The perimeter of the triangle below is 4x + 3y. Find the measure of the missing side.

Answer:

D

Step-by-step explanation:

I hope thats correct

Answer:

Step-by-step explanation:

Step-by-step explanation:

11.

[tex] \frac{x - 4}{ \frac{x}{4} - \frac{4}{x} } [/tex]

[tex] \frac{x - 4}{ \frac{ {x}^{2} }{4x} - \frac{16}{4x} } [/tex]

[tex] \frac{x - 4}{ \frac{ {x}^{2} - 16 }{4x} } [/tex]

[tex] \frac{x - 4}{ \frac{(x + 4)(x - 4)}{4x} } [/tex]

[tex] \frac{4x}{x + 4} [/tex]

12.

[tex] \frac{ \frac{ {x}^{2} - 1 }{x} }{ \frac{(x - 1) {}^{2} }{x} } [/tex]

[tex] \frac{ {x}^{3} - x}{ {x}^{3} - 2 {x}^{2} + x } [/tex]

[tex] \frac{x( {x} - 1)(x + 1) }{x( {x} - 1) {}(x - 1) } [/tex]

[tex] \frac{x + 1}{x - 1} [/tex]

13.

[tex] \frac{ \frac{ {t}^{2} }{ \sqrt{ {t}^{2} + 1} } - \sqrt{ {t}^{2} + 1} }{ {t}^{2} } [/tex]

[tex] \frac{ \frac{ {t}^{2} }{ \sqrt{ {t}^{2} + 1 } } - \frac{ {t}^{2} + 1}{ \sqrt{ {t}^{2} + 1 } } }{ {t}^{2} } [/tex]

[tex] \frac{ \frac{1}{ \sqrt{ {t}^{2} + 1 } } }{ {t}^{2} } [/tex]

[tex] \frac{ - \frac{ \sqrt{ {t}^{2} + 1 } }{ {t}^{2} + 1 } }{ {t}^{2} } [/tex]

[tex] - \frac{ \sqrt{ {t}^{2} + 1} }{ {t}^{2}( {t}^{2} + 1) } [/tex]

14.

[tex] \frac{3x { }^{ \frac{1}{3} } - x {}^{ \frac{ - 2}{3} } }{3x {}^{ - \frac{2}{3} } } [/tex]

[tex] \frac{3x - 1}{3} [/tex]

A glucose molecule is the smallest type of protein monomer of starch and cellulose largest of the carbohydrate polymers fundamental unit of genetic material.

A glucose molecule is the monomer of starch and cellulose.

Step-by-step explanation:

So from this, we can conclude that A glucose molecule is the monomer of starch and cellulose.

Learn more about glucose here:

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Answer:

answer it's c)24...

Step-by-step explanation:

i think helping you..... please tell correct or no...

Answer:

p = k(d)/u^2

Step-by-step explanation:

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9514 1404 393

Answer:

  (C)  g = f(-x)

Step-by-step explanation:

g is a reflection of f over the y-axis. Such a reflection replaces x with -x.

  g(x) = f(-x) . . . . . matches choice C

_____

Additional comment

(A) leaves the function unchanged.

(B) is a reflection over the x-axis

(C) is a reflection over the y-axis (applicable here)

(D) is a reflection over the origin (both x- and y-axes)

Answer:

Equation is y=2x+12

The image is a picture of the graph(it's not the best but it's something.

Answer:

Try h=(1-6πs)/6π

Step-by-step explanation:

That's the same answer in another format

Answer:

3.42

Step-by-step explanation:

24/7=3.42

Answer:

Angle DBC = 51

Step-by-step explanation:

Angle ABC = angle ABD + angle DBC

We are given that angle ABC = 122 and angle ABD = 71

So 122 = 71 + angle DBC

* Solve for angle DBC *

Subtract 71 from both sides

122 - 71 = 71 - 71 + angle DBC

51 = angle DBC

Step-by-step explanation:

the correct aanswer is 3 is correct answermark me bbrainleast plz

Answer:

d is the answer

Step-by-step explanation:

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The guitar's volume was amplified, but it was hard to hear the notes since it was so loud.

What word or phrase is a signal word that a context clue might be nearby to help determine the meaning of "amplified"?

Step-by-step explanation:

Answer:

1833 miles is the total distance if the model airplane.

Answer:

2x+1=0.

2x=0-1.

2x=-1.

2x/2=-1/2.

x=-2.

3x+4=0

3x=0-4

3x=-4

3x/3=-4/3

[tex]x = 1 \frac{1 }{3} [/tex]

Answer:

C is the answer to your question

Answer:

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

Answer:

3 eighths are needes to make up the rest of the measure.

Step-by-step explanation:

1/4 + 1/4 + 1/ 8 + x = 1

2/4 + 1/8+x=1

4/8 + 1/8+x=1

5/8 + x=1

x=1 - 5/8

x=3/8

We need three eights.(Because 3/8=1/8+1/8+1/8 and 1/8 represents an eights)

Answer:

8.5 feet and 7.5 feet.

Step-by-step explanation:

Hope this helps :)

If [tex]k\in\mathbb{Z}[/tex] than [tex]k+1\in\mathbb{Z}[/tex] however any [tex]\mathbb{Z}[/tex] divided by 2 is in [tex]\mathbb{Q}[/tex].

But it is not so simple.

If [tex]k[/tex] is odd then [tex]k+1[/tex] is even but when even number is divided by 2, you get an odd number which is in [tex]\mathbb{Z}[/tex].

However if [tex]k[/tex] is even then [tex]k+1[/tex] is odd and when we divide that by 2, you get a number like for example [tex]\frac{5}{2}[/tex] which is not in [tex]\mathbb{Z}[/tex] but rather inside [tex]\mathbb{Q}[/tex]. There are fortunately no irrational numbers.

There is also a problem with zero, zero is neither odd nor even but still an integer. If your [tex]k[/tex] happens to be -1, [tex]k+1=0[/tex], and zero divided by 2 is still just 0 which is in [tex]\mathbb{Z}[/tex].

So to sum up,

If [tex]k[/tex] is odd and not -1, then [tex]\frac{k+1}{2}\in\mathbb{Z}[/tex].

Or to put it in math [tex]\forall k\in\mathrm{odd}-\{-1\}\cup\{0\}\implies\frac{k+1}{2}\in\mathbb{Z}[/tex].

If [tex]k[/tex] is even or -1, then [tex]\frac{k+1}{2}\in\mathbb{Q}[/tex].

Or to put it in math [tex]\forall k\in\mathrm{even}\cup \{-1\}\implies\frac{k+1}{2}\in\mathbb{Q}[/tex].

Notes:

[tex]\mathbb{Z}[/tex] is a set of integers.

[tex]\mathbb{Q}[/tex] is a set of rational numbers.

[tex]\mathbb{Z}\subset\mathbb{Q}[/tex] means integers are a subset of rational numbers, that is, every integer is a also a fraction, however not every fraction is an integer.

Hope this helps :)

Step-by-step explanation:

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Answer:

-5-4i is your answer.

Answer:

{6, 8, 10, 12, 14, 16, 18, 20, ...}

Step-by-step explanation:

even natural numbers >/= 6.

Thus this has no upper limit and the set is thus infinite.

The set of even natural numbers greater than or equal to 6 is

" The natural numbers are those numbers used for counting and ordering. Numbers used for counting are called cardinal numbers."

We know the natural numbers are:

{1, 2, 3, 4, 5, 6, 7,..........}

Now, the set of even natural numbers are:

{2, 4, 6, 8, 10...........}

Therefore, the set of even natural numbers greater than or equal to 6 is

{6, 8, 10, 12,..............}

Learn more about natural numbers here: https://brainly.com/question/8102087

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Answer:

2

Step-by-step explanation:

1+1×5−6+8×(4+4)−62 =

1+1x5-6+8x(8)-62 =

1+5-6+64-62 =

2

Hope this helps! :)