Question 4 of 5
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used
Match each explicit formula to its corresponding recursive formula.
(8) = 5(5)(1-1)
(n) = 3 +5(n-1)
(3) = 5+3(1-1)
7(n) = 3(5)(n-1)
$(n) = 5 +5(n-1)
f(1) = 5
(*) = 3;(n - 1), for 3
(1) = 5
(n) = f(n-1) +5, for n?
f(1) = 5
f(n) = f(n-1) + 3, for n?

Question 4 Of 5Drag The Tiles To The Correct Boxes To Complete The Pairs. Not All Tiles Will Be UsedMatch

Answers

Answer 1

Given:

The recursive formulae.

To find:

The correct explicit formulae for the given recursive formulae.

Solution:

If the recursive formula of a GP is [tex]f(n)=rf(n-1), f(1)=a, n\geq 2[/tex], then the explicit formula of that GP is:

[tex]f(n)=ar^{n-1}[/tex]

Where, a is the first term and r is the common ratio.

The first recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=3f(n-1)[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of a GP with a=5 and r=3. So, the required explicit formula is:

[tex]f(n)=5(3)^{n-1}[/tex]

Therefore, the required explicit formula for the first recursive formula is [tex]f(n)=5(3)^{n-1}[/tex].

If the recursive formula of an AP is [tex]f(n)=f(n-1)+d, f(1)=a, n\geq 2[/tex], then the explicit formula of that AP is:

[tex]f(n)=a+(n-1)d[/tex]

Where, a is the first term and d is the common difference.

The second recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=f(n-1)+5[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of an AP with a=5 and d=5. So, the required explicit formula is:

[tex]f(n)=5+(n-1)5[/tex]

[tex]f(n)=5+5(n-1)[/tex]

Therefore, the required explicit formula for the second recursive formula is [tex]f(n)=5+5(n-1)[/tex].

The third recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=f(n-1)+3[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of an AP with a=5 and d=3. So, the required explicit formula is:

[tex]f(n)=5+(n-1)3[/tex]

[tex]f(n)=5+3(n-1)[/tex]

Therefore, the required explicit formula for the third recursive formula is [tex]f(n)=5+3(n-1)[/tex].


Related Questions

C and D are complementary angles. Which of the following measures cannot be true
Om C= 30° and m D = 60°
Om C= 60° and m2D = 30°
Om C= 65° and m D = 35°
Om C = 55° and m D = 35°

Answers

Answer:

C= 65° and m D = 35°

this cannot be true

Step-by-step explanation:

a complementary angle adds up to 90°

65°+35°=100

90° =/= 100°

I’m stuck on this one help anyone?

Answers

Answer:

just add a small amount to the 2.8 and square the result

Step-by-step explanation:

x x^2

2.8 7.84

2.81 7.8961

2.82 7.9524

2.83 8.0089

2.84 8.0656

2.85 8.1225

2.86 8.1796

2.87 8.2369

Let j=+5 - 5+ |-5 x 1/5
What is the value of+J?

Answers

Answer:

j=|x|

Step-by-step explanation:

The function f(x) = One-sixth (two-fifths) Superscript x is reflected across the y-axis to create the function g(x). Which ordered pair is on g(x)?

Answers

Answer:

[tex](-3,4/375)[/tex]

Step-by-step explanation:

Given

[tex]f(x) = \frac{1}{6}(\frac{2}{5})^x[/tex]

Reflection: Across y-axis

Required

The ordered pair on g(x)

The rule of reflection across y-axis is:

[tex](x,y) = (-x,y)[/tex]

So, we have:

[tex]g(x) = f(-x)[/tex]

f(-x) is:

[tex]f(-x) = \frac{1}{6}(\frac{2}{5})^{-x[/tex]

Recall that:

[tex]g(x) = f(-x)[/tex]

Hence:

[tex]g(x) = \frac{1}{6}(\frac{2}{5})^{-x[/tex]

From the options (missing in the question), the ordered pair is:

[tex](-3,4/375)[/tex]

To check this, we have:

[tex]g(x) = \frac{1}{6}(\frac{2}{5})^{-x[/tex]

[tex]g(-3) = \frac{1}{6}(\frac{2}{5})^{--3[/tex]

[tex]g(-3) = \frac{1}{6}(\frac{2}{5})^{3[/tex]

Expand

[tex]g(-3) = \frac{1}{6}(\frac{8}{125})[/tex]

Simplify

[tex]g(-3) = \frac{1}{3}(\frac{4}{125})[/tex]

Open bracket

[tex]g(-3) = \frac{4}{375}[/tex]

A running track has two semi-circular ends with radius 27m and two straights of length 90.6m as shown.
Calculate the total distance around the track rounded to 1 DP.

Answers

Answer:

350.85

Step-by-step explanation:

90.6*2 = 181.2

27*2 = 54 (diameter)

54*pi = 169.646003294

169.646003294 + 181.2 = 350.846003294

350.846003294 = 350.85


Choose the correct description of the graph of the inequality X - 3 greater than or equal to 25

A. Open circle on 8, shading to the left
B. Closed circle on 8, shading to the left.
C. Open circle on 8, shading to the right.
D. Closed circle on 8, shading to the right.

I’m pretty sure it’s D

Answers

Answer:

D. Closed circle on 8, shading to the right.

2. En una división el dividendo es 445, el divisor es 32, el cociente es 14 y el resto es 7. ¿Está bien hecha? Compruébalo de dos maneras diferentes

Answers

Respuesta:

El cálculo no está bien hecho.

el cociente es 13

El resto es 29

Explicación paso a paso:

Dividendo = 445

Divisor = 32

Cociente = 14

Resto = 7

445/32 = 13,90625

El cociente = 13

Resto = (13.90625 - 13) * 32

Resto = 0.90625 * 32

Resto = 29

Por lo tanto, el cálculo no se realiza correctamente ya que el cociente es 13 y el resto es 29

please help with these two questions!!

Answers

6√5 + 3√6 = 6√5 + 3√6 [cannot be simplified]

; roots do not contain any perfect squares, and the roots are not similar.

6√5(3√6) = 18√30 [can be simplified]

; although roots do not contain any perfect squares, the product rule can be applied to create a singular expression.

if x=3√8, find the value of 1/x

plz its urgent

Answers

Answer:

[tex]\frac{1}{x} =\frac{1}{3\sqrt{8} } =\frac{1(\sqrt{8})}{3\sqrt{8}(\sqrt{8})} =\frac{\sqrt{8}}{3*8} =\frac{\sqrt{8}}{24} =\frac{\sqrt{(2)(2)(2)}}{24}=\frac{2\sqrt{2} }{2(12)} =\frac{\sqrt{2} }{12}[/tex]

An acute angle of a right triangle measures 30°, and the length of the triangle's hypotenuse is 10 ft. Find the missing angle measure and side lengths.

Answers

Answer:

missing angle <60 and side lengths 5, 5[tex]\sqrt{3}[/tex]

Step-by-step explanation:

we understand from the given information that  the triangle in question is a special right triangle

and since this is a special triangle the side lengths follows :

the side length that sees <90 is represented by 2x

the side length that sees <60 is represented by x[tex]\sqrt{3}[/tex]

and the side length that sees <30 is represented by x

2x = 10 so x = 5 and  x[tex]\sqrt{3}[/tex] = 5[tex]\sqrt{3}[/tex]

What value of x will make the equation true?

(Square Root of 5) (square root of 5)=x

Answers

Answer:

(2.236067978)(2.236067978)

=5 ans.

If this is incorrect forgive me

I hope this will help you

stay safe

convert into power notation -1/81​

Answers

Answer:

-1/9^2 is the power notation for your questions

Step-by-step explanations

The probability that Dan buys a sandwich is 0.2.
The probability that Dan gets the bus is 0.9.
Assuming the events are independent, what is the probability that Dan buys a sandwich
and gets the bus?

Answers

Answer:

0.18

Step-by-step explanation:

Find the probability that both independent events occur by multiplying the individual probabilities by each other:

0.2(0.9)

= 0.18

So, the probability is 0.18

Find the line’s slope and a point on the line
Y-4=-3/4(x+5)

Answers

Answer:

The slope is -3/4 and a point on the line is (-5,4)

Step-by-step explanation:

This equation is in point slope form

y -y1 = m(x-x1)

where m is the slope and (x1,y1) is a point on the line

Y-4=-3/4(x+5)

Y-4=-3/4(x -  -5)

The slope is -3/4 and a point on the line is (-5,4)

simplify the following
[tex]simplify \: the \: follwing \: \\ logx \: x9[/tex]
​please I need help

Answers

Answer:

9

Step-by-step explanation:

Using the rules of logarithms

log[tex]x^{n}[/tex] = nlogx

[tex]log_{b}[/tex] b = 1

Then

[tex]log_{x}[/tex] [tex]x^{9}[/tex]

= 9[tex]log_{x}[/tex] x

= 9

Please help me with this, i need help

Answers

Answer:

woa

i  n

Step-by-step explanation:

The square root of 0.25 is 0.5 which is a greater number. Give another number whose square root is larger than the number and explain why.

Answers

Answer:

Another example of a number who's square root is greater than the number is  [tex]\sqrt{0.49}[/tex] which is 0.7

Step-by-step explanation:

This square root is larger than the number because it is a decimal. When you multiply a decimal by a decimal, the decimal point becomes greater. For example: 0.7 multiplied by 0.7 equals 0.49 which has 2 decimal places, while 0.7 only has one.

Answer two questions about Equations A and B:
A. 3(x+2) = 18
B.
r + 2 = 6
1) How can we get Equation B from Equation A?

Answers

Step-by-step explanation:

3x+6=18

3x=18-6

3x=12

x=4

Please help me Find PA.

Answers

PO is 5 by using Pythagorean theorems and it forming a 3,4,5 triangle so PA is PO + OA so it is 8

Solve for x. X/5-x/6=1/3 x = 10 x = 1/90 x = 1/10

Answers

Answer:

x=10

Step-by-step explanation:

I hope this will help you

In a shipment of airplane parts, 6% are known to be defective. If 42 parts are found to be defective, how many parts are in the shipment?

Answers

Answer:

700 parts

Step-by-step explanation:

To find the total amount of parts in the shipment, all we need to do is divide.

6% = 0.06

42 / 0.06 = 700

Best of Luck!

Help pleas like please ASAP

Answers

Answer:

(x+9)(x+5)

Step-by-step explanation:

find 2 numbers that add to 14 and multiply to 45

X+9 x+5 hope that helped

A bus has less than 42 seats. If 36 seats are already occupied, write an
inequality representing the possible number of passengers that can be
added to the bus.
A.) x - 36 < 42
B.) x + 36 < 42
C.) x - 36 > 42
D.) x + 36 > 57

Answers

Answer:

B

Step-by-step explanation:

A x - 36 <42 is wrong because its saying how many can be added

B x +36 < 42 this one is most likely correct because its displays x as how many can be added

C x - 36 > 42 this is wrong because the bus has less than 42 seats

D x + 36 >57 like i said cant be over 42

The inequality representing the possible number of passengers that can be added to the bus is Option(B) x + 36 < 42.

What is inequality ?

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. Inequality is used most often to compare two numbers on the number line by their size. There is always a definite equation to represent it.

How to form the given inequality equation ?

Let x be the number of passengers that can be added to the bus.

It is given that the bus has less than 42 seats and 36 seats are already occupied.

The sum of the remaining seats which are to be filled by the passenger and the 36 seats which are filled, must be less than the total seats that is 42.

Therefore the inequality equation becomes,

x + 36 < 42.

Thus, the inequality representing the possible number of passengers that can be added to the bus is Option(B) x + 36 < 42.

To learn more about inequality equation, refer -

https://brainly.com/question/17448505

#SPJ2

What expression is equal to (3 x 5) x 4

Answers

Answer:

60

Step-by-step explanation:

Step 1:

3 x 5 = 15

Step 2:

15 x 4 = 60

Answer:

well 3. x 5 is 15, then multiply by 4 to get 60.

Step-by-step explanation:

This table shows the relationship of the total number of pieces of fruit to the number of bananas.
Why is StartFraction 6 Over 5 EndFraction not equivalent to Three-halves?

Answers

Given:

The table that shows the relationship of the total number of pieces of fruit to the number of bananas.

To find:

Why is [tex]\dfrac{6}{5}[/tex] not equivalent to [tex]\dfrac{3}{2}[/tex].

Solution:

If a, b, c are real numbers, then

[tex]\dfrac{a}{b}=\dfrac{a\times c}{b\times c}[/tex]

The given fraction is [tex]\dfrac{3}{2}[/tex]. It can be written as:

[tex]\dfrac{3\times 2}{2\times 2}=\dfrac{6}{4}[/tex]

The number 3 is multiplied by 2 to get 6. So, the 2 should also be multiplied by 2. The ratio should be [tex]\dfrac{6}{4}[/tex], not [tex]\dfrac{6}{5}[/tex].

Therefore, the correct option is A.

A car travelling at v kilometers per hour will need a stopping distance, d, in meters without skidding that can be modelled by the function d=0.0067v2+0.15v. Determine the speed at which a car can be travelling to be able to stop within 37m.

I’m need of serious help!

Answers

Answer:

v =  14 km/h

Step-by-step explanation:

d = 0.0067[tex]v^{2}[/tex] + 0.15v

differentiate the function with respect to v to have;

d = 0.0134v - 0.15

given that the distance without skidding = 37 m (0.037 km) , then;

0.037 = 0.0134v - 0.15

0.0134v = 0.037 + 0.15

             = 0.187

v = [tex]\frac{0.187}{0.0134}[/tex]

  = 13.9552

v =  14 km/h

The speed of the car travelling would be 14 km/h to be able to stop within 37m.

Consider the following 8 numbers, where one labelled x
is unknown.
27, 20, 34,
x, 7, 47, 26, 41
Given that the range of the numbers is 63,
work out 2 values of x

Answers

Answer:  70  and -16

==========================================================

Explanation:

For now, we'll assume x is the largest value (aka the max)

Let's sort the values from smallest to largest.

7, 20, 26, 27, 34, 41, 47, x

We see that 7 is the smallest item, so,

range = max - min = x - 7

Set this equal to 63 and solve for x

x-7 = 63

x = 63+7

x = 70

So x could be equal to 70.

---------------------------

Next, we'll assume that x is the smallest value

That means the min is x and 47 is now the max

max - min = range

47 - x = 63

-x = 63-47

-x = 16

x = -16

So if x is the smallest value, then it must be -16

----------------------------

Finally, we'll let x be somewhere between 7 and 47

Unfortunately, we can't pin down a specific value here since we could have lots of possible values. Three such examples are x = 8, x = 9, and x = 10. There are many others.

If your teacher is looking for 2 values only, then I would refer to the previous two sections and ignore this section entirely.

The polygons in each pair are similar. Find the missing side length

Answers

Answer:

24 is the answer because 18/3=6 6x4 is 24

Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region​

Answers

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

Concepts:

Area of Square = s²

s = side

Area of Triangle = bh/2

b = baseh = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

Question # 16

Step One: Find the total area of two squares

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

Step Two: Find the area of the blank triangle

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

Step Three: Subtract the area of the blank triangle from the total area

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

Step One: Find the length of PT

Given:

PR = 4 cmRT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

Step Two: Find the length of S to PT perpendicularly

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Three: Find the area of ΔPST

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Four: Find the length of Q to PT perpendicularly

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Five: Find the area of ΔPQT

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Six: Combine area of two triangles to find the total area

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

How much money invested at 3% compounded monthly for 3 years will yield $520?
$179.42
$475.30
$358.84
$148.78

Answers

Answer:

Step-by-step explanation:

Use this formula:

[tex]A(t)=P(1+\frac{r}{n})^{nt}[/tex] where A(t) is the amount after the compounding is done, P is the initial investment (our unknown), r is the interest rate in decimal form, n is the number of compoundings per year, and t is the time in years. Filling in:

[tex]520=P(1+\frac{.03}{12})^{(12)(3)}[/tex] and simplifying that a bit:

[tex]520=P(1+.0025)^{36[/tex] and a bit more:

[tex]520=P(1.0025)^{36[/tex] and even  bit more:

520 = P(1.094551401) and divide to get

P = $475.30

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