b_{i}} = m_{s}v_{s_{f}} + m_{b}v_{b_{f}} [/tex]
Where:
[tex]m_{s}[/tex]: is the mass of the water skier = 62.0 kg
[tex]m_{b}[/tex]: is the mass of the boat = 775 kg
[tex]v_{s_{i}}[/tex]: is the initial velocity of the skier = 4.50 m/s (as she leaves the dock)
[tex]v_{b_{i}}[/tex]: is the initial velocity of the boat = 0 (it is at rest)
[tex]v_{s_{f}}[/tex]: is the final velocity of the skier =?
[tex]v_{b_{f}}[/tex]: is the final velocity of the boat =?
Since the final velocity of the skier is the same that the velocity of the boat ([tex]v_{f}[/tex]) we have:
[tex] m_{s}v_{s_{i}} + 0 = v_{f}(m_{s} + m_{b}) [/tex]
[tex]v_{f} = \frac{m_{s}v_{s_{i}}}{m_{s} + m_{b}} = \frac{62.0 kg*4.50 m/s}{62.0 kg + 775 kg} = 0.33 m/s
Therefore, the final velocity of the skier and boat is 0.33 m/s to the east.
I hope it helps you!
A person is pushing a box across a table. The measured forces on the box are 10N, 14N, -7N, -10N.
Which force is represented by -7N?
A) force of friction
B) normal force
C) force of gravity
D) push force
Answer:
the answer to this question is c
Answer:
A) force of friction
Explanation:
frictional forces are always negative, they are an opposing force they act opposite to the applied force.
15. You are watching a baseball game on television that 15
being broadcast from 4500 km away. The batter hits
the ball with a loud "crack" of the bat. A microphone
is located 22 m from the batter, and you are 2.0 m from
the television set. On a day when sound travels 343 m/s
in air, what is the minimum time it takes for you to hear
the crack of the bat after the batter hits the ball?
Answer:
t_total = 6.99 s
Explanation:
It asks us how long it takes to hear the sound, for this we must look for the time (t₁) it takes for the sound to reach the microphone, the time it takes for the video signal (t₂) to reach the television and the time (₃) it takes for the TV sound to reach us, so the total delay time is
t_total = t₁ + t₂ + t₂
we look for t1, it indicates that the distance x = 22m
v = x / t
t = x / v
t₁ = 22/343
t₁ = 6.41 10-2 s
time t₂
t₂ = 4500 103/3 108
t₂ = 1.5 10-5 s
time t₃
t₃ = 2/343
t₃ = 5.83 10⁻³
Total time is
t_total = t₁ + t₂ + t₃
t_total = 6.41 10⁻² + 1.5 10⁻⁵ + 0.583 10⁻²
t_total = 6.99 s
Atividade 1) A presença do campo magnético terrestre proporciona alguns efeitos interessantes. Dentre eles estão as auroras polares. Faça uma pesquisa e explique como esse fenômeno ocorre. Atividade 2 Utilizando a simulação mostrada na figura abaixo, aproxime o ímã da bússola em várias posições ao longo do plano. a) O que representam as pequenas agulhas ao redor do ímã? b) O que acontece com a agulha da bússola quando o ímã é movimentado ao seu redor? c) Marque a seleção "Mostrar medidor de campo". Movimente o medidor de campo O que você observa em relação ao campo magnético⃗ , quando o medidor de campo se aproxima do imã? c) Marque a caixa de seleção "planeta Terra". Como são mostradas as polaridades do ímã? Por que aparece dessa forma?
A puck is travelling at a speed of 28 m/s. If it has a mass of 200 g, what is its momentum?
Answer:
Explanation:
Momentum is equal to mass times velocity:
p = mv; therefore,
p = .200(28) and
p = 5.6 [tex]\frac{kg*m}{s}[/tex]
what is the Young's modulus of a perfect rigid body
Answer:
Infinite
Explanation:
Young's modulus is infinite and bulk modulus is zero.
Answer:
Young's modulus is the ratio of tensile stress ( force of elasticity ) to tensile strain ( extension ).
Explanation:
[tex]E = \frac{stress}{strain} [/tex]
lubricants reduce friction by replacing sliding friction with fluid friction
Which of the following statements is incorrect?
1) A ray of light travels from a point A to point B in a path that takes the shortest time
2) In reflection angle of incidence equal to angle of reflection
3) Magnification for a plane mirror is always unity
4) A plane mirror can form only virtual images
Answer:
2
Explanation:
in reflection the incident ray and reflected rays are equal an angle
A car takes a full round of journey in a roundabout with constant speed, as the driver got confused with the route. Can we consider it as a uniform motion? Why?
Answer: The given statement is True
Explanation:
A uniform motion is defined as the motion where an object is moving at a constant speed.
A non-uniform motion is defined as the motion where an object keeps changing its position and does not move at a constant speed.
We are given:
A car takes a full round of journey in a roundabout with constant speed
As the speed remains constant in a circular path, it is considered a uniform motion.
Hence, the given statement is True
a body of mass 5kg moving on a horizontal ground has a coefficient of friction 0.36.find the normal reaction acting on the body?
Answer:
50 N.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 5 Kg
Coefficient of friction (μ) = 0.36
Normal reaction (N) =?
Next, we shall determine the weight of the body. This can be obtained as follow:
Mass (m) = 5 Kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
W = mg
W = 5 × 10
W = 50 N
Finally, we shall determine the normal reaction. This can be obtained as follow:
Weight (W) = 50 N
Normal reaction (N) =?
Normal reaction = weight of the body
N = W = 50 N
Thus, the normal reaction acting on the body is 50 N
What happens when two polarizers are placed in a straight line, one behind the other?
A. They allow light to pass only if they are polarized in exactly the same direction.
B. They block all light if they are polarized in exactly the same direction.
C. They allow light to pass only if their directions of polarizations are exactly 90° apart.
D. They block all light if their directions of polarizations are exactly 90° apart.
E. They block all light If their directions of polarizations are either exactly the same or exactly 90° apart.
please I need the answer right now will mark you brainliest
Answer:
Explanation:
what do u need help with
Answer:
that's for frequency other answers are coming soon
What is the variable unit for acceleration,gravity and height
Answer:
HLW ITS JESS BREGOLI
YOUR ANSWER IS HERE
At different points on Earth's surface, the free fall acceleration ranges from 9.764 m/s2 to 9.834 m/s2[2] depending on altitude and latitude, with a conventional standard value of exactly 9.80665 m/s2 (approximately 32.17405 ft/s2). Locations of significant variation from this value are known as gravity anomalies.
Explanation:
HOPE IT MAY HELP YOU !!
Susan claims that she can throw a dart at a dartboard from a distance of 3.0m and hit the 5.0cm wide bull's-eye if she throws horizontally with a speed of 20 m/s. She starts to throw at the same height as the top of the bull's-eye. Will Susan hit the bull's-eye?
What is being asked? How to calculate?
Hai tiếp điểm hình trụ bằng đồng có đầu hình cầu bán kính R = 70mm, lực ép tiếp điểm F = 100N, Mô đun đàn hồi của đồng là 11.8 * 106(N/cm2). Cho biết: a = 0.86 * (F*R/E)1/3, điện trở suất của đồng là 1.62 * 10-8 (Ω/m), với tiếp điểm đồng thì hệ số K1 = 3,16.10-4 (ΩN1/2). Biết các giá trị ứng suất của đồng là: σdh = 38300 N/cm2; σdẻo = 45000 N/cm2; σd.Nát = 51000 N/cm2. Tính điện trở tiếp xúc trong trường hợp thỏa mãn điều kiện tản dòng lí tưởng và trong trường hợp thực nghiệm.
Answer:
5dhydydyeze6ese6z7zuezuze6ezyezyezzeze
A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Find the velocity of the car at t = 1.0 s, t = 2.0 s and t = 5.0
Answer:
a) [tex]A=5m/s^2[/tex]
b) [tex]V=25m/s[/tex]
Explanation:
From the question we are told that:
Velocity [tex]v=90km/h=25m/s[/tex]
Time [tex]t=5.0s[/tex]
a)
Generally From Newton's motion equation for Average acceleration is mathematically given by
[tex]A=\frac{V-U}{t}[/tex]
Since its from Rest Therefore
[tex]U=0[/tex]
[tex]A=\frac{25m/s-0}{5s}[/tex]
[tex]A=5m/s^2[/tex]
b)
Generally the equation for Average Velocity is mathematically given by
[tex]V=u+at[/tex]
[tex]AT t=1.0s\\\\V=0+5(1)[/tex]
[tex]V=5m/s[/tex]
[tex]AT t=2.0s\\\\V=0+5(2)[/tex]
[tex]V=10m/s[/tex]
[tex]AT t=5.0s\\\\V=0+5(5)[/tex]
[tex]V=25m/s[/tex]
The three scientists credited with using all available data and correctly determing the sturcture of dna from many years of previous work are
Answer:
James Watson, Francis Crick, and Maurice Wilkins
Explanation:
The three scientists that used the available data ( x-ray images of DNA provided by Rosalind Franklin) to correctly determine the structure of DNA are : James Watson, Francis Crick, and Maurice Wilkins.
These scientists discovered the structure of DNA in 1953 and they received, and they receive a Nobel Prize in Physiology or Medicine for their discovery
Activity 1 MATCH IT
Directions: Match Column A to Column B. Write your answer on the space provided before the number.
COLUMN A
__1. Hiking
__2. Orienteering
__3. Zumba
__4. Volleyball
__5.badminton
COLUMN B
A. It is an outdoor navigational recreational activity using specially drawn and detailed maps.
B. Created through on-the –spot aerobics class using the non- traditional music.
C.Going on an extended walk for the purpose of pleasure and exercise.
D. Can be traced from the ingenuity of William J. Morgan in 1895 at Holyoke Massachusetts.
E. Games are held inside the gym to avoid the effect of air in the flight of the shuttle.
Answer:
1. A hiking
2. C
3. B
4. D
5. E
What is centripetal force? A. A force acting parallel to the path of an object in circular B. A force opposing motion along a circular path C. A force acting away from the center of a circular motion D. A force acting toward the center of a circular motion
Answer:
c.
Explanation:
Answer:
Centripetal force is the force acting towards the center of circular motion or path.
[tex]{ \tt{formular : \: F = \frac{m {v}^{2} }{r} }} \\ { \tt{F : \: is \: centripetal \: force}} \\ { \tt{m : \: is \: mass}} \\ { \tt{v : \: is \: velocity}} \\ { \tt{r : \: is \: radius}}[/tex]
Explanation:
Its opposite is centrifugal force which acts away from the center of circular path.
On which planet would your weight be the most and the least?
a) Jupiter and Mercury
b. Jupiter and neptune
c. Saturn and Neptune
d. Saturn and uranus
Answer:
Jupiter and neptune
Explanation:
An 8kg ball travelling at 4m/s collides head on with a 3kg ball travelling at 14m/s. Rhe balls bounce off each other and travel back the way they came. The 8kg ball travels away at 2m/s calculate velocity of 3kg ball after the collision.
Answer:
Explanation:
There are a couple of assumptions I had to make here and also a couple of rules based on what I use in my classroom when I teach the Law of Momentum Conservation. First of all, I am going to call the 8kg ball 1 and say that it is moving to the right (and right is positive), and that means that the 3kg ball is ball 2 and say that it is moving to the left (and left is negative). I had to assume that the 2 balls were moving towards each other; hence, the different signs assigned to their movement. I also added in another significant digit since we have only 1 in most of these values and adding in a .0 is not going to change the value of any number. The Law of Momentum Conservation in this particular instance says
[tex][m_1v_1+m_2v_2]_b=[m_1v_1+m_2v_2]_a[/tex] which is the mathematical way of saying that the momentum after the collision is the same as the momentum before it. Filling in:
[tex][(8.0*4.0)+(3.0*-14)]_b=[(8.0*-2.0)+(3.0*v)]_a[/tex] and doing the math here simplifies to
32 - 42 = -16 + 3.0v and
-10 = -16 + 3.0v and
6.0 = 3.0v so
v = 2.0 (and the positive indicates that ball 2 is now moving to the right)
A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ?
70 N
80 N
75 N
85 N
Answer:
the correct answer is 75 N
Explanation:
This is a translational balancing exercise, let's set a reference system with the x-axis in the direction of the plane and the y-axis perpendicular to the plane.
In this reference system the force to decompose is the weight
sin 42 = Wₓ / W
cos 42 = W_y / W
Wₓ = W sin 42
W_y = W cos 42
Wₓ = 112.1 sin 42 = 75.0 N
W_y = 112.1 cos 42 = 83.3 N
The expression for equilibrium on the x-axis is
Wₓ - fr = 0
fr = Wₓ
fr = 75.0 N
the correct answer is 75 N
Can someone help me with this? I will give brainliest! Ridiculous answers will be reported. Thank you.
Aiden is writing a report about the structure of the atom. In her report, she says that the atom has three main parts and two subatomic particles. Do you agree with her? Why or why not?
Answer:
I don't agree
Explanation:
Atoms have 3 subatomic particles protons, electrons and neutrons,
Q3. (a) The student places 0.5 kg of potato into a pan of water.
During cooking, the temperature of the potato increases from 20 °C to 100°C
The specific heat capacity of the potato is 3400 J/kg °C
80
Calculate the change in thermal energy of the potato. Use the equation:
change in thermal energy = mass * specific heat capacity * temperature change
m = 0.5kg
C = 34001
TA= 20° - 100°
° = 80°C
OʻS x 3400 x 80 - 136000J
136000
Change in thermal energy =
(b) Why is the energy supplied by the cooker greater than that calculated in part (a)?
HELP
Give atleast (5) etypes of cleaning tools , equipment,supplies, and materials that you can find either in your home or school. Identify each use
Answer and Explanation:
Cleaning tools, equipment, supplies, and materials that can be easily found in a school in one each are: scrub brush, sponges, buckets and brooms.
These equipments are essential to promote a clean, organized and safe environment and for this reason, they can be easily found both at school and in a home, since the cleanliness of these two places is essential for the well-being, proactivity and health of the people who attend them.
A horse pulls a wagon with a force of 200 N for a distance of 80 m. How much work
does the horse do?
Answer:
w=f×s
w = 16000 J, hope this helps
A student connects a small solar panel to a 40 a resistor to make a simple circuit. The solar panel produces a voltage of 2 0.
a Calculate the current in the student's circuit.
Ohm's law states that :
[tex]v = ir[/tex]the terms used are :
[tex]r = resistance[/tex][tex]v = potential \: \: difference[/tex][tex]i = current[/tex]let's solve for electric current :
[tex]2 = i \times 40[/tex][tex]i = \dfrac{2}{40} [/tex][tex]i = 0.05 \: A[/tex][tex]i = 50 \: mA[/tex][tex]\mathfrak{good\: \: luck \: \: for \: \: your \: \: assignment}[/tex]