Solve for y.

–5(y − 3) − 10 = –6y

y =

Answer:

-44f - 12

Step-by-step explanation:

Here's the method :

-10f - 6 (-9f + 2 )

-10f + 54f - 12

-44f - 12

Answer:

[tex]44f - 12[/tex]

Step-by-step explanation:

[tex] - 10f - 6( - 9f + 2)[/tex]

[tex] - 6( - 9 + 2)[/tex]

[tex] - 6 \times ( - 9f) - 6 \times 2[/tex]

[tex]6 \times 9f - 6 \times 2[/tex]

[tex]54f - 6 \times 2[/tex]

[tex]54f - 12[/tex]

[tex] - 10f + 54f[/tex]

[tex]( - 10 + 54)f[/tex]

[tex] = 44f - 12[/tex]

Answer:

Yes

Step-by-step explanation:

6 × 18.75 = 112.50

8 × 18.75 = 150.00

11 × 18.75 = 206.25

Answer:

[tex] \frac{5}{8} k = 25 \\ \frac{5k}{8} = 25 \\ 5k = 25 \times 8 \\ 5k = 200 \\ k = \frac{200}{5} \\ k = 40[/tex]

I hope it helped U

stay safe stay happy

Answer:

k=1/40

Step-by-step explanation:

multiple both sides by 8k

5= 25×8k

simplify 25×8k to 200k

5=200k

divide both sides by 200

5/200=k

simplify 5/200 to 1/40

1/40= k

switch sides

k=1/40

Answer:

She didn't change the direction of the sign

Step-by-step explanation:

When dividing both sides by a negative number in an inequality, you must change the sign.

Answer:

7

Step-by-step explanation:

21/3 = 7

Hope this helps!

Answer:

81[tex]y^{8}[/tex][tex]z^{4}[/tex]

Step-by-step explanation:

Answer:

31000 or 31 × 10^3

6.2 (5× 10^3)

Answer:

(G)77

Step-by-step explanation:

44+11=55.

55+22=77.

77+33=110.

110+44=154.

154+55=209.

Answer:

28minutes

Step-by-step explanation:

Use this simple trick, it can be used almost everywhere

Time taken pieces

20mins 5

? 7

An x shape is always multiply and straight line is divide

So (7 x 20) ÷5

If u still don't understand, just comment again

Answer:

Step-by-step explanation:

No that is incorrect 28 is not the answer:

1. 4 cuts every 20 mins it would take one cut every 5 mins. You only need one more cut because 6 cuts make 7 pieces. If you draw it.

1/5= 6/30 so 30 mins!

Answer:

When x takes the value of 4, the expression takes the value of 9.

Step-by-step explanation:

We are given that the expression:

[tex]\displaystyle ax^2 + bx + c[/tex]

Evaluates to 0, 1, and 4 when x = 1, 2, and 3, respectively.

And we want to determine the value of the expression when x = 4.

The expression evaluates to 0 when x = 1. In other words:

[tex]\displaystyle a(1)^2 + b(1) +c = a + b + c = 0[/tex]

We can complete the same for the other two:

[tex]\displaystyle a(2)^2 + b(2) + c = 4a + 2b + c = 1\text{ and } \\ \\ a(3)^2 + b(3) + c = 9a + 3b + c = 4[/tex]

This yields a triple system of equations:

[tex]\displaystyle \left\{ \begin{array}{l} a + b + c = 0 \\ 4a + 2b + c = 1 \\ 9a + 3b + c = 4 \end{array}[/tex]

Solve. We can cancel out the c by multiplying the first equation by negative one and adding it to both the second and the third:

[tex]\displaystyle \begin{aligned} (4a + 2b + c) + (-a - b -c ) &= (-0) + (1) \\ \\ 3a +b &= 1\end{aligned}[/tex]

And:

[tex]\displaystyle \begin{aligned} (9a + 3b + c) + (-a - b -c) &= (-0) + (4) \\ \\ 8a + 2b &= 4\end{aligned}[/tex]

Solve for the two resulting equations. We can multiply the first by negative two and add it to the second:

[tex]\displaystyle \begin{aligned}(8a + 2b) + (-6a -2b) &= (4) + (-2) \\ \\ 2a &= 2 \end{aligned}[/tex]

Hence:

[tex]a = 1[/tex]

Solve for b:

[tex]\displaystyle \begin{aligned} 3a + b &= 1 \\ b&= 1 - 3a \\ b&= 1 - 3(1) \\ b &= -2\end{aligned}[/tex]

And finally, solve for c:

[tex]\displaystyle \begin{aligned} a + b + c &= 0 \\ (1) + (-2) + c &= 0 \\ c &= 1\end{aligned}[/tex]

Hence, our expression is:

[tex]\displaystyle x^2 -2x + 1[/tex]

Then when x = 4:

[tex]\displaystyle (4)^2 - 2(4) + 1= 9[/tex]

In conclusion, when x = 4, the resulting value is 9.

Answer:

11

Step-by-step explanation:

2^10 + 2^10 = 2^x

1024 + 1024 = 2^x

2,048 = 2^x

x = 11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = 11[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\2^{10}+2^{10} = 2^x\\--------------\\\rightarrow 2^{10} = 1024\\\\\rightarrow 1024 + 1024 = 2^x\\\\\rightarrow 2048 = 2 ^x\\\\\rightarrow log(2^x)=log(2048)\\\\\rightarrow xlog(2)=log(2048)\\\\\rightarrow \frac{log(2)}{log(2)} =\frac{log(2048)}{log(2)}\\\\\rightarrow x = \frac{log(2048)}{log(2)}\\\\\rightarrow \boxed{x = 11}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

7, 8, 9

Step-by-step explanation:

1/5 = 6/30

1/3 = 10/30

Answer:

To see whether or not two lines are parallel, we must compare their slopes. Two lines are parallel if and only if their slopes are equal. The line 2x – 3y = 4 is in standard form. In general, a line in the form Ax + By = C has a slope of –A/B; therefore, the slope of line q must be –2/–3 = 2/3.

Answer:

Parallel lines

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

first multiply everything by 6 to get rid of the fractions

then we get 5m-4 -6 = 24m -9m -30

simplify the equation 5m-10=15m-30

subtract 5m from both sides and add 30 to both sides 10m=20

divide by 10, m=2

Answer:

-16

Step-by-step explanation:

x = -3 is less than -2, so you should use the first equation 5x-1

thus, 5(-3)-1 = -16

Answer:

...

Step-by-step explanation:

Answer:

5n+3

Step-by-step explanation:

:)

Answer:

[tex]\alpha n=5n+3[/tex]

Step-by-step explanation:

Answer:

y- intercept, x=0

8(0)-4y=12

y=-3

Answer:

[tex]4y + 6y = 90 \\ 10y = 90 \\ y = 9 \\ thank \: you[/tex]

Step-by-step explanation:

ABCD is a quadrilateral triangle,where AD=BC and <DAB =<CBA.

In ∆ABD and ∆BAC

•AD=BC. (given)

•<DAB=<CBA (given)

•AB=BA. (common side)

Therefore, ∆ABD ≌ ΔBAC. {SAS congruence rule}

Answer:

6.72

Step-by-step explanation:

I multiplied both numbers by 10 to make it easier in my opinion. That made the equation 994.66 x 148

Then, I divided it until i got to the thousandths place. Lastly, i just rounded making it 6.72

Answer:

0.0300300030000...

Step-by-step explanation:

An irrational number has endless non-repeating digits to the right of the decimal point. They can be written as decimals, but not as fractions.

1632 can be written as 3264/2

0.25 can be written as 1/4

0 could be written as 0/0

but 0.0300300030000 cannot be written as a fraction, and it satisfies the condition of an irrational number having endless non-repeating digits to the right of the decimal point.

Answer:

answer) the change is $7.90

15:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^5y^6}{xy^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}y^{6-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4y^4[/tex]

16:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^2y^5}{xy^4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{2-1}y^{5-4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto xy[/tex]

17;-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{4x^5y}{16xy^4}\right)^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{1-2}x^{5-1}y^{1-4})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^4y^{-3})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-3}x^{12}y^{-9}[/tex]

18:-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{5x^3y}{20xy^5}\right)^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^{2}y^{-4})^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-4}x^8y^{-16}[/tex]

19:-

[tex]\\ \qquad\quad\sf\longmapsto y^{-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{y^7}[/tex]

20:-

[tex]\\ \qquad\quad\sf\longmapsto 7^{-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{7^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{49}[/tex]

21:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^{-5}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^5[/tex]

22:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{2^{-4}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 16[/tex]

23:-

[tex]\\ \qquad\quad\sf\longmapsto x^5\times x^{-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4[/tex]

24:-.

[tex]\\ \qquad\quad\sf\longmapsto x^{-6}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^6}[/tex]

25:-

[tex]\\ \qquad\quad\sf\longmapsto x^9(x^{-7})[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{9-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^2[/tex]

Answer:

no soultion

Step-by-step explanation:

did on paper

Answer:

exactly one solution

Step-by-step explanation:

got it right on khan lol

Answer:

12. (2, -3)

13. AH: +15   B: +721   CB: 0   N: +462   WB: -1200

Step-by-step explanation:

12.

When a point is reflected over the x-axis, the y coordinate becomes opposite because you are changing its y value, not its x-value. So (-2, 3) reflecting over the x-axis becomes (-2, -3).

The same concept goes for reflecting over the y-axis. The x coordinate becomes opposite because you are changing its x value. (It's like folding the graph in half and seeing where the point matches up with. So (-2, -3) reflecting over the y-axis becomes (2, -3).

13.

All you have to do is list each artifact and where they were found in relation the sea level (0). If it is above sea level then it is a positive number, below sea level is a negative number.

Arrow head: +15 (since it is 15 feet above sea level)

Woven basket: -1200 (since it is 1200 feet below sea level)

Answer:gggggggggg

Step-by-step explanation:

gggggggggggggggggggggggggggggggggggggg