Solve the inequality. |X+19|<7

Answer:

B.18. 44 miles

Step-by-step explanation:

We are given that

Distance between A and B=8 miles

Angle B=Angle BCQ=40 degree (Alternate interior angles)

Angle ACB=180-Angle ACP-Angle BCQ

Angle ACB=180-40-40=100 degree

In triangle ABC

Angle A+ Angle B +Angle C=180 degree using sum of angles of triangle property

Substitute the values

[tex]\angle A+40+100=180[/tex]

[tex]\angle A+140=180[/tex]

[tex]\angle A=180-140[/tex]

[tex]\angle A=40[/tex] degree

Angle A=Angle B

When two angles are equal of a triangle then the triangle is isosceles triangle.

Therefore, triangle ABC is an isosceles triangle.

[tex]\implies BC=AC [/tex]

Now, Sine law

[tex]\frac{a}{sin A}=\frac{b}{sin B}=\frac{c}{sin C}[/tex]

Using the sine law

[tex]\frac{BC}{sin 40}=\frac{AB}{sin 100}[/tex]

[tex]\frac{BC}{sin 40}=\frac{8}{sin 100}[/tex]

[tex]BC=\frac{8\times sin40}{sin 100}[/tex]

BC=5.22

AC=BC=5.22 miles

Now, total distance covered by the boat=AB+BC+AC

Total distance covered by the boat=8+5.22+5.22=18.44 miles

Hence, option B is correct.

The question is incomplete. The complete question is :

The breaking strengths of cables produced by a certain manufacturer have a mean of 1900 pounds, and a standard deviation of 65 pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, 150 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1902 pounds. Assume that the population is normally distributed. Can we support, at the 0.01 level of significance, the claim that the mean breaking strength has increased?

Solution :

Given data :

Mean, μ = 1900

Standard deviation, σ = 65

Sample size, n = 150

Sample mean, [tex]$\overline x$[/tex] = 1902

Level of significance = 0.01

The hypothesis are :

[tex]$H_0 : \mu = 1900$[/tex]

[tex]$H_1 : \mu > 1900$[/tex]

Test statics :

We use the z test as the sample size is large and we know the population standard deviation.

[tex]$z=\frac{\overline x - \mu}{\sigma / \sqrt{n}}$[/tex]

[tex]$z=\frac{1902-1900}{65 / \sqrt{150}}$[/tex]

[tex]$z=\frac{2}{5.30723}$[/tex]

[tex]$z=0.38$[/tex]

Finding the p-value:

P-value = P(Z > z)

             = P(Z > 0.38)

             = 1 - P(Z < 0.38)

From the z table. we get

P(Z < 0.38) = 0.6480

Therefore,

P-value = 1 - P(Z < 0.38)

            = 1 - 0.6480

             = 0.3520

Decision :

If the p value is less than 0.01, then we reject the [tex]H_0[/tex], otherwise we fail to reject  [tex]H_0[/tex].

Since the value of p = 0.3520 > 0.01, the level of significance, then we fail to reject  [tex]H_0[/tex].

Conclusion :

At a significance level of 0.01, we have no sufficient evidence to support that the mean breaking strength has increased.

9514 1404 393

Answer:

  2xy^2

Step-by-step explanation:

The terms are "like" so can be combined. It might be helpful to think of this as an application of the distributive property.

  -3xy^2 +5xy^2 = (-3 +5)xy^2 = 2xy^2

Answer:

RA = 24

Step-by-step explanation:

Since the triangle is isosceles ( 2 equal sides ) , then LU is a perpendicular bisector , so

AU = RU , that is

4r = 18 - 2r ( add 2r to both sides )

6r = 18 ( divide both sides by 6 )

r = 3

Then

RA = 18 - 2r + 4r = 18 + 2r = 18 + 2(3) = 18 + 6 = 24

Answer:

-37 subtract -53

-53 subtract -37 = -16

Step-by-step explanation:

Answer:

The answer is 16

Step-by-step explanation:

-37-(-53) = -37 + 53

You can flip it to 53 - 37 which equals 16.

Hope this helps! :)

*Heads up you can also search this up* ^^

Answer:

-3

Step-by-step explanation:

12x + 1 - 2(y + 2)

=> 12x + 1 - 2y - 4

=> 12x - 3 - 2y

Answer:

-3

Step-by-step explanation:

12x+1-2y-4

12x+1-2y-4

12x-2y-3

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

Answer:

hi

Step-by-step explanation:

Given: The series ∑cₙ[tex]9^n[/tex] is convergent

To find: The series ∑cₙ[tex](-3)^n[/tex] is convergent or not.

Solution: If the radius of convergence R the we can conclude that R≥4

So, the series will converge as -3<9.

Answer:

I think this one is B

Step-by-step explanation:

Answer:

90 cause 90 times 10 is 900 and 10% times 10 is 100%

Step-by-step explanation:

Answer: 90

Step-by-step explanation: 900 × .10 = 90

Answer:

x1 = 2

x2 = 3

Step-by-step explanation:

[tex]x_1=\frac{D_{x1}}{D}\\\\x_2=\frac{D_{x2}}{D}[/tex]

Here D is the coefficient matrix.

Hence

[tex]x_1=\frac{6}{3}\\x_1=2[/tex]

&

[tex]x_2=\frac{9}{3}\\x_2=3[/tex]

Answer:

162 t-shirts, 324 posters

Step-by-step explanation:

Assuming they only sold t-shirts and posters, you can find the amount of t-shirts sold by dividing 486 by 3, or multiplying it by 1/3. This equals 162. This is because one third were t-shirts. To find the rest you just subtract 162 from the total of 486, or multiply 162 by 2. (since you already know the amount of 1/3, 2/3 is double that.)

Answer:

$2,145 ; $147 ; 14 months

Step-by-step explanation:

Given that :

The cash price, that is, the amount that would be paid if customer is to pay the entire amount item is worth at once = $1998

Monthly payment = $143

Period = 15 months

The total installment price ; total amount paid on a monthly pay for 15 months :

(monthly payment * period)

($143 * 15)

= $2,145

The carrying charge :

Installment pay - Cash amount

$(2,145 - 1,998)

= $147

The number of month needed to save at Monthly rate to buy item at it's cash price :

Cash price / monthly payment

$1998 / $143

= 13.97

= 14 months

Answer:

$370,881

Step-by-step explanation:

firstly we we multiply 1,5% by 2yrs. the answer we get is 3,0%. we then multiply 3 % by $123,627 and get $370,881

If Lisa bought a house The value of the house increased by 1.5% each year for 2 years.  The value of the house was £123,627. The initial amount of the house is  95120.7.

Percentage, a relative value indicating hundredth parts of any quantity.

Given,

Lisa bought a house The value of the house increased by 1.5% each year for 2 years

By the end of 2 years, the value of the house was £123,627.

A=P(1+rt)

A is the final amount,

r is rate of interest

t is the time

P is principle amount.

123,627=P(1+1.5/100 (2))

123657=P(1+0.15(2))

123657=P(1+0.3)

123657=1.3P

Divide both sides by 1.3

P=95120.7

The initial amount of the house when Lisa bought is 95120.7

To learn more on Percentage click:

https://brainly.com/question/28269290

#SPJ2

Answer:

There are 256 pairs in all.

Answer:

multiplication by -1 will reflect over the x-axis

multiplication by a positive number will "scale" or "stretch" the function

Step-by-step explanation:

Answer:

c) tan

Step-by-step explanation:

For the 63-deg angle, YZ is the opposite leg. The unknown side, AY, is the adjacent leg. The trigonometric ratio that relates the opposite and adjacent legs is the tangent.

Answer: c) tan

Flip the -1/4, cross deduct and should get 3/2

Answer:

It might be 3/2 or 1 and 1/2.

Answer:

The correct answer is "[tex]0.300993e^{-0.300993x}[/tex]".

Step-by-step explanation:

According to the question,

⇒ [tex]P(x>4)=0.3[/tex]

We know that,

⇒ [tex]P(X > x) = e^{(-\lambda\times x)}[/tex]

⇒     [tex]e^{(-\lambda\times 4)} = 0.3[/tex]

∵ [tex]\lambda = 0.300993[/tex]

Now,

⇒ [tex]f(x) = \lambda e^{-\lambda x}[/tex]

By putting the value, we get

           [tex]=0.300993e^{-0.300993x}[/tex]

If we simplify, both Joe and Hope factored the polynomial correctly but Joe didn't complete it fully.

The first binomial can be further factored:

The quadratic expression needs to have two roots in order to be factored as two binomials.

The discriminant must be positive or zero:

We have a = 3, b = k, c = -8

So we get following inequality:

Since k² is positive for any value of k, the solution is any value of k:

Hope this attachment helps you.

Answer: Power of a quotient

Step-by-step explanation:

The power of quotient basically is:

[tex](\frac{P}{q})^{3} =\frac{P^3}{q^3}[/tex]

I can't see the diagram sorry.

Step-by-step explanation:

Is there supposed to be a picture attached?

Answer:

5

Step-by-step explanation:

When a square root of an expression is multiplied by itself, the result is that expression

5=x

Answer:

about 7.3 years

Step-by-step explanation:

[tex]8600=5000(1+\frac{.075}{4})^{4*t}\\1.72=(1.01875)^{4t}\\log_{1.01875}1.72=4t\\29.19428479=4t\\t=7.298571198[/tex]

Answer:

The answer is t=7.3

Answer:

z = (2xy-x)

Step-by-step explanation:

Let the first number be x and the other number is z.

According to question,

The average of two number is xy i.e.

[tex]\dfrac{x+z}{2}=xy\\\\x+z=2xy\\\\z=2xy-x[/tex]

So, the value of z is (2xy-x) i.e. the other number is (2xy-x).

Answer:

[tex]y = \frac{5ct}{3b}[/tex]

Step-by-step explanation:

[tex]\frac{5t}{4y} =\frac{3b}{4c}[/tex]

1. start by multiplying y to both sides:

y × [tex]\frac{5t}{4y} =\frac{3b}{4c}[/tex] × y

[tex]\frac{5t}{4} =\frac{3b}{4c}y[/tex]

2. divide both sides by [tex]\frac{3b}{4c}[/tex]

[tex]\frac{5t}{4}/\frac{3b}{4c} =\frac{3b}{4c}y/\frac{3b}{4c}[/tex]

[tex]y = \frac{5ct}{3b}[/tex]

That's a question about percentage.

Let's imagine that we want to know how much is 90% of 200. To do this calculation, we should multiply 200 by 90 and then divide the result by 100. We do that because 90% is the same thing that [tex]\frac{90}{100} =0,9[/tex]. So, 90% of 200 is equal to:

[tex]\frac{200\cdot90}{100} =\\\\\frac{18000}{100} =\\\\180[/tex]

Now, imagine that you would like to know how much is 100% of 999. First, we multiply 999 by 100 and divide the result by 999. So, 100% of a number is equal to itself. That's a very important information, because it's possible to understand this:

Now, we can solve our problem! \o/

The options that the percentage is less than 100% are: 35% of 300, 62% of 182 and 89% of 525. Therefore, their answers will be less than the original number.

And, the option that the percentage is greater than 100% are: 250% of 18, 300% of 250 and 120% of 72. So, their answers will be greater than the original number.

On the image, you can see the answer in a table.

I hope I've helped. ^^

Enjoy your studies! \o/

Answer:

A) [ 7/3,  (-7/9)(x/2),  7/27(x-2)^2,  (-7/81)(x-2)^3 ]

B) attached below

Step-by-step explanation:

A)  Using the definition of a Taylor series

The first four nonzero terms of the series for f(x) = 7/ (1 +x), a = 2

= [ 7/3,  (-7/9)(x/2),  7/27(x-2)^2,  (-7/81)(x-2)^3 ]

attached below is the detailed solution

B) Finding Maclaurin series for f(x)

f(x) = e^-5x

attached below

Associated radius of convergence = ∞  ( infinity )

Answer:

Step-by-step explanation:

Let take a look at the given function y = 4x - 1 whose point is located between (1,3) and (4,15) on the graph.

Here, the function of y is non-negative. Now, expressing y in terms of x in y = 4x- 1

4x = y + 1

[tex]x = \dfrac{y+1}{4}[/tex]

[tex]x = \dfrac{1}{4}y + \dfrac{1}{4}[/tex]

By integration, the required surface area in the revolve is:

[tex]S = \int^{15}_{ 3} 2 \pi g (y) \sqrt{1+g'(y^2) \ dy }[/tex]

where;

g(y) = [tex]x = \dfrac{1}{4}y + \dfrac{1}{4}[/tex]

∴

[tex]S = \int^{15}_{ 3} 2 \pi \Big( \dfrac{1}{4}y + \dfrac{1}{4}\Big) \sqrt{1+\Bigg(\Big( \dfrac{1}{4}y + \dfrac{1}{4}\Big)'\Bigg)^2 \ dy }[/tex]

[tex]S = \dfrac{1}{2} \pi \int^{15}_{ 3} (y+1) \sqrt{1+\Bigg(\Big( \dfrac{1}{4}\Big ) \Bigg)^2 \ dy } \\ \\ \\ S = \dfrac{1}{2} \pi \int^{15}_{ 3} (y+1) \dfrac{\sqrt{17}}{4} \ dy[/tex]

[tex]S = \dfrac{\sqrt{17}}{8} \pi \int^{15}_{ 3} (y+1) \ dy[/tex]

[tex]S = \dfrac{\sqrt{17} \pi}{8} (\dfrac{1}{2}(y+1)^2)\Big|^{15}_{3} \\ \\ S = \dfrac{\sqrt{17} \pi}{8} (\dfrac{1}{2}(15+1)^2-\dfrac{1}{2}(3+1)^2 ) \\ \\ S = \dfrac{\sqrt{17} \pi}{8} *120 \\ \\\mathbf{ S = 15 \sqrt{17}x}[/tex]