1 year is what fraction of a decade?
Answer:
It is 1/10
Step-by-step explanation:
One decade has 10 years
[tex]{ \sf{1 \: decade = 10 \: years}} \\ { \sf{ \frac{1}{10} \: decade = 1 \: year}}[/tex]
Answer:
10% , 1/10, or 10/100
Step-by-step explanation:
There are 10 years in a decade
1/10 represents the 1 year out of the 10!
In a group 40% like football ,70% like cricket and 30% like both games
Answer:
40%
Step-by-step explanation:
40+30+70=140
180-140= 40
Find NL. Not sure to to solve this.
Answer:
NL= 2 × HI
x+24 =2 × (X+16)
x+24=2x + 32
2x-x= 24-32
x= – 8
NL=x+24 = –8 +24= 16
So ; NL= 16
I hope I helped you^_^
A trapezoid has one base measuring 12', and the other measuring 13'8". What is the area in square feet if the height of the trapezoid is 9'4"?
(Remember for trapezoids A= (b1 + b2)/2 x h
Answer:
Step-by-step explanation:
buzhou一=12212+13。8.12+13.8=25.8 25.8x9.4=?242.52242.522
The area of the trapezoid is given by A = 121.26 feet²
What is a trapezoid?The Trapezoid is a 4 sided polygon. Two sides of the shape are parallel to each other and they are termed as the bases of the trapezoid. The non-parallel sides are known as the legs or lateral sides of a trapezoid.
There are three types of trapezoids , and those are given below:
a) Isosceles Trapezoid
b) Scalene Trapezoid
c) Right Trapezoid
The area of the Trapezoid is given by
Area of Trapezoid = ( ( a + b ) h ) / 2
where , a = shorter base of trapezium
b = longer base of trapezium
h = height of trapezium
Given data ,
Let the area of the trapezoid be represented as A
Now , the equation will be
Let the height of the trapezium be H = 9.4 feet
The shorter base of the trapezium a = 12 feet
The longer base of the trapezium b = 13.8 feet
Now , Area of Trapezoid = ( ( a + b ) h ) / 2
On simplifying the equation , we get
Area of Trapezium A = ( ( 13.8 + 12 ) 9.4 ) / 2
Area of Trapezium A = 121.26 feet²
Hence , the area of trapezium is 121.26 feet²
To learn more about area of trapezium click :
https://brainly.com/question/12221769
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please answer this question
Answer:
3
Step-by-step explanation:
[tex]log(3x^{3}) - log(x^{2}) = log(\frac{3x^{3}}{x^{2}})\\log(27) - log(x) = log(\frac{27}{x} )\\[/tex]
therefore,
[tex]\frac{3x^{3} }{x^{2} } = \frac{27}{x} \\3x=\frac{27}{x} \\3x^{2} =27\\x= +3\\x=-3[/tex]
however, since logarithms cannot have negative arguments, x can only be +3
i.e. log(-3) is impossible, and will return MATH ERROR on a calculator.
evaluate the expression
Step-by-step explanation:
13
[tex]3 + (20 \div 5) - ( {2}^{2}) [/tex]
[tex]3 + 4 - 4 = 3[/tex]
15
[tex] \frac{10 - {3}^{2} }{20 - (3 \times 4)} [/tex]
[tex] \frac{10 - 9}{20 - 12} [/tex]
[tex] \frac{1}{8} [/tex]
Help!
Which expression is equivalent?
On edge
Answer: Choice B
[tex]x^{1/8}y^{8}[/tex]
======================================================
Explanation:
The two rules we use are
[tex](a*b)^c = a^c*b^c[/tex]
[tex](a^b)^c = a^{b*c}[/tex]
When applying the first rule to the expression your teacher gave you, we can say that:
[tex]\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}[/tex]
Then applying the second rule lets us say
[tex]\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}[/tex]
Therefore,
[tex]\left(x^{1/4}y^{16}\right)^{1/2} = x^{1/8}y^{8}[/tex]
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In short, we just multiplied each exponent inside by the outer exponent 1/2.
So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.
