Solve for x. Round to the nearest tenth of a degree, if necessary.

Solve For X. Round To The Nearest Tenth Of A Degree, If Necessary.

Answers

Answer 1

Sin (angle) = opposite leg / hypotenuse

Sin(x) = 2.1/4

x = arcsin(21./4)

x = 31.7 degrees


Related Questions

I’m stuck somebody can help me

Answers

Answer:

26

Step-by-step explanation:

Answer:

26

Step-by-step explanation:

(g•h)(x) = 2(x²+4)

(g•h)(3)=2(3²+4)

=2(9+4)

=2(13)

=26

what's the formula of


(a+b)³ = ?

Answers

Answer:

(a+b)³=a³+3a²b+3ab²+b³

Answer:

Step-by-step explanation:

Hello!

(a+b)(a+b)(a+b)

(a+b)(a+b) = a²+2ab + b²

(a²+2ab + b²) (a+b)=

a³ + a²b +  2a²b + 2ab² + ab² + b³ =

a³ + b³ +  2a²b + 2ab² + ab²  + a²b

Find the missing side lengths. Leave your answers as radicals in the simplest form.

Answers

Answer:

x = 28, y = 14

Step-by-step explanation:

Use the property of 30°-60°-90° right triangle.

The ratio of sides:

a : b : c = 1 : √3 : 2

Compare with the given:

y : 14√3 : x  = 1 : √3 : 2y = 14√3 / √3 = 14x = 2*14 = 28

Apply the property of 30-90-60 angle

a:b:c=1:√3:2

So

y=14√3/√3=14x=2(y)=2(14)=28

Solve BCD. Round the answers to the nearest hundredth, if necessary.

Answers

Answer:

B

Step-by-step explanation:

here we use trigonometric ratio involving soh,cah,toa

find the value of a and b if [tex]5+√3/7+2√3=a-b√3[/tex]

Answers

Answer:

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Step-by-step explanation:

There are mistakes in the statement, correct form is presented below:

[tex]5+\frac{\sqrt{3}}{7} + 2\sqrt{3} = a - b\cdot \sqrt{3}[/tex].

By direct comparison we have the following system of equations:

[tex]a = 5[/tex] (1)

[tex]\frac{\sqrt{3}}{7}+2\sqrt{3} = -b\cdot \sqrt{3}[/tex] (2)

In (2) we solve for [tex]b[/tex]:

[tex]\left(\frac{1}{7}+2 \right)\cdot \sqrt{3} = -b\cdot \sqrt{3}[/tex]

[tex]b = -\frac{15}{7}[/tex]

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

I need help with this question ​

Answers

Answer:

m

Step-by-step explanation:

If the areas of two similar triangles are equal, prove that they are congruent

Answers

Refer the attached image for the answer

HOPE SO IT HELPS YOU

Correct answer gets brainliest and 5 stars

Answers

Answer:

Does the answer help you?

Perimeter of a semi circle with a diameter of 3.5m​

Answers

Answer:

10.99

Step-by-step explanation:

c=[tex]\pi[/tex]d

c=3.14 x 3.5cm

c=10.99

I really really need help with this

Answers

Answer:

c) 21

Step-by-step explanation:

[tex] \sqrt{169} + \sqrt{64} [/tex]

13+8

answer is 21

Sayad bought a watch and sold to Dakshes at 10% profit. Sayad again sold it to Sahayata for rs 6,050 at 10% profit. i)Find the cost price of Dakshes. ii) Find the cost price of Sayad.​

Answers

Answer:

The cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Step-by-step explanation:

Given that Sayad bought a watch and sold to Dakshes at 10% profit, and Dakshes again sold it to Sahayata for $ 6,050 at 10% profit, to find the cost price of Dakshes and the cost price of Sayad the following calculations must be performed:

6,050 / 1.1 = X

5,500 = X

5,500 / 1.1 = X

5,000 = X

Therefore, the cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

True or false? Any two points are collinear and coplanar

Answers

Answer:

True

Step-by-step explanation:

Any two points are always collinear because you can always connect them with a straight line. Three or more points can be collinear, but they don't have to be. ... Coplanar points: A group of points that lie in the same plane are coplanar. Any two or three points are always coplanar.

If a is an odd integer and b is an even integer, which of the following makes an odd integer?
A.) 3b
B.) a+3
C.) 2(a+b)
D.) a+2b
Explain your answer

Answers

9514 1404 393

Answer:

  D.) a+2b

Step-by-step explanation:

The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...

  A) 3(0) = 0 . . . even

  B) 1 +3 = 4 . . . even

  C) 2(1+0) = 2 . . . even

  D) 1 +2(0) = 1 . . . odd

_____

Additional comment

These rules apply to even/odd:

odd × odd = oddodd × even = eveneven × even = evenodd + odd = evenodd + even = oddeven + even = even

Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.

Urgent ! Help me please

Answers

Answer:

B

Step-by-step explanation:

x -> x and y -> y+5

-1 -> - 1 and - 3 -> 2, so b is the correct answer.

PLEASE HELP I DONT UNDERSTAND

Write the equation of the line in slope-intercept form that is perpendicular to y = x - 2 and that
passes through the point (6,-5). Show all of your work.

Answers

Answer:

y = -x + 1

Step-by-step explanation:

eqn of line: y=mx+c

perpendicular, m1 x m2 = -1

m × 1 = -1

m = -1

y=-x+c

sub x=-5, y=6

6 = -(-5) +c

6 = 5 + c

c = 1

y = -x + 1

in the first quarter austin played for 4 minutes and 30 seconds. wyatt played for 310 seconds who had more playing time

Answers

Answer:

wyatt

Step-by-step explanation:

4:30 mins is 270 seconds

What are the coordinates of the vertices of the image?
A) A'(9,8), B'(-3,-4), C'(1, 2), and D'(1,-2)
B) A'(3,4), B'(3,-4), C'(-5, 2), and D'(1, 2)
C) A'(3,8), B'(-3, 4), C'(1,-2), and D'(-1,2)
D) A'(-3, 4), B'(3,4), C'(5,-2), and D'(-1,-2)​

Answers

The answer is D good luck

Answer:

D

Step-by-step explanation:

I took the quiz

Jia baked two kinds of muffins. She baked 27 blueberry muffins. The number of cranberry muffins she baked is represented by the equation shown.

27 ÷ 3 = 9
Which statement accurately compares the number of blueberry muffins and the number of cranberry muffins?

Jia baked 3 times as many blueberry muffins as cranberry muffins.
Jia baked 9 times as many blueberry muffins as cranberry muffins.
Jia baked 3 times as many cranberry muffins as blueberry muffins.
Jia baked 9 times as many cranberry muffins as blueberry muffins.

Answers

Answer:

she baked 3 times as many cranberry than blueberry muffins

Step-by-step explanation:

i think that because 9×3=27

the amount of the cranberry muffins are 9

BRAINLEST IF CORRECT!!!!!!!

Answers

Answer:[tex]\huge \boxed{x=180-26-90=64}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

You have the angels 180, 26, 90(right angle) and x. So when you add them all up you should get 360 because there aren’t two straight lines. Only line makes a 180 angle. So...

180 + 26 + 90 + x = 360

296 + x = 360

x = 360 - 296

x = 64

URGENT+Brainliest. Convert r=2sin(2theta) into rectangular cords.

Answers

Answer:

try 14n

Step-by-step explanation:

Answer:

[tex]r \: = 2sin2 \theta \\ = > r = 2.2sin\theta.cos\theta \\ = > r = 4sin\theta.cos\theta \: \\ \\ \sf \: we \: know \: that \: \\ x = r \: cos\theta \: \therefore \: cos\theta = \frac{x}{r} \\ \\ y = r \: sin\theta \: \therefore \: sin\theta = \frac{y}{r} \\ \\ \sf \: now \\ \\ r = 4 \times \frac{y}{r} \times \frac{x}{r} \\ = > {r}^{3 } = 4xy \\ \\ \sf \: again \: \: r = \sqrt{ {x}^{2} + {y}^{2} } \\ \\ = > {( \sqrt{ {x}^{2} + {y}^{2} } })^{3} = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{ \frac{3}{2} } = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{3} = 16 {x}^{2} {y}^{2} [/tex]

Please mark me as Brainliest

Analyze the diagram below and complete the instructions that follow.
10
6
B.
'C С
8
Find sin ZA
A 3
5
B. 4
C 1

Answers

Answer:

B. 4/5

Step-by-step explanation:

Sin = Opposite/Hypotenuse

Sin∠A = 8/10 = 4/5

round 1.89 to one decimal place

Answers

Answer:

1.9

Step-by-step explanation:

You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9

PLEASE PLEASE PLEASE PLEASE HELPME I *REALLY* NEED HELP!!!
(ALL LINKS WILL BE REPORTED)
Which of the following pairs of triangles can be proven similar through SSS similarity? PHOTO ATTACHED :))

Answers

Answer:

A

Step-by-step explanation:

since there are 3 corresponding sides shown, the SSS similarity theorem can be utilized.

b - 8 = 9
---------------

Answers

Answer:

b-8=9

b=9+8

b=17

Step-by-step explanation:

hope it will help you mark me as a brilliant.

Answer:

b=17

Step-by-step explanation:

b-8=9

first isolate the variable by adding 8 to both sides

this gives us

b=17

9.
A rocket is launched from the top of a 76-foot cliff with an initial velocity of 135 ft/s. a. Substitute the values into the vertical motion formula h = –16t2 + vt + c. Let h = 0. b. Use the quadratic formula to find out how long the rocket will take to hit the ground after it is launched. Round to the nearest tenth of a second.


A. 0 = –16t2 + 135t + 76; 0.5 s

B. 0 = –16t2 + 76t + 135; 9 s

C. 0 = –16t2 + 76t + 135; 0.5 s

D. 0 = –16t2 + 135t + 76; 9 s

Answers

Answer:

The answer is 2.)

Step-by-step explanation:

Given initial velocity=135 ft/s

& cliff=76 foot

Given quadratic equation

⇒                      (let h=0 it is given)

⇒  

⇒  

⇒    t=8.96≈9 s (the other root is negative)

Hence, rocket will take 9 s to hit the ground after launched.

Answer:  Choice D

0 = 16t^2 + 135t + 76;  9 s

==============================================

Explanation:

The equation we start with is

[tex]h = -16t^2 + vt + c\\\\[/tex]

where v is the starting or initial velocity, and c is the starting height.

We're told that v = 135 and c = 76

We let h = 0 to indicate when the object hits the ground, aka the height is 0 ft.

That means the equation updates to [tex]0 = -16t^2 + 135t + 76\\\\[/tex]

Based on that alone, the answer is between A or D

-------------------

We'll use the quadratic formula to solve for t

We have

a = -16b = 135c = 76

So,

[tex]t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\t = \frac{-135 \pm \sqrt{135^2 - 4(-16)(76)}}{2(-16)}\\\\t = \frac{-135 \pm \sqrt{23,089}}{-32}\\\\t \approx \frac{-135 \pm 151.9506}{-32}\\\\t \approx \frac{-135 + 151.9506}{-32} \ \text{ or } \ t \approx \frac{-135 - 151.9506}{-32}\\\\t \approx \frac{16.9506}{-32} \ \text{ or } \ t \approx \frac{-286.9506}{-32}\\\\t \approx -0.52971 \ \text{ or } \ t \approx 8.96721\\\\[/tex]

We ignore the negative t value because a negative time duration makes no sense.

The only practical solution here is roughly 8.96721 which rounds to 9.0 or simply 9 when we round to the nearest tenth (one decimal place).

In short, the object will hit the ground at the 9 second mark roughly. Or put another way: the object is in the air for about 9 seconds.

From this, we can see that the final answer is choice D.

Keep in mind that we aren't accounting for any wind resistance. Considering this variable greatly complicates the problem and requires much higher level mathematics. So we just assume that there is no wind at this moment.

f(x) = x+3
g(x) = 2x^2-4
find (f times g) (x)

Answers

Step-by-step explanation:

(f*g) (x)=f(x) * g(x)

=(x+3)(2x^2-4)

=2x^3-4x+6x^2-12

pls halp ////////////////

Answers

Answer:

9x^2 + 2x - 5

Step-by-step explanation:

7x^2 - 5x + 3

2x^2 + 7x - 8

__________

9x^2 + 2x - 5

Option B is the correct answer.

Rachel covered a single lap of 1,210 m in 55 s. Calculate her speed in m/s

Answers

Answer:

22 m/s

Step-by-step explanation:

Take the distance and divide by the time

1210 m/55s

22 m/s

Answer:

22m/s

Step-by-step explanation:

[tex]speed = \frac{distantce}{time} \\ = \frac{1210m}{55s} \\ = 22m {s}^{ - 1} [/tex]

F(x)=2x+1 and g(x)=x2-7, find (f+g)(x)

Answers

Answer:

x^2 +2x -6

Step-by-step explanation:

f(x)=2x+1

g(x)=x^2-7,

(f+g)(x) = 2x+1 + x^2 -7

Combine like terms

           = x^2 +2x -6

f (x) = 2x + 1

g (x) = x² - 7

(f+g) (x) = 2x+1 + x² - 7

Adding like terms

⇛ x² + 2x - 6

Which rules define the function graphed below? (15 points cuz I'm stumped)

y=2x+3; y=-1/3x+3
y=2x; y=-1/3x
y=3x+2; y=3x-1
y=-3x+3; y=x+3

Answers

Answer:  Choice A

y=2x+3; y=-1/3x+3

==================================================

Explanation:

The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that [tex]x \le 0[/tex] but I'll set that aside for the other portion).

The right portion is the line y = -1/3x + 3 and it's only graphed when [tex]x \ge 0[/tex]

So we could have this piecewise function

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}[/tex]

Or we could easily swap the "or equal to" portion to move to the first part instead like this

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}[/tex]

Either way, we're involving the equations mentioned in choice A

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