solve the inequality.. help me out asap plss ​

Solve The Inequality.. Help Me Out Asap Plss

Answers

Answer 1

Answer:

[tex]x<\frac{6}{5}[/tex]

Refer to picture for number line

Step-by-step explanation:

To solve this inequality, we want to isolate the variable. We can do this my getting like terms onto one side

[tex]6x-7<2-\frac{3x}{2}[/tex]       [add both sides by 7]

[tex]6x<9-\frac{3x}{2}[/tex]             [add both sides by 3x/2]

[tex]6x+\frac{3x}{2}<9[/tex]             [multiply both sides by 2]

[tex]12x+3x<18[/tex]          [add]

[tex]15x<18[/tex]                  [divide both sides by 15]

[tex]x<\frac{18}{15}[/tex]                     [simplify]

[tex]x<\frac{6}{5}[/tex]

Now that we have out inequality, we want to graph it. Since we know that [tex]x<\frac{6}{5}[/tex], that means we have an open circle. Since x is less than, the arrow would be pointing left.

Solve The Inequality.. Help Me Out Asap Plss

Related Questions

which relation is a function?

Answers

Answer:

Choice A.

Step-by-step explanation:

Every other choice has multiple of the same x-values that have different corresponding y-values.

Y= 2x - 3; Y = (1/2)x - 4

Answers

Answer:

(-2/3, -13/3)

Step-by-step explanation:

Given the expressions;

[tex]y= 2x - 3\\y = (\frac{1}{2} )x - 4[/tex]

Equating both expressions;

[tex]y=y\\2x-3=\frac{1}{2}x-4\\[/tex]

Collect the like terms:

[tex]2x-\frac{1}{2}x=-4+3\\\frac{3x}{2}=-1\\3x=-2\\x=\frac{-2}{3}[/tex]

Substitute [tex]x=\frac{-2}{3}[/tex] into any of the expressions to get 'y'

[tex]Recall\ y= 2x-3\\y=2(\frac{-2}{3} )-3\\y=\frac{-4}{3}-3\\y=\frac{-4-9}{3} \\y=\frac{-13}{3}[/tex]

Hence the solution to the equation is (-2/3, -13/3)

Find x and explain how you found x

Answers

Answer:

x=60

Step-by-step explanation:

There are different ways to find x but this is what I found easiest.

To solve first note that AOD and CFB are vertical angles; this means that they are congruent. AOD consists of two angles with the measurements of 90 and x. CFB consists of two angles with the measurements of 30 and 2x. So, to find x set add the adjacent angles and set them equal to the other pair of angles. The equation would be [tex]90+x=30+2x[/tex]. First, subtract x from both sides; this makes the equation [tex]90=30+x[/tex]. Then, subtract 30 from both sides. This gives the final answer, x=60.

Use the figure to find x.

Answers

Answer:

[tex] x = 8.57[/tex]

Step-by-step explanation:

Here two triangles are given to us , which are attached to each other . Here we can use the concept of Trigonometry to find out the value of x. The angles of the triangle are 60° and 45° . Let the common side be p .

Step 1: Use the ratio of tan in upper triangle

[tex]\rm\implies tan60^o = \dfrac{perpendicular}{base} [/tex]

Substitute the respective values ,

[tex]\rm\implies \sqrt3=\dfrac{p}{7} [/tex]

Cross multiply ,

[tex]\rm\implies p = 7\sqrt3 [/tex]

Step 2: Use the ratio of cos in lower triangle

[tex]\rm\implies cos45^o = \dfrac{base}{hypontenuse} [/tex]

Substitute the respective values ,

[tex]\rm\implies \dfrac{1}{\sqrt2}=\dfrac{x}{7\sqrt3} [/tex]

Cross multiply ,

[tex]\rm\implies x= \dfrac{7\sqrt3}{\sqrt2} [/tex]

Put the approximate values of √2 and √3

[tex]\rm\implies x= \dfrac{7\times 1.732}{1.414} [/tex]

This equals to ,

[tex]\rm\implies \boxed{\blue{\rm \quad x = 8.57\quad}} [/tex]

Hence the value of x is 8.57 .

Answer:

The value of x is [tex]\frac{7\sqrt{6}}{2}[/tex]

Solution given:

AB=7

BD=x

<BAC=60°

<DBC=45°

In right angled triangle ABC

Tan 60°=opposite/adjacent

Tan 60°=BC/AB

Substitute value

[tex]\sqrt{3}[/tex]=[tex]\frac{BC}{7}[/tex]

BC=[tex]7\sqrt{3}[/tex]

again

againIn right angled triangle BCD

againIn right angled triangle BCDUsing Cos angle

Cos 45=adjacent/hypotenuse

Cos45°=BD/BC

Substituting value

[tex]\frac{\sqrt{2}}{2}=\frac{x}{7\sqrt{3}}[/tex]

Doing criss cross multiplication

[tex]\frac{\sqrt{2}}{2}*7\sqrt{3}=x[/tex]

x=[tex]\frac{7\sqrt{6}}{2}[/tex]

what is the sum of the angles of a triangle?

Answers

THE SUM OF ANGLES OF TRIANGLE IS 180 DEGREE.

Point P is plotted on the coordinate grid. If point S is 12 units to the left of point P, what are the coordinates of point S? On a coordinate grid from negative 12 to positive 12 in increments of 2, a point P is plotted at the ordered pair 6, negative 4. (6, −16) (−6, −16) (−6, −4) (6, 4)

Answers

9514 1404 393

Answer:

  (−6, −4)

Step-by-step explanation:

Translating a point 12 units left subtracts 12 from its x-coordinate.

  P(6, -4) +(-12, 0) = S(-6, -4)

The firm has bonds with par value of 10,000,000 VND, coupon rate of 11%, annual interest payment, and the remaining maturity period is 07 years. If the bond's interest rate and current risk level have a return rate of 12%, what price should company C sell the bond in the present?

a.
10,000,000

b.
14,152,000

c.
12,053,000

d.
11,150,000

Answers

It should be letter b

find the length of y, assume the triangles are similar

Answers

Answer:

y = 3.6

Step-by-step explanation:

Since the triangles are similar, we can write the following proportion:

[tex]\frac{y}{6.3} = \frac{2.4}{4.2} = \frac{2.8}{x}[/tex]

We don't need the fraction on the left because it is not necessary to solve for y. Instead, we can simplify the rest:

[tex]\frac{y}{6.3} = \frac{2.4}{4.2}[/tex]

[tex]\frac{y}{6.3} = \frac{0.4}{0.7}[/tex]

Now, we can cross-multiply:

[tex]0.7y = 6.3 * 0.4[/tex]

[tex]0.7y = 2.52[/tex]

[tex]y = 3.6[/tex]

Given:

The length of both triangle are in the same ratio,

2.4:2.8:y = 4.2:x:6.3

To find:

The value of 'y'

Steps:

Since 2.4 : y = 4.2 : 6.3, we can find the value of 'y'

    2.4/y = 4.2/6.3

2.4 * 6.3 = 4.2 * y

     15.12 = 4.2y

15.12/4.2 = y

        3.6 = y

            y = 3.6

Therefore, the value of y is 3.6

Happy to help :)

If you want help, feel free to ask

7/18 - 1/3 , 1/2 - 1/5 - 1/10 and 3 1/2 - 2 5/9 please help thank you ​

Answers

Answer:

Step-by-step explanation:

7/18=7/18

it cant be divided agian

1/3=1/3

it cant be divded agian

1/5=1/5

it cant be divded agian

1/10=1/10

it cant be divded agian

3 1/2=3/2

2 5/9 =10/9

i am not sure if this is what you wanted ...

Suppose the daily customer volume at a call center has a normal distribution with mean 5,500 and standard deviation 1,000. What is the probability that the call center will get between 4,800 and 5,000 calls in a day

Answers

Answer:

0.0665 = 6.65% probability that the call center will get between 4,800 and 5,000 calls in a day.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 5,500 and standard deviation 1,000.

This means that [tex]\mu = 5500, \sigma = 1000[/tex]

What is the probability that the call center will get between 4,800 and 5,000 calls in a day?

This is the p-value of Z when X = 5000 subtracted by the p-value of Z when X = 4800. So

X = 5000

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5000 - 5500}{1000}[/tex]

[tex]Z = -0.5[/tex]

[tex]Z = -0.5[/tex] has a p-value of 0.3085.

X = 4800

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{4800 - 5500}{1000}[/tex]

[tex]Z = -0.7[/tex]

[tex]Z = -0.7[/tex] has a p-value of 0.2420.

0.3085 - 0.2420 = 0.0665

0.0665 = 6.65% probability that the call center will get between 4,800 and 5,000 calls in a day.

answer this question

Answers

Answer:

(-2, 13) (-1,8) (0, 5) (1, 4) (2, 5) (3, 8)

(2.4 , 6) or (-0.4, 6)

Step-by-step explanation:

Graph y = 6 on top of y = [tex]x^{2}[/tex] -2x + 5 and use the points where the two lines meet.

The delivery man checks his route for deliveries.
The map has a scale of 1:250,000.
The distance between the bakery and his last delivery is 35 cm
What is the actual distance?
km.

Answers

9514 1404 393

Answer:

  87.5 km

Step-by-step explanation:

Actual distance is 250000×35 cm = 87.5×10^5 cm = 87.5 km

_____

There are 100 cm in 1 m, and 1000 m in 1 km, so 100,000 cm = 10^5 cm in 1 km

i need the answer no explanation

Answers

Answer:

the answer is option D because it cant be division or multiplication and minus does not work

Answer:

log 1/9 * log k

Step-by-step explanation:

[tex]\frac{1}{9} /k[/tex] = 1/9 * k/1 = 1/9 * k

1289 +(-1236) + (2434) =
0 -1431
O 2345
O 2487
0 -1956

Answers

Answer:

This answer is 2487

which will be the third one

Hope this help

Can somebody help me to solve this?

Answers

Answer:

B

Step-by-step explanation:

Given

[tex]\sqrt{ab}[/tex] = [tex]\sqrt{bc}[/tex] ( square both sides )

ab = bc ( divide both sides by b ) , then

a = c

Given

[tex]\sqrt{ac}[/tex] = [tex]\sqrt{4c^4}[/tex] ( square both sides )

ac = 4[tex]c^{4}[/tex] ( but a = c) , so

4[tex]c^{4}[/tex] = c² ( subtract c² from both sides )

4[tex]c^{4}[/tex] - c² = 0 ← factor out c² from each term on the left side

c²(4c² - 1) = 0 ← 4c² - 1 is a difference of squares

c²(2c - 1)(2c + 1) = 0

Equate each factor to zero and solve for x

c² = 0 ⇒ c = 0

2c - 1 = 0 ⇒ 2c = 1 ⇒ c = [tex]\frac{1}{2}[/tex]

2c + 1 = 0 ⇒ 2c = - 1 ⇒ c = - [tex]\frac{1}{2}[/tex]

But c > 0 , then c = [tex]\frac{1}{2}[/tex] → B

Real life problem for (-10+-2)=12

Answers

Hello!

[tex]\bf [ (-10) + (-2) ] = 12 [/tex]

[tex]\bf [ (-10) - 2 ] = 12 [/tex]

[tex]\bf -10 - 2 = 12 [/tex]

[tex]\bf -12 ≠ 12 [/tex]

Answer: Wrong

Good luck! :)

Use the distributive property to remove the parentheses.
-5(6u - 4w-2)

Answers

Answer:

-30u + 20w + 10

Step-by-step explanation:

Answer:

-30u+20w+10

Step-by-step explanation:

multiple each term inside the parenthesis by -5. remember negative times negative = positive

plzz help with this question

Answers

Answer: 51 liters of fuel are required

Step by step: start by seeing how many times 476 can go into 1428

(1428/476=3)

Then take your sum of that and multiply it by 17 since that’s the number that correlates with 476

(17x3=51) therefore your answer is 51 liters

Evaluate the expression when a=-7 and y=3 3y-a

Answers

Answer:

3y-a

3.3-7

9-7

2

Step-by-step explanation:

first we have to do multiply by replacing the value of y and the subtract by using the value of a.

Hope this will be helpful for you

6. The area of a rectangular sheet of paper is 300 cm squared. The length is 5 cm more than the width
a) If the width of the rectangle is x cm, state an expression for the length of the rectangle.
b) Write and algebraically solve a quadratic equation to determine the length and
width of the rectangle.

Answers

Answer:

Step-by-step explanation:

width = x

length= x + 5

a)  x + 5

b) x * (x+5) = 300

x^2 + 5x = 300

x^2 + 5x - 300 = 0

Δ = 25 + 1200 = 1225

width = (-5 + 35)/2 = 15 cm

lenght = 15 + 5 = 20 cm

Answer:

a) length = x + 5  

b) [tex]x^{2}[/tex] + 5x - 300 = 0

Step-by-step explanation:

x = width

x + 5 = length

(x)(x + 5) = 300

[tex]x^{2}[/tex] + 5x = 300

[tex]x^{2}[/tex] + 5x - 300 = 0

(x+20)(x-15)

x = -20 or x = 15  ( disregard the -20. measurements can't be negative)

width = 15

length = x+ 5 =  15+5 = 20

Construct the confidence interval for the population standard deviation for the given values. Round your answers to one decimal place. n=21 , s=3.3, and c=0.9

Answers

Answer:

The correct answer is "[tex]2.633< \sigma < 4.480[/tex]".

Step-by-step explanation:

Given:

n = 21

s = 3.3

c = 0.9

now,

[tex]df = n-1[/tex]

    [tex]=20[/tex]

⇒ [tex]x^2_{\frac{\alpha}{2}, n-1 }[/tex] = [tex]x^2_{\frac{0.9}{2}, 21-1 }[/tex]

                  = [tex]31.410[/tex]

⇒ [tex]x^2_{1-\frac{\alpha}{2}, n-1 }[/tex] = [tex]10.851[/tex]

hence,

The 90% Confidence interval will be:

= [tex]\sqrt{\frac{(n-1)s^2}{x^2_{\frac{\alpha}{2}, n-1 }} } < \sigma < \sqrt{\frac{(n-1)s^2}{x^2_{1-\frac{\alpha}{2}, n-1 }}[/tex]

= [tex]\sqrt{\frac{(21-1)3.3^2}{31.410} } < \sigma < \sqrt{\frac{(21.1)3.3^2}{10.851} }[/tex]

= [tex]\sqrt{\frac{20\times 3.3^2}{31.410} } < \sigma < \sqrt{\frac{20\times 3.3^2}{10.851} }[/tex]

= [tex]2.633< \sigma < 4.480[/tex]

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of potato chips that is labeled as 10 ounces should contain at least 10 ounces.Assume that the standard deviation of the packaging equipment yields a bag weight standard deviation of 0.2 ounces. Assume the bag weight distribution is bell-shaped. Determine what average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

Answers

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, [tex]\sigma=0.2[/tex]ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

[tex]P(x\geq 10)=0.99[/tex]

Assume the bag weight distribution is bell-shaped

Therefore,

[tex]P(\frac{x-\mu}{\sigma}\geq 10)=0.99[/tex]

We know that

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Using the value of z

Now,

[tex]\frac{10-\mu}{0.2}=0.99[/tex]

[tex]10-\mu=0.99\times 0.2[/tex]

[tex]\mu=10-0.99\times 0.2[/tex]

[tex]\mu=9.802[/tex]

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

1
Select the correct answer.
Simplify the following expression.

O A.
OB. 12
Oc. 1
OD.
64
Reset
Next

Answers

Answer:

1/64

Step-by-step explanation:

4^ (-11/3) ÷ 4 ^ (-2/3)

We know a^b ÷a^c = a^(b-c)

4 ^(-11/3 - - 2/3)

4^(-11/3 +2/3)

4^(-9/3)

4^ -3

We know a^-b = 1/a^b

1/4^3

1/64

An online retailer processed 60 merchandise return requests from Wyoming and Montana in a day. Return requests from Montana were 5 times as many as those from Wyoming. How many return requests were from Wyoming?
A) 10
B) 25
C) 15
D) 20
E) 5

Answers

The answer is A.10 because five times 10 is equal to 50

The number of merchandise return requests for Wyoming is equal to 10.

Let merchandise return requests from Wyoming be W.

Let merchandise return requests from Montana be M.

Given the following data;

Total number of merchandise return requests for W and M = 60

Translating the word problem into an algebraic equation, we have;

[tex]W + M = 60[/tex]  .....equation 1

[tex]M = 5W[/tex]        ......equation 2

To find the value of W, we would solve the system of equations by using the substitution method;

Substituting eqn 2 into eqn 1, we have;

[tex]W + 5W = 60\\\\6W = 60\\\\W = \frac{60}{6}[/tex]

Wyoming, W = 10 merchandise return requests.

Therefore, the number of merchandise return requests for Wyoming is equal to 10.

Find more information: https://brainly.com/question/8409825

I need two examples of Solve a proportion with a mixed number in one of its numerators. SHOW ALL WORK!!!!!!!!!!!!

Answers

Answer:

A proportion equation is something like:

[tex]\frac{A}{B} = \frac{x}{C}[/tex]

Where A, B, and C are known numbers, and we want to find the value of x.

Now we want two cases where in one of the numerators we have a mixed number, where a mixed number is something like:

1 and 1/3

which actually should be written as:

1 + 1/3

1) a random problem can be:

[tex]\frac{1 + 1/3}{4} = \frac{x}{5}[/tex]

We can see that the numerator on the left is a mixed number.

First, let's rewrite the numerator then:

1 + 1/3

we need to have the same denominator in both numbers, so we can multiply and divide by 3 the number 1:

(3/3)*1 + 1/3

3/3 + 1/3 = 4/3

now we can rewrite our equation as:

[tex]\frac{4/3}{4} = \frac{x}{5}[/tex]

now we can solve this:

[tex]\frac{4/3}{4} = \frac{4}{3*4} = \frac{x}{5} \\\\\frac{1}{3} = \frac{x}{5}[/tex]

now we can multiply both sides by 5 to get:

[tex]\frac{5}{3} = x[/tex]

Now let's look at another example, this time we will have the variable x in the denominator:

[tex]\frac{7}{12} = \frac{3 + 4/7}{x}[/tex]

We can see that we have a mixed number in one numerator.

Let's rewrite that number as a fraction:

3 + 4/7

let's multiply and divide the 3 by 7.

(7/7)*3 + 4/7

21/7 + 4/7

25/7

Then we can rewrite our equation as

[tex]\frac{7}{12} = \frac{25/7}{x}[/tex]

Now we can multiply both sides by x to get:

[tex]\frac{7}{12}*x = \frac{25}{7}[/tex]

Now we need to multiply both sides by (12/7) to get:

[tex]x = \frac{25}{7}*\frac{12}{7} = 300/49[/tex]

Which of the following is the most accurate statement about statistics?

a) We can absolutely be 100% certain in accurately generalizing the characteristics of entire population based on the sample data

b) By analyzing data, we may be able to identify connections and relationships in our data

c) We can explore in the midst of variation to better understand our data

d) limited data or experience likely generates less confidence

e) Non of the above

Answers

Answer:

b) By analyzing data, we may be able to identify connections and relationships in our data.

Step-by-step explanation:

In statistics decisions are based on probability sampling distributions. As statics is collection and analysis of data along with its interpretation and presentation.

i spend 3 hours a day out of a 8 hour shift, what percentage is that

Answers

Answer:

0.375 = 38%

Step-by-step explanation:

Just divide 3 from 8 and that will give you 0.375

Then you round that to the nearest  one which is 38 and

that will get your percentage

Answer: 37.5%

Step-by-step explanation: I just divided 3 by 8 then once I got my answer I moved the decimal point over to the right by 2.

a site is 90m long and 45m wide what is the area of the site

Answers

Answer:4050m^2

Step-by-step explanation:

Assuming that the site is rectangular

Area= l x W

90 X 45

=4050

Answer:

1050m

How I got the answer: I assume the site is a rectangle so I'll use the formula for finding the area of a rectangle. Using the formula length times width I solved this problem. The length is 90m. The width is 45. When a question says x meters long it means the length is x meters. In other words long = length     wide = width in a math problem.  90 times 40 is 1050m

Given C(4, 3) and D(-4, -3) are two points on a circle, centered at the origin. Given
that CD is a diameter of the circle,
a) Find the radius of the circle.

b) State the equation of the circle

Answers

Answer:000

Step-by-step explanation:000

Determine whether the following problem involves a permutation or combination.​ (It is not necessary to solve the​ problem.)
How many different ​-letter passwords can be formed from the letters ​S, T​, U​, ​W, X​, Y​, and Z if no repetition of letters is​ allowed?

The problem involves (combination or permiation) because the (order or number) of letters selected (does or does not) matter.

Answers

Answer:

Step-by-step explanation:

The order matters

stuwxyz is different than zyxwuts

You have 7 letters

The number of permutations is 7! which is 7*6*5*4*3*2*1 = 5040

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