sketch the graph of the equation: y=x, y=-x,

Answer:

C.

84

Step-by-step explanation:

This question is solved using proportions.

From the sample:

11 + 3 = 14 out of 13 + 11 + 3 = 27 would rate the test something other than easy.

Out of 162:

Applying the rule of three:

14 - 27

x - 162

Applying cross multiplication:

[tex]27x = 14*162[/tex]

[tex]x = \frac{14*162}{27}[/tex]

[tex]x = 84[/tex]

Thus the correct answer is given by option C.

Answer:

I hope this helps

Step-by-step explanation:

Answer:

Step-by-step explanation:

It's 5/7

You get that by having a calculator that does that. If you don't then the way to do it is multiply the numerator and denominator by 1.25

4 * 1.25 = 5

5.6 * 1.25 = 7

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Answer:

  E.  384 cu ft

Step-by-step explanation:

The sum of length and width is half the perimeter, so the width is ...

  (40/2) -12 = 8 . . . feet

The depth is half that, so is 8/2 = 4 feet.

The volume is ...

  V = LWH = (12 ft)(8 ft)(4 ft) = 384 ft³

Answer:

Sorry I dont really understand wish I could help:(

Step-by-step explanation:

Answer:

[tex]\sqrt{10}[/tex]

[tex]\sqrt{5 } ^{2} + \sqrt{5 } ^{2} = x^{2}[/tex]

[tex]x^{2} =10[/tex]

Step-by-step explanation:

Answer:

B. Yes. By SSS~

Step-by-step explanation:

From the diagram given, we have the corresponding sides of both triangles as follows:

RQ/KL = 24/20 = 6/5

QP/LM = 18/15 = 6/5

RP/KM = 12/10 = 6/5

From the above, we can see that the ratio of the corresponding side lengths of both triangles are equal. This means that all three sides of one triangle are proportional to all corresponding sides of the other triangle.

The SSS similarity theorem states that if all sides of one triangle are proportional to all corresponding sides of another, then both triangles are similar to each other.

Therefore, ∆KLM ~ ∆RQP by SSS similarity.

Answer:

B

Step-by-step explanation:

Reason...sum of angles in a triangle is equal to 180⁰

R+V+T=180⁰

60⁰+90⁰+x⁰=180⁰

150⁰+x⁰=180⁰

x⁰=180⁰-150⁰

:. x⁰=30⁰

===================================================

Explanation:

Ignore lines VS and SU. They're unnecessary clutter.

Triangle VRT is a right triangle with angles T = x, R = 60, V = 90

For any triangle, the angles must add to 180

T+R+V = 180

x+60+90 = 180

x+150 = 180

x = 180-150

x = 30

Or you could note that R+T = 90 Solves to T = 30 since triangle VRT is a right triangle. The rule with any right triangle is that the acute angles are always complementary (aka they add to 90 degrees).

Step 2

−2y = 15 − 2z

should be

−2y = -30 + 4a

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Answer:

  10 and 24

Step-by-step explanation:

We know that some of the Pythagorean triples that appear in math problems are (3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17).

These have (perimeter, area) values of (12, 6), (30, 30), (56, 84), (40, 60).

For some scale factor n, we want (p·n, a·n²) = (60, 120). Of the triangles listed, we see that the (5, 12, 13) triangle scaled by n=2 will satisfy the problem requirements. (30·2, 30·2²) = (60, 120)

The side lengths are 10 and 24.

__

Check

For the side lengths we found, the perimeter is 10+24+26 = 60; the area is 1/2(10)(24) = 120. The hypotenuse is 2×13 = 26 = 24+2.

__

In the attached, one side is x, the other is y. The hypotenuse is (x+2). The square root equation comes from ...

  x² +y² = (x+2)²   ⇒   y² = (x² +4x +4) -x²   ⇒   y² = 4x +4 = 4(x +1)

_____

Additional comment

The graph shows the solution of the various constraints. At least, the combination of constraints will give a quadratic equation in x. They can be combined in a way that gives a cubic equation in x. Either way, we prefer the graphical or "guess and check" approach (above) as being easier to do.

Using the third equation in the attachment to write an expression for y, we have ...

  y = 58 -2x

Substituting that into the second equation gives ...

  (x(58 -2x)/2 = 120

  29x -x² = 120

  x² -29x +120 = 0

  (x -5)(x -24) = 0 . . . . x = 5 or 24.

The root x=5 is a legitimate solution to the pair of equations we chose to solve. The line y=58-2x intersects the hyperbola xy/2 = 120 in two places. However, (x, y) = (5, 48) does not satisfy the hypotenuse requirement that x+2 > y.

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Answer:

  x = 8

Step-by-step explanation:

By AA similarity, ΔABD ~ ΔCDE. So, corresponding sides are proportional.

  AB/BD = CD/DE

  x/12 = 4/6

  x = 12(4/6)

  x = 8

Answer:

too complex:<

Step-by-step explanation:

120cm+120cm=240cm (2 squirrels + 2 air spaces)

90cm+90cm=180cm (2 rats + 2 air spaces)

240cm-180cm=(2 squirrels + 2 air spaces) - (2 rats + 2 air spaces)

                       =2 squirrels + 2 air spaces - 2 rats - 2 air spaces

                       =2 squirrels - 2 rats

                       =60cm

1 squirrel - 1 rat = 60cm divided by 2

                         = 30cm

120cm + 90cm = squirrel + air space + rat + air space

                        = 210cm

I've no idea!! This qn is too challenging!!

But i hope the above workings might help you in a way or another:>

The table is 105cm tall.

Two or more expressions with an Equal sign is called as Equation.

Let the table is x

Squirrel is y

Rat is z

From 1st diagram

x+y-z=120...(1)

From 2nd diagram

x+z-y=90...(2)

Add 1 and 2

x+y-z+x+z-y=120+90

2x=210

Divide both sides by 2

x=105

Hence, the table is 105cm tall.

To learn more on Equation:

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[tex]\\ \sf\longmapsto Area=Length\times Breadth[/tex]

[tex]\\ \sf\longmapsto Area=48(36)[/tex]

[tex]\\ \sf\longmapsto Area=1728in^2[/tex]

[tex]\\ \sf\longmapsto Area=144ft^2[/tex]

[tex]\\ \sf\longmapsto Area=48yard^2[/tex]

Answer:

gang nem

Step-by-step explanation:

Answer:

Hello,

Step-by-step explanation:

AB=DC=b, AD=BC=a

p=BD, q=AC

angle ABC=x

[tex]AB^4+AD^4+AB^2*AD^2=AC^2*BD^2\\\\b^4+a^4+b^2a^2=(a^2+b^2+2abcos(X))(a^2+b^2-2abcos(X)\\\\(a^2+b^2+2a^2b^2)-a^2b^2=((a^2+b^2)^2-4a^2b^2*cos^2(X))\\\\\\4a^2b^2cos^2(X)=a^2b^2\\\\\\cos^2(X)=\dfrac{1}{4} \\\\(cos(X)-\dfrac{1}{2} )(cos(X)+\dfrac{1}{2} )=0\\cos(x)=\frac{1}{2} \ or\ cos(X)=\dfrac{-1}{2} \\\\\\X=60^o =\dfrac{\pi}{3} rad \ or \ X=120^o=\dfrac{4\pi}{3} rad\\\\\\\\Product=\dfrac{\pi}{3}*\dfrac{4\pi}{3} =\boxed{\dfrac{4\pi^2}{9}}\\[/tex]

The answer is 670.408, because 6x100=600, 7x10=70, 4x1/10 as a decimal is 0.4, 8x1/1,000 as a decimal is 0.008. Then, you add all of those [tex]600+70+0.4+0.008=670.408[/tex].

Answer:

a

Step-by-step explanation:

Lateral faces that are parallel is not a property of a regular pyramid. The correct option is A.

Any pyramid whose base is a regular polygon and whose lateral edges are all of the same lengths is said to be regular.

The properties of a regular pyramid are:-

Lateral faces that are congruent isosceles triangles. Lateral edges that are congruent and the volume of the pyramid is equal to one-third the product of the area of its base and its altitude.

Hence, option A is correct.

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Answer:

  f, h, g

Step-by-step explanation:

You can look at the slope of the tangent lines to the graphs at any given x-value. At x=5, we see that g(x) is the flattest curve and f(x) is the steepest.

In order from greatest to least growth rate, the functions are ...

  f(x), h(x), g(x)

Answer:

d part is correct because in associative property the brackets and the numbers CAN be shifted

Answer: 33% is moisture content

Step-by-step explanation:

120kg - 80kg = 40kg

40 of 120 is %

Work:

40/120 = 0.33

0.33x100

= 33%

Answer:

a. 24.12 ft³/hr b. 0.0768 ft/hr

Step-by-step explanation:

a. Find the rate at which the volume of water in the pool is increasing at time t=6 hours.

The net rate of change of volume of the cylinder dV/dt = volume flow rate in - volume flow rate out

Since volume flow rate in = P(t) and volume flow rate out = R(t),

dV/dt = P(t) - R(t)

[tex]\frac{dV}{dt} = P(t) - 18e^{0.04t}[/tex]

We need to find the rate of change of volume when t = 6.

From the table when t = 6, P(6) = 47 ft³/hr

Also, substituting t = 6 into R(t), we have R(6)

[tex]\frac{dV}{dt} = P(t) - 18e^{0.04t}[/tex]

[tex]\frac{dV}{dt} = 47 - 18e^{0.04X6}\\\frac{dV}{dt} = 47 - 18e^{0.24}\\\frac{dV}{dt} = 47 - 18 X 1.27125\\\frac{dV}{dt} = 47 - 22.882\\\frac{dV}{dt} = 24.118 ft^{3}/hr[/tex]

dV/dt ≅ 24.12 ft³/hr

So, the rate at which the water level in the pool is increasing at t = 6 hours is 24.12 ft³/hr

b. How fast is the water level in the pool rising at t=6 hours?

Since the a rate at which the water level is rising is dV/dt and the volume of the cylinder is V = πr²h where r = radius of cylinder = 10 ft and h = height of cylinder = 5 feet

dV/dt = d(πr²h)/dt = πr²dh/dt since the radius is constant and dh/dt is the rate at which the water level is rising.

So, dV/dt = πr²dh/dt

dh/dt = dV/dt ÷ πr²

Since dV/dt = 24.12 ft³/hr and r = 10 ft,

Substituting the values of the variables into the equation, we have that

dh/dt = dV/dt ÷ πr²

dh/dt = 24.12 ft³/hr ÷ π(10 ft)²

dh/dt = 24.12 ft³/hr ÷ 100π ft²

dh/dt = 0.2412 ft³/hr ÷ π ft²

dh/dt = 0.2412 ft³/hr

dh/dt = 0.0768 ft/hr

So, the arate at which the water level is rising at t = 6 hours is 0.0768 ft/hr

Answer:

a1=6 a2=15 a3=33 a4=69 a5=141

Step-by-step explanation:

an=2an-1+3

We should attempt n=2 to find the second term

a2=2a1+3= 2*6+3=15

n=3 to find the third term

a3=2a2+3= 2*15+3=33

n=4 to find the fourth term

a4=2a3+3=2*33+3=69

n=5 to find the fifth term

a5= 2a4+3=2*69+3= 141

Area of parallelogram = b × h

Base = x + 7

Height = x + 3

ATQ

Area = (x + 7) ( x + 3)

x² + 3x + 7x + 21

x² + 10x + 21

Answered by Gauthmath must click thanks and mark brainliest

Answer:

Step-by-step explanation:

Answer:

It can be the point E or the point D

Answer:

Answer:f(2)=-3(2)^2+2*2+11

Answer:f(2)=-3(2)^2+2*2+11 =-3*4+4+11

Answer:f(2)=-3(2)^2+2*2+11 =-3*4+4+11 =-12+4+11

Answer:f(2)=-3(2)^2+2*2+11 =-3*4+4+11 =-12+4+11 =3

hence, f(2)=3

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Answer:

  a. 5/10

  b. 2.5/10

  c. 1/10

  d. 4/10

Step-by-step explanation:

To find the numerator, multiply each fraction by 10.

  a. (1/2)(10) = 5, so 1/2 = 5/10

  b. (1/4)(10) = 2.5, so 1/4 = (2.5)/10 or (5/2)/10

  c. (3/30)(10) = 1, so 3/30 = 1/10

  d. (12/30)(10) = 4, so 12/30 = 4/10

Answer:

y"= 2 wich is positive

Step-by-step explanation:

Step-by-step explanation:

Our equation is: y=(x-3)²

x should be replaced by x-4

y=(x-3)²

y=[(x-4)-3]²

y=(x-4-3)²

y=(x-7)²

The graph is still a parabola but with a different vertex

The vertex here is :

y= (x-7)²

y= x²-14x-49

y'= 2x-14

solve y'=0

2x-14=0

2x=14

x=7

You can easily find it without derivating by dividing -14 by -2

since: x²-14x-49

a=1 b= -14  c=-49

-b/2a = 14/2 = 7

the image of 7 is:

y=(7-7)² = 0

so the coordinates of the new vertex are (7,0) and it's a maximum

since y">0

y'= 2x-14

y"= 2 wich is positive

Answer:

sadia is 32

Step-by-step explanation:

sadia : father : total

3          6          9

Divide 96 by 9

96/9 = 32/3

Multiply each by 32/3

sadia :     father : total

3*32/3    6*32/3  9*32/3

32                 64          96

There are 50 different possible debating teams that could be selected as obtained using COMBINATION.

Since there are EQUAL number of juniors and seniors ;

Then we have 5 of each.

Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION

since the team MUST contain 4 SENIORS and 2 JUNIORS

4 Seniors from 5  = 5C4 = 5

2 Juniors from 5 = 5C2 = 10

Hence, (5C4 * 5C2) = 5 * 10 = 50

Hence, there are 50 different possible debating teams that could be selected.

Learn more about COMBINATION :

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Answer:

one property of log is that if the log expressions have the same base (in this case, 2), then you can multiply the added logs.

The answer would then be D