The equation below is written in words. x plus ten equals two. What's the value of x?

Answer:

40.60-35=5.6

Step-by-step explanation:

Profit is cost minus the amount you sold it for

An old campfire is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount of [tex]^{14}\text{C}[/tex] ​. Estimate the minimum age of the charcoal, noting that  [tex]2^{10} = 1024[/tex]

Answer:

57300 years

Step-by-step explanation:

Using the relation of an half-life time in relation to fraction which can be  expressed as:

[tex]\dfrac{N}{N_o} = (\dfrac{1}{2})^{\frac{t}{t_{1/2}}[/tex]

here;

N represents the present atom

[tex]N_o[/tex] represents the  initial atom

t represents the time

[tex]t_{1/2}[/tex] represents the half - life

Given that:

Its charcoal is found to contain less than 1/1000 the normal amount of [tex]^{14}\text{C}[/tex] ​.

Then ;

[tex]\dfrac{N}{N_o} = \dfrac{1}{1000}[/tex]

However; we are to  estimate the minimum age of the charcoal, noting that  [tex]2^{10} = 1024[/tex]

so noting that [tex]2^{10} = 1024[/tex], then:

[tex]\dfrac{1}{1000}> \dfrac{1}{1024}[/tex]

[tex]\dfrac{1}{1000}> \dfrac{1}{2^{10}}[/tex]

[tex]\dfrac{1}{1000}> (\dfrac{1}{2})^{10}[/tex]

If

[tex]\dfrac{N}{N_o} = \dfrac{1}{1000}[/tex]

Then

[tex]\dfrac{N}{N_o} > (\dfrac{1}{2})^{10}[/tex]

Therefore, the estimate of the minimum time needed is 10 half-life time.

For [tex]^{14}\text{C}[/tex] , the normal half-life time = 5730 years

As such , the estimate of the minimum age of the charcoal =  5730 years × 10

= 57300 years

Answer:

40% solution = 20 gallons

80% solution = 60 gallons

Step-by-step explanation:

x = gallons of 40% solution

y = gallons of 80% solution

Total volume is:

x + y = 80

Total amount of fertilizer is:

0.40 x + 0.80 y = 0.70 (80)

Solve by substitution.

0.40 x + 0.80 (80 − x) = 0.70 (80)

0.40 x + 64 − 0.80 x = 56

0.40 x = 8

x = 20

y = 60

Answer:

Step-by-step explanation:

[tex]xy^{2}[/tex],   [tex]5y^{2}x[/tex],   [tex]\frac{-3}{5}[/tex][tex]xy^{2}[/tex]

[tex]-3x^{2}y[/tex],   [tex]\frac{2}{3}[/tex][tex]yx^{2}[/tex]

Hope this helps

plz mark it as brainliest!!!!!

Answer:

16

Step-by-step explanation:

Follow the rules of PEMDAS

8÷2(2+2)

Parentheses

8÷2(4)

Exponents

we have none

Multiply and Divide from left to right

4(4)

16

Then Add and Subtract from left to right

Answer:

16

Step-by-step explanation:

In order to understand the answer to the problem, we need to know the correct order of operations, through the acronym PEMDAS

PEMDAS

P: Parentheses

E: Exponent

M: Multiply

D: Divide

A: Add

S: Subtract

First add everything in the parentheses to get 4

Then divide 8 by 2 to get 4

4 times 4 = 16

8/2= 4

2+2=4

4 x 4 = 16

Answer: 2*√18 + 3*√2 + √162 = 18*√2

Step-by-step explanation:

I guess that the equation is:

2*√18 + 3*√2 + √162

And we want to simplify it.

first 18 = 9*2

then we can write:

2*√18 = 2*√(9*2) = 2*3*√2 = 6*√2

and 162/9 = 18

then we can write:

√162 = √(9*18) = √9*√18 = 3√18

now we can use the previous step: √18 = 3*√2

and:

√162 = 3*(3*√2) = 9*√2

now we can write our equation as:

6√2 + 3√2 + 9√2 = (6 + 3 + 9)√2 = 18*√2

And now we can not simplify it further more, so here we end.

Answer:

B. 18 sqrt 2

Step-by-step explanation:

This is the correct letter and answer on edge, if thats what youre using:)

Answer:

Null Hypothesis: H0:μ ≤ 16.8

Alternative Hypothesis: Ha: μ > 16.8

Step-by-step explanation:

We are told that affer testing the hypothesis (at the 5% level of significance), that the average price-earnings ratio increased from the past value of 16.8.

It means that the past value was not more than 16.8.

This follows that the null hypothesis is given as;

H0:μ ≤ 16.8

And since it has been discovered that the ratio increased from the past value of 16.8, the alternative hypothesis is;

Ha: μ > 16.8

Answer:

x=2

Step-by-step explanation:

2(1+3x)=14​

Divide each side by 2

2/2(1+3x)=14/2

1+3x = 7

Subtract 1 from each side

3x =7-1

3x = 6

Divide by 3

3x/3 = 6/3

x =2​

Answer:

D

Step-by-step explanation:

Step 1: Find the factors of 4 and -6

-4x² +11x-6

-4x           3  

1x           -2

(This works because -4 x -2 multiple to 8 and 3 x 1 gives you 3 and when you add it up it gives you the 'b' term)

Step 2: Read the numbers from left to right starting from the top to bottom

(-4x+3)(1x-2)

Therefore the answer to the question is D.

Answer:

A

explain

= -4x^2-11x-6

= -4x^2-8x-3x-6

= -4x(x+2)-3(x+2)

= (x+2) (-4x-3)

= -(4x+3) (x+2)

Answer:

Step-by-step explanation:

Since the the track is circular

Circumference of a circle = πd

where

d is the diameter

π = 3.14

From the question

diameter = 150 feet

Circumference = 150π

= 150(3.14)

We have the final answer as

Hope this helps you

Answer:

471.23 ft

Step-by-step explanation:

The circumference of this space is C = πd = (150 ft)π, or approximately

471.23 ft

Answer:

B. y=12x

Step-by-step explanation:

x = # of books bought

so then y=12x

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

[tex]\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}[/tex]

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

[tex]\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907[/tex]

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

[tex]\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}[/tex]

[tex]\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45[/tex]

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

Answer:

42 Dimes, 10 Nickels.

Step-by-step explanation:

Dimes are worth $0.10, nickels are worth $0.05.

If D = number of dimes, and N = number of nickels, then the following equations are true:

0.10D + 0.05N = 4.70

D + N = 52

Next, let's multiply the first equation by 10 so that we can subtract the second one from it.

D + 0.50N = 47

(-) D + N = 52

Subtracting the second equation from the first one gives:

-0.5N = -5

-0.5N/-0.5 = -5/-0.5

N = 10

Finally, substitute N in the original second equation to find D.

D + 10 = 52

D + 10 - 10 = 52 - 10

D = 42

Answer:

(a). x = 80°

(b). x = 7.2 units

Step-by-step explanation:

Angle formed between the tangents from a point outside the circle measure the half of the difference of intercepted arcs.

(a). Here the intercepted arcs are,

    Measure of major arc = 360° - 100°

                                        = 260°

    Measure of minor arc = 100°

   x° = [tex]\frac{1}{2}[m(\text{Major arc})-m(\text{Minor arc})][/tex]

       = [tex]\frac{1}{2}(260-100)[/tex]

    x = 80°

(b). If a secant and tangent are drawn form a point outside the circle, then square of the measure of tangent is equal to the product of the measures of the secant segment and and its external segment.

x² = 4(4 + 9)

x² = 4 × 13

x² = 52

x = √52

x = 7.211 ≈ 7.2 units

===================================================

Work Shown:

a = -27 = first term

r = 1/3 = common ratio, note how this is between -1 and 1

We start with -27 and multiply by 1/3 each time to get the next term

S = infinite sum

S = a/(1-r), which only works because -1 < r < 1 is true

S = -27/(1-1/3)

S = -27/(2/3)

S = (-27/1) divided by (2/3)

S = (-27/1) times (3/2)

S = (-27*3)/(1*2)

S = -81/2

As you generate and add up the terms of the sequence, the infinite sum slowly starts to approach -81/2 = -40.5; we'll never actually achieve this sum exactly. Think of it as approaching an asymptote.

[tex]13ab^3+39a^2b^5\\\\\boxed{\boxed{\boxed{13ab^3(1+3ab^2)}}}\\\\[/tex]

Brazil number one.

Answer:

there's no answer for that equation

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, let me solve a question that is exactly like this one.

A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation 5 mpg. A pizza delivery company buys 43 of these cars. What is the probability that the average mileage of the fleet is greater than 33.5 mpg?

Answer:

Given that the mean (μ) is 34 miles per gallon (mpg) with a standard deviation (σ) 5 mpg. The sample (n) is 43.

The z score is used in statistics to determine by how much the raw score is above or below the mean. It is given by:

[tex]z=\frac{x-\mu}{\sigma} \\for\ a \ sample\ size:\\z=\frac{x-\mu}{\sigma/\sqrt{n} }[/tex]

For the average mileage of the fleet is greater than 33.5 mpg (x > 33.5):

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }\\z=\frac{33.5-34}{5/\sqrt{43} } =-0.66[/tex]

From the normal distribution table, The probability that the average mileage of the fleet is greater than 33.5 mpg = P(x > 33.5) = P(z > -0.66) = 1 - P(z < -0.66) = 1 - 0.2546 = 0.7454 = 74.54%

Answer:

1. step 4

2.idk

3. step 2

4.-5n = 1 --------->  n= -1/5

n + 15 = -10 -------> -25

n/5 = -1/5 ------> n = -1

n - 13 = -12 ------> n = 1

5. cant see the drop down menu or possible answers

but if an answer is the addition one thing

then the second one is the subtraction thing

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given the sequence of interest earned by Marius on his savings account as

200, 208, 216.30, 225, …, the sequence of interest forms a geometric sequence since they have a common ratio.

[tex]r =\frac{T_2}{T_1}= \frac{T_3}{T_2}= \frac{T_4}{T_3}\\ r =\frac{208}{200}= \frac{216.30}{208}= \frac{225}{216.30} \approx 1.04[/tex]

To get how much total interest will Marius have earned by the 30th year the account is active, we will find the sum of the first 30 terms of the geometric sequence as shown.

[tex]S_n =\frac{ a(r^n-1)}{r-1} \ for \ r> 1\\ \\\\ n = 30, a = 200, r = 1.04\\S_{30} = \dfrac{ 200(1.04^{30}-1)}{1.04-1}\\\\S_{30} = \dfrac{ 200(3.243-1)}{0.04}\\\\S_{30} = \dfrac{ 200(2.243)}{0.04}\\\\S_{30} = \dfrac{ 448.6}{0.04}]\\\\S_{30} = 11,215[/tex]

Hence total interest that Marius will earn by the 30th year the account is active is 11,215.

the correct answer is

S30= 200(1-1.04^n)/1-1.04

i took the test

Answer:

The answer is C. SSA ≅ SSA.

Step-by-step explanation:

To check for similar triangles, SSA congruence would not work because the other side can be any length. Also, there is not an SSA postulate because this theorem by itself cannot prove congruence.

The other three properties do work because they show congruence unlike the other congruent factors.

hypotenuse goes to the line across from the right angle. adjacent is the bottom one. lastly opposite is the left one.

Step-by-step explanation:

Hi, there!!

According to the question, we should find the hypotenuse, adjacent, and opposite to the refrence angle A ,right.

so, let's simply work with it,

hypotenuse (h)= AC {side opposite to the 90° is always a hypotenuse}.

opposite (p)= BC { as the side opposite to the refrence angle is always perpendicular or opposite}

adjacent (b)= AB { as remaining side is always base or adjacent}

Hope it helps....

Answer:

[tex]Mean = 5.6[/tex]

Step-by-step explanation:

Given

[tex]7,4,6,4,7[/tex]

Required

Determine the mean

Mean is calculated as thus;

[tex]Mean = \frac{\sum x}{n}[/tex]

Where n is the number of observation;

In this case;

[tex]n = 5[/tex]

and [tex]\sum x[/tex] is the sum of the observations

The expression becomes

[tex]Mean = \frac{7+4+6+4+7}{5}[/tex]

[tex]Mean = \frac{28}{5}[/tex]

[tex]Mean = 5.6[/tex]

Hence, the mean of the population is 5.6

Answer:

90% confidence the Population mean number of texts per day

(42.2561 ,47.1439)

Step-by-step explanation:

Step(i):-  

Given sample size 'n' = 147

mean of the sample size x⁻ = 44.7

standard deviation of the sample 'S' = 17.9

90% confidence the Population mean number of texts per day

[tex](x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,(x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })[/tex]

Step(ii):-

Degrees of freedom

       ν=n-1=147-1=146

t₀.₁₀ =  1.6554

[tex](x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,(x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })[/tex]

[tex](44.7 - 1.6554 \frac{17.9}{\sqrt{147} } ,(44.7 + 1.6554 \frac{17.9}{\sqrt{147} })[/tex]

(44.7 - 2.4439 ,44.7 + 2.4439 )

(42.2561 ,47.1439)

Conclusion:-

90% confidence the Population mean number of texts per day

(42.2561 ,47.1439)

Answer:

C. Line chart

Step-by-step explanation:

Answer:

B. Histogram

Step-by-step explanation:

Histogram uses time.

55 I hope this helps you!

Answer:

The  equation is  [tex]r = \frac{4 }{ 1 + cos (\theta )}[/tex]

Step-by-step explanation:

From the equation we are told that

    The  Eccentricity: e = 1

    The  Directrix is   y = 4

Generally the polar equation for e =  1  and  y  =  + c is mathematically represented as

         [tex]r = \frac{e * c }{ 1 + ecos (\theta )}[/tex]

So

         [tex]r = \frac{1 * 4 }{ 1 + 1 * cos (\theta )}[/tex]

        [tex]r = \frac{4 }{ 1 + cos (\theta )}[/tex]

Answer:

8x - 4

Step-by-step explanation:

8x - 4

Translated algebraically expression is 8x-4

What is expression?

Expressions is the defined as mathematical statements that have a minimum of two terms containing variables or numbers.

Given verbal expression that,

8 times a number x is subtracted by 4

(1) Let x = the unknown number.

(2) "8 times a number of x" is translated algebraically as 8x

(3) "same number x is subtracted by 4" is translated algebraically as 8x -4

Putting analyses together translated algebraically into the following equation as the result : 8x-4

Learn more about algebraic expressions

https://brainly.com/question/13947055

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Answer:

|88-x| ≤ 14

Step-by-step explanation:

their score has to be within 14 points of 88.

if their score is above 88, the number will be negative, but the absolute value makes the number positive. if that number is still within 14 of 88, they pass.

if their score is below 88, the number will be negative, and the absolute value keeps the number positive. if that number is still within 14 of 88, they pass.

Answer:

The probability that one man sampled from this population has a weight between 72kg and 88kg is 0.6826.

Step-by-step explanation:

The complete question has the data of mean = 80 kg and standard deviation = 8kg

We have to find the probability between 72 kg and 88 kg

Since it is a normal distribution

(x`- u1 / σ/ √n) < Z >( x`- u2 / σ/ √n)

P (72 <x>88) = P ( 72-80/8/√1) <Z > ( 88-80/8/√1)

= P (-1<Z> 1) = 1- P (Z<1) - P (Z<-1)

= 1- 0.8413- (- 0.8413)= 1- 1.6826= 0.6826

So the probability that one man sampled from this population has a weight between 72kg and 88kg is 0.6826.

Answer:

0.3333

Step-by-step explanation:

Given the following :

Sample mean(m) = 4.001 inch

Standard deviation(sd) = 0.002 inch

Key specification : = 4 ± .003 inches

Upper specification LIMIT ( USL) : (4 + 0.003) = 4.003 inches

Lower specification limit (LSL) : (4 - 0.003) = 3.997 inches

Cpk is found using the relation:

min[(USL - mean) / (3 * sd), (mean-LSL) / (3*sd)]

min[(4.003 - 4.001)/(3*0.002), (4.001 - 3.997)/(3*0.002)]

min[(0.002 / 0.006), (0.004 / 0.006)]

min[(0.33333, 0.66667)

Therefore Cpk = 0.3333

Because 0.33333<0.66667