The distance between Kuala Pilah and Bangi is x km. A bus travelled from Kuala Pilah to Bangi at an average speed of 80 km/h. On the return journey from Bangi to Kuala Pilah, the bus travelled at an average speed of 100 km/h and it took 15 minutes less than the previous one. Calculate the value of x.

A. 80 km
B. 100 km
C. 120 km
D. 160 km​

Step-by-step explanation:

this is confusing.

first the description says "the internal dimensions".

and then it tells us the thickness of the tank walls (1cm).

so, I am not sure what the given numbers describe.

in any case, the volume is length × width × height.

so, either

48×38×32

or

46×36×31 (as for length and width we need to consider 2 walls, one on each end, for the height only one wall, as the tank is open and lidless.

whatever you choose, make sure to mark the result as cm³.

Answer:

No solution.

Step-by-step explanation:

[tex]6m-m=\frac{5}{6}(6m-10)\\5m=5m-\frac{25}{3}\\0\neq -\frac{25}{3}[/tex]

Therefore, there is no solution.

If you can give the proportion then it would be better.

I am asuming

8:x::9:36

Then 8:x::1:4

So x = 32

Answered by Gauthmath must click thanks and mark brainliest

Answer:

x = 32

Step-by-step explanation:

[tex]\frac{8}{x}[/tex] = [tex]\frac{9}{36}[/tex] = [tex]\frac{1}{4}[/tex] ( cross- multiply )

x = 8 × 4 = 32

Answer:

18 feet

Step-by-step explanation:

To convert : multiply the length value by 3

=> 6 x 3

=> 18 feet

Answer:

105

Step-by-step explanation:

25 days = Food for 630 men

30 days = x           (Inverse variation)

30 * x = 630 * 25

x = 630 * 25/30

  = 21 * 25

  = 525 men.

630 - 525 = 105 men.

Therefore, 105 men must be transferred to another camp so that the food lasts for 30 days.

Answer:

3x^3 ⋅ √2x

Step-by-step explanation:

Answer:

B .62.5 m

Step-by-step explanation:

convert Kmh-1 in to ms-1

30 Kmh-1 = (30×1000) ÷3600 = 8.3ms-1

60 Kmh-1 = (60×1000) ÷3600 = 16.6 ms-1

acceleration = (16.6 - 8.3) ÷ 5 = 1.66 ms-2

V^2 = U^2 +2aS

(16.6)^2 = (8.3)^2 + 2×1.66 ×S

S = 62.5 m

Answer and Step-by-step explanation:

Simply use the Pythagorean Theorem to solve.

The Pythagorean Theorem is used to solve for a side in right triangles.

[tex]A^{2} +B^{2}= C^{2}[/tex]

Plug the sides values into the equation.

[tex]A^{2} + 13^2 = 20^2\\\\A^2 + 169 = 400\\\\A^2 = 231\\\\A = 15.1987[/tex]<- This is the answer.

#teamtrees #PAW (Plant And Water)

Answer:

Sure:)! the answer is-487.5

Step-by-step explanation:

As said in the problem pie=3 as determined in the problem. Hence, the answer is 487.5

Hope this helps :)!

Step-by-step explanation:

[tex]volume = \frac{4}{3} \pi \: {r}^{3} \\ = here\pi = 3 \\ then \: v = \frac{4}{3} \times 3 \times {5}^{3} \\ = 4 \times 125 \\ = 500 {in}^{3} \\ thank \: you[/tex]

Answer:

2.1

Step-by-step explanation:

The expected value of a probability is given by the formula:

E(x) = Σxp(x)

Therefore from the table showing the winnings of a game, the expected value of the probability distribution is:

E(x) = Σxp(x) = (0 * 0.5) + (2 * 0.2) + (4 * 0.15) + (6 * 0.1) + (10 * 0.05)

E(x) = 0 + 0.4 + 0.6 + 0.6 + 0.5 = 2.1

Hence we can conclude that the expected value of the winnings of the game is 2.1.

Answer:

40 oranges are there in 100 fruites.

Answer/Step-by-step explanation:

1. To find the area of the shaded region, you'd find the area of the white rectangular shape, next, find the area of the whole triangular shape, then find the difference of their areas to get the area of the shaded region. Thus, the formula to use would be:

Area of shaded region = area of triangle - area of rectangle

Area of shaded region = ½*base*height - length*width

1. a. Volume of triangular prism = area of triangular base * height of prism

Volume of triangular prism = ½bh * H

Where,

b = 6 m

h = 4 m

H = 8 m

Substitute

Volume of prism = ½*6*4*8

Volume of prism = 96 m³

b. Volume of sphere = ⁴/3πr³

Where,

r = 9 cm

Substitute

Volume = ⁴/3*π*9³

Volume = ⁴/3*π*729

Volume ≈ 3,053.6 cm³ (nearest tenth)

2. Use Pythagorean theorem to find the height of the cone

radius of the cone (r) = ½(16) = 8 cm

Slant height (l) = 11 cm

height (h) = ?

Using Pythagorean theorem, we have:

h = √(l² - r²)

Substitute

h = √(11² - 8²)

h = √(57)

h ≈ 7.5 cm (nearest tenth)

b. Volume of the cone = ⅓πr²h

where,

r = 8 cm

h = 7.5 cm

Volume = ⅓*π*8²*7.5

Volume = 502.7 cm³ (nearest tenth)

Answer:

y=-20m+500

Step-by-step explanation:

please mark this answer as brainlist

Answer:

(x-y)^2

p^2+p^2

Step-by-step explanation:

^2 means square

Answer:

see explanation

Step-by-step explanation:

x² - y² ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

x² - y²

= (x - y)(x + y)

------------------------------

(p + p)²

= (2p)²

= 2p × 2p

= 4p²

Answer:

Is this answer correct.Does the anwer help you

Answer:

The answer is in the screenshot -6x-6

Step-by-step explanation:

Answer: SA = 644 cm²

Step-by-step explanation:

STEP ONE: Find the surface area of the smaller rectangle (green)

There are in total 5 sides because one of the sides is not shown on the surface level.

Upper base = 3 × 3 = 9 cm²

4 sides = 3 × 8 × 4 = 96 cm²

Total = 9 + 96 = 105 cm²

STEP TWO: Find the surface area of the larger rectangle (orange)

There are in total 5 whole sides with one side covered by the base of the smaller rectangle (green) which should later be subtracted.

Front and back = 7 × 10 × 2 = 140 cm²

Left and right = 7 × 12 × 2 = 168 cm²

Lower base = 10 × 12 = 120 cm²

Upper base = 10 × 12 - 3 × 3 = 111 cm²

Total = 140 + 168 + 120 + 111 = 539 cm²

STEP THREE: Find the total surface area

SA = Green + Orange = 105 + 539 = 644 cm²

Hope this helps!! :)

Please let me know if you have any questions

Answer:

p=8

Step-by-step explanation:

-5log(p+1)+2=-8

-5log(p+1)=-10

log(p+1)=2

p+1=9, p=8

Answer:

B. First quartile

Step-by-step explanation:

The first quartile is the first 25% of a line graph, and the median of the lower half of a data set would be the median of the median, which means it would split the graph at 25%

Answer:

-5

Step-by-step explanation:

since it is a lose, it is represented by a negative sign.

Answer:

0.8 -4*0.8-7=0.8*2x-1

0.8-3.2-7=1.6x-1

0.8-10.2+1=1.6x

1.8-10.2=x1.6

-8.4=x 1.6

x= -8.4 / 1.6

x= - 5.25

Answer:

(0.7465 , 0.8429 )

Step-by-step explanation:

Confidence Level - "P" values  

90% 1.645

Confidence Interval - "P" values  

(0.7465 , 0.8429 )  

Answer:

solving for X it would be (-infinity ♾️, +infinity ♾️) or all real numbers

Answer:

20 is the answer

Step-by-step explanation:

x+3x+10=90(right angle triangle)

4x=90-10

x=80/4

x=20°

Answer:

x = 20

Step-by-step explanation:

Based on the square indication at the corner of the angle, we can assume it's a right angle, so 90°. This means that x + 3x + 10 = 90. Solve it like any algebraic equation, isolating x. add x to 3x + 10, this would net you 4x + 10 = 90. Subtract 10 on both sides of the equation to further isolate x, meaning 4x = 80. Simplify this, dividing 4 on both sides, meaning x = 20.

Answer:

Step-by-step explanation:

The formula for finding the area of a pentagon(regular) given 1 side is

A = [tex]\frac{1}{4}\sqrt{5(5+2\sqrt{5})}s^{2}\)[/tex]

s (the side) = 12

Area = [tex]\frac{1}{4}\sqrt{5(5+2\sqrt{5})}12^{2}\)[/tex]

Area = [tex]\frac{1}{4}\sqrt{5(5+2\sqrt{5})}144\)[/tex]

Area = sqrt(5(5 + 2*2.2361) * 36

Area = sqrt(5( 5 + 4.4721)) * 36

Area = sqrt(5*9.4721) * 36

Area = sqrt(47.3606) * 36

Area = 6.882 * 36

Area = 247.7485

The area of the circle = pi r*2 but we don't have r.

If you know any trig, the formula for the radius of the circle is

R = s/(2*sin(180)/n)     n = 5 because you are using a 5 sided figure.

R = 12/(2*sin(180/5)

R = 12/2* sin(36)

R = 6 / sin(36)

R = 10.207

So the area of the circle is pi * R^2

Area = 3.14 * 10.2078^2

Area = 327.1854

The area of the shaded part is the difference between the 2 areas we found

Answer: 327.1854 -  247.7485

Answer: 79.44

Answer: will be A

Step-by-step explanation:

Answer:

C: 119 square inches

Step-by-step explanation:

We are given;

Slant height; L = 5 in

Base area; B = 49 in²

Since it's a square pyramid, the base portion has a square shape.

Thus, area of base = x²

Where x is a side of the square.

Thus;

x² = 49

x = √49

x = 7

Perimeter of base = 7 × 4 = 28 in

Area of pyramid = ½PL + B

Plugging in the relevant values;

Area of pyramid = (½ × 28 × 5) + 49

Area of pyramid = 119 in²

Step-by-step explanation:

Her father is 34 years old

[tex]\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{6+11}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{17}{4}[/tex]

2:-

[tex]\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}[/tex]

[tex]\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}[/tex]

[tex]\\ \sf\longmapsto \dfrac{155+225}{35}[/tex]

[tex]\\ \sf\longmapsto \dfrac{380}{35}[/tex]

[tex]\\ \sf\longmapsto 12[/tex]

3:-

[tex]\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{132+160}{30}[/tex]

[tex]\\ \sf\longmapsto \dfrac{292}{30}[/tex]

4:-

[tex]\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}[/tex]

[tex]\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}[/tex]

[tex]\\ \sf\longmapsto 4+\dfrac{10}{3}[/tex]

[tex]\\ \sf\longmapsto \dfrac{12+10}{3}[/tex]

[tex]\\ \sf\longmapsto \dfrac{22}{3}[/tex]

[tex] \bf \large \longrightarrow \: \: 1 \frac{1}{2} \: + \: 2 \frac{3}{4} \: = \: \\ [/tex]

[tex] \bf \large \longrightarrow \: \: \frac{3}{2} \: + \: \frac{11}{4} \\ [/tex]

[tex] \bf \large \longrightarrow \: \: \frac{6 \: + \:11 }{4} \\ [/tex]

[tex] \bf \large \longrightarrow \: \: \frac{17}{4} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: 4 \frac{3}{7} \: + \: 6 \frac{1}{5} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{31}{7} \: + \: \frac{31}{5} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{155 \: + \: 217}{35} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{372}{35} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: 4 \frac{2}{5} \: + \: 5 \frac{2}{6} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{22}{5} \: + \: \frac{32}{6} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{132 \: + \: 160}{30} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{292}{30} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: 3 \frac{7}{7} \: + \: 3 \frac{1}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{28}{7} \: + \: \frac{10}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \cancel\frac{28 ^{4} }{7 \: ^{1} } \: + \: \frac{10}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{4}{1} \: + \: \frac{10}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{12 \: + \: 10}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{22}{3} \\ [/tex]