PLEASE HELP! WILL MARK BRAINLIEST

[tex] \sf \: c = 3 \\ \sf \: d = 4 \\ \\ \sf \: 5cd \: = \: ?\\ \\ \sf \:5 cd \hookrightarrow \\ \sf = 5 \times (3) \times (4) \\ \sf = 5 \times 12 \\ = \underline{ \bf \: 60}[/tex]

-> Just substitute the values given for variables c & d in the equation 5cd & you'll get the answer.

Answer: V=9.4 cm^3

Step-by-step explanation:

[tex]V=\pi r^2h\\V=\pi (1)^2(3)\\V=9.4cm^3[/tex]

Answer:

Domain: (-2, 2]

Range: (-5, 4]

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

According to the graph, we see that our x values span from -2 to 2. Since -2 is an open dot and 2 is a closed dot, they are exclusive and inclusive, respectively:

(-2, 2] or -2 < x ≤ 2

According to the graph, we see that our y values span from -5 to 4. Since -5 is an open dot and 4 is a closed dot, they are exclusive and inclusive, respectively:

(-5, 4] or -5 < y ≤ 4

Answer:

x = 54

y = 144

Step-by-step explanation:

y = (10-2)×180/10 = 144

x = 180-90-(180-144) = 54

Answered by GAUTHMATH

Answer:  Radius is 21.2537 units, to 6 sig figs

Step-by-step explanation:  

I'll assume the circumference is simply 133.541 units^2.  Circumference (C) is C = 2*pi*R, where R is the radius.  Thus, R = C/(2*pi),

 R = (133.541/2*(3.14159) to 6 sig figs

 R = 21.2537 units

Answer:

3.69

Step-by-step explanation:

9% of 41 is (9/100)*41=369/100=3.69

Answer:

I believe its negative nonlinear association

Step-by-step explanation:

The line is going down so its definitely negative

And the line is not straight so its not linear

Therefore, its negative nonlinear association

Answer:

5x​(5x+1)^2

= 5x(25x^2+10x+1)

= 125x^3+50x^2+5x

Answer:

4/5 foot

Step-by-step explanation:

Add the lengths together

1/2 +3/10

Get a common denominator

1/2 *5/5  + 3/10

5/10 + 3/10

8/10

Simplify the fraction by dividing the top and bottom by 2

4/5

[tex]\rm \implies \: Total \: \: length \: \: of \: \: tape \: = \: \frac{1}{2} \: + \: \frac{3}{10} \\ [/tex]

[tex]\bf \large \rightarrow \: \: \frac{5 \: + \: 3}{10} \: = \: \frac{8}{10} \\ [/tex]

Now , simplifying the fraction in simplest form.

[tex]\bf \large \rightarrow \: \: \cancel\frac{8 \: \: ^{4} }{10 \: \: ^{5} } \: = \frac{4}{5} \\ [/tex]

Christian have 4/5 foot of tape have now.

Answer:

sub to the students notice the best of luck in life is good and u don't know what to do

9514 1404 393

Answer:

  after 89 years

Step-by-step explanation:

For principal p, interest rate r, and number of years t, the two account balances are ...

  a = p·e^(rt) . . . . continuous compounding

  a = p(1+r)^t . . . . annual compounding

Using the given values, we have

  3000·e^(0.07t) . . . . . compounded continuously

  20000·1.05^t . . . . . . compounded annually

We want to find t so these are equal.

  3000·e^(0.07t) = 20000·1.05^t

  0.15e^(0.07t) = 1.05^t . . . . divide by 20,000

  ln(0.15) +0.07t = t·ln(1.05) . . . . take natural logarithms

  ln(0.15) = t·(ln(1.05) -0.07) . . . . subtract 0.07t

  t = ln(0.15)/(ln(1.05) -0.07) ≈ -1.8971/-0.02121 . . . . . divide by the coefficient of t

  t ≈ 89.4 ≈ 89

The two accounts will have the same balance after 89 years.

Answer:

below

Step-by-step explanation:

In short, we will add both coefficients together to combine like terms.

3x + 5x → x(3 + 5) → 8x

If you have a value like 2x and 2, you cannot combine them because they do not have the same variable.

Best of Luck!

Answer:

[tex] \sin(120) \\ = \sin(90 + 30) \\ = \cos(30) \\ = \frac{ \sqrt{3} }{2} \\ \\ \tan( \frac{3\pi}{4} ) \\ = \tan(135) \\ = \tan(90 + 45) \\ = - \cot(45) \\ = - 1[/tex]

[tex]\\ \rm\longmapsto sin120[/tex]

[tex]\\ \rm\longmapsto sin(90+30)[/tex]

[tex]\\ \rm\longmapsto cos30[/tex]

[tex]\\ \rm\longmapsto \dfrac{\sqrt{3}}{2}[/tex]

Now

[tex]\\ \rm\longmapsto tan\left(\dfrac{2\pi}{4}\right)[/tex]

[tex]\\ \rm\longmapsto tan135[/tex]

[tex]\\ \rm\longmapsto -1[/tex]

Answer:

given in a triangle rst and another triangle ratOn a coordinate plane, triangle R S T has points (0, 0), (negative 2, 3), (negative 3, 1). Triangle R prime S prime T prime has points (2, ...

9 votes

Answer:

1) perimeter = sum of all the sides = 3y+9+2y+4+y+3+2y+4 = 8y+20

2) P = 4(5x-2) = 20x-8

Answer:

916.11 ft³

Step-by-step explanation:

(9×6)×7.83/2×13/3

= 211.41×13/3

= 916.11 ft³

Answered by GAUTHMATH

Answer:

916.11 ft³

Step-by-step explanation:

Answer:

1}6 times

Step-by-step explanation:

2}Yes.New York and Mast has the same number of president which is four

3}Yes,this can be done using piechart.

4}I am still working on this question

Answer:

$879.190 = $879.19

$532.626 = $532.627

Step-by-step explanation:

You round up for the tenths place if the hundredths place is above five, but you round down for the tenths place if the hundredths place is below five. For example, 0 is below five for $879.190, so I round to 9.

Answer:

9b /a^5/2

Step-by-step explanation:

9√(a^-5 b^2)

9 sqrt( a^ -5 b^2)

Rewriting sqrt as ^1/2

9 ( a^ -5 b^2)^1/2

9 ( a^ -5) ^1/2 ( b^2)^1/2

we know that  an exponent to an exponent means multiply

9 a^ (-5*1/2)  b^(2*1/2)

9 a^-5/2 b^1

9b a^ -5/2

We know that x^-y = 1/x^y

9b /a^5/2

Answer:

[tex]\frac{9b}{a^{2} }[/tex][tex]\sqrt{\frac{1}{a} }[/tex] should be the answer of the problem that you posted

if you try to solve using [tex]\sqrt{x}[/tex]    as as [tex]x^{\frac{1}{2} }[/tex]

then [tex](a^{-5)} ^{\frac{1}{2} } \\[/tex] =  [tex](a^{-5/2)}[/tex] = [tex]\frac{1}{a^{\frac{5}{2} } }[/tex]

[tex]\frac{1}{a^{\frac{5}{2} } }[/tex] * 9b = [tex]\frac{9b}{a^{\frac{5}{2 } } }[/tex]

Step-by-step explanation:

[tex]9 \sqrt{(a^-5 b^2)}[/tex]

[tex]x^{-1} = \frac{1}{x}[/tex]

[tex]a^{-5} = \frac{1}{a^{5} }[/tex]

[tex]\sqrt{b^{2} } = b[/tex]

[tex]a^{4}[/tex] a's can be removed from the radicle (one will be left in because you have a^5)

[tex]\frac{9b}{a^{2} }[/tex][tex]\sqrt{\frac{1}{a} }[/tex]

QUESTION-:

The inequalities x < -5 and -X > -5 are the same.

True

False

ANSWER-:

FALSE

!! HOPE ITS HELP U !!

Step-by-step explanation:

The formula for area is l x b. This stands for length and breadth. I can multiply 1000(100) to get 100,000m. The area of the lawn is 100,000 m.

HOPE IT HELPS YOU

MARK ME BRAINLIEST

Answer:

5/1 or 5

Step-by-step explanation:

4 cup of lemonade is $20

then,

1 cup of lemonade is 20 ÷4 =5

9514 1404 393

Answer:

  ∠4 = 108°

Step-by-step explanation:

Angles 2 and 4 together form a "linear pair". That is, the sum of them is 180°, a "straight angle." They are supplementary.

  ∠4 = 180° -∠2 = 180° -72°

  ∠4 = 108°

Answer:

1

Step-by-step explanation:

x-1+ 1 /5*( x-1)=0

(x-1)*6/5=0

x=1

Answer: 0

Step-by-step explanation:

Slope of x = -3 is infinite / undefined (there is infinite/no defined change in y for a given change in x). Remember, line x = -3 slopes straight up.

Perpendicular means at a 'right angle to'.

The only kind of line that is perpendicular to a vertical line is a horizontal line, which is like y = 15 or y = 5 or something. The slope of such lines is always zero, because there is no change in line's rise for a given run.

7(5 + t) - 4(t + 4) =

= 35 + 7t - 4t - 16 =

= 7t - 4t + 35 - 16 = 3t + 19

Answer:

here,

L.H.S;

1-tanA / 1+tanA

=1-1/cotA / 1+1/cotA

= cotA-1/cotA / cotA+1/cotA

=cotA-1 / cotA+1

= R.H.S

proved

Answer:

if it's a math proof, i will think this is answer

Step-by-step explanation:

Answer:

[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}[/tex]

Step-by-step explanation:

The question is not properly formatted (see attachment for the frequency table and the options)

Required

The conditional relative frequency table by column

We have:

[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12} & {28} & {40} & {Not\ Employed} & {38} & {72} & {110}& {Total} & {50} & {100} & {150} \ \end{array}[/tex]

To get the conditional frequency by column, we simply divide each cell by the corresponding total value (on the last row)

So, we have:

[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12/50} & {28/100} & {40/150} & {Not\ Employed} & {38/50} & {72/100} & {110/150}& {Total} & {50/50} & {100/100} & {150/150} \ \end{array}[/tex]

[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}[/tex]

Angle 3 and Angle 5 are corresponding angles. Corresponding angles lie in the same relative position. As such, they are congruent.

50x - 100 = 25x + 25

25x - 100 = 25

25x = 125

x = 5

Angle 3 = 50(5) - 100 = 250 - 100 = 150

Angle 5 = 25(5) + 25 = 125 + 25 = 150

Hope this helps!