Answer:
77.5% probability that this ball traveled fewer than 216 feet.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 247 feet and a standard deviation of 41 feet.
This means that [tex]\mu = 247, \sigma = 41[/tex]
What is the probability that this ball traveled fewer than 216 feet?
The probability as a decimal is the p-value of Z when X = 216. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{216 - 247}{41}[/tex]
[tex]Z = 0.756[/tex]
[tex]Z = 0.756[/tex] has a p-value of 0.775
0.775*100% = 77.5%
77.5% probability that this ball traveled fewer than 216 feet.
The following frequency distribution presents the five most frequent reasons for hospital admissions in U.S. community hospitals in a recent year.
Reason Frequency (in thousands)
Congestive heart failure 990
Coronary atherosclerosis 1400
Heart attack 744
Infant birth 3800
Required:
a. Construct a frequency bar graph.
b. Construct a relative frequency distribution.
c. Construct a relative frequency bar graph.
d. Construct a relative frequency Pareto chart.
Answer:
See Explanation
Step-by-step explanation:
Given
[tex]Reason \to Frequency[/tex]
[tex]Congestive\ heart\ failure \to 990[/tex]
[tex]Coronary\ atherosclerosis\to 1400[/tex]
[tex]Heart\ attack \to 744[/tex]
[tex]Infant\ birth\to 3800[/tex]
Solving (a): Frequency bar graph
To do this, we simply plot the reasons (on the x-axis) against the frequency (on the y-axis).
See attachment
Solving (b): Relative frequency distribution
The relative frequency is calculated as:
[tex]RF = \frac{F}{Total}[/tex]
Where
[tex]Total = 990+1400+744+3800[/tex]
[tex]Total = 6934[/tex]
So, we have:
[tex]Congestive\ heart\ failure \to \frac{990}{6934} = 0.1427[/tex]
[tex]Coronary\ atherosclerosis\to \frac{1400}{6934} = 0.2019[/tex]
[tex]Heart\ attack \to \frac{744}{6934} = 0.1073[/tex]
[tex]Infant\ birth\to \frac{3800}{6934} = 0.5481[/tex]
So, the relative distribution is:
[tex]Reason \to Frequency \to Relative\ Frequency[/tex]
[tex]Congestive\ heart\ failure \to 990 \to 0.1427[/tex]
[tex]Coronary\ atherosclerosis\to 1400 \to 0.2019[/tex]
[tex]Heart\ attack \to 744 \to 0.1073[/tex]
[tex]Infant\ birth\to 3800 \to 0.5481[/tex]
Solving (c): Relative frequency bar graph
To do this, we simply plot the reasons (on the x-axis) against the relative frequency (on the y-axis).
See attachment
Solving (d): Relative frequency Pareto chart
First, calculate the cumulative relative frequency
This is done by adding up the previous relative frequency,
So, we have:
[tex]Reason \to Relative\ Frequency \to Cumulative[/tex]
[tex]Congestive\ heart\ failure \to 0.1427 \to 0.1427[/tex]
[tex]Coronary\ atherosclerosis \to 0.2019 \to 0.2019+0.1427=0.3446[/tex]
[tex]Heart\ attack \to 0.1073\to 0.3446+0.1073 = 0.4519[/tex]
[tex]Infant\ birth \to 0.5481 \to 0.5481+4519 =1[/tex]
So, we have:
[tex]Reason \to Relative\ Frequency \to Cumulative[/tex]
[tex]Congestive\ heart\ failure \to 0.1427 \to 0.1427[/tex]
[tex]Coronary\ atherosclerosis \to 0.2019 \to 0.3446[/tex]
[tex]Heart\ attack \to 0.1073\to 0.4519[/tex]
[tex]Infant\ birth \to 0.5481 \to 1[/tex]
Next, we simply plot the reasons (on the x-axis) against the cumulative relative frequency (on the right) and the left of the Pareto chart.
See attachment
NO LINKS!!!
Change the standard form equation to vertex form and compare the function to the parent function y = x^2.
1. y = x^2 - 2x - 2
Completing the square gives
[tex]x^2-2x-2=(x-1)^2-3[/tex]
and comparing to [tex]y=x^2[/tex], the graph of [tex]y=x^2-2x-2[/tex] would be a horizontal shift to the right by 1 unit, and a vertical shift down by 3 units.
Hope this help!!!
Have a nice day!!!
How many kiloliters are there in 19,000 milliliters?
A. 19
B. 1.9
C. 0.019
D. 0.0019
Answer:
C
Step-by-step explanation:
To convert milli- to kilo-, move the decimal point six places to the left
A cheetah can run at a speed of 70 miles per hour. Which representation shows the distance a cheetah can travel
at this rate?
I’ll give brainliest
Answer:
Sorry if this is wrong, but seeing the question I think the best answer following the question would be answer B, because for A it shows that 1 hour is 35 miles when it says 70 miles in 1 hour, not C because as the time rises so does the distance, and I checked D and it's wrong.
Step-by-step explanation:
Find the equation of the line with m=6 and b = -7. Write the equation in slope intercept form.
Answer: [tex]y=6x-7[/tex]
Step-by-step explanation:
We use the formula y=mx+b to put it into slope-intercept form
m=6 (slope)
b=-7 (y-intercept)
Therefore, the answer is y=6x-7
Zahara frosted eleven cupcakes today. Dania frosted seven times as many. How many cupcakes did Dania frost?
what is the prime factorization of 225 in exponent form
Answer:
prime factorization of 225 = 32•52.
Step-by-step explanation:
The number 225 is a composite number so, it is possible to factorize it. 225 can be divided by 1, by itself and at least by 3 and 5.
A composite number is a positive integer that has at least one positive divisor other than one or the number itself. In other words, a composite number is any integer greater than one that is not a prime number.
At the beginning of the year, the odometer on an SUV read 37,532 miles. At the end
of the year, it read 52,412 miles. If the car averaged 24 miles per gallon, how many
gallons of gasoline did it use during the year?
He used 620 gallons of gas
The table shows the results of an experiment in which the spinner shown above was spun 50 times. Find the experimental probability of each outcome.
not shaded
Answer:
[tex]P(x < 4) = \frac{9}{50}[/tex]
Step-by-step explanation:
Given
[tex]n(S) = 50[/tex]
See attachment for distribution
Required
[tex]P(x < 4)[/tex]
This is calculated as:
[tex]P(x < 4) = \frac{n(1) + n(2) + n(3)}{n(S)}[/tex]
Using the data on the frequency distribution table, we have:
[tex]P(x < 4) = \frac{4 + 2 + 3}{50}[/tex]
[tex]P(x < 4) = \frac{9}{50}[/tex]
Linear function please help it’s due in 30 mins
(2104ft)(1 yd/3 ft)(1 football field/100 yds
9514 1404 393
Answer:
7 1/75 football fields
Step-by-step explanation:
Multiply it out. The units of feet and yards cancel, leaving football fields.
= (2104·1·1)/(3·100) football fields ≈ 7.0133... football fields
= 7 1/75 football fields
Solve the system of equations
4x + 2y + 1 = 1
2x − y = 1
x + 3y + z = 1
Answer:
x = 1/4
y = -1/2
z = 9/4
Step-by-step explanation:
Here we have a system of 3 equations with 3 variables:
4*x + 2*y + 1 = 1
2*x - y = 1
x + 3*y + z = 1
The first step to solve this, is to isolate one of the variables in one of the equations, let's isolate "y" in the second equation:
2*x - y = 1
2*x - 1 = y
Now that we have an expression equivalent to "y", we can replace this in the other two equations:
4*x + 2*(2*x - 1) + 1 = 1
x + 3*(2*x - 1) + z = 1
Now let's simplify these two equations:
8*x - 1 = 1
7*x - 3 + z = 1
Now, in the first equation we have only the variable x, so we can solve that equation to find the value of x:
8*x - 1 = 1
8*x = 1 + 1 = 2
x = 2/8 = 1/4
Now that we know the value of x, we can replace this in the other equation to find the value of z.
7*(1/4) -3 + z = 1
7/4 - 3 + z = 1
z = 1 + 3 - 7/4
z = 4 - 7/4
z = 16/4 - 7/4 = 9/4
z = 9/4
Now we can use the equation y = 2*x - 1 and the value of x to find the value of y:
y = 2*(1/4) - 1
y = 2/4 - 1
y = 1/2 - 1
y = -1/2
Then the solution is:
x = 1/4
y = -1/2
z = 9/4
7 degrees per millisecond converted to 7 degrees per second
Step-by-step explanation:
find the arithmetic mean of given data 12 15 18 20
Evan invested $800 in an account that pays 3.25% interest compounded annually.
Assuming no deposits or withdrawals are made, find how much money Evan would
have in the account 12 years after his initial investment. Round to the nearest tenth
(if necessary).
Answer:
Evans would have $852.8
Step-by-step explanation:
Given
[tex]PV = \$800[/tex]
[tex]r = 3.25\%[/tex]
[tex]t = 2[/tex]
[tex]n = 1[/tex] --- annually'
Required
The future value
This is calculated using:
[tex]FV = PV*(1 + \frac{r}{n})^{nt[/tex]
So, we have:
[tex]FV = 800 * (1 + 3.25\%/1)^{2*1}[/tex]
[tex]FV = 800 * (1 + 3.25\%)^{2}[/tex]
[tex]FV = 800 * (1 + 0.0325)^{2}[/tex]
[tex]FV = 800 * (1 .0325)^2[/tex]
[tex]FV = 852.845[/tex]
[tex]FV = 852.8[/tex]
FV =
simplify 16 + 15 - 5
how can i solve the following
2(x + 3) = x - 4
Answer:
x=-10
Step-by-step explanation:
2(x+3)=x-4
2*x+2*3=x-4
2x+6=x-4
2x-x=-4-6
x=-10
Answer:
[tex]x = - 10[/tex]
Step-by-step explanation:
Let's solve:
[tex]2(x+3)=x−4[/tex]
Step 1: Simplify both sides of the equation.
[tex]2(x+3)=x−4 \\ (2)(x)+(2)(3)=x+−4(Distribute) \\ 2x+6=x+−4 \\ 2x+6=x−4[/tex]
Step 2: Subtract x from both sides.
[tex]2x+6−x=x−4−x \\ x+6=−4[/tex]
Step 3: Subtract 6 from both sides.
[tex]x+6−6=−4−6 \\ x=−10[/tex]
A study was conducted to determine whether there were significant differences between medical students admitted through special programs (such as retention incentive and guaranteed placement programs) and medical students admitted through the regular admissions criteria. It was found that the graduation rate was 92.4% for the medical students admitted through special programs. Be sure to enter at least 4 digits of accuracy for this problem!
If 12 of the students from the special programs are randomly selected, find the probability that at least 11 of them graduated.
prob =
At least 4 digits!
If 12 of the students from the special programs are randomly selected, find the probability that exactly 9 of them graduated.
prob =
At least 4 digits!
Would it be unusual to randomly select 12 students from the special programs and get exactly 9 that graduate?
no, it is not unusual
yes, it is unusual
If 12 of the students from the special programs are randomly selected, find the probability that at most 9 of them graduated.
prob =
At least 4 digits!
Would it be unusual to randomly select 12 students from the special programs and get at most 9 that graduate?
yes, it is unusual
no, it is not unusual
Would it be unusual to randomly select 12 students from the special programs and get only 9 that graduate?
no, it is not unusual
yes, it is unusual
Answer:
A) 0.7696
B) 0.0474
C) Yes it's unusual
D) 0.05746
E) No, it is not unusual
F) No, it is not unusual
Step-by-step explanation:
This is a binomial probability distribution question.
We are told that 92.4% of those admitted graduated.
Thus; p = 92.4% = 0.924
From binomial probability distribution, q = 1 - p
Thus;
q = 1 - 0.924
q = 0.076
Formula for binomial probability distribution is;
P(x) = nCx × p^(x) × q^(n - x)
A) At least 11 graduated out of 12.
P(x ≥ 11) = P(11) + P(12)
P(11) = 12C11 × 0.924^(11) × 0.076^(12 - 11)
P(11) = 0.3823
P(12) = 12C12 × 0.924^(12) × 0.076^(12 - 12)
P(12) = 0.3873
P(x ≥ 11) = 0.3823 + 0.3873
P(x ≥ 11) = 0.7696
B) that exactly 9 of them graduated out of 12. This is;
P(9) = 12C9 × 0.924^(9) × 0.076^(12 - 9)
P(9) = 0.0474
C) We are not given significance level here but generally when not given we adopt a significance level of α = 0.05.
Now, exactly 9 out of 12 that graduated which is P(9) = 0.0474.
We see that 0.0474 is less than the significance level of 0.05. Thus, we can say that it is unusual to randomly select 12 students from the special programs and get exactly 9 that graduate
D) that at most 9 of them out of 12 graduated.
P(x ≤ 9) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9)
This is going to be very long so I will make use of an online probability calculator to get the values of P(0) to P(8) since I already have P(9) as 0.0474.
Thus, we have;
P(0) = 0
P(1) = 0
P(2) = 0
P(3) = 0.00000001468
P(4) = 0.00000040161
P(5) = 0.00000781232
P(6) = 0.00011081163
P(7) = 0.00115477385
P(8) = 0.00877476184
Thus;
P(x ≤ 9) = 0 + 0 + 0 + 0.00000001468 + 0.00000040161 + 0.00000781232 + 0.00011081163 + 0.00115477385 + 0.00877476184 + 0.04741450256
P(x ≤ 9) = 0.05746
E) P(x ≤ 9) = 0.05746 is more than the significance level of 0.05, thus we will say it is not unusual.
F) from online binomial probability calculator, probability of getting only 9 out of 12 is more than the significance value of 0.05. Thus, we will say it is not unusual
Which is a stretch of an exponential decay function?
f(x)=4/5(5/4)x
f(x)=4/5(4/5)x
f(x)=5/4(4/5)x
f(x)=5/4(5/4)x
On a particular game show, there are 8 covered buckets and 2 of them contain a ball.
To win the game, a contestant must select both buckets that contain a ball. Find the
probability that a contestant wins the game if he/she gets to select 4 of the buckets.
Answer:
0.2143 = 21.43% probability that a contestant wins the game if he/she gets to select 4 of the buckets.
Step-by-step explanation:
The buckets are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x sucesses is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of sucesses.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
8 covered buckets, so N = 8.
4 buckets are selected, so n = 4.
2 contain a ball, which means that k = 2.
Find the probability that a contestant wins the game if he/she gets to select 4 of the buckets.
This is P(X = 2). So
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 2) = h(2,8,4,2) = \frac{C_{2,2}*C_{6,2}}{C_{8,2}} = 0.2143[/tex]
0.2143 = 21.43% probability that a contestant wins the game if he/she gets to select 4 of the buckets.
ou want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the population proportion. You would like to be 99% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required
Answer: the required sample size =1658944
Step-by-step explanation:
When the prior population proportion for the study is unknown , then the formula for sample size is [tex]Sample \ size = 0.25(\dfrac{z^*}{Margin\ of \ error})^2[/tex]
z-value for 99% confidence = 2.576
[tex]Sample \ size = 0.25(\dfrac{2.576}{0.001})^2\\\\=0.25(2576)^2\\\\=1658944[/tex]
Hence, the required sample size =1658944
how many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 50 L of a 50% alcohol solution
Step-by-step explanation:
Question 264138: How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? x=8 gallons of 65% solution is used. 20-8=12 gallons of 40% solution is used.
please mark as brainliest
The Isosceles Trapezoid is part of an Isosceles triange with a 32° vertex angle. What is the measure of an acute base angle of the trapezoid?
Answer:
[tex]b = 74^o[/tex] --- acute base
Step-by-step explanation:
Given
See attachment for the figure
Required
The acute base angle of the trapezoid
From the question, the isosceles triangle and the trapezoid share the same base.
Represent the base angle with b.
So:
[tex]b + b + 32^o = 180^o[/tex] --- angles in a triangle
[tex]2b = 180^o-32^o[/tex]
[tex]2b = 148^o[/tex]
Divide by 2
[tex]b = 74^o[/tex]
Helpp please… due at 12:00
Answer:alternate exterior angles
Step-by-step explanation:
Since they’re on the outside of the parallel lines that makes them exterior
Mrs Lefatshe bought 15 metres of cloth.the cost of 1 metre is P69.95. how much did she have to pay?
Answer:
1042.5
Step-by-step explanation:
Given :-
Mrs Lefatshe bought 15 metres of cloth.the cost of 1 metre is P69.95 .Using Unitary Method :-
→ Cost of 1 m is P 69.95
→ Cost of 15m is P ( 69.5 * 15 ) = P 1042.5
What is the proof the outcome (not A)?
9514 1404 393
Answer:
B
Step-by-step explanation:
If the probability of event "A" is 'p', then the probability of the event "not A" is
P(not A) = 1 - P(A) = 1 - p
For p=0.5, this is ...
P(not A) = 1 -0.5 = 0.5 . . . . . matches choice B
Answer:
○B. 0.5 is the proof the outcome (not A).
How much of a radioactive kind of rhodium will be left after 120 seconds if the half-life is 30 seconds and you start with 480 grams?
9514 1404 393
Answer:
30 grams
Step-by-step explanation:
The time 120 seconds is 4 times the half-life of 30 seconds. That means (1/2)^4 = 1/16 of the original amount will remain. That is (480 g)(1/16) = 30 g.
30 g of the radioactive rhodium will be left
When a fair dice is thrown, what is the probability of getting a number greater than 4? (Reduce to simplest form)
Answer:
I searched the q and this is what I found
Step-by-step explanation:
Explanation: Number greater than 4 are 5 and 6 . So required probability is 26=13.
What are the coordinates of the point that is 1/5
of the way from A(-7,-4) to
B(3,6)?
A. (-5,0)
B. (-5,-2)
C. (0,3)
O D. (1,4)
9514 1404 393
Answer:
B. (-5, -2)
Step-by-step explanation:
That point is ...
A + 1/5(B - A)
= (-7, -4) + 1/5(3 -(-7), 6 -(-4)) = (-7, -4) +1/5(10, 10)
= (-7, -4) +(2, 2) = (-5, -2)
The point (-5, -2) is 1/5 of the way from A to B.
I don't get it please Help me
Step-by-step explanation:
A. 2(x+4)=2x+8
=G
B. 3(2x-1)=6x-3
=I
C. 4(x+2)=4x+8
=J
D. 2(x+3)=2x+6
=K
E. 3(4x+1)=12x+3
=H
A - G
B - I
C - J
D - K
E - H
HOPE IT HELP
10. (10.04 MC)
What are the period and phase shift for f(x) = -4 tan(x − n)? (1 point)
T
Period: n; phase shift: x =
2
Period: n; phase shift: x = n
TT
Period: 2n; phase shift: x =
2
Period: 2n; phase shift: x = 0
Answer:
Period: [tex]\pi[/tex]
Phase shift: n
Step-by-step explanation:
Tangent function:
Has the following format:
[tex]f(x) = \tan{ax - n}[/tex]
In which the period is [tex]\frac{\pi}{x}[/tex] and the phase shift is n.
In this question:
[tex]f(x) = -4\tan{(x-n)}[/tex]
[tex]a = 1[/tex], and thus, the period is [tex]\pi[/tex], with a phase shift of n.