PLS HELP! WILL GIVE BRAINLIEST

Answer:

a:h=square root of 0.6

Step-by-step explanation:

thank you for your time today

Answer:

none of the above

Step-by-step explanation:

KHAN

Answer:

18.63

Step-by-step explanation:

[tex] \frac{6}{10} = 0.6 \\ \frac{3}{100} = 0.03[/tex]

[tex]10 + 8 + 0.6 + 0.03 = 18.63[/tex]

Answer:

1st expression= rational 2nd expression= rational 3rd expression = irrational

Step-by-step explanation:

The first and second expressions are rational because they both equal whole numbers (4 and 3) while the last expression equals a decimal that goes on forever with no end, thus making it irrational.

Answer:

they travel 115 km/h long

Answer:

(-9/2,-1)

Step-by-step explanation:

Use the midpoint formula to find the midpoint of the line segment.

Answer:

Step-by-step explanation:

x - first

x + 12 - second

x + (x + 12) = 44

2x=44-12

x=16

first number is 16

second number is 16+12=28

two numbers are 16 and 28

16 and 28 are the required two numbers when one number exceeds another by 12 and their sum is 44

One number exceeds another by 12 and their sum is 44

We need to find the two numbers

Two expressions with equal sign is called equation.

Let x be the first number

x + 12 be the  second number

x + (x + 12) = 44

2x=44-12

x=16

Therefore first number is 16

second number is 16+12=28

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Answer:

5^6

Step-by-step explanation:

This is because the exponent is how many numbers are in the multiplication equation, in this case, five. Because there are six five's being multiplied together, our exponent is six.

Here we want to see which type of set is a band's setlist.

We will see that it is a discrete set.

We can define two types of sets

Continue sets are those, like the name implies, continuous (or dense). Examples can be the set of real numbers.

Discrete sets are those that have "gaps" between consecutive elements. For example, the integer set is a discrete set. Particularly, discrete sets can be quantized (counted).

Now, we have a list of songs, that can be written as:

L  = {song 1, song 2, song 3, ...}

Here we can see that we have separated elements. Thus, this is a discrete set. This happens because we clearly can separate the element "song 1" from "song 2" (there may be a lapse of time between them, defining the end of the first one), so we have the "gaps" mentioned above.

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[tex]\\ \sf\longmapsto 0.49=\dfrac{49}{100}[/tex]

[tex]\\ \sf\longmapsto 0.093=\dfrac{93}{1000}[/tex]

[tex]\\ \sf\longmapsto 0.021=\dfrac{21}{1000}[/tex]

[tex]\\ \sf\longmapsto 0.103=\dfrac{103}{1000}[/tex]

Answer:

join me on no comments yet the story is about to the turf and a bagane and pinni geting step by step explanation friendship is not working properly and the story of a y I have a mantra and sister about your self and the story of the story is a bagane unda and the story and the portion of the story of the story of the story is about the event of a y you know if

Answer:

Step-by-step explanation:

Answer:

Answer = he made 7,000 in July and sold 10 cars in august.

Step-by-step explanation:

Answer:

The value of 6 in 675,002 is 1,000 times greater than the value of 6 in 385,621.

Answer:

5/10, 1, 2/4,

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

It just is

92.000.070.108

Step-by-step explanation:

Thousand has 3 zeros, a million has 6 and a billion has 9.

So for ninety-two billion, you take 92 and add 9 zeros behind it because a billion has 9 zeros

(92.000.000.000)

The scaled factor is 3 for all of them.

We need to find the equation which is equidistant to the given points.

[tex]A(-2,6,3)[/tex] and [tex]B(5,3,-3)[/tex]

This can be done using the distance formula.

Let us take a point [tex]P(x,y,z)[/tex] which is equidistant from both points so

[tex]\sqrt{(x+2)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-5)^2+(y-3)^2+(z+3)^2}\\\Rightarrow y^2-12y+x^2+4x+z^2+49-6z=y^2-6y+x^2+z^2+6z+43-10x\\\Rightarrow 7x-3y-2z+1=0[/tex]

The required equation is [tex]7x-3y-2z+1=0[/tex]

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Answer:

-1/4

Step-by-step explanation:

-0.25

Answer:

Yes. It is a rational number.

Answer:

[tex]f=12-\frac{t}{20}[/tex]

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

2x + (14 • 2) = 30

2x + 28 = 30

2x = 30 - 28

2x = 2

x = 2/2

x = 1

Hope this helps you. Do mark me as brainliest.

Answer:

-7/19

Step-by-step explanation:

First simplify the fractions. 18/-57= -6/19.

-6/19x7/6=-42/114

-42/114=-7/19

I hope this helps! I also put it into an online calculator to make sure it is right and it is!

Answer:

is this u want?

Step-by-step explanation:

if no so sorry..

Answer:

Question unclear

Step-by-step explanation:Your probally asking what times 8 gives us 80. If you are than 10!

[tex]3\cdot[(2\cdot6-5)+(8:4)]-1=\\\\=3\cdot[(12-5)+2]-1=3\cdot(7+2)-1=\\\\=3\cdot9-1=27-1=\boxed{26}[/tex]

Differentiate both sides with respect to x and solve for the derivative dy/dx :

[tex]\dfrac{\mathrm d}{\mathrm dx}\left[x^2y^2+xy\right] = \dfrac{\mathrm d}{\mathrm dx}[2] \\\\ \dfrac{\mathrm d}{\mathrm dx}\left[x^2\right]y^2 + x^2\dfrac{\mathrm d}{\mathrm dx}\left[y^2\right] + \dfrac{\mathrm d}{\mathrm dx}\left[x\right]y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ 2xy^2 + x^2(2y)\dfrac{\mathrm dy}{\mathrm dx} + y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ (2x^2y+x)\dfrac{\mathrm dy}{\mathrm dx} = -2xy^2-y \\\\ \dfrac{\mathrm dy}{\mathrm dx} = -\dfrac{2xy^2+y}{2x^2y+x}[/tex]

This gives the slope of the tangent to the curve at the point (x, y).

If the slope of some tangent line is -1, then

[tex]-\dfrac{2xy^2+y}{2x^2y+x} = -1 \\\\ \dfrac{2xy^2+y}{2x^2y+x} = 1 \\\\ 2xy^2+y = 2x^2y+x \\\\ 2xy^2-2x^2y + y - x = 0 \\\\ 2xy(y-x)+y-x = 0 \\\\ (2xy+1)(y-x) = 0[/tex]

Then either

[tex]2xy+1 = 0\text{ or }y-x=0 \\\\ \implies y=-\dfrac1{2x} \text{ or }y=x[/tex]

In the first case, we'd have

[tex]x^2\left(-\dfrac1{2x}\right)^2+x\left(-\dfrac1{2x}\right) = \dfrac14-\dfrac12 = -\dfrac14\neq2[/tex]

so this case is junk.

In the second case,

[tex]x^2\times x^2+x\times x=x^4+x^2=2 \\\\ x^4+x^2-2 = (x^2-1)(x^2+2)=0[/tex]

which means either

[tex]x^2-1 = 0 \text{ or }x^2+2 = 0 \\\\ x^2 = 1 \text{ or }x^2 = - 2[/tex]

The second case here leads to non-real solutions, so we ignore it. The other case leads to [tex]x=\pm1[/tex].

Find the y-coordinates of the points with x = ±1 :

[tex]x=1 \implies y^2+y=2 \implies y=-2 \text{ or }y=1 \\\\ x=-1\implies y^2-y=2\implies y=-1\text{ or }y=2[/tex]

so the points of interest are (1, -2), (1, 1), (-1, -1), and (-1, 2).