plz find the answers​

Answer:

the work done by the two students is 28,875 J

Explanation:

Given;

applied force, f = 825 N

distance through which the car is pushed, d = 35 m

The work done by the two students who pushed the 825 N across 35 m lot is calculated as follows;

Work done = force x distance

Work done = 825 N x 35 m

Work done = 28,875 Nm = 28,875 J

Therefore, the work done by the two students is 28,875 J

Answer:

v_f = 30 m/s

Explanation:

v_f = v_I + a*t

v_f = 0m/s + (9.81m/s²)*(3s)

v_f = 29.43m/s

v_f = 30 m/s

Since the object is being launched horizontally off the cliff the only vertical force acting on the ball is gravity which is an acceleration of 9.81m/s². So we have all the flowing information to use the the kinematic equation: v_f = v_I + a*t.

41.23

v(B,E)=40 GOING EAST

V(R,E)=10 COMING DOWN

then 41.23

Answer:

v = 17.68 m/s

Explanation:

Given that,

While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.

After the police car passes, its frequency is 460Hz.

We need to find the speed of the police car.

The formula is as follows :

[tex]v=\dfrac{v_o(f-f')}{f+f'}[/tex]

Put all the values,

[tex]v=\dfrac{343(510-460)}{510+460}\\\\=17.68\ m/s[/tex]

So, the speed of the police car is 17.68 m/s.

Answer:

The pressure the hand is less than the pressure on the fingers holding the string

Explanation:

The force with which the archer is pushing against the bow = 120 N

The area on which the force acts on the hand > The area the force acts on the fingers

Pressure = Force/Area

Pressure ∝ 1/Area

The larger the area, the lesser the pressure

The pressure acting on the hand which exerts the force with a larger area is less than the pressure on the finger which exerts the same force on a smaller area

The correct option is therefore;

The pressure the hand is less than the pressure on the fingers holding the string

Answer:

The answer should be: 1.20 A

Explanation:

By the work-energy theorem, the total work done on the mass as it swings is

W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J

No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.

If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.

Now, if w is the amount of work done by friction/air resistance, then

(176.4 N) h - w = 153 J

If you know the starting height h, then you can solve for w.

Answer:

C. 14.93 m

Explanation:

The given frequency of the wave, f = 100 Hz

The given equation for the wave speed, v, is presented as follows;

v = f × λ

The speed of sound in water, v = 1,493 m/s

Therefore, we get;

The wavelength, λ = v/f

∴ λ = 1,493 m/s/(100 Hz) = 14.93 m

The wavelength, λ = 14.93 m.

Answer:

// EDU HACK REDDIT EDITON //

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var iframe = document.getElementById("stageFrame");

for (i = 0; i < 1; i++) {

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  if (running == null) { running = true; console.log('Program Loaded! Enjoy!') }

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 },1000);

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}

Explanation:

Answer: 8000N

Explanation: since it is frictionless that means it has 100% efficiency therefore the mechanical advantage is 1 meaning the load equals to the effort

Answer:

• riding on a Ferris wheel whose entrance and exit are the same

• walking around the block, starting from and ending at the same house

• running exactly one lap around a racetrack

Explanation:

Displacement simply means the.change in position of an object. In a situation whereby the initial and final position are thesame, the displacement will be zero.

The statements that describe a situation with a displacement of zero include:

• riding on a Ferris wheel whose entrance and exit are the same

• walking around the block, starting from and ending at the same house

• running exactly one lap around a racetrack

Answer:

• riding on a Ferris wheel whose entrance and exit are the same

• walking around the block, starting from and ending at the same house

• running exactly one lap around a racetrack

Explanation:

B,C,E

Answer:

300 m/s

Explanation:

The difference in time between the two bangs is 1 s.

Thus;

t2 - t1 = 1

We know that distance/time = speed.

Thus;

d2/v - d1/v = 1

Multiply through by v to get;

d2 - d1 = v

Where v is speed of sound in air.

d1 = 350 m

d2 = (150 × 2) + 350 = 650 m

Thus;

v = d2 - d1 = 650 - 350 = 300 m/s

Answer:

55

Explanation:95-40=55

i hope i did the math right if i didnt please tell me

Explanation:

TEMPLE HINDUS MOSQUE MUSLIMS TEMPLE HINDUS MOSQUE MUSLIMS

Answer:

1) C. 2.5 x 10⁴ Pa

2) C. 75 cm³

Explanation:

Question 1.

Given the following data;

To find the final pressure, P2, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P1V1 = P2V2

Making P2 the subject of formula, we have;

P2 = (P1V1)/V2

Substituting into the formula, we have;

P2 = (1 * 10⁵ * 5)/20

P2 = (500,000)/20

Final pressure, P2 = 25,000 Pa or 2.5 x 10⁴ Pa.

Question 2.

Given the following data;

To find the final volume, we would use Boyle's law;

Mathematically, Boyles law is given by;

PV = K

P1V1 = P2V2

Making V2 the subject of formula, we have;

V2 = (P1V1)/P2

Substituting into the formula, we have;

V2 = (190 * 30)/76

V2 = 5700/76

Final volume, V2 = 75 cm³

[tex]Option \: (b)[/tex]

Explanation:

Second STATEMENT SAYS REGARDING TO THE CHEMICAL poison

Answer: Given: h₀=5cm

p=30cm

hi

f=45cm

require: q=?

hi=?

formulas:

1/f=1/p+1/q

hi/h₀=q/p

calculations:1/q=1/f-1/p

1/q=1/45-1/30

1/q=0.022=0.033

1/q=  =    -0.011

q=1/-0.011

q=   -90.91cm

hi=p × h₀/q

hi=30ₓ5/-90.91

hi=150/-90.91

hi= -1.65cm

image is virtual , erect and diminished

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Answer:

It increases twice the original

Explanation:

The kinetic molecular theory of matter states that: ... The average amount of empty space between molecules gets progressively larger as a sample of matter moves from the solid to the liquid and gas phases. There are attractive forces between atoms/molecules, and these become stronger as the particles move closer together.

Answer:

1.7p

Explanation:

Answer:

ballance

i just took the quiz

Answer:

A is the answer!

Explanation:

Edge 2021

Answer:

A

Explanation:

Edge

C. Your feet push down on the ground, and the ground pushes up on your feet.

When Your feet push down on the ground, and the ground pushes up on your feet. This is the correct example of action and reaction pair. The correct option is C.

Newton's third law of motion states that " for every action, there is an equal and opposite reaction".

This means that if object "1" exerts a force on object "2", then object "2" will exert an equal and opposite force on object "1".

In mathematical terms, the third law can be expressed as:

F₁₂ = - F₂₁

Where

F₁₂ = the force exerted by object "1" on object "2",

F₂₁ =the force exerted by object "2" on object "1".

The negative sign indicates that the two forces are equal in magnitude but opposite in direction.

This law applies to all objects in the universe, and it is essential for understanding how objects interact with each other. It explains how a rocket is propelled into space, how a person can walk on the ground, and how a bird can fly through the air.

For example: when a person walks on the ground, their foot exerts a force on the ground. According to Newton's third law, the ground will then exert an equal and opposite force on the foot, pushing the person forward. This allows the person to walk and move forward.

Similarly, when a bird flies through the air, the bird's wings exert a force on the air, and the air exerts an equal and opposite force on the bird, lifting it up and allowing it to fly.

Here in the question,

When you push down on the ground with your feet, the ground pushes up on your feet with an equal and opposite force. This pair of forces are equal in magnitude and opposite in direction, satisfying the conditions of Newton's third law of motion.

Whereas,

Option A describes two separate forces acting on you, but these are not action-reaction pairs because they are not equal in magnitude and opposite in direction.

Options B and D both describe forces acting in opposite directions, but they are not action-reaction pairs because they do not involve two objects interacting with each other.

Therefore, in option C Your feet push down on the ground, and the ground pushes up on your feet, which is the correct option.

To learn more about Newton's law of motion  click:

brainly.com/question/29775827

#SPJ7

Answer:

focal length :

[tex]{ \tt{f = \frac{r}{2} }} \\ focal \: length = \frac{36}{2} = 18 \: cm[/tex]

From linear magnification:

[tex]{ \tt{ \frac{1}{m} + 1 = \frac{u}{f} }} \\ \frac{1}{9} + 1 = \frac{u}{18} \\ \\ u = \frac{18 \times 10}{9} \\ u = 20 \: cm[/tex]

The object must be at 20 cm

Answer:

Explanation:

The formula for this, the easy one, is

[tex]N=N_0(\frac{1}{2})^{\frac{t}{H}[/tex] where No is the initial amount of the element, t is the time in years, and H is the half life. Filling in:

[tex]N=48.0(\frac{1}{2})^{\frac{49.2}{12.3}[/tex] and simplifying a bit:

[tex]N=48.0(.5)^4[/tex] and

N = 48.0(.0625) so

N = 3 mg left after 12.3 years

How many half-lifes is 49.2 years ?

(49.2 years) / (12.3 years per half-life)  =  4 half-lifes.

In 4 half-lifes, (1/2) · (1/2) · (1/2) · (1/2) of the original sample remains.

That's (1/2⁴) or (1/16) of the original.

(1/16) of 48.0 mg  =  3 mg .

=======================

Step-by-step:

== Start with 48 mg .

== After one half-life, 24 mg remains.

== Then, after the second half-life, 12 mg remains.

== Then, after the third half-life, 6 mg remains.

== Then, after the fourth half-life, 3 mg remains.

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

[tex]\sf{\qquad{\qquad{\underline{\underline{ Projectile~motion }}}}}[/tex]

If an object is given an initial velocity in any direction and then allowed to travel freely under gravity only, it is called a projectile motion.

It is basically 3 types

The path followed by a projectile is called its trajectory.

Projectile motion is when an object moves in a bilaterally symmetrical, parabolic path.

The path that the object follows is called its trajectory.

Projectile motion only occurs when there is one force applied at the beginning, after which the only influence on the trajectory is that of gravity