Solve using substitution.


6x + y = 7

8x + 9y = 17

(_,_)


Please help me I really need it

Answers

Answer 1
You take the first equation and make a value for y. So 6x + y =7 change it to :
y = -6x + 7
Now in the second equation replace the “y” with -6x +7 this is what it means to use substitution method . Your combined equation will now be :
8x + 9(-6x + 7) =17
Now do distributive property and you get :
8x + -54x +63 =17
Now combine like terms ;
-46x +63 =17
-46x =-46
x = 1
Now replace 1 for X value and we can get the value of Y .
Y=1
X=1

Related Questions

1 year is what fraction of a decade?

Answers

Answer:

It is 1/10

Step-by-step explanation:

One decade has 10 years

[tex]{ \sf{1 \: decade = 10 \: years}} \\ { \sf{ \frac{1}{10} \: decade = 1 \: year}}[/tex]

Answer:

10% , 1/10, or 10/100

Step-by-step explanation:

There are 10 years in a decade

1/10 represents the 1 year out of the 10!

evaluate the expression

Answers

Step-by-step explanation:

13

[tex]3 + (20 \div 5) - ( {2}^{2}) [/tex]

[tex]3 + 4 - 4 = 3[/tex]

15

[tex] \frac{10 - {3}^{2} }{20 - (3 \times 4)} [/tex]

[tex] \frac{10 - 9}{20 - 12} [/tex]

[tex] \frac{1}{8} [/tex]

Find NL. Not sure to to solve this.

Answers

Answer:

NL= 2 × HI

x+24 =2 × (X+16)

x+24=2x + 32

2x-x= 24-32

x= – 8

NL=x+24 = –8 +24= 16

So ; NL= 16

I hope I helped you^_^

X+24 =2(x+16)
X +24 = 2x +32
24-32= 2x-x
X = -8
NL = x+24
NL = -8+24
NL = 16

please answer this question​

Answers

Answer:

3

Step-by-step explanation:

[tex]log(3x^{3}) - log(x^{2}) = log(\frac{3x^{3}}{x^{2}})\\log(27) - log(x) = log(\frac{27}{x} )\\[/tex]

therefore,

[tex]\frac{3x^{3} }{x^{2} } = \frac{27}{x} \\3x=\frac{27}{x} \\3x^{2} =27\\x= +3\\x=-3[/tex]

however, since logarithms cannot have negative arguments, x can only be +3

i.e. log(-3) is impossible, and will return MATH ERROR on a calculator.

In a group 40% like football ,70% like cricket and 30% like both games

Answers

Answer:

40%

Step-by-step explanation:

40+30+70=140

180-140= 40

A trapezoid has one base measuring 12', and the other measuring 13'8". What is the area in square feet if the height of the trapezoid is 9'4"?

(Remember for trapezoids A= (b1 + b2)/2 x h

Answers

Answer:

Step-by-step explanation:

buzhou一=12212+13。8.12+13.8=25.8          25.8x9.4=?242.52242.522

The area of the trapezoid is given by A = 121.26 feet²

What is a trapezoid?

The Trapezoid is a 4 sided polygon. Two sides of the shape are parallel to each other and they are termed as the bases of the trapezoid. The non-parallel sides are known as the legs or lateral sides of a trapezoid.

There are three types of trapezoids , and those are given below:

a) Isosceles Trapezoid

b) Scalene Trapezoid

c) Right Trapezoid

The area of the Trapezoid is given by

Area of Trapezoid = ( ( a + b ) h ) / 2

where , a = shorter base of trapezium

b = longer base of trapezium

h = height of trapezium

Given data ,

Let the area of the trapezoid be represented as A

Now , the equation will be

Let the height of the trapezium be H = 9.4 feet

The shorter base of the trapezium a = 12 feet

The longer base of the trapezium b = 13.8 feet

Now , Area of Trapezoid = ( ( a + b ) h ) / 2

On simplifying the equation , we get

Area of Trapezium A = ( ( 13.8 + 12 ) 9.4 ) / 2

Area of Trapezium A = 121.26 feet²

Hence , the area of trapezium is 121.26 feet²

To learn more about area of trapezium click :

https://brainly.com/question/12221769

#SPJ2

Help!
Which expression is equivalent?
On edge

Answers

Answer: Choice B

[tex]x^{1/8}y^{8}[/tex]

======================================================

Explanation:

The two rules we use are

[tex](a*b)^c = a^c*b^c[/tex]

[tex](a^b)^c = a^{b*c}[/tex]

When applying the first rule to the expression your teacher gave you, we can say that:

[tex]\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}[/tex]

Then applying the second rule lets us say

[tex]\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}[/tex]

Therefore,

[tex]\left(x^{1/4}y^{16}\right)^{1/2} = x^{1/8}y^{8}[/tex]

-------------

In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

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