Suppose x varies directly with the square root of y and inversely with the cube root of z. What equation models this combined variation?

Answers

Answer 1

Answer:

[tex]\huge\boxed{x = k \frac{\sqrt{y} }{\sqrt[3]{z} }}[/tex]

Step-by-step explanation:

Given that:

1) x ∝ √y

2) x ∝ [tex]\frac{1}{\sqrt[3]{z} }[/tex]

Combining the proportionality

=> x ∝ [tex]\frac{\sqrt{y} }{\sqrt[3]{z} }[/tex]

=> [tex]x = k \frac{\sqrt{y} }{\sqrt[3]{z} }[/tex]

Where k is the constant of proportionality.


Related Questions

Gail bought 5 pounds of oranges and 2 pounds of bananas for $14. Her husband later bought 3 pounds of oranges and 6 pounds of bananas for $18. What was the cost per pound of the oranges and the bananas?

Answers

Answer:

1 pound of Oranges = $2

1 pound of Bananas = $2

Step-by-step explanation:

O = Oranges

B = Bananas

=> 5o + 2b = 14

=> 2b = 14 - 5o

=> b = 14/2 - 5/2o

=> b = 7 - 2.5o

3o + 6b = 18

=> 3o + 6( 7 - 2.5o ) = 18

=> 3o + 42 - 15o = 18

=> -12o + 42 = 18

=> -12o = -24

=> -o = -2

=> o = 2

One pound of oranges costs $2.

So,

5 (2) + 2b = 14

=> 10 + 2b = 14

=> 2b =4

=> b = 2

One pound of bananas also costs $2.

Answer: cost of orange per pound = 2$
Cost of banana per pound = 2$

Explanation:



You are rolling a 6-sided number cube with the numbers 1 through 6. Which of the following represents the probability of rolling an even number?
0
1/6
1/2
1

Answers

Answer:

1/2

Step-by-step explanation:

The probailty of an event A is:

● P(A) = ( outcomes that give A) / (total number of possible outcomes)

Let A be the event in wich we get an even number.

● The sample space is {2,4,6}

So there are 3 possible outcomes that give A .

The six-sided dice has 6 outcomes

● { 1,2,3,4,5,6}

■■■■■■■■■■■■■■■■■■■■■■■■■■

● P(A) = 3/6 = 1/2

Answer:

1/2

Step-by-step explanation:

i took the test

use the diagram to answer the question. AB corresponds to which line segment?

Answers

Answer:

DE

Step-by-step explanation:

I hope this helps!

Find the​ mean, variance, and standard deviation of the binomial distribution with the given values of n and p. ​, The​ mean, ​, is nothing. ​(Round to the nearest tenth as​ needed.)

Answers

Complete Question

Find the​ mean, variance, and standard deviation of the binomial distribution with the given values of n and p. ​, The​ mean, ​, is nothing. ​(Round to the nearest tenth as​ needed.)

    p =  0.6   n =  18

Answer:

The mean   [tex]\mu = 10.5[/tex]

The standard deviation [tex]\sigma = 2.08[/tex]

The  variance   [tex]var = 4.32[/tex]

Step-by-step explanation:

From the question we are told that

      The probability of success   is  [tex]p = 0.6[/tex]

      The  sample size is [tex]n = 18[/tex]

  Generally given that the distribution is binomial, then the probability of failure is mathematically represented as

              [tex]q = 1- p[/tex]

substituting values

              [tex]q = 1- 0.6[/tex]

              [tex]q =0.4[/tex]

Generally the mean is mathematically evaluated as

             [tex]\mu = np[/tex]

substituting values

             [tex]\mu = 18 * 0.6[/tex]    

             [tex]\mu = 10.5[/tex]

The  standard deviation is evaluated as

              [tex]\sigma = \sqrt{npq}[/tex]

substituting values

               [tex]\sigma = \sqrt{18 * 0.6 * 0.4}[/tex]

              [tex]\sigma = 2.08[/tex]

The variance is evaluated as

               [tex]var = \sigma^2[/tex]

substituting value

              [tex]var = 2.08^2[/tex]

              [tex]var = 4.32[/tex]

SAVINGS ACCOUNT Ms. Cole pays $2 a month
for online banking at her credit union. What is
the change in the balance of her account if she
pays this fee for 6 months?

Answers

Answer: $12 less.

Step-by-step explanation:

Given: Ms. Cole pays $2 a month  for online banking at her credit union.

In 6 months she will pay = 6 x ($2)

= $12

It means that he balance will be decreased by $12 [as the amount was debited from the balance].

So, the change in the balance of her account if she pays this fee for 6 months = $12 less.

which function's graph has asymphotes located at the values x=+=n pi ? 1. y=csc x 2. y= cos x 3. y=tan x 4. y=cot x answer choices: A. 2 only B. 1 and 4 only C. 1 only D. 1 and 3 only please help!! ):

Answers

Here is the answer c I’d choose the cheeseburger

Which property of equality was used to solve this equation?
X-5 = -14
X-5 + 5 = -14 + 5
x= -9

OA. addition property of equality

OB. subtraction property of equality

OC. multiplication property of equality

OD.division property of equality

Answers

Answer:

OA. addition property of equality

Step-by-step explanation:

In the second step of the problem, you can see they add 5 to both sides of the equation. So, it is the addition property of equality.

Answer:

addition property of equality

Step-by-step explanation:

X-5 = -14

Add 5 to each side using the addition property of equality

X-5 + 5 = -14 + 5

x= -9

Find the distance between (8,4) and (8,8).

Answers

Answer:

From the given points above, the distance between them is 4 units.

Step-by-step explanation:

In order to find the distance between the two points, we must know the distance formula.

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Now, we plug in our numbers from the coordinate points that we are given to their respectful places.

[tex]d=\sqrt{(8-8)^2+(8-4)^2}[/tex]

Now, we solve. First, simplify the terms in parentheses. So, subtract 8 from 8 and subtract 4 from 8.

[tex]d=\sqrt{(0)^2+(4)^2}[/tex]

Next, solve for the exponents.

[tex]d=\sqrt{0+16}[/tex]

Add the numbers in the radical.  

[tex]d=\sqrt{16}[/tex]

Solve the radical.

[tex]d=4[/tex]

So, the distance  between the two given points is 4 units.

A grass seed company conducts a study to determine the relationship between the density of seeds planted (in pounds per 500 sq ft) and the quality of the resulting lawn. Eight similar plots of land are selected and each is planted with a particular density of seed. One month later the quality of each lawn is rated on a scale of 0 to 100. The sample data are given below where x denotes seed density, and y denotes lawn quality.x 1 1 2 3 3 3 4 5y 30 40 40 40 50 65 50 50The sample linear correlation coefficient is r=0.600. At the 1% significance level, do the data provide sufficient evidence to conclude that seed density and lawn quality are positively linearly correlated?

Answers

Answer:

I think it  -1.50 to 10.58

Step-by-step explanation:

PLEASE ANSWER ASAP!!!


Fill in the box for the missing numerator in the set of equivalent expressions in the picture

Answer options are also shown in picture




any unrelated answer will be reported​

Answers

Answer:

A. 14z - 28

Step-by-step explanation:

simplify z² - 3z

a. z(z - 3)

the denominator on the right has z(z - 3). but it is also multiplied by (z - 2)

this means the numerator must also be multiplied by (z - 2)

14 x (z - 2) = 14z - 28

hope this helps :)

An artifact was found and tested for its carbon-14 content. If 72% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)? (Carbon-14 has a half-life of 5,730 years).

Answers

Answer:

  2700 years

Step-by-step explanation:

The exponential function for the fraction remaining is ...

  r(t) = (1/2)^(t/5730)

where r is the remaining fraction and t is the time in years. We can solve for t to get ...

  log(r) = (t/5730)log(1/2)

  t = 5730·log(r)/log(1/2)

For the given r=0.72, the age of the artifact is estimated to be ...

  t = 5730·log(0.72)/log(0.5) ≈ 2700 . . . years

How many petals are on the graph? Find the trigonometric form of a given function.

Answers

Answer:

Attachment 1 : Option A,

Attachment 2 : Option C

Step-by-step explanation:

( 1 ) Here we know that " n " is 6. Now remember if n is odd, the number of petals on the graph will be n. However if n is even, the number of petals on the graph will be 2n.

6 is even, and hence the number of petals will be 2(6) = 12 petals. Solution : 12 petals

( 2 ) To solve such problems we tend to use the equation [tex]z = x + y * i = r(cos\theta +isin\theta)[/tex] where [tex]r = \sqrt{x^2+y^2}[/tex] etc. Here I find it simpler to see each option, and convert each into it's standard complex form. It might seem hard, but it is easy if you know the value of (cos(5π / 3)) etc...

The answer here will be option c, but let's prove it,

cos(5π / 3) = 1 / 2,

sin(5π / 3) = [tex]-\frac{\sqrt{3}}{2}[/tex]

Plugging those values in for " [tex]8\left(\cos \left(\frac{5\pi }{3}\right)+i\sin \left(\frac{5\pi }{3}\right)\right)[/tex] "

[tex]8\left(-\frac{\sqrt{3}i}{2}+\frac{1}{2}\right)[/tex]

= [tex]8\cdot \frac{1}{2}-8\cdot \frac{\sqrt{3}i}{2}[/tex] = [tex]4-4\sqrt{3}i[/tex]

Hence proved that your solution is option c.

The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales representatives make an average of 43 sales calls per week on professors. Several reps say that this estimate is too low. To investigate, a random sample of 29 sales representatives reveals that the mean number of calls made last week was 44. The standard deviation of the sample is 4.1 calls. Using the 0.050 significance level, can we conclude that the mean number of calls per salesperson per week is more than 43? H0: μ ≤ 43 H1: μ > 43 Compute the value of the test statistic. (Round your answer to 3 decimal places.)

Answers

Answer:

The critical region for α= 0.05 is Z > ± 1.645

The calculated value of Z= 1.100

Step-by-step explanation:

The null and alternate hypotheses are given

H0: μ ≤ 43

H1: μ > 43  one tail test

∝= 0.05

n= 29

Standard Deviation= s= 4.1

Mean = μ0 = 44

For one tail test the z value of α= ± 1.645

The critical region for α= 0.05 is Z > ± 1.645

The test statistic is given by

z=μ0-μ/ s/√n

Z= 44-43/4.1/√29

Z= 1/4.1/√29

Z= 1.100

Since the calculated value Z= 1.100 does not  fall in the critical region , We reject H0 and may conclude that the mean number of calls per salesperson per week is not more than 43

In the figure below. MN is the arc of a circle with center L. If the length of arc MN is 6π, what is the area of sector LMN?

Answers

On a number​ line, the coordinates of​ X, Y,​ Z, and W are −7​, −2​, 2​, and 7​, respectively. Find the lengths of the two segments below. Then tell whether they are congruent. XY and

Which choice shows the product of 22 and 49 ?

Answers

Answer:

1078

Step-by-step explanation:

The product of 22 and 49 is 1078.

Answer:

1078 is the product

Step-by-step explanation:

Consider the function f(x) = (x − 3)2(x + 2)2(x − 1). The zero has a multiplicity of 1. The zero −2 has a multiplicity of .

Answers

Answer:

The zero 1 has a multiplicity of 1.

The zero -2 has a multiplicity of 2.

Hope this clears up any confusion :)

Step-by-step explanation:

Answer:

The zero  1  has a multiplicity of 1.

The zero −2 has a multiplicity of  2 .

Step-by-step explanation:

0 = -12 + 4y - 3x whats the slope

Answers

Answer:

3/4 is the slope

Step-by-step explanation:

We want to put this in slope intercept form

y = mx+b  where m is the slope and b is the y intercept

0 = -12 + 4y - 3x

Subtract 4y from each side

-4y = -3x-12

Divide each side by -4

-4y/-4 = -3x/-4 -12/-4

y = 3/4 x +3

Answer:

Slope=3/4

Step-by-step explanation:

0=-12+4y-3x (Add 12 on the other side)

12=4y-3x (Add 3x on the other side)

3x+12=4y (Divide by 4)

y=3/4+3

Factor the polynomial: 11x− xy +11y−x2

Answers

[tex]11x- xy +11y-x^2=\\-x^2-xy+11x+11y=\\-x(x+y)+11(x+y)=\\-(x-11)(x+y)[/tex]

Answer:

(x - 11)(-x - y)

Step-by-step explanation:

To factor the polynomial 11x - xy + 11y - x² completely, let's group the terms and factor them separately.

Rearranging the terms, we have:

11x - xy + 11y - x²

Let's rearrange the terms again to group similar terms together:

x² + 11x - xy + 11y

Now, we can factor out the common factor from each pair of terms:

x(-x + 11) - y(x - 11)

Simplifying further, we can factor out -1 from the first pair of terms:

-x(x - 11) - y(x - 11)

Now, notice that we have a common factor of (x - 11) in both terms. Factoring out this common factor, we obtain:

(x - 11)(-x - y)

Therefore, the polynomial 11x - xy + 11y - x² can be factored completely as (x - 11)(-x - y).

[09.01]

Identify the domain of the equation y=x2 - 6x + 1. (1 point)

Answers

Answer:

All real numbers.

Step-by-step explanation:

As there are no restrictions on the values of x, the domain is all real numbers.

Answer:

All real numbers.

Step-by-step explanation:

A train is running at the speed of 90 mph. The length of the train is 300 ft. How long would it take to cross a railway platform 492 ft long?

Answers

Answer:

Time = 1.45152 seconds

Step-by-step explanation:

1 foot = 0.000189 mile

300 ft = 300*0.000189

300 ft = 0.0567 miles

492 ft = 492*0.000189

492 ft = 0.092988 miles

Distance left to be covered by the train

= 0.092988-0.0567

= 0.036288 miles

Speed= 90mph

Time taken = distance/speed

Time taken= 0.036288/90

Time = 4.032*10^-4 hour

Time = 4.032*10^-4*60*60

Time = 1.45152 seconds

In a genetics experiment on peas, one sample of offspring contained green peas and yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of that was expected? 350 127 3 4 The probability of getting a green pea is approximately . (Type an integer or decimal rounded to three decimal places as needed.) Is this probability reasonably close to ? Choose the correct answer below. 3 4 A. No, it is not reasonably close. B. Yes, it is reasonably close.

Answers

Complete Question

In a genetic experiment on peas, one sample of offspring contained 436 green peas and 171 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? The probability of getting a green pea is approximately: Is the probability reasonably close to 3/4?

Answer:

The  probability is  [tex]P(g) =0.72[/tex]

Yes the result is reasonably close

Step-by-step explanation:

From the question we are told that

   The  number of  of  green peas is  [tex]g = 436[/tex]

     The number of yellow peas is  [tex]y = 171[/tex]

   The sample size is  [tex]n = 171 + 436 = 607[/tex]

The probability of getting an offspring pea that is green is mathematically represented as

       [tex]P(g) = \frac{g}{n}[/tex]

        [tex]P(g) = \frac{436}{607}[/tex]

        [tex]P(g) =0.72[/tex]

Comparing  [tex]P(g) =0.72[/tex]  to   [tex]\frac{3}{4} = 0.75[/tex] we see that the result is reasonably close

Put the following numbers in order from least to greatest: π/2,-4,0.09,17,√3,-1/7,√225

Answers

Answer:

-4, -1/7,0.09,π/2,√3 ,√225,17

Step-by-step explanation:

π/2, is approx 1.5

-4,

0.09,

17,

√3 is approx 1.7

,-1/7, is approx -.143

√225 = 15

From most negative to greatest

-4, -1/7,0.09,π/2,√3 ,√225,17

Answer:

[tex]-4, -1/7, 0.09, \pi/2, \sqrt3, \sqrt{225}, 17[/tex]

Step-by-step explanation:

So we have the numbers:

[tex]\pi/2, -4, 0.09, 17, \sqrt3, -1/7, \sqrt{225}[/tex]

(And without using a calculator) approximate each of the values.

π is around 3.14, so π/2 is around 1.57.

17 squared is 289, so 1.7 squared is 2.89. Thus, the square root of 13 is somewhere between 1.7 and 1.8.

-1/7 can be divided to be about -0.1429...

And the square root of 225 is 15.

Now, use the approximations to place the numbers:

[tex]\pi/2\approx1.57; -4; 0.09;17;\sqrt3 \approx1.7; -1/7\approx-0.14;\sqrt{225}=15[/tex]

The smallest is -4.

Next is -1/7 or about -0.14

Followed by the first positive, 0.09.

And then with π/2 or 1.57

And then a bit bigger with the square root of 3 or 1.7.

And then with the square root of 225 or 15.

And finally the largest number 17.

Thus, the correct order is:

[tex]-4, -1/7, 0.09, \pi/2, \sqrt3, \sqrt{225}, 17[/tex]

which best defines a service

Answers

Answer:

A service could be multiple things.

Step-by-step explanation:

Like, working as a scribe in a nursing home helping old people. Or, being part of a leadership club at school that funds food banks and things like that

Answer:

a

Step-by-step explanation:

Abel and Cedric will share a total of $180. Abel will receive half as much as Cedric. What amount. in dollars, will Cedric receive (Disregard the $ sign when gridding your answer.)

Answers

Answer:

Abel receives $60, and Cedric receives $120

Step-by-step explanation:

Let Abel's share = A

Let Cedric's share = C

we are given the following

A + C = 180  - - - - - (1)   (Abel and Cedric will share a total of $180)

[tex]A = \frac{C}{2}\ - - - - - - - (2)[/tex] (Abel will receive half as much as Cedric. )

from equation 2:

[tex]A = \frac{C}{2}\\ C = 2A\ - - - - - - (3)[/tex]

putting this value of C in eqn (3) into eqn (1)

A + (2A) = 180

3A = 180

∴ A = 180 ÷ 3 = 60

to find C, let us replace the value of A in eqn (3) with 60

C = 2A - - - - (3)

C = 2 × 60

C = 120

Therefore, Abel receives $60, and Cedric receives $120

1. The mean performance score on a physical fitness test for Division I student athletes is 947 with a population standard deviation of 205. Select a random sample of 64 of these students. Hint: we have a sample so use the standard error. What is the probability the mean of the sample is below 900

Answers

Answer:

0.033316

Step-by-step explanation:

We use the z score formula to solve for this question.

Since we are given the number of samples in the question, our z score formula is given as:

z = (x-μ)/ S.E

where x is the raw score

μ is the sample mean

S.E is the Standard error.

x is the raw score = 900

μ is the sample mean = Population mean = 947

Standard error =

This is calculated as Population standard deviation/ √No of samples

= 205/√64.

= 205/8

= 25.625

We proceed to calculate the z score

z = (x-μ)/ S.E

z = 900 - 947/25.625

= -1.83415

Using the z score table for normal distribution,

P(x≤ z) = P(z ≤ -1.83) = P(x ≤ 900)

P(x<900) = 0.033316

Therefore, the probability the mean of the sample is below 900 is 0.033316

A die is rolled 200 times with the following results. Outcome 1 2 3 4 5 6 Frequency 32 36 44 20 30 38 What is the experimental probability of rolling the given result? 3 a. 0.22 c. 0.44 b. 0.78 d. 0.23

Answers

Answer:

.22

Step-by-step explanation:

The number of times a 3 was rolled is 44 out of 200

The experimental probability is  44/200 = .22

The frequency of rolling a 3 was 44.

So... 44/200

After dividing we get 0.22

Therefore, the answer is A

Best of Luck!

In a recent survey of 100 students, 34 said that they took a Math class as a freshman, 59 said that they took an English class as a freshman and 12 said they took both classes.

Required:
How many students took neither class as a freshman?

Answers

Answer:

19 students

Step-by-step explanation:

We will use the set notation to solve this question.

let n(U) be the total number of students surveyed = 100

n(M) be the number of student that took math = 34

n(E) be the number of student that took English = 59

n(M∩E) be the number of student that took both classes= 12

n(M∪E)' be the number of student that took neither class = ?

Using the formula n(U) = n(M∪E) + n(M∪E)'

n(M∪E)' = n(U)-n(M∪E)

Before we can get the number of student that took neither class i.e n(M∪E)'  we need to  get n(M∪E).

n(M∪E) = n(M)+n(E)- n(M∩E)

n(M∪E) = 34+59-12

n(M∪E)  = 81

Since n(M∪E)' = n(U)-n(M∪E);

n(M∪E)' = 100-81

n(M∪E)' = 19

Hence 19 students took neither class as a freshmen.

X = y + 12
How to solve for variable

Answers

Answer:

x-y=12

Step-by-step explanation:

Which of the following represents the largest number?
A. 1.75 * 10^6
B .1.25 * 10^6
C. 2.75 * 10^5
D. 3.82 * 10^5

Answers

Answer:

A

Step-by-step explanation:

A 1.75 * 10^6 = 1750000

B  1.25 * 10^6 = 1250000

C 2.75*10^5  = 275000

D 3.82*10^5 = 82000

option A (1.75 * 10⁶) represents the largest number among the given options.

To determine which of the given numbers represents the largest number, we can compare the exponents of 10 in each option.

A. 1.75 * 10⁶

B. 1.25 * 10⁶

C. 2.75 * 10⁵

D. 3.82 * 10⁵

Comparing the exponents:

A: 10⁶

B: 10⁶

C: 10⁵

D: 10⁵

Since both options A and B have an exponent of 10⁶, we need to compare the coefficients.

1.75 is greater than 1.25, so option A (1.75 * 10⁶) represents the largest number among the given options.

Therefore, the answer is A. 1.75 * 10⁶.

Learn more about exponents here

https://brainly.com/question/5497425

#SPJ2

The probability that a company will launch the product A and B are 0.45 and 0.60 respectively, in main while, probability that both products launched, is 0.35. what is the probability that Neither will of these products launch ? At least one product will be launched ?

Answers

Answer:

a) what is the probability that Neither will of these products launch ?

= 0.30

b) At least one product will be launched ?

= 0.70

Step-by-step explanation:

From the above question, we have the following information:

P(A) = 0.45

P(B) = 0.60

P(A ∩ B) = P(A and B) launching = 0.35

Step 1

We find the Probability that A or B will launch

P (A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 0.60 + 0.45 - 0.35

= 1.05 - 0.35

= 0.70

a) what is the probability that Neither will of these products launch ?

1 - Probability ( A or B will launch)

= 1 - 0.70

= 0.30

b)At least one product will be launched?

This is equivalent to the probability that A or B will be launched

P (A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 0.60 + 0.45 - 0.35

= 1.05 - 0.35

= 0.70

Other Questions
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