Answer:
see explaination
Explanation:
Case 1) When we consider vapor pressure of H2O;
Let the pressure is 1 atm OR 760 torr.
As H2 is collected over water, we have to consider the vapor pressure of H2O as well.
Using data i.e. vapor pressure of H2O at 40° C = 55.365 torr
So, pressure of H2 = P = 760 - 55.365 = 704.635 torr = 704.635/760 = 0.9272 atm
Volume of H2 = 80 ml = 0.08 liter
Temperature (T) = 40 + 273 = 313 K
Gas constant (R) = 0.0821 L atm/mol K
Let n is moles of H2. Applying ideal gas equation;
PV = nRT
n = PV/RT = 0.9272 * 0.08 / 0.0821 * 313
n = 0.00289 moles
Mass of H2 = moles * molar mass = 0.00289 * 2.016 = 0.00582 grams
OR 5.8*10^-3 grams ...Answer
----> Case 2) When we don't consider vapor pressure;
Pressure of H2 = 1 atm, all other parameters will remain same as in case 1.
So, mass of H2 = 6.3*10^-3 grams
But Case 1) is correct approach as in question it is mentioned that H2 is collected over water.
Describe the catenation property of carbon by illustrating the formation of a straight chain and branched chain compounds
Answer:
Catenation refers to the ability of an atom to link to other atoms of the same kind to form a chain.
Explanation:
Catenation is the binding of an element to itself through covalent bonds to form chain or ring .Catenation can also be defined as the self-linking of atoms of an element to form chains and rings. This definition can be extended to include the formation of layers like two-dimensional catenation and space lattices like three-dimensional catenation. Thus, we can boldly say that, Catenation occurs when atoms of the same element covalently bond to one another to create a chain or ring.
Catenation occurs most readily in carbon, forming covalent bonds to and longer chains and structures with other carbon atoms. This is why the vast number of organic compounds are found in nature. Carbon is best known for its catenation properties, with the analysis of catenated carbon structures in organic chemistry.
Carbon is by no means the only element capable of forming such catenae, however, and several other main group elements are capable of forming a wide range of catenae, including silicon, sulfur, and boron. In group 14, the high bond energy of carbon makes it able to self-link almost indefinitely when compared with other members of the group which form only a few bonds to other atoms of the same element.
516 mL of a 3.82 M sodium sulfate (Na2SO4) solution is diluted ith .875 L of water. What is the new concentration in molarity?
Answer: 1.42
Explanation:
What is the symbol for the entity that has 17 protons, 20 neutrons, and 18 electrons?
hEy!!!
Chlorine(CL) is the symbol for the entity that has 17 protons,20 neutrons and 18 electrons.
Hope it will be helpful to you...
Answer:chlorine
Explanation:
What is the molality of a solution that contains 31.0 g HCl in 5.00 kg water? (molar mass of
HCI = 36.46 g/mol)
Answer:
0.17M
Explanation:
5kg of water contains 5 liters as the density of water is 1000 [tex]kgm^{-3}[/tex]
Therefore one liter of water contains 31/5=6.2g of HCl
Molality of the solution = 6.2/36.46 =0.17M
If an insufficient amount of liquid unknown had been used, how would this have effected the value of the experimental molar mass
Answer:
Actual yield reduces the more.
Explanation:
An actual yield of the course of a chemical reaction is the mass of a product actually obtained from the reaction.
In practice you see it and It is usually less than the theoretical yield.
Various reasons may come up to explain this away but here is one:
• incomplete reactions, simply put here some of the reactants do not react to form the product.
The same applies in the question about the actual yield will reduce significantly in molar mass now that insufficient amount of reagent are used.
What is the concentration of a solution if 0.450 mol of NaCl dissolved in 750 mL of water?
Answer:
.6mol/L
Explanation:
molarity = number of moles / volume of solvent (in L)
750mL / 1000mL/L = .75L
M = .450mol / .75L
M = .6mol/L
which of the following is associated with the use of genetic engineering to clone farm
animals?
A.
Cloning could improve the availability of food in some areas
B.
The success rate for animal cloning is currently low.
C.
There is controversy associated with cloning farm animals
D.
all of these
Answer:D all of these
Explanation:
I just did it and that’s the correct answer
The roles of hydrochloric acid (HCl) in the digestive system?
Answer:
There are several roles of HCl in the digestive system. Some of them are as follows:
There is HCl present in the gastric juice of your stomach, otherwise known as stomach acid. The acidic nature of the HCl in the stomach acid make it useful for quickly breaking down food.HCl's acidic nature also allows it to kill bacteria and other pathogens that you may have ingested, keeping you safe from their dangerous effects.HCl can also contribute Hydrogen ions, which helps to activate pepsinogen, a substance secreted by the stomach wall. The activated pepsinogen is then converted into pepsin, which aids in the digestion of proteins. Because of this, HCl essentially keeps the systems of protein digestion in check. Too much or too little of it can be dangerous.HCl also makes sure that vitamins are properly absorbed and acts as a communicator to other organs in the digestive system.Use the graph to determine which is greater, the heat of fusion or the heat of vaporization. Explain how you used the graph to determine that.
(The substance is water)
Answer:
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Rate Law & Reaction Kinetics Chemistry 11 Chapter 17 1. For the reaction 3 ClO - (aq) → ClO - 3(aq) + 2 Cl - (aq) doubling the concentration of ClO - quadruples the initial rate of formation of ClO - 3 . What is the rate expression for the reaction? 2. The reaction C 6 H 5 N 2 Cl (aq) + H 2 O (l) → C 6 H 5 OH (aq) + N 2(g) + HCl (aq) is first order in C 6 H 5 N 2 Cl and zero order in H 2 O. What is the rate expression? 3. For the reaction H 3 PO 4(aq) + 3I - (aq) + 2H + (aq) → H 3 PO 3(aq) + I - 3(aq) + H 2 O (l) the rate expression under certain conditions is R = k[H 3 PO 4 ][I - ][H + ] 2 . What method(s) could be used if you want to double the reaction rate? 4. What is the overall order of reaction for each of the following: a) R = k[NO 2 ] 2 b) R = k c) R = k[H 2 ][Br 2 ] ½ d) Rate = k[NO] 2 [O2]
Answer:
1) Rate = K [ClO⁻]²
2) Rate = K [C6H5N2Cl]
3) - Double the concentration of H3PO4.
- Double the concentration of I⁻
4) Check Explanation
Explanation:
A reaction's rate law is written as a product of the reaction's rate constant, k, and the concentration of the respective reactant(s) raised to the power of the order of reaction.
The order of a reaction with respect to a reactant is the power that the concentration of that specific reactant has in the rate law. It shows how dependent on each reactant , the rate of the reaction.
1) 3ClO⁻ (aq) → ClO³⁻ (aq) + 2 Cl⁻ (aq)
Doubling the concentration of ClO⁻ quadruples the initial rate of formation of ClO³⁻. What is the rate expression for the reaction?
Rate = k [ClO⁻]ⁿ
When [ClO⁻] is doubled, Rate is quadrupled, this shows that the reaction is second order with respect to the only reactant.
Rate = K [ClO⁻]²
2. The reaction
C6H5N2Cl (aq) + H2O (l) → C6H5OH (aq) + N2 (g) + HCl (aq) is first order in C6H5N2Cl and zero order in H2O. What is the rate expression?
Normally, the rate of reaction is equal to the rate constant multiplied by the each reactant's concentration raised ti the power of the order, so,
Rate = K [C6H5N2Cl]¹ [H2O]
Rate = K [C6H5N2Cl]
3. For the reaction
H3PO4 (aq) + 3I⁻ (aq) + 2H + (aq) → H3PO3(aq) + I³⁻(aq) + H2O
(l) the rate expression under certain conditions is R = k[H3PO4][I⁻][H⁺]² . What method(s) could be used if you want to double the reaction rate?
Rate = k[H3PO4][I⁻][H⁺]²
Indicating a first order relationship between the rate and the concentration of H3PO4 & I⁻ and second order with respect to H⁺.
So, any attempt to double the rate of reaction will entail a direct doubling of the one of the reactants with a first order relationship with the rate of reaction.
4. What is the overall order of reaction for each of the following.
a) R = k[NO2]² b) R = k c) R = k[H2][Br2] ½ d) Rate = k[NO]² [O2]
Note that overall order of a reaction is the sum of all the orders of the reactants that appear in the rate law.
a) R = k[NO2]²
Overall order is obviously 2.
b) R = k
Overall order is evidently 0.
c) R = k [H2] [Br2]^ ½
Overall order = 1 + ½ = (3/2)
d) Rate = k[NO]2 [O2]
Overall order = 2 + 1 = 3
Hope this Helps!!!
Which picture shows how the moon from earth when it’s in the position
Explanation:
This picture shows how the moon from earth when it is in position
Silver (1) oxide → silver + oxygen gas
Answer: come on lets link can do what i do
HELP ASAP!!!! PLEASE AND THANK YOU!!!! Aluminum, which has a specific heat capacity of 0.902 J/g◦C and a mass of 20.9 g absorbs 348.0 J of energy. The final temperature (T2) is 100.0◦C. Calculate the initial temperature (T1).
Answer:
81.54 °C
Explanation:
Use the equation
q = mcΔT
348 = 20.9(0.902)(100-t)
t = 81.54 °C
*note, you don't have to convert these to kelvin since the difference will be the same
Indicate which molecules demonstrate the correct bonding for carbon atoms. Check all that apply.
CH4
CH3CH4CH2
CH3CH2CH2CH3
CH2CH2CH4
The correct answer is:
CH4
CH3CH2CH2CH3
Answer:
CH4 and CH3 CH2 CH2 CH3
Explanation:
Answer:
CH4 and CH3CH2CH2CH3
Explanation:
its right on edg
A container is filled with 10 mol of gas and the pressure (Pi) is measured. If 5 mol are removed, what is the new pressure (Pf)?
Answer:
1/2 of the Pi
Explanation:
PV = nRT
we are going to assume the only things changing are pressure and number of mols, so we change the formula and substitute the variables to make it what we are looking for
[tex]\frac{Pi}{ni} = \frac{Pf}{nf}[/tex]
then we will assume Pi as 1 as it is not given, so we can state it easier
[tex]\frac{1atm}{10mol} = \frac{xatm}{5mol}[/tex]
then either cross multiply or just work it out to be
[tex]\frac{1}{2}[/tex] which we can say as "half of the initial pressure" as no number is given for initial pressure
Which statements describe inorganic compounds? Check all that apply
Inorganic compounds contain carbon
Inorganic compounds usually lack carbon
Inorganic compounds are not associated with or made from living things,
Inorganic compounds include fruits and vegetables,
Inorganic compounds include salt and water
Answer:
b, c, e
Explanation:
Inorganic compounds usually lack carbon.
Inorganic compounds are not associated with or made from living things.
Inorganic compounds include salt and water.
Answer:
yes the answer id bce
Explanation:
Polyatomic ion formula for aluminum hydroxide
Answer:
Al(OH)3 ? i hope this is what you mean.
Answer:
The formula for aluminum hydroxide is Al(OH)3.
Explanation:
Typically, metal hydroxides form strong bases in solution. Aluminum hydroxide is special compound because it is amphoteric. This means it can react as a base or as an acid.
Describe an autopsy table
After the body is cleaned, the body is weighed and measured before being placed on the autopsy table for reexamination. The autopsy table is typically a slanted, aluminum table with raised edges that has several faucets and drains used to wash away collecting blood during the internal investigation.
Answer:
A table used to scientifically determine the cause of death of a human or animal
Explanation:
g A chemistry student needs of thiophene for an experiment. She has available of a w/w solution of thiophene in benzene. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to significant digits.
The given question is not complete, the complete question is:
A chemistry student needs 5.00 g of thiophene for an experiment. She has available 0.50 kg of a 28.7% w/w solution of thiophene in benzene, Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button Be sure your answer has the correct number of significant digits. X
Answer:
The correct answer is 17.4 grams.
Explanation:
As mentioned in the given question, 28.7 percent w/w solution thiophene in benzene shows that,
(wt. of thiophene / wt. of thiopene + benzene) * 100 = 28.7
0.50 kg of the solution indicates that it is 500 grams of the solution.
Therefore, the amount of thiophene found in the 500 grams of the solution is,
500 g * 28.7 / 100 = 143.5 gm
Thus, 143.5 grams of thiophene is found 500 grams of the solution.
Now, 1 gram of thiophene will be in 500/143.5 of solution.
Therefore, 5 grams of thiophene will be in 500/143.5 * 5 g of the solution = 17.42 grams of the solution.
Hence, the mass of the solution to be used by the student in the given case will be 17.4 grams.
Which metal is most easily oxidized?
A) Cu B) Ag C) Mg D) Co
Answer:
It is Magnesium because magnesium is the most active out of those three
Explanation:
The metal which is most easily oxidized is : ( C ) Magnesium ( Mg )
What is Oxidization ?
Oxidization involves the process of the addition of oxygen and the removal of electrons from a compound when Magnesium reacts with oxygen it easily gets oxidized when compared to other metals in the question since magnesium is the most active.
Hence we can conclude that The metal which is most easily oxidized is : ( C ) Magnesium ( Mg ).
Learn more about oxidization :https://brainly.com/question/8990767
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Please real answers only , 100 pts and brainliest .
what is A , B and C?
Answer:
A = 1.2L
B = 506.6 torr
C = 13.5 °C
Answer:
A = 1.2L B = 506.6 torr and C = 13.5 °C
have a nice day :)
Two liquids, A and B, have equal masses and equal initial temperatures. Each is heated for the same length of time over identical burners. Afterward, liquid A is hotter than liquid B. Which has the larger specific heat? Two liquids, A and B, have equal masses and equal initial temperatures. Each is heated for the same length of time over identical burners. Afterward, liquid A is hotter than liquid B. Which has the larger specific heat? Liquid A. There's not enough information to tell. Liquid B.
Answer:
Liquid A.
Explanation:
Specific heat is defined as the amount of heat required per unit of mass to raise the temperature by one degree celsius.
When two liquids are heated, the liquid with larger specific heat is the one which is hotter. That is because is required more energy to decrease its temperature by 1°C.
Thus, in the problem, liquid A has the larger specific heat
Two atoms of the same element
Answer:
Isotope
Explanation:
.
5.0 mg of radioactive nobelium-253 was removed from the reactor to be
used in an experiment. It took 291 seconds (just under 5 minutes) to
get the sample from the reactor to the laboratory. How many milligrams
of nobelium-253 remained upon arrival to the laboratory? The half-life
of nobelium-253 is 97 seconds.
Answer:
Explanation:
Half life of Nobelium-253 is 97 seconds . That means after every 97 seconds half of the Nobelium amount will be disintegrated .
Time taken in bringing the sample to laboratory = 291 seconds
291 second = 291 / 97 half life
n = 3
N = [tex]N_0 (\frac{1}{2})^n[/tex]
N₀ is original mass , N is mass after n number of half life.
N = 5 mg x [tex](\frac{1}{2})^3[/tex]
= .625 mg
Only 0.625 mg of Nobelium-253 will be left .
Which of the following are peninsulas in Southeast Asia?
A.
the Miramar Peninsula and the Tasmanian Peninsula
B.
the Indochinese Peninsula and the Malay Peninsula
C.
the Philippine Peninsula and the Vietnam Peninsula
D.
the Irrawaddy Peninsula and the Mekong Peninsula
Answer:
B.
Explanation:
Answer:
B
Explanation:
Complex ions with different ligands have different colors because the ligands: Group of answer choices are different colors affect the energy levels of the lone-pair electrons on the metal have different energies for their bonding electrons affect the energy levels of the metal d orbitals have different energies for their lone-pair electrons
Answer:
The correct answer is the second last statement, that is, it affects the energy levels of the metal d orbitals.
Explanation:
It is because of the d-d transition of electrons that the metal complexes exhibit color. When bonding of the ligands takes place with the transition metal ion, a repulsion results between the electrons in the d orbitals of the metal ion and the electrons found within the ligands. This increases the d orbitals' energy level.
However, based on the alignment of the d orbitals in the space, all of the energies do not get elevated by the same level, it gets dissociate into two groups. This dissociation of the d-orbitals relies upon the ligand's strength. More amount of energy would be required to encourage an electron from the lower orbitals groups to the move towards the higher ones in case if the splitting is more.
Greater energy is equivalent to shorter wavelengths in terms of the color of the light absorbed. The complex ions possessing different ligands show distinct kinds of colors as the energy levels of the d orbitals of the metal get affected by the ligands.
1. A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0% Pb(NO3)2 by mass (d: 1.134 g/mL). How many grams of PbI2 should form?
Pb(NO3)2(aq) + 2 KI(aq) PbI2(s) + 2 KNO3(aq)
Answer:
[tex]m_{PbI_2}=18.2gPbI_2[/tex]
Explanation:
Hello,
In this case, we write the reaction again:
[tex]Pb(NO_3)_2(aq) + 2 KI(aq)\rightarrow PbI_2(s) + 2 KNO_3(aq)[/tex]
In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:
[tex]n_{Pb(NO_3)_2}=\frac{0.14gPb(NO_3)_2}{1g\ sln}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2} *\frac{1.134g\ sln}{1mL\ sln} *96.7mL\ sln\\\\n_{Pb(NO_3)_2}=0.04635molPb(NO_3)_2\\\\n_{KI}=\frac{0.12gKI}{1g\ sln}*\frac{1molKI}{166.0gKI} *\frac{1.093g\ sln}{1mL\ sln} *99.8mL\ sln\\\\n_{KI}=0.07885molKI[/tex]
Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:
[tex]0.04635molPb(NO_3)_2*\frac{2molKI}{1molPb(NO_3)_2} =0.0927molKI[/tex]
But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:
[tex]m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2[/tex]
Best regards.
When you need to produce a variety of diluted solutions of a solute, you can dilute a series of stock solutions. A stock solution has a significantly higher concentration of the given solute (typically 101 to 104 times higher than those of the diluted solutions). The high concentration allows many diluted solutions to be prepared using minimal amounts of the stock solution. What volume of a 6.01 M stock solution do you need to prepare 100. mL of a 0.3624 M solution of HCl?
Answer:
Volume of stock solution needed = 6.0299 mL
Explanation:
Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.
This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.
Data:
M1 = 6.01 M stock solution concentration
M2 = 0.3624 M diluted solution concentration
V2 =100 mL diluted solution volume
V1 = ? stock solution volume
M1 * V1 = M2 * V2
[tex]V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL[/tex]
How are plastic containers different from paper containers? How are they the same?
Answer:
Paper is Not Reuseable like plastic.
Explanation:
In a different experiment, the student uses a calorimeter which is perfectly insulated. She fills the calorimeter with 100.0 g of 25.00°C dilute HCl solution and adds 0.594 g Mg metal (24.3 g/mol). The final temperature of the apparatus comes to 41.83°C. Remember, the solution is made-up of the solute and the solvent. The specific heat for magnesium is negligible compared to the aqueous solution. What is the Molar Heat of Enthalpy for this reaction?
Answer:
Explanation:
Mg + 2HCl = Mg Cl₂ + H₂
.594 g = .594 / 24.3
= .02444 mole
Heat evolved = msΔ T , m is mass of water ( solvant ) , s is specific heat of water , Δ T is rise in temperature
= 100 x 4.2 x ( 41.83 - 25 )
= 7068.6 J
.02444 mole of Mg evolves 7068.6 J of heat
1 mole of Mg evolves 7068.6 /.02444 J
= 289222.6 J
= 289 kJ .
Molar heat enthalpy = 289 kJ .
