Line segment JM has endpoints with coordinates 0 and 25 on a number line. Points K and L are on segment JM. K has a coordinate of 5 and point L has a coordinate of 12. Find the probability that a point on JM is placed first on JL and a second point is not placed on KL.

Answer:

A

Step-by-step explanation:

-2x-4>8

-2x>12

-x>6

x<-6

Answer:

[tex]x < - 6[/tex] (first option)

Step-by-step explanation:

[tex] - 2x - 4 > 8[/tex]

[tex] - 2x > 8 + 4[/tex]

[tex] - 2x > 12[/tex]

[tex] = x < - 6[/tex]

Answer:

The answer Is A 1 1/5 < -2 2/5

Step-by-step explanation:

It says that this statement is true because 1 1/5 is to the left of -2 2/5 on the number line but it is actually to the right because -2 2/5 is negative while 1 1/5 is positive therefore making it larger and the correct statement would be that    1 1/5 > -2 2/5

Answer:

19/20 cups

Step-by-step explanation:

Add the amounts together

1/4 + 7/10

Get a common denominator of 20

1/4 *5/5   + 7/10 *2/2

5/20 + 14/20

19/20

Answer:

19/20

Step-by-step explanation:

find a common denominator then do the same with the numerator then add.

Step-by-step explanation:

Hi there!

According to the question;

nth term (tn) = 3n+8

a).

T1 = 3*1+8

= 11

b).

t7 = 3*7+8

= 29

c).

t14 = 3*14+8

= 50

Therefore, t1 = 11, t7 = 29, t14 = 50.

Hope it helps!

Answer:

11, 29, 50

Step-by-step explanation:

To find the appropriate term , substitute the term number into the rule, that is

(a) t₁ = 3(1) + 8 = 3 + 8 = 11

(b) t₇ = 3(7) + 8 = 21 + 8 = 29

(c) t₁₄ = 3(14) + 8 = 42 + 8 = 50

Answer:

you have $ 8

Step-by-step explanation:

cheque wrote ,=$10

and he threw =$2

then total $ left will be $8

please mark me brainleast

-8/10,-12/15,-16/20,-20/25,-24/30,etc.

The number sets that apply to -4/5 is the fractions.

Fractions represent the parts of a whole or collection of objects.

A fraction has two parts. The number on the top of the line is called the numerator and the number on the top of the line is called the denominator.

Now the given number is,

-4/5

-4/5 is a fraction. A fraction has two components numerator and denominator. This can positive or negative. Other example of fractions include 1/2,3/2,-5/2,-1/3.

The numbers who are not fractions are 0, 3, 6, 7.7.

Thus, the number sets that apply to -4/5 is the fractions.

To learn more about fractions:

brainly.com/question/445498

#SPJ2

I think the given figure will help you....

Step-by-step explanation:

with God everything is possible

explanation

because we go to church

Answer:

x =1.28

Step-by-step explanation:

4w=5.12

Divide each side by 4

4w/4 = 5.12/4

x =1.28

Answer:

199 pages

Step-by-step explanation:

The average number of words on the page is 300.  Because there are 59,540 words and 59540/300 = 198.46 (approximately), there are 199 pages in the book (because the 0.46 pages would be the last page).

Answer:

[tex]2\sqrt{2} \\2[/tex]

Step-by-step explanation:

[tex]\sqrt{8} = \sqrt{4*2} = \sqrt{4} * \sqrt{2} = 2*\sqrt{2} = 2\sqrt{2} \\\\\sqrt[3]{8} = \sqrt{2*2*2} = 2[/tex]

Answer:

I noticed that  [tex]\sqrt{8\\}[/tex] does not have 3 on it like the second one. And i wonder that the answers would be different from each other

[tex]2\sqrt{2}[/tex]

2

Step-by-step explanation:

Citydog Screen Printers received two orders for a t-shirt designed for a math symposium. The first order was for 40 shirts at a total cost of $295 and the second order was for an additional 80 shirts at a total cost of $565. Each order included a shipping and handling charge.

Then we have to writer a linear equation, for which I got: y-27/4x+25. We also had to find the cost per t-shirt, for which I got: $31.75. The last part I don't understand, however: fidn the shipping and handling charge.

The second word problem is:

It costs Consolidated Cereals Corporation $1050 to produce 100 boxes of corn flakes and $1250 to produce 500 boxes. I found the cost function: c(x)=1/2x+1000 but don't know how to determine the fixed cost and the variable cost per box (mainly because I have no idea what those are.)

Cost= m x+b

x is the cost per shirt, b is the handling charge

295=40m+b

565=80m+b

subtract the first equation from the second:

370=40x solve for m, the cost of each shirt. Then solve for b, put all that into y= mx+b

One the second question,

Cost= variable cost * n + Fixedcosts or

cost= n*v+F

1250=500v+f

1050=100v+f

subtract the second equation from the first

200=400v solve for v, and it is 1/2 dollar. Solve for f, the fixed cost, and it looks as if it is 1000 dollars.

Answer:

Option 3

Step-by-step explanation:

If he burned off 400 calories from 1500 consumed calories, he has 1100 consumed calories.  1900 - 1100 = 800 calories left to consume.

While option 2 also says no, it's not the right reason.  

The calories left to consume for the day is 800 calories.

No, 1,100 will cause him to exceed 1,900.

Given,

Jace has consumed 1,500 calories so far today.

He has also burned off 400 calories at the gym.

He would like to keep his daily calorie total to 1,900 calories per day.

We need to find how many calories he has left to consume for the day.

And see which option is the best choice.

We have,

Calories consumed in a day = 1500

Burned calories = 400

Calories to keep in a day = 1900

Find the Calories left

= 1500 - 400

= 1100

Find how many calories need to be consumed to keep 1900 calories.

= Calories needed to keep in a day - calories remaining after burned

= 1900 - 1100

= 800

We see that the calories left to consume is 800 calories.

So 1100 is not a viable solution. It will cause him to exceed 1,900.

Thus,

The calories left to consume for the day is 800 calories.

No, 1,100 will cause him to exceed 1,900.

Learn more about finding the calories needed to consumed to keep daily calories here:

https://brainly.com/question/12862654

#SPJ2

Answer:

[tex]f'(x)=1+\ln x[/tex]

Step-by-step explanation:

[tex]f'(x)[/tex] is notation for the first derivative of [tex]f(x)[/tex].

Recall the product rule:

[tex](f\cdot g)'=f'\cdot g+g'\cdot f[/tex]

Therefore, we have:

[tex]\displaystyle \frac{d}{dx}(x\ln x)=\frac{d}{dx}(x)\cdot \ln(x)+\frac{d}{dx}(\ln x)\cdot x[/tex]

Note that:

[tex]\displaystyle \frac{d}{dx}(x)=1,\\\\\frac{d}{dx}(\ln x)=\frac{1}{x}[/tex]

Simplify:

[tex]\displaystyle \frac{d}{dx}(x\ln x)=1\cdot \ln x+\frac{1}{x}\cdot x, \\\\\frac{d}{dx}(x\ln x)= \ln x+1=\boxed{1+\ln x}[/tex]

The derivative is:

[tex] \bold{f(x) \: = \: x \: \times \: (In(x))}[/tex]

[tex] \bold{f'(x) \: = \: \frac{d}{dx} (x \: \times \: In(x))}[/tex]

[tex] \bold{f'(x) \: = \: \frac{d}{dx} (x) \: \times \: In(x) \: + \: x \: \times \: \frac{d}{dx} (In(x))}[/tex]

[tex] \bold{f'(x) \: = \: 1In(x) \: + \: x \: \times \frac{1}{x} }[/tex]

[tex] \bold{f'(x) \: = \: In(x) \: + \: x \: \times \: \frac{1}{x} }[/tex]

[tex] \boxed{ \bold{f'(x) \: = \: In(x) \: + \: 1}}[/tex]