(Ramanujan's Taxi) Srinivasa Ramanujan indian mathematician who became famous for his intuition for numbers. When the English mathemematician G.H. Hardy came ot visit him in the hospital one day, Hardy remarked that the number if his taxi was 1729, a rather dull number. To which Ramanujan replied, "No, Hardy! It is a very interesting number. It is the smallest number expressible as the sum of two cubes in two different ways." Verify this claim by writing a program Ramanujan.java that takes a command-line argument N and prints out all integers less than or equal to N that can be expressed as the sum of two cubes in two different ways. In other words, find distinct positive integers a, b, c, and d such that а3 + b3 = c3 - d3. Hint: Use four nested for loops, with these bounds on the loop variables: 0 < a < 3√N, a < b < 3√N - a3, a < c < 3√N and c < d < 3√N - C3; do not explicitly compute cube roots, and instead use x . x *x < y in place of х < Math.cbrt (y).
$ javac Ramanujan.java
$ java Ramanujan 40000
1729 = 1"3 + 12^3 = 9^3 + 10"3
4104 = 2^3 + 16^3 = 9^3 + 15^3
13832 = 2^3 + 24^3 = 18^3 + 20^3
39312 = 2^3 + 34^3 = 15^3 + 33^3
32832 = 4^3 + 32^3 = 18^3 + 30^3
20683 = 10^3 + 27^3 = 19^3 + 24^3

Answer:

d. you can determine the average age of emoji users based on emoji use.

Explanation:

The infographic displays 100 most common emoji used in text messaging. This information can be used to determine percentages of text message which contains particular emoji. This details can not determine the age of emoji user based in emoji use.

Answer:

Are you talking about the bruce willis is superman basically? Because if so i don't think so because that is a future event that hasn't happened yet also that film sucks.

Explanation:

Answer:

The pseudo-code describes steps in an algorithm or another system in plain language. Pseudo-Code is often designed for human reading rather than machine reading with structural conventions of a normal language of programming.

Natural languages consist of phrases, usually declarative phrases, with a sequence of information.

Explanation:

For learning HTML we recommend a simple text editor like Notepad (PC) or TextEdit (Mac).

mark me brainliestt :))

Answer:

If you want to use HTML editor in windows, you can use notepad. And if you want to use HTML editor on your phone than you need to install any editor on your phone.

Explanation:

If you want to use another app than notepad in pc, laptop, mac, OS or Linux, you can download a editor known as Visual Studio Code. If you want to do another language you can also do it in it. You can do all programming languages in it.

In a relational database, the three basic operations used to develop useful sets of data are:

[tex]\sf\purple{a.\: Select, \:project,\: and\: join. }[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

The basic operations used to develop useful sets of data in relational database are Select, Project and Join.

Hence, the basic operations are select, project, and join.

Learn more : https://brainly.com/question/14760328

Answer:

Test if L(M1-2) is empty.

Construct FA M2-1 from M1 and M2 which recognizes the language L(>M2) - L(>M1).

COMMENT: note we use the algorithm that is instrumental in proving that regular languages are closed with respect to the set difference operator.

Test if L(M2-1) is empty.

Answer yes if and only if both answers were yes.

Explanation:

An algorithm must be guaranteed to halt after a finite number of steps.

Each step of the algorithm must be well specified (deterministic rather than non-deterministic).

Three basic problems:

Given an FA M and an input x, does M accept x?

Is x in L(M)

Given an FA M, is there a string that it accepts?

Is L(M) the empty set?

Given an FA M, is L(M) finite?

Algorithm for determining if M accepts x.

Simply execute M on x.

Output yes if we end up at an accepting state.

This algorithm clearly halts after a finite number of steps, and it is well specified.

This algorithm is also clearly correct.

Testing if L(M) is empty.

Incorrect "Algorithm"

Simulate M on all strings x.

Output yes if and only if all strings are rejected.

The "algorithm" is well specified, and it is also clearly correct.

However, this is not an algorithm because there are an infinite number of strings to simulate M on, and thus it is not guaranteed to halt in a finite amount of time.

COMMENT: Note we use the algorithm for the first problem as a subroutine; you must think in this fashion to solve the problems we will ask.

Correct Algorithm

Simulate M on all strings of length between 0 and n-1 where M has n states.

Output no if and only if all strings are rejected.

Otherwise output yes.

This algorithm clearly halts after a finite number of steps, and it is well specified.

The correctness of the algorithm follows from the fact that if M accepts any strings, it must accept one of length at most n-1.

Suppose this is not true; that is, L(M) is not empty but the shortest string accepted by M has a length of at least n.

Let x be the shortest string accepted by M where |x| > n-1.

Using the Pumping Lemma, we know that there must be a "loop" in x which can be pumped 0 times to create a shorter string in L.

This is a contradiction and the result follows.

COMMENT: There are more efficient algorithms, but we won't get into that.

Testing if L(M) is finite

Incorrect "Algorithm"

Simulate M on all strings x.

Output yes if and only if there are a finite number of yes answers.

This "algorithm" is well specified and correct.

However, this is not an algorithm because there are an infinite number of strings to simulate M on, and thus it is not guaranteed to halt in a finite amount of time.

COMMENT: Note we again use the algorithm for the first problem as a subroutine.

Correct Algorithm

Simulate M on all strings of length between n and 2n-1 where M has n states.

Output yes if and only if no string is accepted.

Otherwise output no.

This algorithm clearly halts after a finite number of steps, and it is well specified.

The correctness of the algorithm follows from the fact that if M accepts an infinite number of strings, it must accept one of length between n and 2n-1.

This builds on the idea that if M accepts an infinite number of strings, there must be a "loop" that can be pumped.

This loop must have length at most n.

When we pump it 0 times, we have a string of length less than n.

When we pump it once, we increase the length of the string by at most n so we cannot exceed 2n-1. The problem is we might not exceed n-1 yet.

The key is we can keep pumping it and at some point, its length must exceed n-1, and in the step it does, it cannot jump past 2n-1 since the size of the loop is at most n.

 This proof is not totally correct, but it captures the key idea.

COMMENT: There again are more efficient algorithms, but we won't get into that.

   Other problems we can solve using these basic algorithms (and other algorithms we've seen earlier this chapter) as subroutines.

       COMMENT: many of these algorithms depend on your understanding of basic set operations such as set complement, set difference, set union, etc.

Given a regular expression r, is Lr finite?

Convert r to an equivalent FA M.

COMMENT: note we use the two algorithms for converting a regular expression to an NFA and then an NFA to an FA.

Test if L(M) is finite.

Output the answer to the above test.

Given two FAs M1 and M2, is L(M1) = L(M2)?

Construct FA M1-2 from M1 and M2 which recognizes the language L(>M1) - L(>M2).

COMMENT: note we use the algorithm that is instrumental in proving that regular languages are closed with respect to the set difference operator.

Test if L(M1-2) is empty.

Construct FA M2-1 from M1 and M2 which recognizes the language L(>M2) - L(>M1).

COMMENT: note we use the algorithm that is instrumental in proving that regular languages are closed with respect to the set difference operator.

Test if L(M2-1) is empty.

Answer yes if and only if both answers were yes.

Answer:

Program.java  

import java.util.Scanner;  

public class Program {  

   public static boolean isPalindrome(String str){

       int start = 0, end = str.length()-1;

       while (start < end){

           if(str.charAt(start) != str.charAt(end)){

               return false;

           }

           start++;

           end--;

       }

       return true;

   }  

   public static int countPalindromePairs(String[] inarr){

       int count = 0;

       for(int i=0; i<inarr.length; i++){

           for(int j=i+1; j<inarr.length; j++){

               StringBuilder sb = new StringBuilder();

               sb.append(inarr[i]).append(inarr[j]);

               if(isPalindrome(sb.toString())){

                   count++;

               }

           }

       }

       return count == 0 ? -1 : count;

   }

   public static void main(String[] args) {

       Scanner sc = new Scanner(System.in);

       String line = sc.next();

       String[] inarr = line.split(",");

       int count = countPalindromePairs(inarr);

       System.out.println("RESULT: "+count);

   }

}

Explanation:

OUTPUT:

Answer and Explanation:

Deadlock occurs when two operating systems on the same computer are hindering each other's execution, getting blocked, waiting for each one to run first. This can happen when a preemption has not occurred, when a mutual exclusion has occurred, or when one of the systems causes the other to not execute.

File manager is software that allows a computer user to create directories and organize files inside and outside of them.

Process is the term used to determine the functioning of computer software. When a software is started, it uses its own programming code to perform a specific activity.

Multiprogramming is the term used for the moment when an operating system allows the user to run more than one software at the same time. For this to happen, the computer needs to have a high processing capacity, to handle the effort of running several software simultaneously.

Software Classification is the process that determines the composition and different aspects that make up a software. In this way, it is possible to understand the usefulness and programming of this software.

Virtual memory is the use of secondary memory for caching. This allows the user to share files more securely and quickly, in addition to alleviating the problems that limited memory presents.

Answer:

d. call WriteInt

Explanation:

Required

Instruction to write to decimal integer

Of the 4 instructions, the call WriteInt instruction is used write to a decimal integer.

This is so, because the WriteInt instruction writes a signed decimal integer to standard output.

This implies that the output will have a sign (positive or negative) and the output will start from a digit other than 0 (i.e. no leading zero)

Answer:

The program in C++ is as follows:

#include <iostream>

#include <vector>

using namespace std;

int main(){

vector<int> nums;

int num;

cin>>num;

while(num != -1){

 nums.push_back(num);

 cin>>num; }  

for (auto i = nums.begin(); i != nums.end(); ++i){

    cout << *i <<endl; }

return 0;

}

Explanation:

This declares the vector

vector<int> nums;

This declares an integer variable for each input

int num;

This gets the first input

cin>>num;

This loop is repeated until user enters -1

while(num != -1){

Saves user input into the vector

 nums.push_back(num);

Get another input from the user

 cin>>num; }

The following iteration print the vector elements

for (auto i = nums.begin(); i != nums.end(); ++i){

    cout << *i <<endl; }

Answer:

false

Explanation:

function should contain more codes

Solution :

App.java:  

import Controller.Controller;

import Model.Model;

import View.View;  

public class App

{  

public static void main(String[] args) // Main method

{  

Model model = new Model(); // Creates model object.    

View view = new View(); // Creates view object.    

Controller controller = new Controller(view, model); // Creates controller object that accepts view and model objects.    

}

}  

[tex]\text{Controller.java:}[/tex]  

package Controller;  

[tex]\text{impor}t \text{ Model.Model;}[/tex]

import View.View;  

[tex]\text{public class Controller}[/tex]

{

Model model; // Model object    

View view; // View object

public Controller(View v, Model m) // Method that imports both model and view classes as objects.

{

model = m;    

view = v;  

//view.basicDisplay(model.getData()); // basicDisplay method from View class prints FootballPlayer objects as Strings from Model class.  

view.basicDisplay(model.getMembers().get(1).getAttributeName(3));    

view.basicDisplay(model.getMembers().get(1).getAttribute(3));    

view.basicDisplay(model.getMembers().get(1).getAttributeNames());    

view.basicDisplay(model.getMembers().get(1).getAttributes());    

view.basicDisplay("size of names=" + model.getMembers().get(1).getAttributeNames().size());    

view.basicDisplay("size of attributes=" + model.getMembers().get(1).getAttributes().size());

}  

}  

FootballPlayer.java:

package Model;  

import java.util.ArrayList;  

public class FootballPlayer extends Person implements TableMember { // Used "extends" keyword to inherit attributes from superclass Person, while using "implements" to implement methods from TableMember interface.    

private int number; // Creating private attribute for int number.    

private String position; // Creating private attribute for String position.  

public FootballPlayer(String name, int feet, int inches, int weight, String hometown, String highSchool, int number, String position) // Full parameter constructor for FootballPlayer object (using "super" keyword to incorporate attributes from superclass).

{

super(name, feet, inches, weight, hometown, highSchool); // Used super keyword to include attributes from superclass.  

this.number = number; // Value assigned from getNumber method to private number instance variable for FootballPlayer object.  

this.position = position; // Value assigned from getPosition method to private position instance variable for FootballPlayer object.    

}  

public FootballPlayer() // No parameter constructor for FootballPlayer object.

{

this.number = 0; // Default value assigned to private number instance variable under no parameter constructor for FootballPlayer object.    

this.position = "N/A"; // Default value assigned to private position instance variable under no parameter constructor for FootballPlayer object.    

}  

Override

public String getAttribute(int n) // getAttribute method that is implemented from interface.

{

switch (n) { // Switch statement for each attribute from each FootballPlayer object. Including two local attributes, denoted by this. While the others are denoted by "super".

case 0:

return String.valueOf(this.number); // Use of the dot operator allowed me to discover String.valueOf method to output int attributes as a string.

case 1:

return this.position;

case 2:

return super.getName();

case 3:

return super.getHeight().toString();

case 4:

return String.valueOf(super.getWeight());

case 5:

return super.getHometown();

case 6:

return super.getHighSchool();

default:

return ("invalid input parameter");

}

}  

Override

public ArrayList<String> getAttributes() // getAttributes ArrayList method that is implemented from interface.

{

ArrayList<String> getAttributes = new ArrayList<>();    

for(int i = 0; i <= 6; i++){ // For loop to add each attribute to the getAttributes ArrayList from getAttributes method.    

getAttributes.add(getAttribute(i));    

}    

return getAttributes;

}  

Override

public String getAttributeName(int n) // getAttributeName method implemented from interface.

{

switch (n) { // Switch statement for the name of each attribute from each FootballPlayer object.

case 0:

return "number";

case 1:

return "position";

case 2:

return "name";

case 3:

return "height";

case 4:

return "weight";

case 5:

return "hometown";

case 6:

return "highSchool";

default:

return ("invalid input parameter");

}  

}  

Answer:

[tex]E = 14.81\%[/tex]

Explanation:

Given

[tex]n = 150[/tex]

[tex]\sigma = 0.78[/tex]

[tex]c = 0.98[/tex]

Required

The margin of error (E)

This is calculated as:

[tex]E = z * \frac{\sigma}{\sqrt{n}}[/tex]

When confidence level = 0.98 i.e. 98%

The z score is: 2.326

So, we have:

[tex]E = 2.326 * \frac{0.78}{\sqrt{150}}[/tex]

[tex]E = 2.326 * \frac{0.78}{12.247}[/tex]

[tex]E = \frac{2.326 *0.78}{12.247}[/tex]

[tex]E = \frac{1.81428}{12.247}[/tex]

[tex]E = 0.1481[/tex]

Express as percentage

[tex]E = 14.81\%[/tex]

Answer: B. Perform a hash on the file for comparison with the vendor’s hash.

Explanation:

Before installing the firmware update, the step that the technician should perform to ensure file integrity is to perform a hash on the file for comparison with the vendor’s hash.

Hashing refers to the algorithm that is used for the calculation of a string value from a file. Hashes are helpful in the identification of a threat on a machine and when a user wants to query the network for the existence of a certain file.

Answer:

The function is as follows:

def get_win_percentage(self):

       return self.team_wins / (self.team_wins + self.team_losses)

Explanation:

This defines the function

def get_win_percentage(self):

This calculates the win percentage and returns it to main

       return self.team_wins / (self.team_wins + self.team_losses)

See attachment for complete (and modified) program.

Answer: def get_win_percentage(self):

Explanation: got it right on edgen

Answer:

semicolon is the answer

Answer:

adress: 10101100.00010000.1 0000000.00000000

netmask: 11111111.11111111.1 0000000.00000000

Network:   172.16.128.0/17       10101100.00010000.1 0000000.00000000 (Class B)

Explanation:

ex: 10 -> 00001010

200 ->11001000

Answer:

I think digital,versatile

computer is an electronic digital versatile machine because once a task is initiated computer proceeds on its own till its completation.

Answer:

The function of the suites application is to create presentations and perform numerical calculations.

Explanation:

Answer:

The right answer is "Hardware crash".

Explanation:

Thus the above is the right solution.

Answer:

Acronis True Image is the one I would recommend out of these mentioned online backup services.

Explanation:

The evaluations and reviews of each of the online backup services are as follows:

a. iDrive

For this, we have:

Speed = 60% - fair

Security = 100% - excellent

Privacy = 88% - very good

Features = 95% - excellent

Pricing = 85% - Very good

Because of its various features, pricing, and usability, IDrive reviews suggest that it is a very efficient online backup solution. However, there have been complaints concerning its speed and the fact that there are no monthly plans available.

b. Carbonite

For this, we have:

Speed = 60% - fair

Security = 100% - excellent

Privacy = 87% - very good

Pricing = 85% - very good

File backup and restoration = 75% - good

Carbonite reviews reveal that it is simple to use and provides limitless backup for one device. The main drawback is that it has extremely poor backup speeds.

c. Acronis True Image

This is fast, simple and intuitive

It has complete control over the backup updates, including how and when they occur.

It is not expensive.

Acrnonis True image is a powerful backup storage service. It enables data and file backup and restoration from USB drives.

Many reviewers of Acrnonis True image have stated that they have had no issues with its service, that it is worth purchasing, and that there are no concerns.

d. Backblaze

For this, we have:

Speed = 75% - good

Security = 75% - good

Privacy = 70% - decent

Pricing = 100% - excellent

Support = 95% - excellent

Features = 65% - decent

File back-up and restoration = 70% - decent

Backblaze is one of the most popular internet backup services. This storage service, however, does not allow for ustomization.

Recommendation

Acronis True Image is the one I would recommend out of these mentioned online backup services. This is due to the fact that it delivers a large amount of accurate and high-quality data storage. It is quick, simple and intuitive, which is what most people care about. Furthermore, reviewers have stated that this service is quite effective and that there have been very few issues with it. The other services demonstrate that their services have flaws, such as lack of customization and slowness.

Answer:

a,b,c,d,f,g are true only e is false

Answer:

(i) C is increased (S, B same)

Explanation:

Cache are items which are stored in the computer at a hidden place. These are sometimes unwanted and they may hinder the speed and performance of the device. They exist to bridge speed gap.

Answer:

Some popular examples of today's interpreters are:

Explanation:

An interpreter executes the commands directly in an object code or a machine code, written in a program or a scripting language.

The Interpreter can be referred to as system software that can read and execute the programme instead of interpreting programmes. This interpretation includes high-level source code, pre-compiled programmes and scripts.

It is important to note that the interpreter translates programme by programme line, meaning that one statement is translated on one go. This feature makes it easy for programmers to check any line on debugging but slows the whole programme running time.

Answer:

Explanation:

Pink: Down 5 then left 2.

Yellow: Left 3 and down 2.

Green: Right 7, down 4 and left 1.

Purple: Up 6 and left 9.

Red: Left 7, down 5 and left 1.

You can do the last one, blue :)

Answer:

Explanation:

u=up, d=down, r=right, l=left

yellow: l3d2

pink: d5l2

green: r7d4l1

purple: u6l9

red: l7d5l1

blue: r2u7l5

Answer:

Following are the response to the given question:  

Explanation:

Build a spring, sink, vertices, and vertices for each car for a household. Every unit in the stream is a human. Attach the source from each vertical of a family with such a capacity line equivalent to the family size; this sets the number of members in each household. Attach every car vertices to the sink with the edge of the car's passenger belt; this assures the correct number of people for every vehicle. Connecting every vertex in your household to any vertex in your vehicle with a capacity 1 border guarantees that one family member joins a single car. The link between both the acceptable allocation of people to vehicles as well as the maximum flow inside the graph seems clear to notice.

Answer:

1 is the answer because ur trying to trick us

Explanation: