the coefficients corresponding to k=0,1,2,5 in the expression (x+y)^5 are

Answer:

C

Step-by-step explanation:

It is 8.6 because we are finding the difference and using subtraction.  

So I did 68.8-59.9 and I got 8.6

Answer:

x=–2

Step-by-step explanation:

x-8=-10

x=-10-8

x=–2

Answer:

-8= -10

, = -10+8

, = -2

Answer:

255

Step-by-step explanation:

Given :

Simplify the expression :

25(0.3x-4)-5(1.5x-6)+100(13/4)

Open each Bracket:

7.5x - 100 - 7.5x + 30 + 325

7.5x - 7.5x - 100 + 30 + 325

= 255

The simplified equation = 255

Answer:

5/33

Step-by-step explanation:

The probability of selecting a white marble is 4/12 = 1/3(because we have 4 white marbles and 12 marbles in total )

The probability of selecting a blue marble is 5/11 (because we have 5 blue marbles and 11 marbles left(1 has been drawn already) )

Probability of selecting a white and then blue marble equals 1/3*5/11 = 5/33

9514 1404 393

Answer:

   0.0056

Step-by-step explanation:

  f(x) = √(49 +x)

  f'(x) = 1/(2√(49 +x))

A linear approximation of f(x) expanded about x=0 is ...

  f(x) ≈ f(0) + f'(0)x = 7 +x/(2·7)

Then for √53, we have x=4

  f(4) ≈ 7 +4/14 = 7 2/7 . . . . . approximate √53 using differentials

__

The calculator value of √53 is about 7.280110, so the difference in results is ...

  approx - actual ≈ 7.285714 -7.280110 = 0.005604 ≈ 0.0056

Answer:

"Members of a population are organized in clusters, each of which is representative of the population, and then whole clusters are randomly selected to make up the sample"

Step-by-step explanation:

In cluster random sampling, "the population is divided, usually geographically, into groups that generally have the same size.  A certain number of groups are randomly chosen, and every individual in the chosen groups are chosen for the sample."

In accord with this logic, the second choice, "Members of a population are organized in clusters, each of which is representative of the population, and then whole clusters are randomly selected to make up the sample" seems to be correct.

NOTE: This may not be the correct answer. I am simply basing my answer on the definition I have learnt.

Answer:

B

Step-by-step explanation:

Answer:

if I had known this

Step-by-step explanation:

then I won't be using this app right now..

Answer:

x=12,y=3

Step-by-step explanation:

x/6-y/3=1

x can equal 12 because 12/6 is equal to 2.

y can equal 3 because 3/3 equals 1

2-1=1

A fraction means division.

To find the decimal equivalent of a fraction, divide the top number by the bottom number.

9514 1404 393

Answer:

Step-by-step explanation:

1a. Vertical angles share a vertex and are composed of opposite rays. Here, angles 2 and 4 are vertical angles.

1b. Consecutively numbered angles are adjacent, as are angles 1 and 5. The pairs of interest can be chosen from ...

  1&2, 2&3, 3&4, 4&5, 5&1

__

2. Angles 1 and 3 have the same measure, because they are vertical angles. Then we have ...

  78° = (5x -2)°

  80 = 5x . . . . . . . divide by °, add 2

  16 = x . . . . . . . divide by 5

Answer:

a). 5√6

[tex] \sqrt{10} \times \sqrt{15} \\ = ( \sqrt{5} \times \sqrt{2} ) \times ( \sqrt{5} \times \sqrt{3} ) \\ = {( \sqrt{5}) }^{2} \times ( \sqrt{2} \times \sqrt{3} ) \\ = 5 \times ( \sqrt{6} ) \\ = 5 \sqrt{6} [/tex]

Answer:

y = 54/25 when x = 4.

Step-by-step explanation:

y is given by the equation:

[tex]\displaystyle y = p\times q^{x-1}[/tex]

Where p and q are numbers.

We are also given that when x = 1, y = 10 and when x = 6, y = 0.7776.

And we want to determine the value of y when x = 4.

Since y = 10 when x = 1:

[tex]\displaystyle (10) = p\times q^{(1)-1}[/tex]

Simplify:

[tex]10 = p \times q^0[/tex]

Any number (except for zero) to the zeroth power is one. Hence:

[tex]p=10[/tex]

Thus, our equation is now:

[tex]y = 10\times q^{x-1}[/tex]

When x = 6, y = 0.7776. Thus:

[tex](0.7776) = 10\times q^{(6)-1}[/tex]

Simplify and divide both sides by ten:

[tex]\displaystyle 0.07776 = q^5[/tex]

Take the fifth root of both sides:

[tex]\displaystyle q = \sqrt[5]{0.07776}[/tex]

Use a calculator. Hence:

[tex]\displaystyle q = \frac{3}{5} = 0.6[/tex]

Our completed equation is:

[tex]\displaystyle y = 10\times \left(\frac{3}{5}\right)^{x-1}[/tex]

Then when x = 4, y equals:

[tex]\displaystyle \begin{aligned} y &= 10\times \left(\frac{3}{5}\right)^{(4)-1} \\ \\ &= 10\times \left(\frac{3}{5}\right)^3 \\ \\ &= 10\times \left(\frac{27}{125}\right) \\ \\ &= \frac{54}{25}\end{aligned}[/tex]

Answer:

The relation is linear

Step-by-step explanation:

Answer:

Yes, the relationship shown is linear. The equation of the line is y=-1.25x-13.25.

Step-by-step explanation:

This data is linear as y decreases at a constant rate. The equation of a line is y=mx+b, where m=slope and b=y intercept

To find m:

m=[tex]\frac{y2-y1}{x2-x1}[/tex]

m=[tex]\frac{(-2)-(-7)}{(-9)-(-5)}[/tex]

m=[tex]\frac{5}{-4}[/tex]

m=[tex]-\frac{5}{4}[/tex]=-1.25

To find b, you can use any of the given points:

(-9,-2)

(-2)=-1.25(-9)+b

-2=11.25+b

-2-11.25=b

b=-13.25

Therefore, using the calculated values for m and b:

y=mx+b

y=-1.25x-13.25

Answer:

the correct answer is |x – 18| ≤ 4

just took the test

Step-by-step explanation:

Answer:

the answer for y=4 and x=4✔3

It's divergent because 1/√(5 - x) is defined only for x < 5, which means the integral from 5 to infinity doesn't exist.

Answer:

Step-by-step explanation:

e = 61°, f = 119°, and d = 90°

We know that vertically opposite angles are equal.

So, e = 61° [Vertically opposite angles]

We know that linear pair of angles are supplementary (180°).

So, f + 61° = 180° [Linear pair of angles]

=> f = 180° - 61°

=> f = 119°

and d + 90° = 180° [Linear pair of angles]

=> d = 180° - 90°

=> d = 90°

Answer:

FALSE.The ratio of the volumes of two similar solid polyhedra is equal to the square of the ratio between their edges. This statement is false. A polyhedron is a shape that has no gaps between their edges or vertices.

Answer:

it's false

~~~~~~~~~~~

Answer:

9

Step-by-step explanation:

90+81+mising angle=180, missing angle is 9

Answer:

114 cm²

Step-by-step explanation:

Surface area of the rectangular prism,

2×(wl+hl+hw)

=2×(3×8+3×8+3×3)

= 2×(24+24+9)

= 2×(57)

=114 cm²

Answer:

Should be (C). Can't verify.

545

ED2021

because it's value will always be same

Answer:

This value doesn't depend on x or y

It'll be the same things always

16 book marks has been sold

Answer:

16 bookmarks

Step-by-step explanation:

9/72 = 2/x

72/9 = 8

2 x 8 = 16

hope this helps

Answer:

Sixteen million, one hundred and seven thousand, three hundred twenty

Step-by-step explanation:

Answer:

[tex]216\ km^2[/tex]

Step-by-step explanation:

1. Approach

The surface area of a three-dimensional figure is the two-dimensional distance around the figure.  The easiest way to find the surface area of a figure is to find the area of each of its facets, then add up the area to get the total surface area. The given pyramid is composed of four congruent triangles and a square. Find the area of one of the triangles, and then the area of the rectangle. Multiply the area of the triangle by four to account for the fact that there are four congruent triangles. Then add the area of the base to the result, the result attained is the surface area of the prism.

2. Find the area of the triangles

The formula to find the area of a triangle is the following:

[tex]A_t=\frac{b*h}{2}[/tex]

Where (b) represents the base and (h) represents the height of the triangle. Substitute the given values into the formula and solve for the answer.

[tex]A_t=\frac{b*h}{2}[/tex]

[tex]A_t=\frac{9*7.5}{2}[/tex]

[tex]A_t=\frac{67.5}{2}[/tex]

[tex]A_t=33.75[/tex]

3. Find the area of the rectangle

The formula to find the area of a rectangle is the following,

[tex]A_r=b*h[/tex]

Substitute the given values in and solve,

[tex]A_r=b*h[/tex]

[tex]A_r=9*9[/tex]

[tex]A_r=81[/tex]

4. Find the total surface area

Multiply the area of the triangle by four to account for the fact that there are four triangles. Then add its area to the area of the rectangle.

[tex]A_t+A_t+A_t+A_t+A_r=A[/tex]

[tex]4(A_t)+(A_r)=A[/tex]

[tex]4*33.75+81=A[/tex]

[tex]135+81=A[/tex]

[tex]216=A[/tex]

The partial fraction expansion takes the form

-6x/((x + 2) (x + 8)) = a/(x + 2) + b/(x + 8)

Both factors in the denominator are linear, so the numerators in the corresponding partial fractions have degree 1 - 1 = 0 and are thus constants.

Combine the fractions on the right side into one with a common denominator, then set the numerators on both sides of the equation equal to each other:

-6x = a (x + 8) + b (x + 2)

Expand the right side and collect terms by powers of x :

-6x = (a + b) x + (8a + 2b)

It follows that

a + b = -6   and   8a + 2b = 0

==>   a = -2   and   b = 8

So we end up with

-6x/((x + 2) (x + 8)) = -2/(x + 2) + 8/(x + 8)

Answer:

17.5ml- of 10 percent solution, 17.5ml- of 20 percent solution

Step-by-step explanation:

35:100*15=5.25- ml of alkali in the base solution

Suppose we need x ml of 10 percents solution and 35-x - of 20 percents.

Then The quantity of alkali in the first one (10 percents) is x/100*10=0.1x

when in the second one we have (35-x)/100*20= 7-0.2x of alkali

0.1x+7-0.2x=5.25

7-0.1x= 5.25

0.1x=1.75

x=17.5- 0f 10 percents

35-17.5=17.5 - of 20 percents

Answer:

Step by step proof shown below.

Step-by-step explanation:

To prove the equation, you need to apply the Logarithm quotient rule and the Logarithm power rule. Here's how the quotient rule looks like.

[tex]log_b(x/y) = log_b(x) - log_b(y)[/tex]

And here's how the power rule looks like

[tex]log_a(x)^n = nlog_a(x)[/tex]

First let's apply the quotient rule.

[tex]\frac{f(x+h)-f(x)}{h} = \frac{log_a(x+h)-log_a(x) }{h} = \frac{log_a(\frac{x+h}{x} )}{h}[/tex]

Now we can do some quick simplification, and apply the power rule.

[tex]\frac{1}{h} log_a(1 + \frac{h}{x} ) = log_a(1+\frac{h}{x} )^\frac{1}{h}[/tex]

Let f = ln(x + √(x ² + y ²)) ln(sin(y/x)).

Then the total differential is

[tex]\mathrm df = \dfrac{\mathrm d\left(x+\sqrt{x^2+y^2}\right)}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\mathrm d\left(\sin\left(\frac yx\right)\right)}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\mathrm dx + \frac{\mathrm d(x^2+y^2)}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\cos\left(\frac yx\right)\,\mathrm d\left(\frac yx\right)}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\mathrm dx + \frac{2x\,\mathrm dx+2y\,\mathrm dy}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}}\right)\dfrac{\cos\left(\frac yx\right)\frac{x\,\mathrm dy-y\,\mathrm dx}{x^2}}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\left(2x+\sqrt{x^2+y^2}\right)\,\mathrm dx +2y\,\mathrm dy}{x\sqrt{x^2+y^2}+x^2+y^2\right)\ln\left(\sin\left(\dfrac yx\right)\right) \\\\ \indent + \dfrac1{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}}\right)(x\,\mathrm dy-y\,\mathrm dx)[/tex]

[tex]\mathrm df = \left(\left(\dfrac{2x+\sqrt{x^2+y^2}}{x\sqrt{x^2+y^2}+x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) - \dfrac y{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dx \\\\ \indent + \left(\dfrac{2y}{x\sqrt{x^2+y^2}+x^2+y^2}\ln\left(\sin\left(\dfrac yx\right)\right)+\dfrac1x\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dy[/tex]