Please help me!
The Farmer's Ranch House
9. The farmer's house is shown in the diagram below. He wants to build a screened-in patio on the back of his house.
Use the figure to answer the questions. (6 points)
a The area of the patio is planned to be (x + 10x - 200) square feet. What will the length be?
Patio
Patio
**10) - 0-10)
Original
House
b.
What is the area of the original house in simplest form?
Terigth
c
The farmer decides to extend the width of the patio. The area of the patio with the extension is now (x2 + 12x-160) square feet. By how
many feet will the patio be extended from what you found in part a?
Answers
Answer:
The answer is below
Step-by-step explanation:
a) The patio is in the form of a rectangle. The patio has a width of (x - 10) ft. Therefore given that the area of the patio is x² + 10x - 200, hence:
[tex]Area=length*breadth\\\\x^2+10x-200=length*(x -10)\\\\x^2+20x-10x-200=length*(x -10)\\\\x(x+20)-10(x+20)=length*(x -10)\\\\(x-10)(x+20)=length*(x -10)\\\\length=x +20[/tex]
b) Area of original house = length of house * breadth of house
The length of house = length of patio = x + 20; breadth of house = x + 10; therefore:
Area of original house = (x + 20)(x + 10) = x² + 10x + 20x + 200
Area of original house = x² + 30x + 200
c) If the width is extended, hence:
[tex]Area=length*breadth\\\\x^2+12x-160=(x+20)*width\\\\x^2+20x-8x-160=(x+20)*width\\\\x(x+20)-8(x+20)=(x+20)*width\\\\(x-8)(x+20)=(x+20)*width\\\\width=x-8\\\\Extended \ width=(x-8)-(x-10)\\\\Extended \ width=2\ feet[/tex]
Related Questions
WILL GRANT BRAILIEST PLZ REAL ANSWERS ONLY OR REPORTING!
Answers
Hello,
If the question is simplify then
we suppose x not equal to 5 and x not equal to -5
[tex]\dfrac{x^2-10x+25}{(x-5)(x+5)} \\\\=\dfrac{(x-5)^2}{(x-5)(x+5)} \\\\=\dfrac{x-5}{x+5} \\\\[/tex]
else
if the question is to find the euclidian 's quotient then
[tex]\dfrac{x^2-10x+25}{(x-5)(x+5)} \\\\= 1 + \dfrac{-10x+30}{x^2-25} \\\\=1-\frac{10}{x+5} \\[/tex]
euclian's quotient is 1
remainder is -10/(x+5)
Question 19 (5 points)
Determine the measure of
82.49
43.1°
55.0° °
46.3°
Answers
Answer: 43.1 degrees (choice B)
==================================================
Work Shown:
Use the law of sines
sin(A)/a = sin(C)/c
sin(A)/20 = sin(82)/29
sin(A) = 20*sin(82)/29
sin(A) = 0.68294349
A = arcsin(0.68294349)
A = 43.074088
A = 43.1 degrees
Answer:
43.1°
Step-by-step explanation:
Hello, just finished the quiz and the correct answer is 43.1 degrees.
Use the substitution method to solve the system of equations.
A. (5,-7)
B. (-1,-5)
C. (-1,5)
D. (2,-1)
Answers
Answer:
correct ans is d
Step-by-step explanation:
click the photo to see process
What is the value of the expression shown below?
(3/6) 2 + 7 x 4 -5
A 6 1/4
B 6 1/2
C 23 1/4
D 23 1/2
Answers
Answer:
24
Step-by-step explanation:
(3/6) 2 + 7 × 4 - 5
0.5 × 2 + 7 × 4 - 5
1 + 7 × 4 - 5
1 + 28 - 5
29 - 5
24
A farmer in China discovers a mammal
hide that contains 37% of its original
amount of C-14.
N = Noekt
No = inital amount of C-14 (at time
t=0)
N = amount of C-14 at time t
k= 0.0001
t = time, in years
Answers
Answer:
Step-by-step explanation:
I'm going to take a giant leap here and guess that you are looking for how old this mammal hide is. At least that's what I'm going to work out for you. Filling in the formula is relatively easy as long as we remember that the initial amount of hide was 100%:
[tex]37=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get
[tex].37=e^{-.0001t}[/tex] In order to get that t down from its current position, we have to take the natural log of both sides. The reason we do natural log as opposed to common log is because the natural log will cancel out the e:
[tex]ln(.37)=ln(e^{-.0001t})[/tex] and again, because the log cancels out the e we have:
ln(.37) = -.0001t and divide both sides by -.0001 to get
t = 9942.5 years
Answer:
answer is 9943
Step-by-step explanation:
A worker has asked her supervisor for a letter of recommendation for a new job. She estimates that there is an 80 percent chance that she will get the job if she receives a strong recommendation, a 40 percent chance if she receives a moderately good recommendation, and a 10 percent chance if she receives a weak recommendation. She further estimates that the probabilities that the recommendation will be strong, moderate, and weak are 0.7, 0.2, and 0.1, respectively. a. How certain is sh
Answers
Answer:
65 percent certain to get the job
Step-by-step explanation:
The given parameters are;
The chance that she gets the job if she receives a strong recommendation, P(J|S) = 80 percent = 0.8
The chance that she gets the job if she receives a moderately good recommendation, P(J|M) = 40 percent = 0.4
The chance that she gets the job if she receives a weak recommendation = 10 percent, P(J|W) = 0.1
The probability that the recommendation will be strong, P(S) = 0.7
The probability that the recommendation will be moderate, P(M) = 0.2
The probability that the recommendation will be weak, P(W) = 0.1
Therefore, the probability that she gets the job given any condition, is given as follows;
P(J) = P(J|S)×P(S) + P(J|M)×P(M) + P(J|W)×P(W)
∴ P(J) = 0.8 × 0.7 + 0.4×0.2 + 0.1×0.1 = 0.65
Therefore, she is 65 percent certain to get the job
Maths Aryabhatta
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Solve the following pair of linear equations using substitution method :-
2x+3y + 5 = 0 ; 5x-3y+9=0
Answers
Answer:
(- 2, - [tex]\frac{1}{3}[/tex] )
Step-by-step explanation:
Given the 2 equations
2x + 3y + 5 = 0 → (1)
5x - 3y + 9 = 0 → (2)
Rearrange (1) expressing 3y in terms of x by subtracting 2x + 5 from both sides
3y = - 2x - 5
Substitute 3y = - 2x - 5 into (2)
5x - (- 2x - 5) + 9 = 0 ← distribute parenthesis on left side and simplify
5x + 2x + 5 + 9 = 0
7x + 14 = 0 ( subtract 14 from both sides )
7x = - 14 ( divide both sides by 7 )
x = - 2
Substitute x = - 2 into either of the 2 equations and solve for y
Substituting into (1)
2(- 2) + 3y + 5 = 0
- 4 + 3y + 5 = 0
1 + 3y = 0 ( subtract 1 from both sides )
3y = - 1 ( divide both sides by 3 )
y = - [tex]\frac{1}{3}[/tex]
solution is (- 2, - [tex]\frac{1}{3}[/tex] )
Someone help me asap
Answers
Answer:
A
Step-by-step explanation:
There are 270 minutes in 4.5 hrs.
divide that by 45, you get 6.
50*3^6 is 36,450
find m to cos²x-(m²-3)sinx+2m²-3=0 have root
Answers
Answer:
[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex] would ensure that at least one real root exists for this equation when solving for [tex]x[/tex].
Step-by-step explanation:
Apply the Pythagorean identity [tex]1 - \sin^{2}(x) = \cos^{2}(x)[/tex] to replace the cosine this equation with sine:
[tex](1 - \sin^{2}(x)) - (m^2 - 3)\, \sin(x) + 2\, m^2 - 3 = 0[/tex].
Multiply both sides by [tex](-1)[/tex] to obtain:
[tex]-1 + \sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 3 = 0[/tex].
[tex]\sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 2 = 0[/tex].
If [tex]y = \sin(x)[/tex], then this equation would become a quadratic equation about [tex]y[/tex]:
[tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex].
[tex]a = 1[/tex].[tex]b = m^{2} - 3[/tex].[tex]c = -2\, m^{2} + 2[/tex].However, [tex]-1 \le \sin(x) \le 1[/tex] for all real [tex]x[/tex].
Hence, the value of [tex]y[/tex] must be between [tex](-1)[/tex] and [tex]1[/tex] (inclusive) for the original equation to have a real root when solving for [tex]x[/tex].
Determinant of this quadratic equation about [tex]y[/tex]:
[tex]\begin{aligned} & b^{2} - 4\, a\, c \\ =\; & (m^{2} - 3)^{2} - 4 \cdot (-2\, m^{2} + 2) \\ =\; & m^{4} - 6\, m^{2} + 9 - (-8\, m^{2} + 8) \\ =\; & m^{4} - 6\, m^{2} + 9 + 8\, m^{2} - 8 \\ =\; & m^{4} + 2\, m^{2} + 1 \\ =\; &(m^2 + 1)^{2} \end{aligned}[/tex].
Hence, when solving for [tex]y[/tex], the roots of [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] in terms of [tex]m[/tex] would be:
[tex]\begin{aligned}y_1 &= \frac{-b + \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) + \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) + (m^{2} + 1)}{2} = 2\end{aligned}[/tex].
[tex]\begin{aligned}y_2 &= \frac{-b - \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) - \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) - (m^{2} + 1)}{2} \\ &= \frac{-2\, m^{2} + 2}{2} = -m^{2} + 1\end{aligned}[/tex].
Since [tex]y = \sin(x)[/tex], it is necessary that [tex]-1 \le y \le 1[/tex] for the original solution to have a real root when solved for [tex]x[/tex].
The first solution, [tex]y_1[/tex], does not meet the requirements. On the other hand, simplifying [tex]-1 \le y_2 \le 1[/tex], [tex]-1 \le -m^{2} + 1 \le 1[/tex] gives:
[tex]-2 \le -m^{2} \le 0[/tex].
[tex]0 \le m^{2} \le 2[/tex].
[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
In other words, solving [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] for [tex]y[/tex] would give a real root between [tex]-1 \le y \le 1[/tex] if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
On the other hand, given that [tex]y = \sin(x)[/tex] for the [tex]x[/tex] in the original equation, solving that equation for [tex]x\![/tex] would give a real root if and only if [tex]-1 \le y \le 1[/tex].
Therefore, the original equation with [tex]x[/tex] as the unknown has a real root if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
The pair of equations y = 0 and y = -7 has how many solutions?
Answers
Answer:
2 solutions so it can be inferred that it might be a quadratic
Step-by-step explanation:
Answer:
no solutions
Step-by-step explanation:
y = 0 and y = - 7 are horizontal parallel lines.
Since they are parallel, they never intersect and so have no solutions.
Find the length of the segment that joins the points (-5,4) and (7,-1)
Answers
Answer:
13
Step-by-step explanation:
Calculate the length using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (- 5, 4) and (x₂, y₂ ) = (7, - 1)
d = [tex]\sqrt{(7-(-5))^2+(-1-4)^2}[/tex]
= [tex]\sqrt{(7+5)^2+(-5)^2}[/tex]
= [tex]\sqrt{12^2+25}[/tex]
= [tex]\sqrt{144+25}[/tex]
= [tex]\sqrt{169}[/tex]
= 13
Find cos R.
A. cos R =29/21
B. cos R =21/20
C. cos R =21/29
D. cos R =20/29
Answers
Answer:
The answer is 12 %R
Step-by-step explanation:
Answer:
[tex]\text{C. }\cos R=21/29[/tex]
Step-by-step explanation:
In any right triangle, the cosine of an angle is equal to its adjacent side divided by the hypotenuse.
From the diagram, we know:
Angle R's adjacent side is 21The hypotenuse (longest side) of the right triangle is 29Therefore, the cosine of angle R must be [tex]\boxed{\frac{21}{29}}[/tex]
Help me please and thank you :)
Answers
Answer:
A
Step-by-step explanation:
We have the equation:
[tex]\displaystyle \frac{3}{8}y=2+x[/tex]
And we want to determine whether or not this represents a direct proportion.
First, let's solve for y. Multiply both sides by 8/3:
[tex]\displaystyle y=\frac{16}{3}+\frac{8}{3}x[/tex]
Remember that direct proportions must pass through the origin point on a graph. In other words, their y-intercept or constant value is zero.
Since the constant value here is not zero (it is 16/3), the equation is not direct proportion.
Our answer is A.
Which of the following equations have no solutions?
Choose all answers that apply:
Α.
5x + 5 = -42 – 5
B
-4x + 5= -42 - 4
–4x + 5 = -4x – 5
D
4x + 5 = -4x + 5
Answers
Answer: b and c
a) 5x + 5 = -4x - 5
9x = - 10
x = -10/9
-
b) - 4x + 5 = -4x - 4
0x = -9 (no solution)
-
c) -4x + 5 = -4x - 5
0x = -10 (no solution)
-
d) 4x + 5 = -4x + 5
8x = 0
x = 0
-
hope it helps.
Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.
Maths assignment
( x+y,x-y)=(3,1)
Answers
Step-by-step explanation:
I hope this will help you
When do you need to state a domain in your final answer?
Answers
Answer:
Not sure what you are asking.
Domain is all x values .
It can be stated in coordinates (x,y). X is the input. Y is output
It can be stated in Domain Notations such as {x | x ≥ 0}
Answer this question plz
Answers
Answer:
i) 9xy
ii) 75
Step-by-step explanation:
i) add those factor
ii) get that factor
hope it helps
please mark as barinliest
Thankyou.. :)
GIVING BRAINLIEST ANSWER PLZ ';CCC
Answers
Answer:
slope= difference in y ÷difference in x
=y-y1÷x-x1
=-3-(-1)÷-3-1
=-3+1÷-3-1
=-2÷-4
=1/2
Step-by-step explanation:
hope this is helpful
Y2 -Y1 ÷ X2-X1
-1 - 1 ÷ -3 - -3= 0.5 or 1/2
IM AM SO CONFUSED
Find the solution set.
8x2 - 2x – 1=0
Separate the two values with a comma.
Answers
Hello,
Answer (1/2,-1/4)
[tex]8x^2-2x-1=0\\\\8x^2-4x+2x-1=0\\\\4x(2x-1)+2x-1=0\\\\(2x-1)(4x+1)=0\\\\sol=\{\dfrac{1}{2} ,-\dfrac{1}{4} \}\\[/tex]
which graph shows a set of ordered pairs that represent a function. help im on a time limit!
Answers
Answer:
first one
Step-by-step explanation:
10 pointssss!!!!!:))
write the formula of the function y whose graph is shown.
a).
[tex]y = \frac{2}{x} [/tex]
b).
[tex]y = \frac{1}{ x } + 2[/tex]
c).
[tex]y = \frac{1}{x - 2} [/tex]
plss, I need helpp!!!!
Answers
9514 1404 393
Answer:
(a) y = 2/x
Step-by-step explanation:
The vertical and horizontal asymptotes are the axes, so there is neither a vertical nor a horizontal offset to the parent function y = 1/x. There is a vertical stretch by a factor of 2, so the describing function is ...
y = 2/x
Which expression has a value of 15 when n = 7?
1: 43 minus 5 n
2: 3 n minus 5
3: 6 n minus 28
4: 19 minus StartFraction 28 Over n EndFraction
Answers
Answer:
[tex]19-\frac{28}{n}[/tex] is the expression with the value of 15 when n = 7
Step-by-step explanation:
To find the expression whose value is 15, substitute the value of n = 7 in each given expression.
Expression 1:
[tex]43-5n[/tex]
Substitute the value of n & simplify,
[tex]43-5(7)[/tex]
[tex]43-35=8[/tex]
Since the value of the expression is 8 which is not equal 15.
Hence expression [tex]43-5n[/tex] does not have value of 15 when n = 7.
Expression 2:
[tex]3n-5[/tex]
Substituting the value of n & simplify,
[tex]3(7)-5[/tex]
[tex]21-5=16[/tex]
Since the value of the expression is 16 which is not equal 15.
Hence expression [tex]3n-5[/tex] does not have value of 15 when n = 7.
Expression 3:
[tex]6n-28[/tex]
Substituting the value of n & simplify,
[tex]6(7)-28[/tex]
[tex]42-28=14[/tex]
Since the value of the expression is 14 which is not equal 15.
Hence expression [tex]6n-28[/tex] does not have value of 15 when n = 7.
Expression 4:
[tex]19-\frac{28}{n}[/tex]
Substituting the value of n & simplify,
[tex]19-\frac{28}{7}[/tex]
[tex]19-4=15[/tex]
Since the value of the expression is 15 which is equal 15.
Hence expression [tex]19-\frac{28}{n}[/tex] has the value of 15 when n = 7.
Question 22 (5 points)
If the legs of a right triangle are 20 units and 21 units, what's the length of the
hypotenuse?
29 units
4.4 units
6.4 units
22 units
Answers
through my working i got to 41² is the hypotenuse.
21²+20²=c²
factor out the square
(21+20)²=c²
41²=c²
and 41² is 1681
Answer:
29 units
Step-by-step explanation:
i just took the quiz
A gap 2 m deep has the shape of a truncated pyramid with rectangular bases. The length and width of the top base is 3x1.5 m and of the bottom base it is 1x0.5 m. To paint one square meter of a gap surface we need 0.25 liters, of a green paint color, How many liters of the paint color, we will need, if we want to paint just the side walls and the bottom base of the gap? Show working please.
Answers
Answer:
Volume of paint required is 3.125 litres.
Step-by-step explanation:
It would be noted that each side walls would have the shape of a trapezium. So that the areas of each wall can be determined as:
wall 1 = [tex]\frac{1}{2}[/tex](a + b) h
= [tex]\frac{1}{2}[/tex](0.5 + 1.5)2
= 2 [tex]m^{2}[/tex]
wall 2 = [tex]\frac{1}{2}[/tex](a + b) h
= [tex]\frac{1}{2}[/tex](1 + 3)2
= 4 [tex]m^{2}[/tex]
wall 3 = [tex]\frac{1}{2}[/tex](a + b) h
= [tex]\frac{1}{2}[/tex](0.5 + 1.5)2
= 2 [tex]m^{2}[/tex]
wall 4 = [tex]\frac{1}{2}[/tex](a + b) h
= [tex]\frac{1}{2}[/tex](1 + 3)2
= 4 [tex]m^{2}[/tex]
Total area of the walls = 2 + 2 + 4 + 4
= 12 [tex]m^{2}[/tex]
Area of the bottom base = l x b
= 1 x 0.5
= 0.5 [tex]m^{2}[/tex]
Total area to be painted = 12 + 0.5
= 12.5 [tex]m^{2}[/tex]
But to paint one square meter of a gap surface, we need 0.25 litres of a green paint color. Thus, to paint 12.5 [tex]m^{2}[/tex] of the gap surface:
12.5 x 0.25 = 3.125
The litres of paint required is 3.125.
Area of this figure
Answers
1) 2*14 = 28
2) 9*6 = 54
3) 3*5 = 15
Final area= 27+54+15 so It’s 97 ft^2
Situation:
Find the substance's half-life, in days.
• Round your answer to the nearest tenth.
A 25 gram sample of a substance that's
used for drug research has a k-value of
0.1229.
Enter the correct answer.
N = Noe
-kt
DONE
No = initial mass (at time t = 0)
?
N = mass at time t
k = a positive constant that depends on
the substance itself and on the units
used to measure time
t = time, in days
Answers
Answer:
5.6 days
Step-by-step explanation:
We are given;
Initial Mass; N_o = 25 g
Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)
k = 0.1229
Formula is given as;
N_t = N_o•e^(-kt)
Plugging in the relevant values;
12.5 = 25 × e^(-0.1229t)
e^(-0.1229t) = 12.5/25
e^(-0.1229t) = 0.5
(-0.1229t) = In 0.5
-0.1229t = -0.6931
t = -0.6931/-0.1229
t = 5.6 days
Find the missing Angles
Answers
1. a = 68
b = 112
c = 68
2. a = 127
3. a = 35
b = 40
c = 35
d = 70
4. a = 20
b = 70
c = 20
d = 70
e = 110
5. a = 90
b = 90
c = 42
d = 48
e = 132
6. a = 70
b = 55
c = 25
Reese read twice as many pages Saturday than she read Sunday. If she read a total of 78 pages over the weekend, how many pages did Reese read Sunday?
Answers
Given:
Reese read twice as many pages Saturday than she read Sunday.
She read a total of 78 pages over the weekend.
To find:
The number of pages she read on Sunday.
Solution:
Let x be the number of pages she read on Sunday.
Reese read twice as many pages Saturday than she read Sunday. So, the number of pager she read on Saturday is 2x.
Total number of page she read over the weekend is:
[tex]Total=x+2x[/tex]
[tex]Total=3x[/tex]
She read a total of 78 pages over the weekend.
[tex]3x=78[/tex]
[tex]x=\dfrac{78}{3}[/tex]
[tex]x=26[/tex]
Therefore, Reese read 26 pages on Sunday.
How is mathematical thinking established? How can we have mathematical thinking?
修改翻译结果
Answers
Translate How is mathematical thinking established? How can we have mathematical thinking? in to Chinese.
数学思维是如何建立的？ 怎样才能有数学思维？
One number is 9 times another. Their product is 27 times their sum. Find the numbers.
the answer is not 3 btw
Answers
Answer:
270 & 30
Step-by-step explanation:
let the number is n,
the equation :
n× 1/9 n= 27(n +1/9 n)
1/9 n² = 27n + 3n
1/9 n² = 30n
1/9n²- 30n = 0
n(1/9n -30)= 0
n = 0 or
1/9n = 30 => n = 30×9 = 270
270 is a number,
the other : 270/9 = 30
