please help she wont go to the next aswer

Answer:

The answer is 144,5

Step-by-step explanation:

144,5/170×100 =85%

[tex]\sf Your \: question \: is \: incomplete. \: [/tex]

______________________

[tex]\sf \: I \: believe \: this \: is \: the \: answer \: you \: wanted[/tex] ⟹

[tex]\sf If \: the \: discriminant \: of \: an \: equation \: is \: zero, \: then \\ \sf \: the \: equation \: will \: have \:\underline{ 1 \: real \: solution \: with \: real \: and \: equal \: roots}.[/tex]

[tex]\boxed{ \sf{Explanation}} [/tex]

[tex]\sf If \: discriminant \: of \: quadratic \: equation \: ax^{2} + bx + c \: \\ \sf is \: b^{2} - 4ac = 0 \: then \: it \: will \: have \\ \sf↦\underline{1 \: real \: solution \: with \: real \: and \: equal \: roots.} [/tex]

Answer:

see explanation

Step-by-step explanation:

If b² - 4ac = 0

Then the roots are real and equal

Step-by-step explanation:

Answer:f(x)=-5x^(2)-3x+9 this is the standard form

Answer:  D) reflection across y = -x

Explanation:

When we reflect over y = x, we basically swap x and y. So for instance, the point (3,1) becomes (1,3).

When reflecting over y = -x, we will do the same thing but we'll make each coordinate swap in sign from positive to negative (or vice versa). The rule for reflecting over y = -x is [tex](x,y) \to (-y,-x)[/tex]

So if we apply that rule to point A(3,1) then it becomes A ' (-1, -3).

Similarly, B(1,5) moves to B ' (-5, -1)

Finally, C(6,9) becomes C ' (-9, -6)

Answer: $15927.183

Step-by-step explanation:

Price of good= $29,000

Trade discount = 40½ 20¼/5

The first discount will be:

= 40½ × $29000

= $11745

Then, the price after the first discount will be:

= $29000 - $11475

= $17255

Then, the second discount will be:

= $17255 × 20¼%

= $3494.14

Then, the price after the second discount will be:

= $17255 - $3494.14

= $13760.86

The third discount will be:

= $13760.86 × 5%

= $688.043

Then, the total discount will be:

= $11745 + $3494.14 + $688.043

= $15927.183

Therefore, the trade discount is $15927.183.

Answer:

[tex]5.06 x 10^{-3}[/tex]

Step-by-step explanation:

Move decimal 3 place to right.

Because the decimal was moved to right, the exponent is negative.

Answer:

[tex]{ \tt{ = \frac{ {p}^{2} + 8p + 16 }{ {p}^{2} - 16 } }} \\ \\ = { \tt{ \frac{ {(x + 4)}^{2} }{(x - 4)(x + 4)} }} \\ \\ = { \tt{ \frac{(x + 4)}{(x - 4)} }}[/tex]

The value of y is 3.

Answer:

Solution given;

: y + 3 = –y + 9

add +y on both term

y+y+3=-y+y+9

subtract both side by 3

2y+3-3=9-3

2y=6

divide both side by 2

2y/2=6/2

y=3

Answer:

y = 3

Step-by-step explanation:

y + 3 = –y + 9

Add y to each side

y+y + 3 = –y +y+ 9

2y +3 = 9

Subtract 3 from each side

2y+3-3 = 9-3

2y = 6

Divide by 2

2y/2 = 6/2

y = 3

Let S be the sum. So you have

S = 1 + 2 + 3 + … + 2004 + 2005 + 2006

as well as

S = 2006 + 2005 + 2004 + … + 3 + 2 + 1

Then

2S = (1 + 2006) + (2 + 2005) + … + (2005 + 2) + (2006 + 1)

2S = 2007 + 2007 + … + 2007 + 2007

2S = 2006 × 2007

S = (2006 × 2007)/2

S = 2,013,021

which makes the last two digits 21.

Answer:

4

Step-by-step explanation:

Answer:

answer is A

hope it helps please mark as brainliest answer and give me thanks

Answer:

0.18

Step-by-step explanation:

Answer:

Step-by-step explanation:

C = 16 * 3 = 48

Answer:

Let the MP of 1 article = Rs 1

MP of 15 article = Rs 15

SP of (15+1) articles = 15 x 96/100

= Rs 14.40

CP of 16 article = 14.40/135 x 100

= Rs 32/3

CP of 1 article = 32/3x16

= Rs 2/3

Required % = 1/3 x 3/2 x 100

= 50

Step-by-step explanation:

[tex] \frac{3}{15} = \frac{1}{5} = 0.2 \\ 0.92 = \frac{23}{25} \\ 0.92 > 0.2[/tex]

Answer:

The answer is 9:30 pm :D.

Answer:

1. x = -2 , 3

2. x = - 1, 5

3. -1, 6/5

4. - 0/3, 1.3

Step-by-step explanation:

1.

[tex]ln(x+5)=ln(x-1)+ln(x+1)\\\\x+ 5 = (x-1)(x+1)\\\\x + 5 = x^2 - 1\\\\x^2 - x - 6 = 0 \\\\x^2 - 3 x + 2 x - 6 =0 \\\\x(x-3)+2(x-3)=0\\\\x = -2 and 3[/tex]

2.

[tex]e^{x^{2}}=e^{4x +5}\\\\x^2 - 4x - 5 = 0 \\\\x^2 - 5x + x - 5 = 0 \\\\x (x-5)+1 (x-5)=0\\\\x = -1 and 5[/tex]

3.

[tex]log_{4}(5x^2 +2)=log_{4}(x +8)\\\\5x^2 - x - 6 = 0 \\\\5 x^2 - 6 x + 5x- 6 = 0 \\\\5 x (x + 1)-6(x+1)=0\\\\x = -1 and \frac{6}{5}[/tex]

4.

[tex]log(x-1)+log 5x = 2\\\\5 x (x-1) =2 \\\\5x^2 - 5x -2 = 0 \\\\x = \frac{5\pm\sqrt{25+40}}{10}\\\\x = \frac{5\pm 8}{10}\\\\x = 1.3, - 0.3[/tex]

Answer:

C=125°

Step-by-step explanation:

Hi there!

To find angle C, we can use the cosine law:

[tex]cosC=\frac{a^2+b^2-c^2}{2ab}[/tex]

Plug in the given information

[tex]cosC=\frac{9^2+3^2-11^2}{2(9)(3)}[/tex]

[tex]cosC=\frac{-31}{54}[/tex]

[tex]C=cos^-^1(\frac{-31}{54})[/tex]

[tex]C=cos^-^1(\frac{-31}{54})\\C=125[/tex]

Therefore, angle C is approximately 125 degrees.

I hope this helps!

4ⁿ + 4ⁿ⁺¹ + 4ⁿ⁺² + 4ⁿ⁺³ + 4ⁿ⁺⁴

= 4ⁿ (4⁰ + 4¹ + 4² + 4³ + 4⁴)

= 4ⁿ × 341

= 4ⁿ × 11 × 31

Answer:

a) 128°

b) Opposite angles of a cyclic quadrilateral add up 180°

Step-by-step explanation:

→ Work out ABD

180 - 116 = 64°

→ Use the theorem 'The angle at the centre is twice the angle at the centre'

2 × 64 = 128°

→ Use the cyclic quadrilateral theorem

Opposite angles of a cyclic quadrilateral add up 180°

The value of x is 128 degree when the angle CBD is of 116 degree.

It is a four sided polygon having four angles and four corners.

Firstly we find angle ABD which is 180-116=64 Degrees because the angle at the center is twice the angle on the any point of circle.

So the value of x becomes 2*64=128 degrees.

By using the cyclic quadrilateral theorem opposite angles of a cyclic quadrilateral has a sum of 180 degrees.

Learn more about cyclic quadrilateral theorem at https://brainly.com/question/27420229

#SPJ2

Answer:

Step-by-step explanation:

The slope of line u is 9/2; the line perpendicular to that is the opposite reciprocal...opposite sign and the flip of the fraction. The perpendicular slope is -2/9

Answer:

(0,1,3,5)

Step-by-step explanation:

Set g(x) equal to each respective range and solve for x

[tex]3x + 2 = 2[/tex]

[tex]3x + 2 = 5[/tex]

[tex]3x + 2 = 11[/tex]

[tex]3x + 2 = 17[/tex]

If we solve for each, we get

[tex]x = 0[/tex]

[tex]x = 1[/tex]

[tex]x = 3[/tex]

[tex]x = 5[/tex]

So our domain is

(0,1,3,5)

C. Because C right now

Option C is correct, the equivalent expression of √8x⁷y⁸ is 2x³y⁴√2x

An expression is combination of variables, numbers and operators.

The given expression is √8x⁷y⁸

Square root of eight times x power seven y power eight.

Now we have to find the equivalent expression.

Equivalent expressions are expressions that work the same even though they look different.

We have to simplify the given expression

√4×2x⁶.xy⁸

We get 2x³y⁴√2x

Hence, Option C is correct, the equivalent expression of √8x⁷y⁸ is 2x³y⁴√2x

To learn more on Expressions click:

https://brainly.com/question/14083225

#SPJ7

Answer:

Y= -1/2X- 2

Step-by-step explanation:

-3 - 11 = -14

2-(-5) = 7

7/-14 = -1/2

-3 = 2(-1/2) + b

-3 = -1 + b

-2 = b

Y= -1/2X-2

The probability of not winning would be :

1 - probability of winning

This is written as:

1 - n/n+3

Now to simplify as a single fraction rewrite as:

N+3/n+3 - n/n+3

Simplify to get : 3/n+3

Answer:

2 solutions

i hope this will help you

Answer:

functions are expressions that involve 2 variables, a dependent and an independant variable

example: x=3 isn't a function, but 2y=6-x is

Answer:

Entran 9 cuadrados en la hoja

Se puden hacer 10 tarejtas por que hay un cuadradro de 10*10 extra.

Step-by-step explanation:

El area de la hoja sera:

[tex]A_{Hoja}=30*30=900 \:cm^{2}[/tex]

Ahora el area de cada tarjeta es:

[tex]A_{tarjeta}=10*10=100\: cm^{2}[/tex]

Para determinar cuantos tarjetas entran en la hoja debemos vidivir las aras encontradas arriba:

[tex]\frac{A_{Hoja}}{A_{tarjeta}}=\frac{900}{100}=9[/tex]

Entonces entran 9 cuadrados en la hoja

Se puden hacer 10 tarejtas por que hay un cuadradro de 10*10 extra.

Espero te haya sido de ayuda!

Answer:

B

add the two together.... 5x^3 is the only cube A or B  only x is 6x and only B  has that

Step-by-step explanation:

Answer:

your answer is B

[tex]f(x)=2x^{2} +6x-4[/tex]

[tex]g(x)=5x^{3} -6x^{2} -3[/tex]

[tex](f+g)x=2x^{2} +6x-4+5x^{3} -6x^{2} -3[/tex]

[tex]=5x^{3} -4x^{2} +6x-7[/tex]

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