Someone help me with these math problems please !! (It is not obligatory to put the explanation so I save time and you will answer me more quickly please!

Answer:

d.{(8,1),(−4,1),(3,5),(0,4),(−1,2)} - function

Step-by-step explanation:

a.{(2,4),(2,6),(2,8),(2,10),(2,12)}

Each value of x goes to more than one value of y- this is not a function

b. {(−5,−4),(−4,−3),(−3,−2),(−4,−5),(−2,−1)}

The value of x at -4 goes to more than one value of y- this is not a function

c.{(0,3),(−6,8),(−3,5),(0,−3),(7,11)}

The value of x at 0 goes to more than one value of y- this is not a function

d.{(8,1),(−4,1),(3,5),(0,4),(−1,2)}

 Each value of x goes to only one value of y- this is a function

Answer:

B

Step-by-step explanation:

The correct answer is B

p = 6/11.

So we have a bag that contains 6 red marbles and 6 green marbles.

Then the total number of marbles that are in that bag is:

6 + 6  = 12

There are 12 marbles in the bag, and we assume that all marbles have the same probability of being randomly drawn.

Now we draw two marbles, we want to find the probability that one is red and the other is green.

The first marble that we draw does not matter, as we just want the second marble to be of the other color.

So, suppose we draw a green one in the first attempt.

Then in the second draw, we need to get a red one.

The probability of drawing a red one will be equal to the quotient between the red marbles in the bag (6) and the total number of marbles in the bag (12 - 1 = 11, because one green marble was drawn already)

Then the probability is:

p = 6/11.

Notice that would be the exact same case if the first marble was red.

Then we can conclude that the probability of getting two marbles of different colors is:

p = 6/11.

Answer:

In my opinion, I think a sum of 5.

Step-by-step explanation:

Since you are tossing two dice, you will likely get a higher value than 3.

How many ways can a 3 come up ?

1  -  2

2  -  1

How many ways can a 5 come up ?

1  -  4

2  -  3

3  -  2

4  -  1

There are four ways to roll a 5, but only two ways to roll a 3.

So a sum of 5 is more likely.

Answer:

a. The 1's are heavier than the x's. There isn't a whole number on top of the x's.

b. The equation would be 2x<9 because the 9 is greater(heavier) than the 2x. To continue to solve you would divide 2 by both sides. That would turn into x<9/2.

Step-by-step explanation:

Answer:

x = 25/2

y = 5

Step-by-step explanation:

The angles are corresponding angles and corresponding angles are equal when the lines are parallel

4x+8y = 18y

We also know that 18y +90 = 180 since they form a straight line

18y +90 = 180

Subtract 90 from each side

18y+90-90=180-90

18y = 90

y =5

Now we can solve for x

4x+8y = 18y

4x+8y-8y = 18y-8y

4x = 10y

Since y = 5

4x = 10(5)

4x = 50

4x/4 = 50/4

x = 25/2

x = 50/4

Answer:

x + y + z.

Step-by-step explanation:

x² + y² + 2xy - z²

= (x + y)^2 - z^2

This is the difference between 2 squares so the factors are:

(x + y + z) and (a + y - z).

Answer: The factors are (x+y+z) and (x+y-z)

In other words, it factors to (x+y+z)*(x+y-z)

=====================================================

Work Shown:

[tex]x^2 + y^2 + 2xy - z^2\\\\(x^2 + 2xy + y^2) - z^2\\\\(x+y)^2 - z^2\\\\(x+y+z)(x+y-z)\\\\[/tex]

Notes:

Answer:

156.25

Step-by-step explanation:

1/2 × b ×h =12.5

12.5 ×9 =156.25 hope you ace it

268×7(34-56)÷890

= -5159

Must click thanks and mark brainliest

Answer:

a).

[tex] \sin(2x) = \frac{1}{2 \sqrt{2} } \\ \\ 2x = { \sin }^{ - 1} ( \frac{1}{2 \sqrt{2} } ) \\ \\ 2x = 45 \degree[/tex]

since sine is in the 2nd quadrant, other angle = 180° - x:

[tex]2x = 45 \degree, \: 135 \degree[/tex]

we must make two rotations since it's a double angle:

[tex]2x = 45 \degree, \: 135\degree, \: 225\degree, \: 315\degree, \: 495\degree, \: 675\degree \\ [/tex]

divide each angle by 2:

[tex]x = 22.5\degree, \: 67.5\degree, \: 112.5\degree, \: 157.5\degree, \: 247.5\degree, \: 337.5\degree \\ [/tex]

Answer = {x: x = 22.5°, 67.5°, 112.5°, 157.5°, 247.5, 337.5°}

b).

[tex] \sin(3z) = - 0.42 \\ 3z = { \sin }^{ - 1} ( - 0.42) [/tex]

since ans is negative, we take the quadrants of cosine and tangent:

[tex]3z = 204.8\degree, \: 335.2\degree [/tex]

we make three rotations:

[tex]3z = 384.8\degree, \: 515.2\degree, \: 695.2\degree, \: 875.2\degree, \: 1055.2\degree, \\ [/tex]

answer is {z : z = 128.3°, 171.7°, 231.7°, 291.7°, 351.7°}

Answer:

11,580.00

Step-by-step explanation:

So basically all you need to do is round to the nearest 0.01 or the hundredths place. What you would do is round each place by so and you will eventually get the answer of 11,580.00

Hope this helps!!! Have a good rest of your day! :)

Answer:

True

Step-by-step explanation:

The powers must be arranged from highest to lowest for both the numerator and the denominator, so the terms will line up during the subtraction steps.

Answer:

Therefore, three consecutive integers that add up to 312 are 103, 104, and 105. We know our answer is correct because 103 + 104 + 105 equals 312 as displayed above

Answer:

102, 104, 106

Step-by-step explanation:

If each number is an even integer, then the one's place must be an even number like 2 4 6. 102 + 104 + 106 = 312

Answer:

maybe it's D ( not sure tho)

The answers are in the red rectangles with the work.

Let me know if something is unreadable.

Answer:

Hello,

remainder is 15/8

Step-by-step explanation:

[tex]\begin{array}{c|ccc|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&1&1&1\\x=\dfrac{1}{2} &&\dfrac{1}{2} &\dfrac{3}{4} &\dfrac{7}{8} \\---&---&---&---&---\\&1&\dfrac{3}{2}&\dfrac{7}{4}&\dfrac{15}{8}\\\end{array}\\\\\\x^3+x^2+x+1=(x-\dfrac{1}{2} )*(x^2+\dfrac{3}{2}x+\dfrac{7}{4}) +\dfrac{15}{8}[/tex]

Set up a ratio of height/ shadow

2.7/1.56 = x/38.25

Cross multiply:

1.56x = 103.275

Divide both sides by 1.56

X = 66.2

Round to nearest meter = 66

Answer: 66 meters

Answer:

A.  10(15) + 10n = $ made for babysitting

B. $270

Step-by-step explanation:

B. 10(15) + 10(12)

150 + 120 = $270

Answer:

(2,2)

Step-by-step explanation:

x=4-y

2 ( 4 - y )+ 3y= 12

2y = 12 -8

y= 2

substitute y in first eq. :

x=4 - 2

x= 2

Answer:

l think the answer is =C for this area of triangle

Answer:

3x^3y^7.

Step-by-step explanation:

8 * x^2 * y^3 * 3/8 * x * y^4

= 8 * 3/8 * x^2 * x * y^3 * y^4

= 3x^3y^7.

Answer:

3x^3y^7

Step-by-step explanation:

( 8 x^2 y^3) *( 3/8 x y^4)

Multiply the coefficients

8 * 3/8 = 3

Multiply the x terms

x^2*x = x^3

Multiply the y terms

y^3 * y^4 = y^(3+4) = y^7

Put them back together

3x^3y^7

Answer:

Option B

Step-by-step explanation:

You'll find one solution for this, so this system has one solution

Answer:

B.

Step-by-step explanation:

Just did it and got it correct

Answer:

6:150

Step-by-step explanation:

If you like my answer mark me brainliest

Answer:

1:25

Step-by-step explanation:

1.5m=150cm

6:150

1:25

1. 1/2

2. Y

3. 1 left 3 ups. (-1, 3)

Answer:

[tex] \frac{(c - 7)}{2} = - 5 \\ c - 7 = - 5 \times 2 \\ c - 7 = - 10 \\ c = - 10 + 7 \\ c = - 3[/tex]

I hope I helped you^_^

Answer:

d = 450 ft

Step-by-step explanation:

Hi there!

First, we can find the angle in the triangle at the point of the helicopter, the angle opposite [tex]d[/tex]. Subtract 48° from 90°:

90-48=42

Now, given that this is a right triangle and we have an angle and the side adjacent the angle, we can solve for [tex]d[/tex] by using the tangent ratio:

[tex]tan\theta=\displaystyle \frac{opposite}{adjacent}[/tex]

Replace θ with 42°, "opposite" with [tex]d[/tex], and "adjacent" with 500 ft:

[tex]tan(42)=\displaystyle \frac{d}{500}[/tex]

Multiply both sides by 500 to isolate [tex]d[/tex]:

[tex]500*tan(42)=d\\450=d[/tex]

Therefore, d = 450 ft when rounded to the nearest whole number.

I hope this helps!

Answer:

firstly find the gradient given by the equation

m=y2-y1/x2-x1

in this case x1 is -12,x2 is -17, y1 is -8 and y2 is-16

m=-16+8/-17+12

=-8/-5 or1.6

then use the equation

y-y1=m(x-x1)

y+8=1.6(x+12)

y+8=1.6x+19.2

y=1.6x+11.2

I hope this helps and sorry if it's wrong

Answer:

[tex]{ \bf{ \sec( \theta) = \frac{10}{6} }}[/tex]

Step-by-step explanation:

[tex]{ \boxed{ \bf{ \cos( \theta) = \frac{adjacent}{hypotenuse} }}}[/tex]

Adjacent = 6

Hypotenuse = 10

[tex]{ \sf{\sec( \theta) = \frac{1}{ \cos( \theta) } }}[/tex]

therefore:

[tex]{ \sf{ \sec( \theta) = \frac{hypotenuse}{adjacent} }} \\ \\ { \sf{ \sec( \theta) = \frac{10}{6} }}[/tex]