someone please help!!

Answer:

[tex]{ \bf{15x + 30 = 180}}[/tex]

Answer:

X would be 63.9

Hope it helps

Step-by-step explanation:

The value of the variable 'x' using the cosine formula will be 63.9 units.

It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function.

Trigonometric functions examine the interaction between the dimensions and angles of a triangular form.

The value of 'x' is given by the cosine of the angle ∠QSR. And the cosine of an angle is the ratio of the base and hypotenuse of the right-angle triangle. Then we have

cos 35° = x / 78

x = 63.9

The value of the variable 'x' using the cosine formula will be 63.9 units.

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Answer:

m(x)

Step-by-step explanation:

Answer:

B: g(x) = -4(x + 3)^2

Step-by-step explanation:

When we shift to the left by a units

we have the new equation become

( x + 3)^2

Stretching by a factor of 4, we have it that;

4(x + 3)^2

reflecting over the x-axis means the y-axis value becomes negative

So we have

g(x) = -4(x + 3)^2

Answer:

a=1

Step-by-step explanation:

Hopefully this helps :)

The equation of the parabola is: y = (x - 2)² - 2. Finding the value of A

The vertex of the parabola is at (2,-2). Since the parabola opens upward, the equation of the parabola will be of the form:

y = A(x - 2)² - 2

We can plug the point (3,-1) into this equation to find the value of A.

-1 = A(3 - 2)² - 2

Simplifying the right side of the equation, we get:

-1 = A - 2

Adding 2 to both sides of the equation, we get:

1 = A

Therefore, the value of A is 1.

Writing the equation of the parabola

The equation of the parabola is:

y = (x - 2)² - 2

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Répondre:

Benoit a 10 ans

Explication étape par étape :

Laisser :

Âge de Thomas = x

Benoit age = y

il y a 5 ans :

x - 5 = 5 (y - 5)

x - 5 = 5y - 25 - - (1)

Aujourd'hui :

x = 3y - - (2)

Mettez x = 3y dans (1)

3 ans - 5 = 5 ans - 25

Recueillir des termes similaires

3 ans - 5 ans = - 25 + 5

-2a = - 20

Diviser les deux côtés par - 2

y = 10

Answer:

(10, - 1 )

Step-by-step explanation:

Given the 2 equations

x - 3y = 13 → (1)

x + 2y = 8 → (2)

Rearrange (1) making x the subject by adding 3y to both sides

x = 3y + 13 → (3)

Substitute x = 3y + 13 into (2)

3y + 13 + 2y = 8

5y + 13 = 8 ( subtract 13 from both sides )

5y = - 5 ( divide both sides by 5 )

y = - 1

Substitute y = - 1 into (3) for corresponding value of x

x = 3(- 1) + 13 = - 3 + 13 = 10

solution is (10, - 1 )

Answer:

[tex] {x}^{3} + 5 {x}^{2} - x - 5 \\ {x}^{2} (x + 5) - 1(x + 5) \\ (x + 5)( {x}^{2} - 1)[/tex]

Answer:

Step-by-step explanation:

[tex]\frac{14}{4}*\frac{33}{10}=\frac{7}{2}*\frac{33}{10}\\\\ =\frac{7*33}{2*10}\\\\=\frac{231}{20}\\\\=11\frac{11}{20}[/tex]

Answer:

they exceeded their goal by 668 cans.

Step-by-step explanation:

multiplying 524 by 7 you get 3668, then subtracting 3,000 from that you get 668.

Step-by-step explanation:

there is something wrong with what your write here as problem description.

either there is something missing in the main expression, or in the answer options.

given your nth-term expression 7n-2, none of the 4 answer options can fit.

so, I thought, maybe there was a typo.

the possible interpretations of the expression could be

7n - 2

7(n-2)

[tex] {7}^{n} - 2[/tex]

[tex] {7}^{n - 2} [/tex]

we know that

a1 = 1

a2 = either

a1 + 2 = 3

a1 - 2 = -1

a1 + 7 = 8

a1 - 7 = -6

so, we can eliminate both negative answer options, because they would cause only negative sequence elements, but the main expression (neither of the 4 possibilities) does not allow that.

but also none of the 4 possibilities of the expression delivers any of the 4 values for a2 as described above.

7×2 - 2 = 14 - 2 = 12

7(2-2) = 7×0 = 0

7² - 2 = 49 - 2 = 47

[tex] {7}^{2 - 2} = {7}^{0} = 1[/tex]

similar not for a3.

so, if I consider your answer options right, we have 4 possible arithmetic sequences:

1. 1, 3, 5, 7, 9, 11, 13, 15, ...

2. 1, -1, -3, -5, -7, -9, -11, -13, ...

3. 1, 8, 15, 22, 29, 36, 43, 50, ...

4. 1, -6, -13, -20, -27, -34, -41, ...

the nth term expression is for

a. an = 2n - 1

b. an = 2×(-n) + 3 = 2×(-n + 1) + 1

c. an = 7n - 6

d. an = 7×(-n) + 8 = 7×(-n + 1) + 1

so, please pick the right expression from this list, and then use the answer option with the same letter.

Answer:

D

Step-by-step explanation:

because 3x - 12y = 15 has only numbers that are divisible by 3 leaving just one single x term, and the other terms simply reduce their used numbers to still integer numbers (4 and 5).

this makes it easier to be used in the other equation.

Answer:

c) 25 cm^2

d) 52.5 cm^2

Step-by-step explanation:

5*2 = 1

10/2 = 5

40/2 = 20

20+5 = 25

This is just scratch work^

Step-by-step explanation:

Explanation is in the attachment

hope it is helpful to you

Answer:

[tex]-----------[/tex]

hope it helps...

have a great day!!

Answer:

$3

Step-by-step explanation:

Let c represent the cost of a box of cereal and let m represent the cost of a jug of milk.

Create a system of equations:

2c + m = 8.5

3c + 2m = 14

Solve by elimination by multiplying the top equation by -2:

-4c - 2m = -17

3c + 2m = 14

Add them together and solve for c:

-c = -3

c = 3

So, a box of cereal costs $3

A box of cereal cost $3 if two boxes and a jug of milk cost $8.50, and three boxes and two jugs of milk cost $14.00.

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

It is given that, two boxes of cereal and a jug of milk cost $8.50, and three boxes of cereal and two jugs of milk cost $14.00

Let c stand for the price of a box of cereal and m for the price of a milk jug.

The obtained system of equations is as follows,

2c + m = 8.5

3c + 2m = 14

Multiply the top equation by -2 to reach the solution by elimination:

-4c - 2m = -17

3c + 2m = 14

Put them all together to find c:

-c = -3

c = 3

Thus, a box of cereal cost $3 if two boxes and a jug of milk cost $8.50, and three boxes and two jugs of milk cost $14.00.

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Given:

The equation is:

[tex]3-2|0.5x+1.5|=2[/tex]

One solution of this equation is -2.

To find:

The another solution of the given equation.

Solution:

We have,

[tex]3-2|0.5x+1.5|=2[/tex]

It can be written as:

[tex]-2|0.5x+1.5|=2-3[/tex]

[tex]-2|0.5x+1.5|=-1[/tex]

Divide both sides by -2.

[tex]|0.5x+1.5|=0.5[/tex]

After removing the modulus, we get

[tex]0.5x+1.5=\pm 0.5[/tex]

Case I:

[tex]0.5x+1.5=0.5[/tex]

[tex]0.5x=0.5-1.5[/tex]

[tex]0.5x=-1[/tex]

Divide both sides by 0.5.

[tex]x=-2[/tex]

Case II:

[tex]0.5x+1.5=-0.5[/tex]

[tex]0.5x=-0.5-1.5[/tex]

[tex]0.5x=-2[/tex]

Divide both sides by 0.5.

[tex]x=-4[/tex]

One solution of the given equation is [tex]x=-2[/tex] and the another one is [tex]x=-4[/tex].

Therefore, the correct option is B.

Answer:

6 yds

Step-by-step explanation:

If we label the shorter side as x, the longer side can be represented as 2x + 2. Now, we can write an equation to model the situation. The area of a rectangle is the sides multiplied by each other:

84 = x(2x + 2)

84 = 2x^2 + 2x

Since all terms are divisible by two, we can divide both sides by it:

42 = x^2 + x

We can write the quadratic equation in standard form:

x^2 + x - 42 = 0

Now, we can factor. We are looking for numbers that multiply to -42 and add to 1. These numbers are 7 and -6. Factored the equation would be written as followed:

(x + 7)(x - 6) = 0

Using the zero-product property, we can obtain two equations and solve them:

x + 7 = 0

x  = -7

x - 6 = 0

x = 6

Since the side of a rectangle can't be negative, the answer must be 6 yds.

Answer:

Step-by-step explanation:

We'll start with going form exponential to radical, since it may be easier to follow. For example,

[tex]x^{\frac{4}{3}[/tex] can be written, in radical form, as

[tex]\sqrt[3]{x^4}[/tex]. What happens is that the denominator of the fraction serves as the index (the number that sits in the bend of the radical) and the numerator serves as the power on the variable (or number, if that's the case). Let's look at another one:

[tex]4^{\frac{2}{3}[/tex] becomes

[tex]\sqrt[3]{4^2}=\sqrt[3]{16}=\sqrt[3]{8*2}=2\sqrt[3]2}[/tex]

And you can go the other way with it. For example,

[tex]\sqrt[5]{x^4}[/tex] becomes

[tex]x^{\frac{4}{5}[/tex], etc. Get it?

Answer:

When you're given a problem in radical form, you may have an easier time if you You can rewrite every radical as an exponent by using the following property — the top ... For example, 643/2 is easier if you write it as (641/2)3 = 83 = 512 rather than (643)1/2,  Rewrite the entire expression using rational exponents.

Answer:

the side XY

Step-by-step explanation:

we know 2 angles in a triangle. but are 45 degrees.

that means the third angle Z is 180-45-45 = 90 degrees.

the side opposite of the largest angle is the longest side.

opposite of Z is the side XY.

Answer:

x = 3, x = 9

Step-by-step explanation:

When solving this problem, keep the general format of a logarithm in mind:

[tex]b^x=y\\log_b(y)=x[/tex]

Where, (b) represents the base, (x) is the exponent, and (y) is the evalutaor. Please note that others might use slightly different terminotoly than what is used in this answer.

One is given the following expression, and is asked to solve for the parameter (x);

[tex]log_5(x-4)=1-log_5(x-8)[/tex]

First, manipulate the exquestion such that all of the logarithmic expressions are on one side. Use inverse operations to do this.

[tex](log_5(x-4))+(log_5(x-8))=1[/tex]

Now use the Logarithmic Base Change rule to simplify. The Logarithmic Base Change rule states the following;

[tex]log_b(x)=\frac{log(x)}{log(b)}[/tex]

Remember, if no base is indicated in a logarithm, then the logarithm's base is (10). Apply the Logarithmic Base Change rule to this problem;

[tex]\frac{log(x-4)}{log(5)}+\frac{log(x-8)}{log(5)}=1[/tex]

Now remove the denominator. Multiply all terms in the equation by the least common denominator; ([tex]log(5)[/tex]) to remove it from the denominator on the left side.

[tex](\frac{log(x-4)}{log(5)}+\frac{log(x-8)}{log(5)}=1)*(log(5))[/tex]

[tex]log(x-4)+log(x-8)=log(5)[/tex]

All logarithms have the same base, the left side of the equation has the addition of logarithms. This means that one can apply the Logarithm product rule. The logarithm product rules the following;

[tex]log_b(x*y)=(log_b(x))+(log_b(y))[/tex]

This rule can be applied in reverse to simplify the left side of the equation. Rather than rewriting the product of logarithms as two separate logarithms being added, one can rewrite it as one logarithm getting multiplied.

[tex]log(x-4)+log(x-8)=log(5)[/tex]

[tex]log((x-4)(x-8))=log(5)[/tex]

Now used inverse operations to bring all of the terms onto one side of the equation:

[tex]log((x-4)(x-8))=log(5)[/tex]

[tex]log((x-4)(x-8))-log(5)=0[/tex]

Similar to the Logarithm product rule, the Logarithm quotient rule states the following;

[tex]log_b(x/y)=(log_b(x))-(log_b(y))[/tex]

One can apply this rule in reverse here to simplify the logarithms on the left side:

[tex]log((x-4)(x-8))-log(5)=0[/tex]

[tex]log(\frac{(x-4)(x-8)}{5})=0[/tex]

The final step in solving this equation is to use the Logarithm of (1) property. This property states the following:

[tex]log_b(1)=0[/tex]

When applying this property here, one can conclude that the evaluator must be equal to (1), therefore, the following statements can be made.

[tex]log(\frac{(x-4)(x-8)}{5})=0[/tex]

[tex]\frac{(x-4)(x-8)}{5}=1[/tex]

Inverse operations,

[tex]\frac{(x-4)(x-8)}{5}=1[/tex]

[tex](x-4)(x-8)=5[/tex]

[tex](x-4)(x-8)-5=0[/tex]

Simplify,

[tex](x-4)(x-8)-5=0[/tex]

[tex]x^2-12x+32-5=0[/tex]

[tex]x^2-12x+27=0[/tex]

Factor, rewrite the quadratic expression as the product of two linear expressions, such that when the linear expressions are multiplied, the result is the quadratic expression:

[tex]x^2-12x+27=0[/tex]

[tex](x-3)(x-9)=0[/tex]

Now use the zero product property to solve. The zero product property states that any number times (0) equals (0).

[tex]x=3,x=9[/tex]

Hello,

I suppose the question is solve for x.

[tex]\displaystyle log_5\ (a)=\dfrac{ln (a)}{ln (5)} \\\\log_5(x-4)=1-log_5(x-8)\\\\\dfrac{ln(x-4)}{ln(5)} =1- \dfrac{ln(x-8)}{ln(5)}\\\\ln(x-4)=ln(5)-ln(x-8)\\\\ln(x-4)+ln(x+8)=ln(5)\\\\ln((x-4)*(x-8))=ln(5)\\\\(x-4)*(x-8)=5\\\\x^2-12x+27=0\\\\\Delta=12^2-4*27=36=6^2\\\\x=9\ or\ x=3\\\\Sol=\{3,9\}\\[/tex]

For Moderators,

this is a mathematical resolution without any bla-bla sentences that you will easily find. (I can not do it sorry)

Answer:

5

Step-by-step explanation:

Have a phd in mathematics! Congrats on your first question!!!! Send me a brainlist :)

Answer:

8 - 4[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Given: [tex]\frac{26}{4 + \sqrt{3} }[/tex]

To express the given question in the form a + b[tex]\sqrt{3}[/tex], we first have to rationalize the denominator of the expression.

Rationalizing the denominator, we have;

[tex]\frac{26}{4 + \sqrt{3} }[/tex] * [tex]\frac{4 - \sqrt{3} }{4 - \sqrt{3} }[/tex]  = [tex]\frac{104 -26\sqrt{3} }{16 -4\sqrt{3} + 4\sqrt{3}- 3 }[/tex]

= [tex]\frac{104 - 26\sqrt{3} }{16 - 3}[/tex]

 = [tex]\frac{26(4 - \sqrt{3} }{13}[/tex]

= 2(4 - [tex]\sqrt{3}[/tex])

= 8 - 4[tex]\sqrt{3}[/tex]

The required form of the given question is therefore 8 - 4[tex]\sqrt{3}[/tex]

Answer:

yes

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

[tex]f(x) = {x}^{2} + 10 \\ \therefore \: f(2) = {2}^{2} + 10 \\ \therefore \: f(2) = 4 + 10 \\ \therefore \: f(2) = 14 \\ \\ g(x) = |x| \\ \therefore \:g(2) = |2| \\ \therefore \:g(2) = 2 \\ \\ f(2) + g(2) = 14 + 2 \\ \red{ \bold{(f + g)(2) = 14}}[/tex]

Step by step Explanation:

[tex]f(x) = x2 + 10g(x) = 1[/tex]

[tex](f + g)(2).[/tex]

Step 1

The equation is in standard form.

Step 2

Divide both sides by x.

Step 3

Dividing by x undoes the multiplication by x.

Step 4

Divide x 2 + 10 g x by x.

My Answer is.

Answer:

565.2cm³

Step-by-step explanation:

the radius= 6/2= 3 cm

the height= 20cm

the volume= 3.14× 3²×20

= 3.14×180= 565.2 cm³

Check the picture below.

Answer:

C. 16 mi.

Step-by-step explanation:

This situation forms a right triangle: the distances 32 miles south and 24 miles east are the legs, and the original southeast course is the hypotenuse.

Use the pythagorean theorem, a² + b² = c² to solve for c, the length of the southeast course.

a² + b² = c²

32² + 24² = c²

1600 = c²

40 = c

So, the southeast course is 40 miles long.

Find how many miles the pilot traveled on the alternate route:

32 + 24

= 56

Find the difference in extra miles:

56 - 40

= 16

So, the pilot was forced to fly 16 extra miles.

The correct answer is C. 16 mi.

Answer:

16

Step-by-step explanation:

On Edge 2022

Answer:

Step 3

Step-by-step explanation:

Leonardo is solving the equation 4 (x minus one-fifth) = 2 and two-thirds. His work is shown. Where is his error?

Given :

4(x - 1/5) = 2 2/3

Open the bracket

4x - 4/5 = 2 2/3

Add 4/5 to both sides

4x - 4/5 + 4/5 = 8/3 + 4/5

Lcm of 3 and 5 = 15

4x = (40 + 12) / 15

4x = 40/15 + 12/15

4x = 52/15

Multiply by 1/4

4x * 1/4 = 52/15 * 1/4

x = 52 / 60

x = 13 / 15

Hence, the error is in step 3

15/5 * 3 = 12

Rather ; Leonardo wrote 16

Answer:

Step-by-step explanation:

eq. of line with slope m and intercept 3 is

y=mx+3

∵ it passes through (10,53)

53=10m+3

10m=53-3=50

m=50/10=5

y=5x+3

so standard form of eq. is

5x-y+3=0

or

5x-y=-3