Solve the following problem. Round to one decimal place if necessary.

Answer:

(-3,-4)

Step-by-step explanation:

Answer:

408

Step-by-step explanation:

Surface area formula is A=2(wl+hl+hw)

Substituting these values into the formula you would get

2·(3·8+4·8+4·3)=136

136 accounts for one rectangular prism.

Since you have 3 multiply 136 by 3 which would leave you with 408

Answer:

280 in²

Step-by-step explanation:

The opposite faces are congruent , then surface area (SA ) is

SA = top/ base + front/ back + 2 sides

note for the front/ back and 2 sides we have 3 + 3 + 3 = 9 in

   SA  = 2(8 × 4) + 2(8 × 9) + 2(4 × 9)

         = 2 × 32 + 2 × 72 + 2 × 36

        = 64 + 144 + 72

      = 280 in²

Answer:

B. its B

Step-by-step explanation:

The answer is B! :)

Answer:

vsddddddddddddddddddddddddddddddddddddddddddddddddddddddbgtresxvzjdhdf;lsjb

Step-by-step explanation:

Answer:

The Best is B = 44.985

Step-by-step explanation:

(A)First thing is that 0.10 times 750 is 75$

(B)but the 29.99 divided buy 500 equal 0.05998.

then you multiplier by 750 which equal 44.985.

this is the best way I hope this helps :)

MACARONI AND AN POT THATS AN WAAAAAPP

Answer:

√2 and √3

Step-by-step explanation:

Answer:

Step-by-step explanation:

√2 and 5√2 are two irrational numbers

√2 * 5√2 = [tex]5*\sqrt{2*2} = 5 * 2 = 10[/tex]

and here 10 is an integer

Answer:

Step-by-step explanation:

y = k x

Total cost = y

number of pounds = x

constant = 0.59

Equation

y = 0.59 x

Answer:

Step-by-step explanation:

2,3,5,6, 8,11,13          Are correct.

Answer:

x = 2

Step-by-step explanation:

(x+16)/3 = 3x

=> x+16 = 3x × 3

=> x+16 = 9x

=> 16 = 9x - x

=> 16 = 8x

=> 16/8 = x

=> 2 = x

Answer:

Step-by-step explanation:

Solve the equation for n:

The number is 80

Answer:

Number is 40

Step-by-step explanation:

Let the number be n

(n - 20)/2 = 30

(n - 20) = 2 × 30

n = (2 × 30) + 20

n = 60 + 20

n = 80

Answer:

don't know sorry forgive me

Answer and Step-by-step explanation:

To simplify, distribute the negative number.

-(11 + 2b)

-11 - 2b is the answer.

#teamtrees #PAW (Plant And Water)

I hope this helps!

Answer:

-11 -2b

Step-by-step explanation:

-(11+2b)

Distribute the minus sign

-11 -2b

Answer:

4

Step-by-step explanation:

4 times 4 is 16. 7 less than 16 is 9.

Answer:

4

Step-by-step explanation:

You can use a simple formula for finding the answer to problems like these. You read it out and put your information in order and use a variable (such as x) in place of the number.

4 * x - 7 = 9

Then solve by getting your variable alone on one side.

Add 7 to both sides: 4 * x = 16

Divide both sides by 4: x = 4

Answer: a =  - 1/5 or a = -0.2

Step-by-step explanation:

-9a – 10 – 6a + 7 = 0

>> -9a-6a = 10-7

>> -15a = 3

>> -15a/ - 15 =3 / - 15 ( divide by -15 both side)

>> a = - 1/5 or -0.2

Answer:

any file to have a reference?

Answer: A

Step-by-step explanation:

Answer:

-6 < x < 6

Step-by-step explanation:

Domain refers to the list of all x-values included in the function. In this instance, the list of x-values in this function is between -6 and 6.

Answer:

Step-by-step explanation:

1) 7/10 × 2/21

1/15

2) 9/16 × 10/21

90/336

15/56

3) 11/12 × 26/55

13/30

4) 2/6 × 18/12 × 2/3

72/216

1/3

5) ⅚ × 9/10

45/60

3/4

Answer:

Reflection is shown in the graph.

Answer:

A

Step-by-step explanation:

-2x-4>8

-2x>12

-x>6

x<-6

Answer:

[tex]x < - 6[/tex] (first option)

Step-by-step explanation:

[tex] - 2x - 4 > 8[/tex]

[tex] - 2x > 8 + 4[/tex]

[tex] - 2x > 12[/tex]

[tex] = x < - 6[/tex]

Answer:

.55555555 infinitely or .556

Step-by-step explanation:

Answer:

BC = 12

Step-by-step explanation:

23 - (2 + 9)

23 - 11 = 12

BC = 12

Answer:

Just study and pay attention in class and take good notes. I would say that you should pay more attention when they teach you the trigonometry unit.

Answer:

320/420 = 4/3

Step-by-step explanation:

4/7= x /560

Cross multiply

7x = 2240

Divide by 7:

x=320

The school has 320 boys and 240 girls

I hope this helps u:)

Answer:

Problem(1):     [tex]21[/tex]

Problem(2):     Side length = [tex]\frac{1}{4}[/tex]    Area = [tex]\frac{1}{16}[/tex]

Problem(3):     Boys = [tex]320[/tex]     Girls = [tex]240[/tex]

Step-by-step explanation:

(Notes steps are cut from this answer so that it isn't too long)

1. Problem (1)

One is given the following information:

The most logical first step is to solve for the value of (x). One can solve for the numerical value of (x) with the first equation.

[tex]x+\frac{1}{x}=5[/tex]

Multiply the entire equation by (x),

[tex]x^2+1=5x[/tex]

Inverse operations put the equation in the general format of a quadratic equation. The general format of a quadratic equation is as follows,

[tex]ax^2+bx+c=0[/tex]

Put the given equation in this format,

[tex]x^2-5x+1=0[/tex]

Now use the quadratic formula to solve for the value of (x). The quadratic formula uses the coefficients of the terms in a quadratic equation to find the roots of the equation. The quadratic formula is as follows,

[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]

Use the coefficients of the terms in the given quadratic equation in the formal, then simplify to solve for solutions of the given equation,

[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(1)(1)}}{2(1)}[/tex]

Simplify,

[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(1)(1)}}{2(1)}[/tex]

[tex]\frac{5(+-)\sqrt{21}}{2}[/tex]

Now substitute these values into the equation and simplify, even though there are two values of (x), there will only be one solution,

[tex]((\frac{5+\sqrt{21}}{2}-\frac{1}{\frac{5+\sqrt{21}}{2}})^2[/tex]                                      [tex]((\frac{5-\sqrt{21}}{2}-\frac{1}{\frac{5-\sqrt{21}}{2}})^2[/tex]  

[tex](\frac{5+\sqrt{21}}{2}-\frac{2}{5+\sqrt{21}})^2[/tex]                                      [tex](\frac{5-\sqrt{21}}{2}-\frac{2}{5-\sqrt{21}})^2[/tex]

Convert to a common denominator,

[tex](\frac{5+\sqrt{21}}{2}*\frac{5+\sqrt{21}}{5+\sqrt{21}}-\frac{2}{5+\sqrt{21}}*\frac{2}{2})^2[/tex]                   [tex](\frac{5-\sqrt{21}}{2}*\frac{5-\sqrt{21}}{5-\sqrt{21}}-\frac{2}{5-\sqrt{21}}*\frac{2}{2})^2[/tex]

[tex](\frac{(5+\sqrt{21})^2-4}{2(5+\sqrt{21})})^2[/tex]                                           [tex](\frac{(5-\sqrt{21})^2-4}{2(5-\sqrt{21})})^2[/tex]

Simplify,

[tex](\frac{25+10\sqrt{21}+21-4}{10+2\sqrt{21}})^2[/tex]                                     [tex](\frac{25-10\sqrt{21}+21-4}{10-2\sqrt{21}})^2[/tex]

[tex](\frac{42+10\sqrt{21}}{10+2\sqrt{21}})^2[/tex]                                              [tex](\frac{42-10\sqrt{21}}{10-2\sqrt{21}})^2[/tex]

[tex]\frac{1764+840\sqrt{21}+2100}{100+40\sqrt{21}+84}[/tex]                                      [tex]\frac{1764-840\sqrt{21}+2100}{100-40\sqrt{21}+84}[/tex]

[tex]\frac{3864+840\sqrt{21}}{184+40\sqrt{21}}[/tex]                                               [tex]\frac{3864-840\sqrt{21}}{184-40\sqrt{21}}[/tex]

[tex]21[/tex]                                                            

2. Problem (2)

All four sides of a square are congruent (have the same measure), thus dividing the perimeter of a square by (4) will yield the side length of the square,

[tex]Perimeter\ of\ the\ square: 4\\Side\ length: \frac{1}{4}[/tex]

The area is the two-dimensional space that a figure takes up, in the case of a square, the area is the side length times itself:

[tex]A=(\frac{1}{4})^2=\frac{1}{16}[/tex]

3. Problem (3)

Let (x) represent the amount by which the ratio of boys to girls was scaled down. Assuming that these are the only two genders in the school, one can state that the sum ratio coefficients times the scaling value for both boys and girls, will equal the total number of people in the school. Thus, one can form the following equation and solve it with inverse operations and simplification,

[tex]boys + girl = total\ students\\4x + 3x = 560\\7x = 560\\x = 80[/tex]

Now substitute this into the expression for the two genders in this scenario, respectively, to solve for the actual number of students of that gender,

Boys,                         Girls,

[tex]4(x)[/tex]                             [tex]3(x)[/tex]

[tex]4(80)[/tex]                           [tex]3(80)[/tex]

[tex]320[/tex]                              [tex]240[/tex]

Answer: (5,3)

Step-by-step explanation:

A 180 degree rotation will take you to sector b which is (+,+), so I knew it was going to be positive.

Answer:

165/14

Step-by-step explanation:

(7-4) + 17 / -14 + 2 x 5

3 + 17/-14 + 2 x 5

3 - 17/14 + 2 x 5

3 - 17/14 + 10

165/14

9514 1404 393

Answer:

Step-by-step explanation:

The x-axis is a horizontal line. As such, it has a slope of zero. The equation of a horizontal line is ...

  y = constant

__

For the line through (-5, 4), the constant must match the y-coordinate: 4. The equation is ...

  y = 4

As we said above, the slope of that horizontal line is zero.

The perpendicular line will be a vertical line of the form x=constant. The slope of a vertical line is undefined.

Answer:

Hope it helped

Step-by-step explanation:

The restricted domain that makes the given function one to one is (-∞,0] or [0.∞) and the inverse function  would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

An inverse function or an anti function is defined as a function, which can reverse into another function.

Now the given quadtratic function is,

f(x) = x² + 2

Now vertex of the given quadratic function is (0,2)

Thus the range of the function is [2,∞)

If we restrict the domain of this function to either (-∞,0} or [0.∞), it will become one to one function.

Now the inverse function is given as,

y = x² + 2

Upon interchanging x and y, we get:

x = y² + 2

⇒ y² = x - 2

or, y = ±[tex]\sqrt{x-2}[/tex]

Hence, the inverse function would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

Thus, the restricted domain that makes the given function one to one is (-∞,0] or [0.∞) and the inverse function  would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

To learn more about function :

https://brainly.com/question/17210215

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