Stock prices used to be quoted using eighths of a dollar. Find the total price of the transaction. 400 shares of national semi at 135 1/2

Answer:

B) x=80°

Step-by-step explanation:

This is a hexagon, so it has interior angles equaling 720°.  (N-2)*180

So the equation would be

78+134+136+132+2x+x=720

480+3x=720

3x=720-480

3x=240

x=80°

Nope, i dont think so

Answer:

no the numbers are infinite

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

answer is a on edg

Answer:

8

Step-by-step explanation:

Ham with or without cheese-2 choices

Bologna with or without cheese-2 choices

Bologna with cheese with water or juice-2 choices

Bologna without cheese with juice or water-2 choices

Ham with cheese with juice or water -2 choices

Ham without cheese with juice or water -2 choices

2+2+2+2=8

Kile has 8 choices for lunch

Answer:

Step-by-step explanation:

Hello, please consider the following.

[tex]x=x(t)=2cos(t)\\\\dx=\dfrac{dx}{dt}dt=x'(t)dt=-2sin(t)dt[/tex]

and

[tex]y=y(t)=2sin(t)\\\\dy=\dfrac{dy}{dt}dt=y'(t)dt=2cos(t)dt[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

The values of dx and dy are give as -2sin(t)dt and 2cos(t)dt respectively. The answer to the given problem can be stated as,

dy = 2cos(t)dt

And,  dx = -2sin(t)dt.

The integration can be defined as the inverse operation of differentiation. If a function is the integration of some function f(x) , then differentiation of that function is f(x).

The given integral over C is ∫ (x − y) dx + (x + y) dy.

And, the parameters for C are as follows,

x = 2cos(t)

y = 2sin(t)

0 ≤ t ≤ 2π

Now, on the basis of these parameters dx and dy can be found as follows,

x =  2cos(t)

Differentiate both sides with respect to t as follows,

dx/dt = 2d(cos(t))/dt

=> dx/dt = -2sin(t)

=> dx =  -2sin(t)dt

And, y = 2sin(t)

Differentiate both sides with respect to t as follows,

dy/dt = 2d(sin(t))/dt

=> dy/dt = 2cos(t)

=> dy = 2cos(t)dt

Hence, the value of dx and dy as per the given parameters is -2sin(t)dt and 2cos(t)dt respectively.

To know more about integration click on,

https://brainly.com/question/18125359

#SPJ2

Answer: 0.418 < p < 0.512

Step-by-step explanation: A 95% conifdence interval for a population proportion is given by:

[tex]p + z\sqrt{\frac{p(1-p)}{n} }[/tex]

where:

p is the proportion

z is score in z-table

n is sample size

The proportion for people who said "yes" is

[tex]p=\frac{202}{434}[/tex] = 0.465

For a 95% confidence interval, z = 1.96.

Calculating

[tex]0.465 + 1.96*\sqrt{\frac{0.465(0.535)}{434} }[/tex]

[tex]0.465 + 1.96*\sqrt{0.00057}[/tex]

0.465 ± 1.96*0.024

0.465 ± 0.047

Interval is between:

0.465 - 0.047 = 0.418

0.465 + 0.047 = 0.512

The interval with 95% of confidence is between 0.418 and 0.512.

Answer:

Note that orthogonal to the plane means perpendicular to the plane.

Step-by-step explanation:

-1x+3y-3z=1 can also be written as -1x+3y-3z=0

The direction vector of the plane -1x+3y-3z-1=0 is (-1,3,-3).

Let us find a point on this  line for which the vector from this point to (0,0,5) is perpendicular to the given line. The point is x-0,y-0 and z-0 respectively

Therefore, the vector equation is given as:

-1(x-0) + 3(y-0) + -3(z-5) = 0

-x + 3y + (-3z+15) = 0

-x + 3y -3z + 15 = 0

Multiply through by - to get a positive x coordinate to give

x - 3y + 3z - 15 = 0

Since two of the quantities are squares and the sum of all of three is equal 21, then the possible values of those two quantities are: 1,4,9,16

Let's consider each possibility

1 and 4

21-1-4=16, but 16 is also square and there can be only two square so NO

1 and 9

21-1-9=11, but 11 is prime, so NO

1 and 16

21-1-16=4... 4 is a square ,so NO

4 and 9

21-4-9=8 , 8 is not prime and not a square, so YES

4 and 16

21-4-16=1, but 1 is a square ,so NO

9 and 16

9+16=25>21 so.. NO

Therefore, the amounts in the first three bowls are 4,8,9.

Aswer:I am sure of the answer it is 6 and 42

Step-by-step explanation:

Answer:

Step-by-step explanation:

Using FV = PV(1 + r)^n where FV = future value, PV = present value, r = interest rate per period, and n = # of periods

1/PV (FV) = (PV(1 + r^n)1/PV divide by PV

ln(FV/PV) = ln(1 + r^n) convert to natural log function

ln(FV/PV) = n[ln(1 + r)] by simplifying

n = ln(FV/PV) / ln(1 + r) solve for n

n = ln(2/1) / ln(1 + .08) solve for n, letting FV + 2, PV = 1 and rate = 8% or .08 compound annually

n = 9

n = ln(2/1) / ln(1 + .08/12) solve for n, letting FV + 2, PV = 1 and rate = .08/12 compound monthly

n = 104 months or 8.69 years

n = ln(2/1) / ln(1 + .08/365) solve for n, letting FV + 2, PV = 1 & rate = .08/365 compound daily

n = 3163 days or 8.67 years

Alternatively

A = P e ^(rt)

Given that r = 8%

= 8/100

= 0.08

2 = e^(0.08t)

ln(2)/0.08 = t

0.6931/0.08 = t

t= 8.664yrs

t = 8.67yrs

Which ever approach you choose to use,you will still arrive at the same answer.

Answer:

The answer is:

C. [tex]\bold{x = -1.25h+220}[/tex]

Step-by-step explanation:

Given:

[tex]h=0.8( 220-x )[/tex]

Where [tex]h[/tex] is the heartbeats per minute and

[tex]x[/tex] is the age of person

To find:

Age of person in terms of heartbeats per minute = ?

To choose form the options:

[tex]A.\ x=176-h\\B.\ x=176-0.8h\\C.\ x=-1.25h+220\\D.\ x=h-0.8220[/tex]

Solution:

First of all, let us have a look at the given equation:

[tex]h=0.8( 220-x )[/tex]

It is value of [tex]h[/tex] in terms of [tex]x[/tex].

We have to find the value of [tex]x[/tex] in terms of [tex]h[/tex].

Let us divide the equation by 0.8 on both sides:

[tex]\dfrac{h}{0.8}=\dfrac{0.8( 220-x )}{0.8}\\\Rightarrow \dfrac{1}{0.8}h=220-x\\\Rightarrow 1.25h=220-x[/tex]

Now, subtracting 220 from both sides:

[tex]\Rightarrow 1.25h-220=220-x-220\\\Rightarrow 1.25h-220=-x[/tex]

Now, multiplying with -1 on both sides:

[tex]-1.25h+220=x\\OR\\\bold{x = -1.25h+220}[/tex]

So, the answer is:

C. [tex]\bold{x = -1.25h+220}[/tex]

Answer: x < 28

Step-by-step explanation:

Answer:

The answer is 55, -275, 1375, -6875......

Step-by-step explanation:

Answer:

100,000

You take 1,000 because it's in the thousandths place of 1,255. The value of that one is 1,000 so you multiply that times 100, which is the value of 1 in 82,175.

Answer:

Step-by-step explanation:

Answer:

2 sqrt(41) = x

Step-by-step explanation:

This is a right triangle so we can use the Pythagorean theorem

a^2 + b^2 = c^2

8^2 + 10 ^2 = x^2

64+ 100 = x^2

164 = x^2

Take the square root of each side

sqrt(164) = sqrt(x^2)

sqrt(4) sqrt(41) = x

2 sqrt(41) = x

Answer:

900

Step-by-step explanation:

You have 10 tens not 1 ten

8 * 100 + 10 * 10 + 0*1

800 + 100 + 0

900

Answer:

[tex]900[/tex]

Step-by-step explanation:

[tex]8 \times 100 + 10 \times 10 + 0 \times 1 \\ 800 + 100 + 0 \\ = 900[/tex]

Answer:

- At any time t, the population is:

P = 375t² + 3000t + 1000

- At time t = 3 days, the population is:

P = 13,375

Step-by-step explanation:

Given the rate of change of the population of bacteria as:

dP/dt = 3000/(1 + 0.25t)

we need to rewrite the given differential equation, and solve.

Rewriting, we have:

dP/3000 = (1 + 0.25t)dt

Integrating both sides, we have

P/3000 = t + (0.25/2)t² + C

P/3000 = t + 0.125t² + C

When t = 0, P = 1000

So,

1000/3000 = C

C = 1/3

Therefore, at any time t, the population is:

P/3000 = 0.125t² + t + 1/3

P = 375t² + 3000t + 1000

At time t = 3 days, the population is :

P = 375(3²) + 3000(3) + 1000

= 3375 + 9000 + 1000

P = 13,375

Answer:

$3870

Step-by-step explanation:

Hello, the initial deposit is $1000.

After one year, we will get 1000 + 7%*1000= 1000 * ( 1+7%) = 1000 * (1+0.07)

= 1000 * 1.07

And we want to compound it so the second year we will get

[tex]1000 * 1.07 * 1.07 = 1000 * 1.07^2[/tex]

And after n years, we will get

[tex]1000 * 1.07^n[/tex]

In that example, we want to know how much we will get after 20 years, so this is:

[tex]1000 * 1.07^{20}=3869.684462...[/tex]

Thank you.

When interest is compounded, it means that both the interest and the amount deposited will earn interest.

We are to determine the future value of $1000 with annual compounding.

The formula for calculating future value:

FV = P (1 + r)^n

FV = Future value  

P = amount deposited = $1000

R = interest rate = 7%

N = number of years = 20

$1000 x ( 1.07)^20 = $3,869.68

To learn more about compound interest, please check: https://brainly.com/question/14295570?referrer=searchResults

Answer:

486

Step-by-step explanation:

Hello!

To find the surface area of a cube we use the equation

[tex]S = 6a^{2}[/tex]

S is the surface area

a is the side length

Put what we know into the equation

[tex]S = 6*9^{2}[/tex]

Solve

S = 6 * 81

S = 486

Hope this Helps!

Answer:486[tex]ft^{2}[/tex]

Step-by-step explanation:

surface area= 6[tex]l^{2}[/tex]

l=9

sa=6 ([tex]9^{2}[/tex])= 6 x 81=486[tex]ft^{2}[/tex]

Answer:

217.0588235294118

Step-by-step explanation:

Convert all height to inches.

5' 8" = 68 inches

6' = 72

205/68 = 3.014705882352941

Height/Weight Ratio * Evan's Height = 217.0588235294118

Answer:

Surface area of the box = 168 cm²

Step-by-step explanation:

Amount of cardboard needed = Surface area of the box

Since the given box is in the shape of a triangular prism,

Surface area of the prism = 2(surface area of the triangular bases) + Area of the three rectangular lateral sides

Surface area of the triangular base = [tex]\frac{1}{2}(\text{Base})(\text{height})[/tex]

                                                           = [tex]\frac{1}{2}(6)(4)[/tex]

                                                           = 12 cm²

Surface area of the rectangular side with the dimensions of (6cm × 9cm),

= Length × width

= 6 × 9

= 54 cm²

Area of the rectangle with the dimensions (9cm × 5cm),

= 9 × 5

= 45 cm²

Area of the rectangle with the dimensions (9cm × 5cm),

= 9 × 5

= 45 cm²

Surface area of the prism = 2(12) + 54 + 45 + 45

                                           = 24 + 54 + 90

                                           = 168 cm²

Answer:

  B, E

Step-by-step explanation:

You can use these strategies to compare the given graph and the other representations.

  A & B) See if the point (x, y) = (8, 6) marked on the first graph works in the given equation.

A -- 6y = 8x   ⇒   6(6) = 8(8) . . . FALSE

B -- y = (3/4)x   ⇒   6 = (3/4)8 . . . True

__

  C) Compare this graph to the given graph. They don't match.

__

  D & E) Plot a point from the table on the given graph and see where it falls.

D -- The point (x, y) = (3, 4) lies above the line on the given graph.

E -- The point (x, y) = (4, 3) lies on the given graph.

_____

Choices B and E have the same constant of proportionality as shown in the given graph.

Answer:

B and E

Step-by-step explanation:

Answer:

E(w) = 1600000

v(w) = 240000

Step-by-step explanation:

given data

sequence = 1 million iid  (+1 and +2)

probability of transmitting a +1 =  0.4

solution

sequence will be here as

P{Xi = k } = 0.4              for k = +1

                  0.6              for k = +2

and define is

x1  + x2 + ................ + X1000000

so for expected value for W

E(w) = E( x1  + x2 + ................ +  X1000000 )   ......................1

as per the linear probability of expectation

E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)

E(w) = 1600000

and

for variance of W

v(w) = V ( x1  + x2 + ................ + X1000000 )    ..........................2

v(w) = V x1  + V x2 + ................  + V  X1000000

here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j

so

v(w) = 1000000 ( v(x) )

v(w) = 1000000 ( 0.24)

v(w) = 240000

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

[tex]f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}[/tex]

Now, we distribute the expression of f(x) and find the derivative afterwards.

[tex]f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

a≥0

Step-by-step explanation:

a-82≥-82

a≥-82+82

a≥0

This sequence converges to 0.

Proof: Recall that

[tex]\displaystyle\lim_{n\to\infty}\frac1{\sqrt n}=0[/tex]

is to say that for any given [tex]\varepsilon>0[/tex], there is some [tex]N[/tex] for which [tex]\left|\frac1{\sqrt n}-0\right|=\frac1{\sqrt n}<\varepsilon[/tex] for all [tex]n>N[/tex].

Let [tex]N=\left\lceil\frac1{\varepsilon^2}\right\rceil[/tex]. Then

[tex]n>\left\lceil\dfrac1{\varepsilon^2}\right\rceil\ge\dfrac1{\varepsilon^2}[/tex]

[tex]\implies\dfrac1n<\varepsilon^2[/tex]

[tex]\implies\dfrac1{\sqrt n}<\varepsilon[/tex]

as required.

Answer:

2x + 5y + 15

Step-by-step explanation:

add like terms

(x+x) + (y+y)+3y+15

2x+2y+3y+15

2x + 5y + 15

i hope this helps!

Answer:

105 years

Step-by-step explanation:

Given the function :

Q(t) = 4e^(-0.00938t)

Q = Quantity in kilogram of an element in a storage unit after t years

how long will it be before the quantity is less than 1.5kg

Inputting Q = 1.5kg into the equation:

1.5 = 4e^(-0.00938t)

Divide both sides by 4

(1.5 / 4) = (4e^(-0.00938t) / 4)

0.375 = e^(-0.00938t)

Take the ln of both sides

In(0.375) = In(e^(-0.00938t))

−0.980829 = -0.00938t

Divide both sides by 0.00938

0.00938t / 0.00938 = 0.980829 /0.00938

t = 104.56599

When t = 104.56599 years , the quantity in kilogram of the element in storage will be exactly 1.5kg

Therefore, when t = 105 years, the quantity of element in storage will be less than 1.5kg