Solve for x. Round to the nearest tenth of a degree, if necessary.

Solve For X. Round To The Nearest Tenth Of A Degree, If Necessary.

Answers

Answer 1

Answer:

x =48.6

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp side / hypotenuse

sin x = 54 /72

Taking the inverse sin of each side

sin ^ -1( sin x) =sin ^-1 ( 54/72)

x = 48.59037789

To the nearest tenth

x =48.6


Related Questions

Ai giải giúp mình giải bài này với
[tex]\sqrt{36x^{2} -60x+25} =4[/tex]

Answers

Answer:

x=[tex]\frac{3}{2}[/tex] and x=[tex]\frac{1}{6}[/tex]

Step-by-step explanation:

[tex]\sqrt{36x^2-60x+25}=4[/tex]

=> [tex]\sqrt{36x^2-60x+25}^{2} =4^{2}[/tex]

=> [tex]{36x^2-60x+25}=16[/tex]

=> [tex]36x^2-60x+25-16=16-16[/tex]

=> [tex]36x^2-60x+9=0[/tex]

=> [tex]x_{1,\:2}=\frac{-\left(-60\right)\pm \sqrt{\left(-60\right)^2-4\cdot \:36\cdot \:9}}{2\cdot \:36}\\\\\sqrt{\left(-60\right)^2-4\cdot \:36\cdot \:9}=48[/tex]

=> [tex]x_{1,\:2}=\frac{-\left(-60\right)\pm \:48}{2\cdot \:36}[/tex]

=>[tex]x_{1} = \frac{-\left(-60\right)+48}{2\cdot \:36}\\\\x_{1}=\frac{60+48}{2\cdot \:36}\\\\x_{1}=\frac{108}{72} \\\\\\x_{1}=\frac{3}{2}\\[/tex]

=> [tex]x_{2}=\frac{-\left(-60\right)-48}{2\cdot \:36}\\\\x_{2} =\frac{60-48}{2\cdot \:36}\\\\x_{2}=\frac{12}{2\cdot \:36}\\\\\x_{2}=\frac{12}{72}\\\\x_{2}=\frac{1}{6}[/tex]

Help me solve this please!

Answers

Answer Should be 45

Answered by Gauthmath must click thanks and mark brainliest

Helpless! I need help.

Answers

I have attached the answer below

Answer:

0

Step-by-step explanation:

r=5

So

=5⁴-5(5)³-4(5)²+5(5)+75

=5⁴-5(125)-4(25)+5(5)+75

=625-625-100+25+75

=0

What is the slope of the line that passes through the points (-20, 18) and (30, 14)?

Answers

Answer:

-2/25

Step-by-step explanation:

Use the slope formula: rise/run to find the slope

Answer:

slope = - [tex]\frac{2}{25}[/tex]

Step-by-step explanation:

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 20, 18) and (x₂, y₂ ) = (30, 14)

m = [tex]\frac{14-18}{30-(-20)}[/tex] = [tex]\frac{-4}{30+20}[/tex] = [tex]\frac{-4}{50}[/tex] = - [tex]\frac{2}{25}[/tex]

Draw the graphs of the pair of linear equations : x + 2y = 5 and 2x - 3y = -4 Also find the points where the lines meet the x - axis .

Answers

Answer:

(1, 2)

Step-by-step explanation:

Given the equation of the lines x + 2y = 5 and 2x - 3y = -4

First we need to make x the subject of the formulas

For x+2y = 5

x = 5 - 2y ... 1

For 2x - 3y = -4

2x = -4+3y

x = (-4+3y)/2 ... 2

Equate 1 and 2

5 - 2y =  (-4+3y)/2

2(5-2y) = -4+3y

10 - 4y = -4+3y

-4 -3y = -4-10

-7y = -14

y = 14/7

y = 2

Substitute y = 2 into 1

x = 5 = 2y

x = 5 - 2(2)

x = 5 - 4

x = 1

Hence the point where the lines meet will be at (1, 2)

A line with slope 3 intersects a line with slope 5 at the point (10, 15). What is the distance between the x-intercepts of these two lines?​

Answers

Answer:

2

y = 3x-15

y=5x-35

x1=5

x2=7

distance between = 7-5 = 2

Step-by-step explanation:

Identify one similarity and one difference between the graph of 2x + 4 and the graph of y= -1/2x + 4

Answers

Answer:

Similarity: Both graphs have same y-intercepts.

Difference: Graph 2x + 4 has a slope of 2 while the graphic -½x + 4 has a slope of -½

Step-by-step explanation:

[tex]{ \sf{y = mx + b}}[/tex]

m is the slope

b is the y-intercept

I need help pls pls pls pls

Answers

Answer:

1. -18x+6

multiply everything inside with the number outside the bracket

2. -18x-6

same as number one

3. 18x-12

same as number one

4. -18x-6

same as number one

for 5 I can't see it well but it should be similar

you just need to substitute what's outside the bracket to what Is inside the bracket

Answer: -6 (3x+1)

Step-by-step explanation:

Factor the polynomial -18x-6−18x−6 by it's GCF: -6−6

8x square + 1 + 3square - 2​

Answers

Answer:

8x^2-1+3^2

Step-by-step explanation:

2. Give an example of a rational number that is not a whole number.

Answers

This are a few of Rational numbers are not whole numbers: 8,−3,32,7−5.

Step-by-step explanation: Hope this helps

rational or irrational? and why

Answers

Answer:

rational, simplified number is -0.5

Step-by-step explanation:

(see screenshot)

Which term can be used in the blank of 36x3−22x2−__ so the greatest common factor of the resulting polynomial is 2x? Select two options.

2
4xy
12x
24
44y

Answers

Answer:

[tex]4xy[/tex][tex]12x[/tex]

-------------

[tex]36x^3,\:22x^2,\:4xy[/tex]

Factor 36x³

[tex]2\cdot \:2\cdot \:3\cdot \:3\cdot \:x\cdot \:x\cdot \:x\\[/tex]

Factor 22x²

[tex]11\cdot \:2\cdot \:x\cdot \:x[/tex]

Factor 4xy

[tex]2\cdot \:2\cdot \:x\cdot \:y[/tex]

Common factor

[tex]2x[/tex]

---------------------

[tex]36x^3-22x^2-12x[/tex]

Factor 36x³

[tex]2\cdot \:2\cdot \:3\cdot \:3\cdot \:x\cdot \:x\cdot \:x[/tex]

Factor 22x²

[tex]11\cdot \:2\cdot \:x\cdot \:x[/tex]

Factor 12x

[tex]2\cdot \:2\cdot \:3\cdot \:x[/tex]

Common factor

[tex]2x[/tex]

OAmalOHopeO

Show that the line 4y = 5x-10 is perpendicular to the line 5y + 4x = 35 ​

Answers

Step-by-step explanation:

concept :concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines areconcept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are4y = 5x-10concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are4y = 5x-10or, y = (5/4)x(5/2). .....(1)5y + 4x = 355y + 4x = 35ory = (-4/5)x + 7. ......(2)Let m and n be the slope of equations i and ii, respectively.Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5therefore, mx n = -1Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5therefore, mx n = -1Hence, the lines are perpendicular.

A cylindrical vase has a volume of 192.5 cubic centimeters. The height of this vase is 5 centimeters. The formula for the volume of the cylinder is πr^2h where r is the radius and h is the height of the vase. Find the radius of this vase.(Given that π ≈ 22 / 7 )

Answers

Answer:

3.5 cm

Step-by-step explanation:

v = πr²h

r = radius

π = 22/7

h = height

192.5 = 22/7 x 5 x r²

divide both sides of the equation by (7/22 x 1/5)

192.5 x 7/22 x 1/5 = r²

r² = 12.25

find the square root of both sides

r = 3.5cm

Help please URGRENTTTTT
The graph below shows a company’s profit f(x), in dollars, depending on the price of pens x in dollars sold by the company:
Part A: what do the x-intercepts and maximum value of the graph represent? What are the intervals where the function increasing and decreasing, and what do they represent about the dale and profit?
Part B: what is an approximate average rate of change of the graph from x=3 to x=5, and what does this rate represent?
Part C: describe the constraints of the domain

Answers

Answer:

Part A

The x-intercepts are reflecting zero-profit: (0, 0) and (6, 0).

The maximum value of the graph is at vertex (3, 120): maximum profit when the price is $3.

The function is increasing until the vertex, between x-value of 0 to 3 and is decreasing once it reached the vertex, between x-value of 3 to 6.

In the first interval the sale and profit increases, in the second interval the sale and profit decreases.

Part B

Average rate of change from x = 3 to x = 5 is:

(f(5) - f(3))/(5 - 3) = (60 - 120)/2 = -30

This represents the profit drop of $30 per $1 price increase when price changes from $3 to $5.

Part CThe domain is representing the price. It should be profitable so it is between $0 and $6.

toán 9 nha mọi người

Answers

Answer:

Thamkhao

Step-by-step explanation:

Suppose you buy 6 cans of peaches at $1.10 each, 5 cans of corn for $.89 each, and 3 boxes of breakfast cereal at $3.52 each. a. Write three expressions; one each that shows how to determine the total spent on peaches,
corn and breakfast cereal. (3 pts)

Answers

Si yo tendria que sumar esos numeros daria: 21.61

porque, 6x1.10= 6.60

5x0.89= 4.45

y las tres cajas de cereal 3x3.52

Can someone please check my answers and help/explain #4

Answers

Answer:

(0,8)

Step-by-step explanation:

To get the y-intercept put all x values equal to 0 (because we want to see where y lies on the graph when x is zero.

y=2^0+3

y=2^3

y=8

The y-intercept is (0,8)

As for the rest of the answers.....

1)A) 2[tex]\sqrt{12}[/tex]-5[tex]\sqrt{3}[/tex] = 4[tex]\sqrt{3}[/tex]-5[tex]\sqrt{3}[/tex] so the final answer is -[tex]\sqrt{3}[/tex]

1B) the problem is (3-[tex]\sqrt{7}[/tex])(3+[tex]\sqrt{7}[/tex]) a quick formula to help you solve this type of problem is (a-b)(a+b)= a^2-b^2 so you transform the question to 3^2-[tex]\sqrt{7}[/tex] ^2

to get 9-7 which is 3 therefore the final answer is 3

2) when you transform a function from y=x^2-3 to y=x^2+1 the graph moves 4 units up. So the final answer is b)4 units up

Question 3a and 3b are correct

The surface area of a cylinder is given by the formula

S = 30πr + 2πr2

How many times greater is this compared to a circle with A = πr2

Answers

Answer:

[tex] x = \frac {30}{r} + 2 [/tex]

Step-by-step explanation:

Given the following data;

S.A of cylinder = 30πr + 2πr²Area of circle = πr²

To find how many times greater is the S.A compared to the area, we would have to divide the surface area (S.A) of the cylinder by the area of circle.

Let the unknown variable be x.

[tex] x = \frac {30 \pi r + 2 \pi r^{2}}{\pi r^{2}} [/tex]

Factorizing the numerator, we have;

[tex] x = \frac {\pi r(30 + 2r)}{\pi r^{2}} [/tex]

Dividing both sides by πr, we have;

[tex] x = \frac {30 + 2r}{r} [/tex]

Simplifying further, we would have;

[tex] x = \frac {30}{r} + 2 [/tex]

-5x(x+1)
simplify the answer

Answers

Answer:

[tex]-5x^2-5x[/tex]

Step-by-step explanation:

[tex]-5x\left(x+1\right)\\\\-5x\left(x+1\right)=-5xx-5x\cdot \:1\\\\=-5xx-5x\cdot \:1\\\\=-5x^2-5x[/tex]

Answer:

-5x^2 -5x

Step-by-step explanation:

-5x(x+1)

Distribute

-5x*x  +-5x*1

-5x^2 -5x

| 3 x - 2 | = 4x + 4

Answers

Answer: -2/7

|3x - 2| - 4x = 4

1) (3х - 2) - 4х = 4, if 3x - 2 >= 0

2) -(3x - 2) - 4x = 4, if 3x - 2 < 0

1)

3х - 4х = 4 + 2

-x = 6

x = -6

3х - 2 >= 0

3х >= 2

x >= 2/3 - wrong

2)

-3х + 2 - 4х = 4

-7х = 2

x = -2/7

3x-2<0

3x<2

3(-2/7)<2-right

if an object is bought for rupees 90 and then sold for a loss of 15% how much was it sold for​

Answers

Answer:

76.50

Step-by-step explanation:

We are given the fact that you bought an object for 90 dollars, and in which you sold said object for a loss of 15%, we are then asked how much would that object be sold for.

To find the answer, we need to subtract the original amount by the percent loss, so :

90 - 15%

15% of 90 is 13.5, therefore :

90 - 13.5

76.5

Please explain, thank you

Answers

Answer:

C. 2.

Step-by-step explanation:

The graph descends from the left  so the coefficient of the leading term is negative. It is also a cubic equation with zeros of -20, about 6.5 and about 13. so we can write the equation as below.  The last 2 values can only be guessed because the x axis only shows values which are multiples of 5.

f(x) = a(x + 20)(x - 6.5)(x - 13)   where a is  a negative constant.

(This is only an approximation).

By the Remainder theorem, when the expression is divided by (x + 10):

f(-10) = -20 so we have

-20 = a (-10 + 20)(-10-6.5)(-10 - 13)

(10)(-16.5)(-23)a = -20

a = -20 / (10)(-16.5)(-23)

a = -0.0053

When  the equation is divided by (x - 10) then f(10)  is the remainder so substituting we have as the remainder:

-0.0053(10+20)(10-6.5)(10 -13)

-0.0053 * 30 * 3.5 * -3

= 1.7 approximately.

Looks like the answer is 2.

the perimeter of equilateral triangle is 21m. Find the area. Using Heron's Formula


plzzz answer fast i will mark brainliest.

Answers

Answer:

A ≈ 21.22 m²

Step-by-step explanation:

The area (A) of a triangle using Heron's formula is

A = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]

where s is the semi perimeter and a, b, c the sides of the triangle.

Here the perimeter of the equilateral triangle is 21 m , then

a = b = c = 21 ÷ 3 = 7 m

s = 21 ÷ 2 = 10.5

Then

A = [tex]\sqrt{10.5(10.5-7)(10.5-7)(10.5-7)}[/tex]

   = [tex]\sqrt{10.5(3.5)(3.5)(3.5)}[/tex]

   = [tex]\sqrt{450.1875}[/tex]

   ≈ 21.22 m² ( to 2 dec. places )

Find the missing number.

____ × 7 = 91

please help me

Answers

91 divided by 7 is 13.
13 is the missing number

Answer: 13

Step-by-step explanation:

Take 7 to the other side and divide 91 by 7, the answer will be 13.

Two similar pyramids have similarity ratio 3:5 find the ratio of the areas and the ratio of the volume

Answers

Answer:

Area=9:25 Volume=81:625

Step-by-step explanation:

Should be squared, might be wrong.

Geometry, please answer question ASAP

Answers

BECAUSE ACCORDING TO THE PERIMETER (TRIANGLE ) FORMULA = B * H / 2.

B = BASE.

H = HEIGHT.

THE HEIGHT IS A VARIABLE VLAUE NEEDED IN ORDER TO ONTINUE TO SOLVE AND EVENTUALLY LEADING TO THE ANSWER (TRIANGLE PERIMETER.

With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the entire batch is rejected if there is at least one defective unit. The ABCD Electronics Company has just manufactured 7000 write-rewrite CDs, and 180 are defective. If 6 of these CDs are randomly selected and tested, what is the probability that the entire batch will be rejected

Answers

Answer:

[tex]P = 0.1447[/tex]

Step-by-step explanation:

Given

[tex]n = 7000[/tex] -- total

[tex]d = 180[/tex] --- defective

[tex]r = 6[/tex] --- selected

Required

The probability of rejecting the batch

This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

So, we have:

[tex]Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}[/tex]

The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs

So, we have:

[tex]Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}[/tex]

[tex]Pr = 0.8553[/tex]

Using the complement rule, the probability that the batch will be rejected is:

[tex]P = 1 - 0.8553[/tex]

[tex]P = 0.1447[/tex]

The table shows values for a quadratie function
What is the average rate of change for this function for the interval from 1
Please see
Pic

Answers

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here [ a, b ] = [ 1, 3 ] , then

f(3) = 18 ← value of y when x = 3

f(1) = 2 ← value of y when x = 1

Then

average rate of change = [tex]\frac{18-2}{3-1}[/tex] = [tex]\frac{16}{2}[/tex] = 8 → B

Harish
covers
3/10
of the distance between two cities in
1 4/5
hours. If he travels at the same speed, how much of the total distance would he cover in
3 1/5
hours?

Answers

Answer:

Step-by-step explanation:

Distance traveled in [tex]1\frac{4}{5}[/tex] hours = [tex]\frac{3}{10}[/tex]

Distance traveled in 1 hour = [tex]\frac{3}{10}[/tex] ÷ [tex]1\frac{4}{5}[/tex]

          [tex]=\frac{3}{10}[/tex] ÷ [tex]\frac{9}{5}[/tex]

          [tex]= \frac{3}{10}*\frac{5}{9}\\\\=\frac{1}{2}*\frac{1}{3}\\\\=\frac{1}{6}[/tex]

distance traveled in 3 1/5 hours = [tex]\frac{1}{6}*3\frac{1}{5}[/tex]

 =[tex]=\frac{1}{6}*\frac{8}{5}\\\\=\frac{1}{3}*\frac{4}{5}\\\\=\frac{4}{15}[/tex]

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