Answer:
56.52 cm³
Step-by-step explanation:
[tex]\boxed{volume \: of \: cone = \frac{1}{3} \pi {r}^{2}h }[/tex]
Diameter= 2 ×radius
Radius
= 6 ÷2
= 3cm
Height, h= 6cm
Volume of the cone
[tex] = \frac{1}{3} (3.14)( {3}^{2} )(6)[/tex]
= 56.52 cm³
Please help!!! Urgent ….
9514 1404 393
Answer:
ΔWZT ~ ΔWXY
Step-by-step explanation:
Angle XWY and angle ZWT are vertical angles, so congruent.
The sides on either side of those angles are proportional:
WZ/WX = WT/WY
11/22 = 10/20 = 1/2
so, we can claim similarity by the SAS Theorem.
ΔWZT ~ ΔWXY
Help me please hurry!!
Answer:
answer is 36 centimeter
Step-by-step explanation:
volume of a cylinder=πr^2h
1696=3.14*r^2*15
1696=47.1=r^2
1696-47.1=r^2
1648.9=r^2
[tex]\sqrt{1648.9}[/tex] =r
40.60 =r
here according to the question and option given 40.60 is closest to 36 centimeters.so answer is option d.
Identify the relationship between the graphs of these two equations. y = 5/6x + 5 y = 5/6x - 1
parallel
perpendicular
neither
Answer:
parallel
Step-by-step explanation:
the slope of each line is 5/6 which means the lines are parallel
When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.4 = C, where C is a constant. Suppose that at a certain instant the volume is 400 cm^3 and the pressure is 80 kPa and is decreasing at a rate of 10 kPa/min. At what rate is the volume increasing at this instant?
Answer:
The volume increases at 35.71cm^3/min
Step-by-step explanation:
Given
[tex]PV^{1.4} = C[/tex]
[tex]V = 400cm^3[/tex]
[tex]P =80kPa[/tex]
[tex]\frac{dP}{dt} =-10kPa/min[/tex]
Required
Rate at which volume increases
[tex]PV^{1.4} = C[/tex] [tex]V = 400cm^3[/tex] [tex]P =80kPa[/tex]
Differentiate: [tex]PV^{1.4} = C[/tex]
[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = \frac{d}{dt}C[/tex]
By differentiating C, we have:
[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = 0[/tex]
Rewrite as:
[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} + V^{1.4}*\frac{dP}{dt} = 0[/tex]
Solve for [tex]\frac{dV}{dt}[/tex]
[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} =- V^{1.4}*\frac{dP}{dt}[/tex]
[tex]\frac{dV}{dt} =- \frac{V^{1.4}*\frac{dP}{dt} }{P*(1.4)*V^{0.4}}[/tex]
Substitute values
[tex]\frac{dV}{dt} =- \frac{400^{1.4}*-10 }{80*(1.4)*400^{0.4}}[/tex]
[tex]\frac{dV}{dt} =\frac{400*10 }{80*1.4}[/tex]
[tex]\frac{dV}{dt} =\frac{4000 }{112}[/tex]
[tex]\frac{dV}{dt} =35.71cm^3/min[/tex]
Which choice shows (40+10)+30 correctly rewritten using the associative property and then correctly simplified?
40 + (10 + 30) = 40 + 40 = 80
40 + 30 + 10 = 70 + 10 = 80
40 + (10 +30) = 50 + 30 =80
(10 +40) + 30 = 50 + 30 =80
why is the mean of the set of data is always greater than it's median?
Answer:
One of the basic tenets of statistics that every student learns in about the second week of intro stats is that in a skewed distribution, the mean is closer to the tail in a skewed distribution. So in a right skewed distribution (the tail points right on the number line), the mean is higher than the median.
Step-by-step explanation:
The distribution is said to be right-skewed. In such a distribution, usually (but not always) the mean is greater than the median, or equivalently, the mean is greater than the mode; in which case the skewness is greater than zero.
On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).
Trapezoid GHJK was rotated 180° about the origin to determine the location of G'H'J'K', as shown on the graph. What are the coordinates of pre-image point H?
(2, 3)
(–2, 3)
(3, 2)
(3, –2)On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).
Trapezoid GHJK was rotated 180° about the origin to determine the location of G'H'J'K', as shown on the graph. What are the coordinates of pre-image point H?
(2, 3)
(–2, 3)
(3, 2)
(3, –2)
Answer:
the coordinates of pre - image point H is (3,2)
Answer:
c time for learning
Step-by-step explanation:
Please answer the question in order please.
Answer:
Step-by-step explanation:
Answer and I will give you brainiliest
Answer:
Step-by-step explanation:
Hope this helps u !!
Answer:
first thing B union with c { 2,3,4,5,6}
then this group intersect with A that's will be {1,2,3} intersect with { 2,3,4,5,} the result { 2,3}
What is the probability of tossing a penny and landing on heads 3 times in a row
Answer:
Suppose you have a fair coin: this means it has a 50% chance of landing heads up and a 50% chance of landing tails up. Suppose you flip it three times and these flips are independent. What is the probability that it lands heads up, then tails up, then heads up? So the answer is 1/8, or 12.5%.
describe the transformation of the equation below from the parent function of y=|x| y=|x-4| left 4, right 4, up 4, down4
Answer:
The transformation is right 4
Step-by-step explanation:
Since the transformation occurred inside the absolute value function, this means there will be a horizontal shift. Therefore, the transformation is right 4.
Observe the graph to view the transformation.
What should my answer be?
WILL GIVE BRAINLIST! PUT THESE NUMBERS ON THE PLOT
Answer:
"fair" srry im only in 8th so im d.u.m
Step-by-step explanation:
What is the equation of the line that passes through (-3,-1) and has a slope of
2/5. Put your answer in slope intercept
Answer:
y = 2/5x + 1/5
Step-by-step explanation:
First, plug in the slope.
y = mx+b
y = 2/5x + b
Then, plug in the point given, in order to find b.
-1 = 2/5(-3) + b
-1 = -6/5 + b
1/5 = b
So the final equation is:
y = 2/5x + 1/5
I need help anyone please
Answer:
Base: 7
Height:10
BH divided by two so
7 times 10 = 70 divided by two 35
Base: 7 yd
Height: 10 yd
Area: 35 square yd
([tex]A=\frac{h_{b}b }{2}[/tex] = [tex]\frac{10*7}{2}[/tex] = 35)
hope this helps....
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
prove triangle ACD and BCE are congruent
Given:
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
To prove:
Triangle ACD and BCE are congruent.
Solution:
In triangle ACD and BCE,
[tex]AC=BC[/tex] (Given)
[tex]AC\cong BC[/tex]
[tex]\angle C\cong m\angle C[/tex] (Common angle)
[tex]CD=CE[/tex] (Given)
[tex]CD\cong CE[/tex]
In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.
[tex]\Delta ACD\cong \Delta BCE[/tex] (SAS congruence postulate)
Hence proved.
Answer:
Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD
Given AB=AC∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)
Given BE=CDThen BE−DE=CD−DE
ORBC=CE......................................(2)
In ΔABD and ΔACE
∠ABD=∠ACE ( From 1)
BC=CE (from 2)
AB=AC ( GIven)
∴ΔABD≅ΔACE
So AD=AE [henceproved]
Simplify (-k)^0
Help! Thank you. (:
Answer:
I think 1 is the correct answer
Each sample of water has a 30% chance of containing a particular organic pollutant. Assume that the samples are independent with regard to the presence of the pollutant. Find the probability that, in the next 10 samples, two or less contain the pollutant. (Hint: using the tables in Appendix A will be faster than doing it by hand!)
a) 0.678
b) 0.028
c) 0.041
d) 0.383
Answer:
d) 0.383
Step-by-step explanation:
For each sample, there are only two possible outcomes. Either they contain the pollutant, or they do not. The probability of a sample containing the pollutant is independent of any other sample. Thus, the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
30% chance of containing a particular organic pollutant.
This means that [tex]p = 0.3[/tex]
Next 10 samples
This means that [tex]n = 10[/tex]
Probability that two or less contain the pollutant.
This is:
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.028[/tex]
[tex]P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.121[/tex]
[tex]P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.233[/tex]
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.028 + 0.121 + 0.233 = 0.382[/tex]
A little rounding difference, but the correct answer is given by option d.
how many matches are needed to form figure number 9 and 17? explain
Answer:
Please find the complete question in the attached file.
Step-by-step explanation:
For point 1:
At this point we make up triangles for the first one makes up by 3 matches figure 2 make up by 5 matches figure 3 makes up by 7 matches.
For point 2:
[tex]4 \ \ 5\ \ 6\ \ 7\ \ 8[/tex] you can try to
[tex]9 \ \ 11\ \ 13 \ \ 15 \ \ 17[/tex] draw to find values
For point 3:
number of matches[tex]= 1+2 \times \ figure\ number\\\\[/tex]
For point 4:
[tex]1+2 \times 9=19 \ \ (use \ law \ of\ (iii)) \\\\1+2 \times 17=35[/tex]
Suppose that you have a square pyramid like the one pictured. Which plane section will produce a triangle?
A)
A cut parallel to the vertical axis, but off the vertical axis
B)
A cross section cut parallel with the bottom
C)
A cut parallel to the vertical axis, directly through the vertical axis
D)
Cutting off one of the bottom corners
Answer:
A
Step-by-step explanation:
Find the measure of each angle listed below. Enter only numbers without space.
(1) ∠PTQ
(2) ∠QTR
(3) ∠PTS
9514 1404 393
Answer:
∠PTQ = 45°∠QTR = 15°∠PTS = 120°Step-by-step explanation:
Parallelogram PTSR is divided into two equilateral triangles by diagonal RT. All of the acute angles in that quadrilateral are 60°, and the obtuse angles are 120° (2×60° and also the supplement of 60°).
Triangle PTQ is an isosceles right triangle, so its acute angles are 45°.
∠PTQ = 45°
∠QTR = ∠PTR -∠PTQ = 60° -45°
∠QTR = 15°
∠PTS = 120° . . . . . . obtuse angle in PTSR; sum of ∠PTR and ∠RTS
Select the correct answer.
The y-Intercept of the parent quartic function, f(x) = 24
is translated 3 units to the right and 1 unit down. Which equation represents this
transformation?
OA. g() = (x – 3)4 - 1
OB. g(t) = (x + 3)4 - 1
OC. g(t) = (x - 1)* + 3
OD. g() = (x + 1)4 + 3
Using translation concepts, it is found that the equation that represents this transformation is given by:
A. [tex]g(x) = (x - 3)^4 - 1[/tex]
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
In this problem, the parent function is given by:
[tex]f(x) = x^4[/tex].
Then:
The function is shifted 3 units right, hence x -> x - 3.The function is shifted 1 unit down, hence f(x) -> f(x) - 1.Hence, the equation that represents the transformation is given by:
[tex]g(x) = (x - 3)^4 - 1[/tex]
Which means that option A is correct.
More can be learned about translation concepts at https://brainly.com/question/4521517
#SPJ1
Who ever can help me with geometry homework I’ll give brainlist
Answer:
Step-by-step explanation:
Remark
All of the figures below are rectangles. They all use the same formula: Area = L * W, so I won't repeat the formula for every part.
Left cross arm
L = 11 mw = 9 mArea = 11 * 9Area = 99 m^2Right Cross Arm
L = 11 mW= 9 mArea = 11 * 9Area = 99 m^2Top
L = 13 mW = 9 mArea = 117 m^2Middle
L=13 mW = 11 mArea = 143 m^2First bottom Closest to the center.
L = 13 mW = 9 mArea = 117 m^2Second Bottom
L= 13 mW = 11 mArea 143 m^2Total 718 m^2
In ΔTUV, t = 7 inches, u = 9.4 inches and ∠V=18°. Find the area of ΔTUV, to the nearest 10th of a square inch.
Answer:
10 square inches
Step-by-step explanation:
that is the procedure above
Answer:
Area=10.167=10.2
Step-by-step explanation:
Area=1/2ab sin c
area= 1/2(7)(9.4)sin18
area = 10.167=10.2
this is for delta math
Find the value of a. Round to the nearest tenth, if necessary. 11 24 a
Answer:
21.3
Step-by-step explanation:
It's easier to see how to do this if you transfer the 11 to the bottom of the rectangle. The look at the left triangle. It has 3 sides.
24, 11, and a.
You should be able to find a using
a^2 + 11^2 = 24^2 Expand the squares
a^2 + 121 = 576 Subtract 121 from both sides
a^2 = 576 - 121
a^2 = 455 Take the square root of both sides.
sqrt(a^2) = sqrt(455)
a = 21.33
or
a = 21.3
What is the 8th term of a(n)=6•3^(n-1)
Answer:
13122
Step-by-step explanation:
a(n) = 6 * 3^(n -1)
a(8) = 6* 3^7
3^7 = 2187
a(8) =6 * 2187
a(8) = 13122
Write the following expression in standard place-value form.
Answer:
3408
Step-by-step explanation:
Select the correct answer. Simplify. V75 options: A. 3v5 B. 15v5 C. 25v3 D. 5v3
I need help solving for x
Answer:
x = 25
Step-by-step explanation:
Given a line parallel to a side of the triangle and intersecting the other 2 sides then it divides those sides proportionally, that is
[tex]\frac{40}{24}[/tex] = [tex]\frac{x}{15}[/tex] ( cross- multiply )
24x = 600 ( divide both sides by 24 )
x = 25
Over a season in a women's basketball league Jackson scored 38 more points than the second-highest scorer, Leslie. Together, Jackson and Leslie scored 1134 points during the season. How many points did each player score over the course of the season?
Answer:
leslie will hace 587 score and
jackson =587+31= 618
Step-by-step explanation:
1134 -31/2 = leslie
leslie + 31 = 618
Answer:
see below
Step-by-step explanation: 6 24 10 18
Leslie = x points
Jackson scored 38 more points than Leslie Jackson = x + 38 points
Together, Jackson and Leslie scored 1134 Sum of both scores
Leslie + Jackson = 1134
x + x + 38 = 1134 solve for x Leslie's number of points
2x + 38 = 1134
2x + 38 - 38 = 1134 -38
2x = 1096
2x/2 = 1096 / 1
x = 1096 /2
x = 548 Leslie points
Jackson = Leslie's points + 38 points
= 548 + 38
Jackson's points = 586 points
