Question 4 of 5
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used
Match each explicit formula to its corresponding recursive formula.
(8) = 5(5)(1-1)
(n) = 3 +5(n-1)
(3) = 5+3(1-1)
7(n) = 3(5)(n-1)
$(n) = 5 +5(n-1)
f(1) = 5
(*) = 3;(n - 1), for 3
(1) = 5
(n) = f(n-1) +5, for n?
f(1) = 5
f(n) = f(n-1) + 3, for n?
Answers
Given:
The recursive formulae.
To find:
The correct explicit formulae for the given recursive formulae.
Solution:
If the recursive formula of a GP is [tex]f(n)=rf(n-1), f(1)=a, n\geq 2[/tex], then the explicit formula of that GP is:
[tex]f(n)=ar^{n-1}[/tex]
Where, a is the first term and r is the common ratio.
The first recursive formula is:
[tex]f(1)=5[/tex]
[tex]f(n)=3f(n-1)[/tex] for [tex]n\geq 2[/tex].
It is the recursive formula of a GP with a=5 and r=3. So, the required explicit formula is:
[tex]f(n)=5(3)^{n-1}[/tex]
Therefore, the required explicit formula for the first recursive formula is [tex]f(n)=5(3)^{n-1}[/tex].
If the recursive formula of an AP is [tex]f(n)=f(n-1)+d, f(1)=a, n\geq 2[/tex], then the explicit formula of that AP is:
[tex]f(n)=a+(n-1)d[/tex]
Where, a is the first term and d is the common difference.
The second recursive formula is:
[tex]f(1)=5[/tex]
[tex]f(n)=f(n-1)+5[/tex] for [tex]n\geq 2[/tex].
It is the recursive formula of an AP with a=5 and d=5. So, the required explicit formula is:
[tex]f(n)=5+(n-1)5[/tex]
[tex]f(n)=5+5(n-1)[/tex]
Therefore, the required explicit formula for the second recursive formula is [tex]f(n)=5+5(n-1)[/tex].
The third recursive formula is:
[tex]f(1)=5[/tex]
[tex]f(n)=f(n-1)+3[/tex] for [tex]n\geq 2[/tex].
It is the recursive formula of an AP with a=5 and d=3. So, the required explicit formula is:
[tex]f(n)=5+(n-1)3[/tex]
[tex]f(n)=5+3(n-1)[/tex]
Therefore, the required explicit formula for the third recursive formula is [tex]f(n)=5+3(n-1)[/tex].
Related Questions
A car travelling at v kilometers per hour will need a stopping distance, d, in meters without skidding that can be modelled by the function d=0.0067v2+0.15v. Determine the speed at which a car can be travelling to be able to stop within 37m.
I’m need of serious help!
Answers
Answer:
v = 14 km/h
Step-by-step explanation:
d = 0.0067[tex]v^{2}[/tex] + 0.15v
differentiate the function with respect to v to have;
d = 0.0134v - 0.15
given that the distance without skidding = 37 m (0.037 km) , then;
0.037 = 0.0134v - 0.15
0.0134v = 0.037 + 0.15
= 0.187
v = [tex]\frac{0.187}{0.0134}[/tex]
= 13.9552
v = 14 km/h
The speed of the car travelling would be 14 km/h to be able to stop within 37m.
Answer two questions about Equations A and B:
A. 3(x+2) = 18
B.
r + 2 = 6
1) How can we get Equation B from Equation A?
Answers
Step-by-step explanation:
3x+6=18
3x=18-6
3x=12
x=4
The polygons in each pair are similar. Find the missing side length
Answers
Answer:
24 is the answer because 18/3=6 6x4 is 24
C and D are complementary angles. Which of the following measures cannot be true
Om C= 30° and m D = 60°
Om C= 60° and m2D = 30°
Om C= 65° and m D = 35°
Om C = 55° and m D = 35°
Answers
Answer:
C= 65° and m D = 35°
this cannot be true
Step-by-step explanation:
a complementary angle adds up to 90°
65°+35°=100
90° =/= 100°
2. En una división el dividendo es 445, el divisor es 32, el cociente es 14 y el resto es 7. ¿Está bien hecha? Compruébalo de dos maneras diferentes
Answers
Respuesta:
El cálculo no está bien hecho.
el cociente es 13
El resto es 29
Explicación paso a paso:
Dividendo = 445
Divisor = 32
Cociente = 14
Resto = 7
445/32 = 13,90625
El cociente = 13
Resto = (13.90625 - 13) * 32
Resto = 0.90625 * 32
Resto = 29
Por lo tanto, el cálculo no se realiza correctamente ya que el cociente es 13 y el resto es 29
I’m stuck on this one help anyone?
Answers
Answer:
just add a small amount to the 2.8 and square the result
Step-by-step explanation:
x x^2
2.8 7.84
2.81 7.8961
2.82 7.9524
2.83 8.0089
2.84 8.0656
2.85 8.1225
2.86 8.1796
2.87 8.2369
if x=3√8, find the value of 1/x
plz its urgent
Answers
Answer:
[tex]\frac{1}{x} =\frac{1}{3\sqrt{8} } =\frac{1(\sqrt{8})}{3\sqrt{8}(\sqrt{8})} =\frac{\sqrt{8}}{3*8} =\frac{\sqrt{8}}{24} =\frac{\sqrt{(2)(2)(2)}}{24}=\frac{2\sqrt{2} }{2(12)} =\frac{\sqrt{2} }{12}[/tex]
Consider the following 8 numbers, where one labelled x
is unknown.
27, 20, 34,
x, 7, 47, 26, 41
Given that the range of the numbers is 63,
work out 2 values of x
Answers
Answer: 70 and -16
==========================================================
Explanation:
For now, we'll assume x is the largest value (aka the max)
Let's sort the values from smallest to largest.
7, 20, 26, 27, 34, 41, 47, x
We see that 7 is the smallest item, so,
range = max - min = x - 7
Set this equal to 63 and solve for x
x-7 = 63
x = 63+7
x = 70
So x could be equal to 70.
---------------------------
Next, we'll assume that x is the smallest value
That means the min is x and 47 is now the max
max - min = range
47 - x = 63
-x = 63-47
-x = 16
x = -16
So if x is the smallest value, then it must be -16
----------------------------
Finally, we'll let x be somewhere between 7 and 47
Unfortunately, we can't pin down a specific value here since we could have lots of possible values. Three such examples are x = 8, x = 9, and x = 10. There are many others.
If your teacher is looking for 2 values only, then I would refer to the previous two sections and ignore this section entirely.
Solve for x. X/5-x/6=1/3 x = 10 x = 1/90 x = 1/10
Answers
Answer:
x=10
Step-by-step explanation:
I hope this will help you
Please help me Find PA.
Answers
Help pleas like please ASAP
Answers
Answer:
(x+9)(x+5)
Step-by-step explanation:
find 2 numbers that add to 14 and multiply to 45
Please help me with this, i need help
Answers
Answer:
woa
i n
Step-by-step explanation:
This table shows the relationship of the total number of pieces of fruit to the number of bananas.
Why is StartFraction 6 Over 5 EndFraction not equivalent to Three-halves?
Answers
Given:
The table that shows the relationship of the total number of pieces of fruit to the number of bananas.
To find:
Why is [tex]\dfrac{6}{5}[/tex] not equivalent to [tex]\dfrac{3}{2}[/tex].
Solution:
If a, b, c are real numbers, then
[tex]\dfrac{a}{b}=\dfrac{a\times c}{b\times c}[/tex]
The given fraction is [tex]\dfrac{3}{2}[/tex]. It can be written as:
[tex]\dfrac{3\times 2}{2\times 2}=\dfrac{6}{4}[/tex]
The number 3 is multiplied by 2 to get 6. So, the 2 should also be multiplied by 2. The ratio should be [tex]\dfrac{6}{4}[/tex], not [tex]\dfrac{6}{5}[/tex].
Therefore, the correct option is A.
What expression is equal to (3 x 5) x 4
Answers
Answer:
60
Step-by-step explanation:
Step 1:
3 x 5 = 15
Step 2:
15 x 4 = 60
Answer:
well 3. x 5 is 15, then multiply by 4 to get 60.
Step-by-step explanation:
A bus has less than 42 seats. If 36 seats are already occupied, write an
inequality representing the possible number of passengers that can be
added to the bus.
A.) x - 36 < 42
B.) x + 36 < 42
C.) x - 36 > 42
D.) x + 36 > 57
Answers
Answer:
B
Step-by-step explanation:
A x - 36 <42 is wrong because its saying how many can be added
B x +36 < 42 this one is most likely correct because its displays x as how many can be added
C x - 36 > 42 this is wrong because the bus has less than 42 seats
D x + 36 >57 like i said cant be over 42
The inequality representing the possible number of passengers that can be added to the bus is Option(B) x + 36 < 42.
What is inequality ?An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. Inequality is used most often to compare two numbers on the number line by their size. There is always a definite equation to represent it.
How to form the given inequality equation ?Let x be the number of passengers that can be added to the bus.
It is given that the bus has less than 42 seats and 36 seats are already occupied.
The sum of the remaining seats which are to be filled by the passenger and the 36 seats which are filled, must be less than the total seats that is 42.
Therefore the inequality equation becomes,
x + 36 < 42.
Thus, the inequality representing the possible number of passengers that can be added to the bus is Option(B) x + 36 < 42.
To learn more about inequality equation, refer -
https://brainly.com/question/17448505
#SPJ2
The square root of 0.25 is 0.5 which is a greater number. Give another number whose square root is larger than the number and explain why.
Answers
Answer:
Another example of a number who's square root is greater than the number is [tex]\sqrt{0.49}[/tex] which is 0.7
Step-by-step explanation:
This square root is larger than the number because it is a decimal. When you multiply a decimal by a decimal, the decimal point becomes greater. For example: 0.7 multiplied by 0.7 equals 0.49 which has 2 decimal places, while 0.7 only has one.
please help with these two questions!!
Answers
6√5 + 3√6 = 6√5 + 3√6 [cannot be simplified]
; roots do not contain any perfect squares, and the roots are not similar.
6√5(3√6) = 18√30 [can be simplified]
; although roots do not contain any perfect squares, the product rule can be applied to create a singular expression.
An acute angle of a right triangle measures 30°, and the length of the triangle's hypotenuse is 10 ft. Find the missing angle measure and side lengths.
Answers
Answer:
missing angle <60 and side lengths 5, 5[tex]\sqrt{3}[/tex]
Step-by-step explanation:
we understand from the given information that the triangle in question is a special right triangle
and since this is a special triangle the side lengths follows :
the side length that sees <90 is represented by 2x
the side length that sees <60 is represented by x[tex]\sqrt{3}[/tex]
and the side length that sees <30 is represented by x
2x = 10 so x = 5 and x[tex]\sqrt{3}[/tex] = 5[tex]\sqrt{3}[/tex]
Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region
Answers
Answer:
Question 16 = 22
Question 17 = 20 cm²
Step-by-step explanation:
Concepts:
Area of Square = s²
s = sideArea of Triangle = bh/2
b = baseh = heightDiagonals of the square are congruent and bisect each other, which forms a right angle with 90°
Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.
Solve:
Question # 16
Step One: Find the total area of two squares
Large square: 5 × 5 = 25
Small square: 2 × 2 = 4
25 + 4 = 29
Step Two: Find the area of the blank triangle
b = 5 + 2 = 7
h = 2
A = bh / 2
A = (7) (2) / 2
A = 14 / 2
A = 7
Step Three: Subtract the area of the blank triangle from the total area
Total area = 29
Area of Square = 7
29 - 7 = 22
-----------------------------------------------------------
Question # 17
Step One: Find the length of PT
Given:
PR = 4 cmRT = 6 cmPT = PR + RT [Segment addition postulate]
PT = (4) + (6)
PT = 10 cm
Step Two: Find the length of S to PT perpendicularly
According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal
Length of Diagonal = 4 cm
4 ÷ 2 = 2 cm
Step Three: Find the area of ΔPST
b = PT = 10 cm
h = S to PT = 2 cm
A = bh / 2
A = (10)(2) / 2
A = 20 / 2
A = 10 cm²
Step Four: Find the length of Q to PT perpendicularly
Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.
Length of Diagonal = 4 cm
4 ÷ 2 = 2 cm
Step Five: Find the area of ΔPQT
b = PT = 10 cm
h = Q to PT = 2 cm
A = bh / 2
A = (10)(2) / 2
A = 20 / 2
A = 10 cm²
Step Six: Combine area of two triangles to find the total area
Area of ΔPST = 10 cm²
Area of ΔPQT = 10 cm²
10 + 10 = 20 cm²
Hope this helps!! :)
Please let me know if you have any questions
Choose the correct description of the graph of the inequality X - 3 greater than or equal to 25
A. Open circle on 8, shading to the left
B. Closed circle on 8, shading to the left.
C. Open circle on 8, shading to the right.
D. Closed circle on 8, shading to the right.
I’m pretty sure it’s D
Answers
Answer:
D. Closed circle on 8, shading to the right.
A running track has two semi-circular ends with radius 27m and two straights of length 90.6m as shown.
Calculate the total distance around the track rounded to 1 DP.
Answers
Answer:
350.85
Step-by-step explanation:
90.6*2 = 181.2
27*2 = 54 (diameter)
54*pi = 169.646003294
169.646003294 + 181.2 = 350.846003294
350.846003294 = 350.85
What value of x will make the equation true?
(Square Root of 5) (square root of 5)=x
Answers
Answer:
(2.236067978)(2.236067978)
=5 ans.
If this is incorrect forgive me
I hope this will help you
stay safe
The probability that Dan buys a sandwich is 0.2.
The probability that Dan gets the bus is 0.9.
Assuming the events are independent, what is the probability that Dan buys a sandwich
and gets the bus?
Answers
Answer:
0.18
Step-by-step explanation:
Find the probability that both independent events occur by multiplying the individual probabilities by each other:
0.2(0.9)
= 0.18
So, the probability is 0.18
Find the line’s slope and a point on the line
Y-4=-3/4(x+5)
Answers
Answer:
The slope is -3/4 and a point on the line is (-5,4)
Step-by-step explanation:
This equation is in point slope form
y -y1 = m(x-x1)
where m is the slope and (x1,y1) is a point on the line
Y-4=-3/4(x+5)
Y-4=-3/4(x - -5)
The slope is -3/4 and a point on the line is (-5,4)
How much money invested at 3% compounded monthly for 3 years will yield $520?
$179.42
$475.30
$358.84
$148.78
Answers
Answer:
Step-by-step explanation:
Use this formula:
[tex]A(t)=P(1+\frac{r}{n})^{nt}[/tex] where A(t) is the amount after the compounding is done, P is the initial investment (our unknown), r is the interest rate in decimal form, n is the number of compoundings per year, and t is the time in years. Filling in:
[tex]520=P(1+\frac{.03}{12})^{(12)(3)}[/tex] and simplifying that a bit:
[tex]520=P(1+.0025)^{36[/tex] and a bit more:
[tex]520=P(1.0025)^{36[/tex] and even bit more:
520 = P(1.094551401) and divide to get
P = $475.30
convert into power notation -1/81
Answers
Answer:
-1/9^2 is the power notation for your questions
Step-by-step explanations
simplify the following
[tex]simplify \: the \: follwing \: \\ logx \: x9[/tex]
please I need help
Answers
Answer:
9
Step-by-step explanation:
Using the rules of logarithms
log[tex]x^{n}[/tex] = nlogx
[tex]log_{b}[/tex] b = 1
Then
[tex]log_{x}[/tex] [tex]x^{9}[/tex]
= 9[tex]log_{x}[/tex] x
= 9
Let j=+5 - 5+ |-5 x 1/5
What is the value of+J?
Answers
Answer:
j=|x|
Step-by-step explanation:
In a shipment of airplane parts, 6% are known to be defective. If 42 parts are found to be defective, how many parts are in the shipment?
Answers
Answer:
700 parts
Step-by-step explanation:
To find the total amount of parts in the shipment, all we need to do is divide.
6% = 0.06
42 / 0.06 = 700
Best of Luck!
The function f(x) = One-sixth (two-fifths) Superscript x is reflected across the y-axis to create the function g(x). Which ordered pair is on g(x)?
Answers
Answer:
[tex](-3,4/375)[/tex]
Step-by-step explanation:
Given
[tex]f(x) = \frac{1}{6}(\frac{2}{5})^x[/tex]
Reflection: Across y-axis
Required
The ordered pair on g(x)
The rule of reflection across y-axis is:
[tex](x,y) = (-x,y)[/tex]
So, we have:
[tex]g(x) = f(-x)[/tex]
f(-x) is:
[tex]f(-x) = \frac{1}{6}(\frac{2}{5})^{-x[/tex]
Recall that:
[tex]g(x) = f(-x)[/tex]
Hence:
[tex]g(x) = \frac{1}{6}(\frac{2}{5})^{-x[/tex]
From the options (missing in the question), the ordered pair is:
[tex](-3,4/375)[/tex]
To check this, we have:
[tex]g(x) = \frac{1}{6}(\frac{2}{5})^{-x[/tex]
[tex]g(-3) = \frac{1}{6}(\frac{2}{5})^{--3[/tex]
[tex]g(-3) = \frac{1}{6}(\frac{2}{5})^{3[/tex]
Expand
[tex]g(-3) = \frac{1}{6}(\frac{8}{125})[/tex]
Simplify
[tex]g(-3) = \frac{1}{3}(\frac{4}{125})[/tex]
Open bracket
[tex]g(-3) = \frac{4}{375}[/tex]
