(repost cuz the last didn’t load) please help ‼️

Answer:

Step-by-step explain

the answer is c

Step-by-step explanation:

everything can be found in the picture

The graph of the function f(x)=ax²+bx+c could have the factor of f(x) be ( x + 2) (x - 3)

A relation is a function if it has only One y-value for each x-value.

We can set two functions y₁=x+2 and y₂=x-3

Let us draw these two functions on the graph

We observe that the function  f(x)=ax²+bx+c  intersects y₁ and y₂.

y₁ intersects x axis at (-2, 0)

y₁ intersects y axis at (0, 2)

y₂ intersects x axis at (3, 0)

y₂ intersects y axis at (0, -3)

Hence, the graph of the function f(x)=ax²+bx+c could have the factor of f(x) be ( x + 2) (x - 3)

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Answer: The correct answer is 3x^2-3x

Step-by-step explanation:

I hope this help

Answer:

Answer:

Multiplication properly of equality

Answer:

if two lines in a linear system INTERSECT, they have exactly one point in common.

Answer:

cross each other

Step-by-step explanation:

The point of intersection is the point where both lines will have the same coordinates.

Answer:

a four sided parallelogram where all angles are the same and all sides are the same length

Note: The image of G after the dilation must be G'(5,-5) instead of G'(5,5).

Given:

The vertices of a rectangle are E(4,8), F(2,8), G(2,-2) and H(-4,-2).

The rectangle is dilated with the origin as the center of dilation so that G's is located at (5,-5).

To find:

The algebraic representation that represents this dilation.

Solution:

If a figure is dilated by factor k with origin as the center of dilation, then the dilation is defined as:

[tex](x,y)\to (kx,ky)[/tex]              ...(i)

Let the given rectangle is dilated by factor k with origin as the center of dilation. Then,

[tex]G(2,-2)\to G'(k(2),k(-2))[/tex]

[tex]G(2,-2)\to G'(2k,-2k)[/tex]

The image of G after dilation is G'(5,-5). So,

[tex](2k,-2k)=(5,-5)[/tex]

On comparing both sides, we get

[tex]2k=5[/tex]

[tex]k=\dfrac{5}{2}[/tex]

So, the scale factor is [tex]k=\dfrac{5}{2}[/tex].

Substituting [tex]k=\dfrac{5}{2}[/tex] in (i), we get

[tex](x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)[/tex]

Therefore, the required algebraic representation to represents this dilation is [tex](x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)[/tex].

Answer:

a

Step-by-step explanation:

Answer: y−26=4(x−1)

Step-by-step explanation:

Answer:

y - 2 = -2(x +2)

Step-by-step explanation:

y - 2 = -2(x +2)

Note that the perpendicular bisector to line PQ is constructed and attached accordingly. Here is how to do it.

Note that the first stage is to draw a line PQ. But this has already been done.

Next is to place the compass on P as shown in the image above. If you allow you compass (locked at the same degree) to rotate about point P, you will get a circle. However, that is not the objective.

If you also place your compass on point Q, locked to the same degree as when it was on P, and take a rotation around point Q, you will also get a circle.

At some point, you will notice that both circles intersect at two point, which we can call AB₁ and AB₂.

Now you are done with the compass. Take up your ruler, and place it such that it meet both AB₁ and AB₂ but allowing you space to mark a line connecting both points.

Next, using your live or online pencil tool, draw the line from AB₁ to AB₂. Now you have the Perpendicular bisector which you can call AB₁₂.

Note that a perpendicular bisector is a line or plane that intersects a line segment at its midpoint, forming a right angle and dividing the segment into two equal parts.

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Answer:

D.(4^1/2)^4

hope this helps

have a good day :)

Step-by-step explanation:

Answer

Value of a3³+b³-3ab = -1

Explanation

Given a+b=-1----(1)

On cubeing both sides of equation (1), we get

(a+b)³ = (-1)³

Call 98%

we know the algebraic identity:

(x+y)³ = x³+y³ + 3xy(x+y)

=> a³ + b³ +3ab(a+b)= -1

=> a³ + b³ +3ab(-1)=-1

/* from (1)*/

=> a³ + b³-3ab = -1

Therefore,

Value of a³+b³-3ab = -1

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Answer:

5

Step-by-step explanation:

Multiply -1 on both sides to get rid of the negatives.

4x=20

Divide 4 on both sides

[tex]\frac{4x}{4}[/tex]=[tex]\frac{20}{4}[/tex]

Simplify

x=5

Answer:

5

Step-by-step explanation:

-4x= -20

or, x= -20/-4

or, x=5

Answer:

4/11

Step-by-step explanation:

Let :

x = numerator

x + 7 = denominator [tex]\frac{x}{x + 7}[/tex]

[tex]\frac{x}{x+7} + \frac{1}{4} = \frac{1}{3}[/tex]

[tex]\frac{x + 1}{x + 11} = \frac{1}{3}[/tex]

cross multiply

3(x + 1) = x + 11

3x + 3 = x + 11

combine like terms

3x - x = 11 - 3

2x = 8

x = 4

x + 7 = 4 + 7 = 11

original fraction = 4/11

Answer:

You can do it with your eyes closed

Step-by-step explanation:

Answer:

7/20

Step-by-step explanation:

1 over 10 is .1

3 over 5 is .6

write them out

.1 .2 .3 .4 .5 .6

number between is .35

.35 = 35/100 = 7/20

7/20

Answer:

11

Step-by-step explanation:

Answer:

p=-5

Step-by-step explanation:

5p-3p=-2-8

2p=-10

p=-5

Answer:

x = -1 , - 11,

Step-by-step explanation:

| x | = x

|- x | = x

f(x) = 2 | x + 6 | - 4

x = - 1 , f( - 1) = 2 | - 1 + 6 | - 4 = 2 | 5 | - 4 = 10 - 4 = 6 , True

x = 1 , f( 1 ) = 2 | 1 + 6 | - 4 = 2 | 7 | - 4 = 14 - 4 = 10 , False

x = 11, f( 11 ) = 2 | 11 + 6 | - 4 = 2 | 17 | - 4 = 34 - 4 = 30 , False

x = - 11, f( - 11) = 2 | -11 + 6 | - 4 = 2 | - 5 | - 4 = 10 - 4 = 6 , True

x = 14 , f( 14 ) = 2 | 14 + 6 | - 4 = 2 | 20 | - 4 = 40 - 4 = 36 , False

x = -14 , f( - 14 ) = 2 | - 14 + 6 | - 4 = 2 | - 8 | - 4 = 16 - 4 = 12 , False

x = - 26 , f( - 26) = 2 | -26 + 6 | - 4 = 2 | -20 | - 4 = 40 - 4 = 36 , False

x = 26, f( 26 ) = 2 | 26 + 6 | - 4 = 2 | 32 | - 4 = 64 - 4 = 60 , False

                                                    OR

Given f ( x ) = 6

f( x ) = 2 | x + 6 | - 4

6  = 2 | x + 6 | - 4

6 + 4 = 2 | x + 6| - 4 + 4                 [ adding 4 to both sides ]

10 = 2 | x + 6 | + 0

5 = | x + 6 |                                    [ dividing both sides by 2 ]

[tex]- 5 =\ ( x+ 6) \ = 5\\\\[/tex]                            [tex][ \ | x | = a\ => \ -a \ = x \ = a \ ][/tex]

[tex]- 5 - 6 = \ x + 6 - 6 \ = \ 5 - 6\\[/tex]            [tex][ \ subtracting \ by \ 6 \ ][/tex]

[tex]-11 = \ x \ = - 1[/tex]

Answer:

Step-by-step explanation:

(1,2) and (2,1) are not equal ordered pairs becasue their corresponding elements are not equal.

Two Ordered Pairs are said to be equal if the corresponding first components are equal alongside the corresponding second components are equal.

for example:

(3,1) and (3,1)

here corresponding element of 3 is 3 and of 1 is 1 .so they are called equal ordered pairs.

Answer:

Step-by-step explanation:

Let's FOIL this out and get it into standard form. That gives us:

[tex]h(t)=-4.9t^2+490[/tex] For #1, then:

The height of something when it is on the ground is 0; that means that the h(t) is 0. This allows us to factor the quadratic and solve for t:

[tex]-4.9t^2=-490[/tex] and divide both sides by 4.9 to get

[tex]t^2=100[/tex] so

t = 10. Notice that one of the factors for that quadratic is 10 - t. That factor represents the time it takes to hit the ground. So you might ask why, then, we FOILed this out in the first place if the answer was ight in front of our noses. The reason is becase of #2 that is asking us what the initial height of the object was. That is found in the standard form...in the constant in particular. The initial height is 490 m. That's how you know (because the constant represents the height from which an object is dropped in either free fall, which this is, or in parabolic motion).

Answer:

StartFraction one-fourth EndFraction left-parenthesis x right-parenthesis equals x left-parenthesis 30 plus 60 right-parenthesis.(x) = x(30 + 60)

Step-by-step explanation:

The equation that can be used is:

(1/4)*(30 min + 60 min + x) = x

So the correct option is the first one.

We know that Hiroshi spends:

The total time is:

30 min + 60 min + x

And we know that one-fourth of the total time that he studies is spent on math, then we can write:

(1/4)*(30 min + 60 min + x) = x

This is the equation we need to solve.

Solving it gives:

30 min + 60 min + x = 4x

90 min = 3x

(90 min)/3 = x = 30 min.

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