Answer:
b
Step-by-step explanation:
In general
Given
y = f(x) then y = f(Cx) is a horizontal stretch/ compression in the x- direction
• If C > 1 then compression
• If 0 < C < 1 then stretch
Consider corresponding points on the 2 graphs
(2, 2 ) → (4, 2 )
(4, - 2 ) → (8, - 2 )
Indicating a stretch in the x- direction.
y = f([tex]\frac{x}{2}[/tex] ) with C = [tex]\frac{1}{2}[/tex] , that is 0 < C < 1
stretches the graph in the x- direction by a factor of 2
Thus
y = f([tex]\frac{x}{2}[/tex] ) → b
-2(8 - 1)= complete the following statement
We simplify the expression by subtracting 1 from 8, resulting in 7. We then multiply 7 by -2 to obtain the final answer of -14.
To simplify the given expression, -2(8 - 1), we can start by evaluating the expression inside the parentheses,
8 - 1 = 7
Now, we substitute this value back into the original expression:
-2(7)
Multiplying -2 by 7, we get:
-2 * 7 = -14
Therefore, -2(8 - 1) simplifies to -14.
In this case, we simplified the expression inside the parentheses first and then applied the multiplication operation. It's important to remember that when there is a negative sign in front of parentheses, it distributes to each term inside the parentheses. So, -2 multiplied by 8 gives -16, and -2 multiplied by -1 gives +2. The sum of -16 and +2 is -14.
In summary, when we evaluate the expression -2(8 - 1), the result is -14. This means that if we follow the order of operations (parentheses first, then multiplication), we simplify the expression by subtracting 1 from 8, resulting in 7. We then multiply 7 by -2 to obtain the final answer of -14.
For more such questions on expression
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Write an expression to represent the product of 6 and the square of a number plus 15.
Answer:
6x^2 + 15
Step-by-step explanation:
We don't know what the square of a number is, so we represent it as x^2
The first part tells us to find the product of 6 and the square of a number, so
6x^2
The second part tells us to add 15 so,
6x^2 + 15
The expression that should be represented is [tex]6x^2 + 15[/tex]
Given that
The product of 6.The square of number + 15.Based on the above information,
Let us assume the number should be x
So, from the above information, the expression should be [tex]6x^2 + 15[/tex]
Therefore we can conclude that The expression that should be represented is [tex]6x^2 + 15[/tex]
Learn more about the equation here:brainly.com/question/21105092?
A chocolate company has a new candy bar in the shape of a prism whose base is a 1-inch equilateral triangle and whose sides are rectangles that measure 1 inch by 2 inches. These prisms will be packed in a box that has a regular hexagonal base with 2-inch edges, and rectangular sides that are 6 inches tall. How many candy bars fit in such a box
A coin is tossed. What is the theoretical probability of the coin NOT showing tails?
P(Not tails) =
Answer:
50%
Step-by-step explanation:
its 50% it will land on head and 50% it will land on tails since there is only two sides on a coin
Answer:
1/2 or .5
p(1/2)
Step-by-step explanation:
its simple, there are 2 sides to a coin, so there are 2 possible outcomes. and the question asks what is the probability of the coin landing on one or in other wrds, its asking what is te probilitity of one of the two heads to be up. SO the probility is 1/2
convert the equation f(x)=1/2x^2+3x-2 to vertex form
Answer:
Step-by-step explanation:
Hello, please consider the following.
The "vertex form" is as below.
[tex]y=a(x-h)^2+k\\\\\text{Where (h, k) is the vertex of the parabola.}\\[/tex]
Let's do it!
[tex]f(x)=\dfrac{1}{2}x^2+3x-2\\\\f(x)=\dfrac{1}{2}\left(x^2+3*2*x\right) -2\\\\f(x)=\dfrac{1}{2}\left( (x+3)^2-3^2\right)-2\\\\f(x)=\dfrac{1}{2}(x+3)^2-\dfrac{9}{2}-\dfrac{4}{2}\\\\f(x)=\dfrac{1}{2}(x+3)^2-\dfrac{9+4}{2}\\\\\large \boxed{\sf \bf \ \ f(x)=\dfrac{1}{2}(x+3)^2-\dfrac{13}{2} \ \ }[/tex]
Thank you.
The functions q and r are defined as follows
g(x) = -2x-2
r(x) = x² – 2
Find the value of r(q(4)).
r(9 (4)) =
Answer:
98
Step-by-step explanation:
So we have the two functions:
[tex]g(x)=-2x-2\text{ and } r(x)=x^2-2[/tex]
And we want to find the value of r(g(4)).
To do so, first find the value of g(4):
[tex]g(x)=-2x-2\\g(4)=-2(4)-2\\[/tex]
Multiply:
[tex]g(4)=(-8)-2[/tex]
Subtract:
[tex]g(4)=-10[/tex]
Now, substitute this into r(g(4)):
[tex]r(g(4))\\=r(-10)[/tex]
And substitute this value into r(x):
[tex]r(-10)=(-10)^2-2[/tex]
Square:
[tex]r(-10)=100-2[/tex]
Subtract:
[tex]r(-10)=98[/tex]
Therefore:
[tex]r(-10)=r(g(4))=98[/tex]
Answer:
Step-by-step explanation:
Two angles are adjacent and form an angle of 160. Their difference is 34. Find the angles
Answer:
The angles are 63 , 97
Step-by-step explanation:
Let one angle be x
As sum of two angles is 160, the other angle = 160 - x
Their difference = 34
x - [160- x] = 34
Use distributive property to remove the brackets
x - 160 + x = 34
Add like terms
x + x - 160 = 34
2x - 160 = 34
Add 160 to both sides
2x = 34 + 160
2x = 194
Divide both sides by 2
2x/2 = 194/2
x = 97°
One angle = 97°
Other angle = 160 - 97 = 63°
if the diameter is 20 cm what is the area based on pi
Answer:
[tex]\Large \boxed{\mathrm{100\pi \ cm^2 }}[/tex]
Step-by-step explanation:
[tex]\displaystyle area \ of \ circle \ = \ \pi (\frac{diameter}{2} )^2[/tex]
[tex]\displaystyle A \ = \ \pi ( \frac{20}{2} )^2[/tex]
[tex]\displaystyle A \ = \ \pi ( 10 )^2[/tex]
[tex]\displaystyle A \ = \ 100\pi[/tex]
Given that p=x^2-y^2/x^2+xy
I. Express p in the simplest form
ii. Find the value of p if x=-4 and y=-6
Answer:
p = - [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Given
p = [tex]\frac{x^2-y^2}{x^2+xy}[/tex] ( factorise numerator and denominator )
x² - y² ← is a difference of squares and factors as (x - y)(x + y)
x² + xy ← factor out x from each term
= x(x + y) , thus
p = [tex]\frac{(x-y)(x+y)}{x(x+y)}[/tex] ← cancel (x + y) on numerator/ denominator
= [tex]\frac{x-y}{x}[/tex] ← substitute x = - 4, y = - 6
= [tex]\frac{-4-(-6)}{-4}[/tex]
= [tex]\frac{-4+6}{-4}[/tex]
= [tex]\frac{2}{-4}[/tex] = - [tex]\frac{1}{2}[/tex]
find the value of X in X-X³=17
Answer:
Step-by-step explanation:
Step1: find the interval of roots. Consider -3 and -2
[tex]f(-3) = -7 <0[/tex]
[tex]f(-2) = 18 >0[/tex]
Hence, the root must be on [-3,-2]
Step2: consider the middle point -2.5
[tex]f(-2.5) = 3.875 >0[/tex]
Then, the root must be on [-3, -2.5]
Step 3: Repeat step 2 by finding the value of f at the middle point -2.75
[tex]f(-2.75) = -1.0468 <0[/tex]
Step 3: Repeat step 2 by finding the value of f at the middle point of the interval [-2.75,-2.5] which is -2.625
[tex]f(-2.625) = 1.537 >0[/tex]
Step4: Repeat step 2 on [-2.75, -2.625]
Repeat step 2 until you got the root which is -2.701
ILL GIVE BRAINLIEST!!!! HELP
Two planes have a cruising speed of 750 km/h without wind. The first plane flies for 13 hours against a constant headwind. The second plane flies for 11 hours in the opposite direction with the same wind (a tailwind). The second plane flies for 250 km less than the first plane. Determine two equations that could be used to solve for the wind speed,w, and the distance traveled by the first plane,d.
1. (750+w)(13)=d (750+w)(11)=d+250 2. (750−w)(13)=d (750+w)(11)=d−250 3. (750+w)(13)=d (750−w)(11)=d−250 4. (750−w)(13)=d (750−w)(11)=d+250
Answer:
The correct option is;
2. (750 - w)(13) = d (750 + w)(11) = d - 250
Step-by-step explanation:
The items with information given are;
The cruising speed of the planes = 750 km/h
The first plane flies against a constant headwind = w
The second plane flies against a constant tailwind in magnitude to the headwind
The time duration of flight of the first plane = 13 hours
The time duration of flight of the second plane = 11 hours
The distance flown by the second plane = The distance flown by the first plane - 250 km
When we take the headwind magnitude as, w and the distance flown by the first plane as d, we have;
Speed of flight of the first plane = 750 - w
Speed of flight of the second plane = 750 + w
Therefore, the distance flown by the first plane in 13 hours is given as follows;
(750 - w) × (13) = d
Then we have;
The distance flown by the second plane in 11 hours is (750 + w) × (11) = d.
The correct option is (750 - w)(13) = d, (750 + w)(11) = d - 250
Someone help me plzz
Step-by-step explanation:
distance around the running track means to find the perimeter of whole solid figure
radius(r) = 30/2 =15m
perimeter = 50+ pi× r + 50+ pi × r
= 100 + 2 × pi ×r
= 100 + 2× 22÷7 × 15
= 1360/ 7 m
= 194.285 m
Use slope-intercept form, y = mx + b, to find the value for the y-intercept (b) of a line that has a slope of 6 and passes through the point (3, –5)
Answer:
y=6x-23
Step-by-step explanation:
-5=6(3)+b
-5=18+b
b=-23
If this helps, plz give brainly, I rlly need it!
Answer:
6x-23
Step-by-step explanation:
Which expression is NOT equivalent to 4×38? A. 4×(3×18) B.(4×3)×18 C. (4×18)×3 D. (4×3)×(4×18)
Answer:
Every choice is not equivalent to 4✖️38.
Step-by-step explanation:
4✖️38=152
A. 54✖️4=216
B. 12✖️18=216
C. 72✖️3=216
D. 12✖️72=864
Every choice is not equivalent to 4✖️38.
ACME Hardware is introducing a new product called Greener Cleaner. Complete the table by finding the cost per milliliter for each size based on the sales price. One liter is 1,000 milliliters. (Answer the questions too, please!)
Answer:
Step-by-step explanation:
a). 'Per ml' cost of the small size = [tex]\frac{\text{Sale price of small cane}}{\text{Amount of liquid}}[/tex]
= [tex]\frac{4.50}{250}[/tex]
= $0.018
'Per ml' cost of the medium size = [tex]\frac{\text{Sale price of medium cane}}{\text{Amount of liquid}}[/tex]
= [tex]\frac{9.95}{500}[/tex]
= $0.0199
'Per ml' cost of the large size = [tex]\frac{\text{Sale price of large cane}}{\text{Amount of liquid}}[/tex]
= [tex]\frac{16.95}{1000}[/tex]
= $0.01695
Therefore, expression to compare per ml cost of three containers will be,
$0.0199 > $0.018 > $0.01695
b). Least expensive way to buy the cleaner is to choose the container with least per ml cost.
Cost of 1500 ml cleaner = Cost of 1000 ml cleaner + Cost of 500 ml of cleaner
= Cost of 1000 ml cleaner container + Cost of 'n' containers of 250 ml container
Total cost of 1500 ml = $16.95 + $4.50n
= 16.95 + 2(4.5) [For n = 2]
= $25.95
c). Most expensive way to purchase 1500 ml cleaner is to choose the most expensive cleaners
Cost of 1500 ml cleaner = Cost of 'n' containers of medium size containers
= 9.95(n)
= 9.95(3)
= $29.85
Someone pls help . Thank you sm☄️ .
1) 3 is the Coefficient.
2) 10 is the constant.
3) 10.8 is the ans.
Please help. Calculate the area of the shaded region in each figure use 3.14 for π and round to the nearest 10th if necessary
Can someone plz help me ASAP!!!!!!!!
Answer:
A) The number halfway between -2 and 6 is 2.
B) -10 is halfway between -18 and 8
Help please on question 61!!
Answer:
r = 1
Step-by-step explanation:
2πr = x
πr² = y
x = 2y
2πr = 2πr²
r = 1
An insurance firm reported that "the typical water-skiing accident occurs near the dock from which they start." Which of the following statistical measurements are they most likely discussing? A. mode B. range C. mean D. median
Answer:
The correct option is;
B. Range
Step-by-step explanation:
In descriptive statistics which analyses the quantitative summary of the statistical data, the range is the region or area or the statistical interval where the data is obtained from and as such the range (in descriptive statistics) gives a guide to the dispersion of the statistical information.
The range is best suited for the representation of the dispersion when the size of the data set is small.
complete the square to solve
f(x)=x^2-6x+5
What ratio of 25 dextrose and 10% dextrose should be mixed to make a 20% Dextrose? Comments for What Ratio of 25% Dextrose and 10% Dextrose to make 20% Dextrose? 10 parts 25% and 5 parts 10% solution equals 20% mixture.
Answer:
10:5 OR 2:1
Step-by-step explanation:
Let x be the parts of 25% dextrose and
y be the parts of 10% dextrose are mixed so that
20% dextrose mixture is obtained.
amount of dextrose in the mixture will be 20% of (x+y).
We have to find the value of [tex]\frac{x}y \ OR\ x:y[/tex]
Now, we can apply the concept that sum of amount of dextrose in the two liquids will be equal to the amount of dextrose in the mixture.
[tex]\Rightarrow x \times 25\% + y \times 10\%=(x+y)\times 20\%\\\Rightarrow x \times\dfrac{25}{100} + y \times \dfrac{10}{100}=(x+y)\times \dfrac{20}{100}\\\Rightarrow x \times25 + y \times 10=(x+y)\times 20\\\Rightarrow 25x + 10y=20x+20y\\\Rightarrow 25x -20x =20y-10y\\\Rightarrow 5x=10y\\\Rightarrow \dfrac{x}{y} = \dfrac{10}{5}\\\Rightarrow \bold{x:y=10:5\ OR\ 2:1}[/tex]
So, the answer is 10:5 or 2:1.
Answer:
4.90% is approximately the new Dextrose concentration.
Explanation:
Volume by Volume percent is given by ;
Volume percentage of dextrose solution = 5%
In 100 mL of solution 5 ml of dextrose is present.
Now, volume sterile water added was equal to the 40% of volume of dextrose volume.
So, volume of the sterile water added =
Total volume of the solution after addition of water = 100 mL + 1 mL = 102 mL
New concentration of dextrose will be;
4.90% is approximately the new Dextrose concentration.
Step-by-step explanation:
1. Given thatA={1,2,3,4,5} and B={3,5,10,11,12} and such that U= AUB. I) list down the elements of U,A' and A'UB'. ii) how many subsets do set A have?
Answer:
U = {1, 2, 3, 4, 5, 10, 11, 12}A' = {10, 11, 12}A'∪B' = {1, 2, 4, 10, 11, 12}A has 32 subsetsStep-by-step explanation:
i) The union of the two sets is the list of elements that are in either. Duplicates are listed only once.
U = {1, 2, 3, 4, 5, 10, 11, 12}
A' = U - A = {10, 11, 12}
A'∪B' = {10, 11, 12}∪{1, 2, 4} = {1, 2, 4, 10, 11, 12}
__
ii) A has 5 elements, so has 2^5 = 32 subsets, including the empty set and the whole set.
Find the smallest value of $x$ such that $x^2 + 10x + 25 = 8$.[tex]Find the smallest value of $x$ such that $x^2 + 10x + 25 = 8$.[/tex]
Hello, please consider the following.
[tex]x^2 + 10x + 25 = 8\\\\\text{\bf We can notice that } x^2+10x+25=(x+5)^2 \text{ so}\\\\x^2 + 10x + 25 = (x+5)^2=8\\\\\text{\bf We take the root.}\\\\x+5=\pm\sqrt{8}\\\\\text{\bf We subtract 5}\\\\\boxed{x=-5-\sqrt{8}} \ \ or \ \ x=-5+\sqrt{8}[/tex]
In the box, you can find the smallest solution.
Thank you.
X=3816371/(27×63) solve for x
Answer:
X = 14,700
Step-by-step explanation:
you can use a calculator to get the x.
X=3816371/(27×63)
PLEASE HELP f(x)=x^2 and g(x)=(x-3)^2+2 Describe how the graph of g(x) relates to the graph of its parent function, f(x). (HINT: Think about how f(x) was shifted to get g(x))
Answer:
The graph f(x) was shifted 3 units to the right and shifted 2 units up to get the graph of g(x).
Step-by-step explanation:
From the original graph to the transformed one, we can see that the transformations (x - 3) and + 2 were added to the equation.
The (x - 3) means that the x-value of the vertex will increase by 3, meaning that the graph will shift 3 units to the right.
The +2 will increase the y-value of the vertex by 2, meaning that the graph will move up 2 units.
So, the graph of g(x) relates to f(x) as it is a transformation 3 units to the right and 2 units upwards.
Jeremy drove 180 miles in 3 hours. Find his average rate of change.
Answer:
60 miles per hour
Step-by-step explanation:
Total distance= 180 miles
Total time =3 hours
Average rate of change= ?
Distance= Rate × time
Make Time the subject of the formula
Time= Distance / Rate
Make average rate of change the subject of the formula
Average rate of change = Distance / time
= 180 miles / 3 hours
= 60 miles per hour
It says to find the area of the shaded square, but I not sure how to get the answer.
Answer:
68 square cm
Step-by-step explanation:
Interior square WXYZ is making four right triangles of equal bases (8 cm) and heights (2 cm) inside the square ABCD. Therefore,
Area of shaded Square = Area of square ABCD - 4 times area of one right triangle.
[tex] = {10}^{2} - 4 \times \frac{1}{2} \times 8 \times 2 \\ = 100 - 32 \\ = 68 \: {cm}^{2} [/tex]
HELP! WIll MARK BRAINLIEST! ACME Hardware is introducing a new product called Greener Cleaner. Complete the table by finding the cost per milliliter for each size based on the sales price. One liter is 1,000 milliliters. (Answer the questions too, please!)
Question 1:
Price per milliliter
Small $4.50 / 250ml
Medium $9.95 / 500 ml
Large $16.95 / 1000 ml
Question 2:
$9.95 / 500 ml > $4.50 / 250ml > $16.95 / 1000 ml
Question 3 - 4:
$4.50 / 250ml = ($4.50 * 6) / (250ml * 6 ) = $27 / 1500ml = 0.018
$9.95 / 500 ml = ($9.95 * 3) / (500 ml * 3) = $29.85 / 1500ml = 0.019
$16.95 / 1000 ml = ($16.95 * 3) / (1000 ml * 3) = $50.85 / 1500ml = 0.0339
( Use the first one for question 3 and the second for question 4)
$4.50 / 250ml would be the cheapest way to get 1500ml.
$9.95 / 500ml would be the most expensive way to get 1500ml.
I hope this helps you! Tell me if I'm wrong!
A.) pinky bought 1 1/2 kg of apples and 5 1/4 kg of mangoes and 1 1/2 Kg of oranges. Find the total weight of fruits B.) If her family eats 3/4 Kg of apples and 2 1/2 kg of mangoes and 1/2 Kg of oranges. Find the weight of the fruits left (Can any one say the answer please with explanation if who say the answer first I will mark them as the brainliest)
Answer:
a) The total weight of fruits is [tex]8\,\frac{1}{4}[/tex] kilograms, b) The weight of the fruits left is [tex]4\,\frac{1}{2}[/tex] kilograms.
Step-by-step explanation:
a) The total weight of fruits ([tex]m_{T}[/tex]) is calculated by the following formula:
[tex]m_{T} = m_{a} + m_{m}+m_{o}[/tex]
Where:
[tex]m_{a}[/tex] - Total weight of apples, measured in kilograms.
[tex]m_{m}[/tex] - Total weight of mangoes, measured in kilograms.
[tex]m_{o}[/tex] - Total weight of oranges, measured in kilograms.
If [tex]m_{a} = 1\,\frac{1}{2} \,kg[/tex], [tex]m_{m} = 5\,\frac{1}{4}\,kg[/tex] and [tex]m_{o} = 1\,\frac{1}{2}\,kg[/tex], then:
[tex]m_{T} = 1\,\frac{1}{2}\,kg + 5\,\frac{1}{4}\,kg + 1\,\frac{1}{2}\,kg[/tex]
[tex]m_{T} = \frac{6}{4}\,kg + \frac{21}{4}\,kg + \frac{6}{4}\,kg[/tex]
[tex]m_{T} = \frac{33}{4}\,kg[/tex]
[tex]m_{T} = 8\,\frac{1}{4}\,kg[/tex]
The total weight of fruits is [tex]8\,\frac{1}{4}[/tex] kilograms.
b) The weight eaten by her family is determined by the following expression:
[tex]m_{E} = m_{a,e} + m_{m,e} + m_{o,e}[/tex]
Where:
[tex]m_{a,e}[/tex] - Eaten weight of apples, measured in kilograms.
[tex]m_{m,e}[/tex] - Eaten weight of mangoes, measured in kilograms.
[tex]m_{o,e}[/tex] - Eaten weight of oranges, measured in kilograms.
Given that [tex]m_{a,e} = \frac{3}{4}\,kg[/tex], [tex]m_{m,e} = 2\,\frac{1}{2}\,kg[/tex] and [tex]m_{o,e} = \frac{1}{2}\,kg[/tex], the weight eaten by her family is:
[tex]m_{E} = \frac{3}{4}\,kg + 2\,\frac{1}{2}\,kg + \frac{1}{2}\,kg[/tex]
[tex]m_{E} = \frac{3}{4}\,kg + \frac{10}{4}\,kg + \frac{2}{4}\,kg[/tex]
[tex]m_{E} = \frac{15}{4}\,kg[/tex]
[tex]m_{E} = 3\,\frac{3}{4}\,kg[/tex]
The weight of the fruits left is found by subtraction:
[tex]m_{R} = m_{T}-m_{E}[/tex]
[tex]m_{R} = 8\,\frac{1}{4} \,kg -3\,\frac{3}{4}\,kg[/tex]
[tex]m_{R} = \frac{33}{4}\,kg-\frac{15}{4}\,kg[/tex]
[tex]m_{R} = \frac{18}{4}\,kg[/tex]
[tex]m_{R} = 4 \,\frac{1}{2}\,kg[/tex]
The weight of the fruits left is [tex]4\,\frac{1}{2}[/tex] kilograms.