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The statement "Ten cards are selected out of a 52 card deck without replacement and the number of Jacks is observed. This is an example of a Binomial Experiment" is false.

A binomial experiment is an experiment that is repeated multiple times with each repetition having only two potential outcomes. In a binomial experiment, the probability of success remains constant from trial to trial.

The criteria for a binomial experiment are as follows:

P(x) = (ⁿCₓ)(pˣ)(q^(n-x))

Where p is the probability of success, q is the probability of failure (q = 1 - p), and ⁿCₓ is the combination formula.

Therefore, the statement "Ten cards are selected out of a 52-card deck without replacement and the number of Jacks is observed. This is an example of a "Binomial Experiment" being false. This is because the probability of drawing a jack changes with each trial, as the deck's composition changes after each card is drawn.

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Answer:

Cost price (CP) = Rs20

% Profit = 10%

Selling price (SP) = y

By formula:

% Profit = (Profit/CP) x 100%

But Profit= SP - CP

Therefore;

% Profit = [(SP-CP)/C.P)] x 100%

Substituting, we have:

10% = [(y-20)/20] x 100%

10/100 = (y-20)/20

1/10 = (y-20)/20

1 = (y-20)/2

Cross multiply

y - 20 = 2

y = 2 + 20

y = 22

Therefore, the Sale price is Rs 22

The Variance Inflation Factor (VIF) measures the degree of correlation or the collinearity of the explanatory variables.

VIF quantifies how much each explanatory variable is correlated with a linear combination of the other variables in a multiple regression model. This can help identify variables that are redundant, irrelevant, or harmful to the model's accuracy. The VIF is calculated for each explanatory variable by dividing the variance of the regression coefficient estimates by the variance of the regression coefficient estimates when that variable is excluded from the model.

If the VIF is greater than 1, it indicates that the variance of the regression coefficient estimate for that variable is inflated by the presence of the other variables, which reduces the model's accuracy. Therefore, a VIF greater than 1 is considered to be an indication of collinearity or multicollinearity in the explanatory variables. The VIF measures the degree of correlation or the collinearity of the explanatory variables, and it can identify variables that are redundant, irrelevant, or harmful to the model's accuracy.

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 The 32 ways to get a five-card combination containing two jacks and three aces.

(a) A full house consists of three of one kind and two of another kind. Therefore, there are 13 different choices for the rank of the triplet and 4 cards of the same rank. Once the triplet has been chosen, there are 12 choices for the rank of the pair and 4 cards of the same rank. Therefore, the number of ways to get a full house is as follows:$${13}{\times}{4}{\times}{12}{\times}{4}={7488}$$Therefore, there are 7488 ways to get a full house.(b) In this case, the two jacks and three aces must be chosen out of the 4 jacks and 4 aces in the deck. Therefore, the number of ways to get a five-card combination with two jacks and three aces is as follows:$$\frac{{4\choose2}{4\choose3}{44\choose0}}{5!}={32}$$Therefore, there are 32 ways to get a five-card combination containing two jacks and three aces.

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Answer:153

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer: x < -46/17

Step-by-step explanation:

To solve the inequality:

1/3x - 1/4(x + 2) > 3x - 4/3

First, we simplify the left-hand side by finding a common denominator:

4(1/3x) - 3/4(x + 2) > 3x - 4/3

4/3x - 3/4x - 9/2 > 3x - 4/3

Next, we simplify the equation:

7/12x - 9/2 > 3x - 4/3

To isolate the variable x on one side of the inequality, we will move all the x terms to the left-hand side and all the constants to the right-hand side:

7/12x - 3x > 9/2 - 4/3

-17/12x > 23/6

Finally, we can solve for x by dividing both sides by -17/12, remembering to reverse the inequality because we are dividing by a negative number:

x < (23/6) ÷ (-17/12)

x < -46/17

Therefore, the solution to the inequality is:

x < -46/17

Question 7. C (rectangular pyramid)

Question 8. 17 cm

Answer:

Question 7:C rectangular pyramid

Question 8: C 120 in

A=2(wl+hl+hw)=2·(10·2+5·2+5·10)=160

Step-by-step explanation:

we can use the notation P(A) and apply the definition of probability: P(A) = P(B), P (A ∩ B), and P (A ∪ B) if we have the necessary information.

I believe you meant to say, "Venn diagram". A Venn diagram is a type of graphical representation used to illustrate relationships between sets or groups of objects, concepts, or ideas. It consists of a series of overlapping circles or other closed shapes, with each circle representing a set or group and the overlapping areas representing the relationships or intersections between them.

by the question.

Let A be the event that a student is a cast member of Seussical, and let B be the event that a student is a cast member of Wizard of Oz. Then, we can define the following:

A ∩ B: The event that a student is a cast member of both Seussical and Wizard of Oz.

A ∪ B: The event that a student is a cast member of either Seussical, Wizard of Oz, or both.

A': The event that a student is not a cast member of Seussical.

B': The event that a student is not a cast member of Wizard of Oz.

Based on the information given, we do not know how many students are in each of these events, but we can still make some general observations. For example:

If A and B have no students in common (i.e., A ∩ B = ∅), then the number of students in A ∪ B is equal to the sum of the number of students in A and the number of students in B.

If some students are in both A and B (i.e., A ∩ B is not empty), then the number of students in A ∪ B is equal to the sum of the number of students in A, the number of students in B, and the number of students in A ∩ B. In other words, some students are counted twice when we add up the number of students in A and the number of students in B, so we need to subtract the number of students in A ∩ B to avoid double-counting.

We do not know whether the events A and B are mutually exclusive (i.e., whether A ∩ B = ∅) or not. If they are mutually exclusive, then P(A ∩ B) = 0, and we can use the addition rule of probability to find P (A ∪ B) = P(A) + P(B). If they are not mutually exclusive, then we need to use the general addition rule of probability: P(A ∪ B) = P(A) + P(B) - P(A ∩ B).

Finally, if we want to find the probability that a student chosen at random is a cast member of Seussical,

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Answer:

Step-by-step explanation:

We can simplify the expression by factoring out a common factor of 5^1999 from the numerator:

5^2000 + 5^1999

= 5^1999(5 + 1)

= 5^1999(6)

And we can also factor out a common factor of 5^1997 from the denominator:

5^1999 - 5^1997

= 5^1997(5^2 - 1)

= 5^1997(24)

So the entire expression simplifies to:

(5^2000 + 5^1999) / (5^1999 - 5^1997)

= (5^1999 * 6) / (5^1997 * 24)

= (6/24) * 5^2

= 5/2

Therefore, the value of the expression is 5/2.

The simplified expression using De Morgan's law are  a)x'y'z'u  b)x'y'u c): x'y'u and d)x'y'z'+xy'z'+xyz.

The main idea is to simplify each Boolean expression by repeatedly applying De Morgan's law until each complement operation operates on a single variable.

Then, apply the double complement law to simplify the expression further. In the end, the simplified expression should contain only AND and OR operations without any complement operators acting on multiple variables.

a. 1/ x + yz + u can be simplified using De Morgan's law to: (x'y'z')u'. Then, applying the double complement law, we get the simplified expression as: x'y'z'u.

b. 1/x(y + 2)u can be simplified using De Morgan's law to: x'(y'+2')u'. Then, applying the double complement law, we get the simplified expression as: x'y'u.

c. 1/(x + y)(uv + xy) can be simplified using De Morgan's law to: (x'y')(u' + x'y'). Then, applying the double complement law, we get the simplified expression as: x'y'u.

d. 1/xy + yz + xz can be simplified using De Morgan's law to: (x'+y')(y'+z')(x'+z'). Then, applying the double complement law, we get the simplified expression as: x'y'z'+xy'z'+xyz.

In summary, to simplify Boolean expressions, we can apply De Morgan's law repeatedly and then use the double complement law to remove complement operators acting on a single variable twice.

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The coordinate of centroid of the triangle is (2, 8/3), the coordinate of the circumcenter is (-7/32, 121/24) and the coordinate of orthocenter is (2, 9/2)

a. To find the centroid of a triangle, we take the average of the x-coordinates and the average of the y-coordinates of the vertices. Therefore, the x-coordinate of the centroid is:

(x₁ + x₂ + x₃) / 3 = (-4 + 2 + 8) / 3 = 2

Similarly, the y-coordinate of the centroid is:

(y₁ + y₂ + y₃) / 3 = (0 + 8 + 0) / 3 = 8/3

So the coordinate of the centroid is (2, 8/3).

b. The circumcenter of a triangle is the point where the perpendicular bisectors of the sides of the triangle intersect. To find the circumcenter, we can find the equations of the perpendicular bisectors of any two sides of the triangle and solve for their intersection point.

Let's take the sides formed by vertices (-4, 0) and (2, 8), and vertices (-4, 0) and (8, 0). The midpoint of the first side is ((-4+2)/2, (0+8)/2) = (-1, 4), and the slope of the line passing through the two points is (8-0)/(2-(-4)) = 8/6 = 4/3. Therefore, the equation of the perpendicular bisector passing through (-1, 4) is:

y - 4 = (4/3)(x + 1)

Simplifying this equation, we get:

y = (4/3)x + 13/4

Similarly, the midpoint of the second side is ((-4+8)/2, (0+0)/2) = (2, 0), and the slope of the line passing through the two points is (8-0)/(2-8) = -8/6 = -4/3. Therefore, the equation of the perpendicular bisector passing through (2, 0) is:

y = -(4/3)(x - 2)

To find the intersection point of these two lines, we can set the equations equal to each other and solve for x:

(4/3)x + 13/4 = -(4/3)(x - 2)

x = -7/32

Substituting x = -7/32 into either of the equations, we get:

y = (4/3)(-7/32 + 1) + 4 = 121/24

So the coordinate of the circumcenter is (-7/32, 121/24).

c. The orthocenter of a triangle is the point where the altitudes of the triangle intersect. An altitude of a triangle is a line segment from a vertex of the triangle perpendicular to the opposite side.

Let's take vertex (-4, 0) and find the equation of the line passing through this vertex and perpendicular to the opposite side formed by vertices (2, 8) and (8, 0). The slope of the opposite side is (0-8)/(8-2) = -8/6 = -4/3, so the slope of the line we want is the negative reciprocal of this, which is 3/4. Therefore, the equation of the altitude passing through (-4, 0) is:

y - 0 = (3/4)(x + 4)

Simplifying this equation, we get:

y = (3/4)x + 3

Let's now take vertex (2, 8) and find the equation of the altitude passing through it. The slope of the opposite side formed by vertices (-4, 0) and (8, 0) is (0-0)/(8-(-4)) = 0, which means the altitude passing through (2, 8) is a vertical line passing through (2, 0). Therefore, the equation of this altitude is:

x = 2

Now we need to find the intersection point of these two altitudes. Substituting y = (3/4)x + 3 into the equation x = 2, we get:

y = 9/2

The coordinate of the orthocenter is (2, 9/2)

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Answer: 1500000

Step-by-step explanation:

use a calculator

Answer:

1,500,000

Step-by-step explanation:

Breaking it up into an easier problem:

20x50 = 1,000

30x50=1,500

1,000 x 1,500, aka "adding three zeros" to the end of 1,500, as 1,000 is simply 1 x 10 x 10 x 10, and each 10 has one 0 to it.

Thus, the answer is 1,500,000

Answer:

b = [tex]\frac{S-2la}{h+l}[/tex]

Step-by-step explanation:

S = bh + lb + 2la ( reversing the equation )

bh + lb + 2la = S ( subtract 2la from both sides )

bh + lb = S - 2la ← factor out b from each term on the left side

b(h + l) = S - 2la ← divide both sides by (h + l)

b = [tex]\frac{S-2la}{h+l}[/tex]

To estimate the distance traveled  we need to find the area under the velocity-time graph from 0 to 8 seconds So,The estimate for the distance the car traveled for the first 8 seconds is 4000 meters.

A velocity-time graph is a graphical representation that shows the velocity of an object on the y-axis and time on the x-axis. It is used to depict the change in velocity over time and can provide information about the acceleration or deceleration of an object.

The height of each strip can be estimated by taking the average of the velocities at the beginning and end of the strip.

Using the trapezium rule, the estimated area of each strip is:

Strip 1: 0.5 x (0 + 2) x (0 + (-500)) = -500 m/s

Strip 2: 0.5 x (2 + 4) x (-500 + (-1000)) = -1500 m/s

Strip 3: 0.5 x (4 + 6) x (-1000 + (-500)) = -1500 m/s

Strip 4: 0.5 x (6 + 8) x (-500 + 0) = -500 m/s

The total estimated area is the sum of the areas of the 4 strips:

Total estimated area = -500 + (-1500) + (-1500) + (-500) = -4000 m/s

Since the area represents the distance traveled by the car, we can take the absolute value of the area to get the estimated distance traveled:

Estimated distance traveled is = |-4000| = 4000 meters

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Answer:

Stacy rented a truck for one day there was a base fee of $16.95 and there was an additional charge of 93 cents for each model driven. stacy had to pay $143.43 when he returned the truck. for how many miles did she drive the truck​

Step-by-step explanation:

Let's start by subtracting the base fee from the total cost:

$143.43 - $16.95 = $126.48

Now, we can divide the remaining cost by the cost per mile:

$126.48 ÷ $0.93/mile ≈ 136 miles

Therefore, Stacy drove the truck for approximately 136 miles.

The weight becomes 1/4 of its original value when the distance is multiplied by 2.

According to the question, "the weight of a body above the surface of the earth is inversely proportional to the square of its distance from the center of the earth." We need to determine the effect on the weight when the distance is multiplied by 2.

Let w be the weight of a body, d be the distance from the center of the earth, and k be the constant of variation. According to the question,

w = k / d²

When the distance is multiplied by 2, the new distance is 2d. Therefore, the new weight is given by:

w' = k / (2d)²

w' = k / 4d²

w' = w / 4

Therefore, the weight becomes 1/4 of its original value when the distance is multiplied by 2.

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The probability that more heads are tossed using coin A than coin B is 5/16.

The given data is: Coin A is tossed three times and coin B is tossed two times. We have to find the probability that more heads are tossed using coin A than coin B.

P(E) = Number of favorable outcomes/ Total number of possible outcomes

Coin toss:

There are two possible outcomes in a coin toss, Head or Tail. The probability of getting a head in a coin toss is

1/2 = 0.5.

Therefore, the probability of getting a tail in a coin toss is also 1/2 = 0.5.

Let's calculate the possible outcomes when coin A is tossed three times.

There are 2 possible outcomes when one coin is tossed.

Number of possible outcomes when three coins are tossed = 2 * 2 * 2 = 8

Likewise, the possible outcomes when coin B is tossed two times are:

The number of possible outcomes = 2 * 2 = 4

Therefore, the total number of possible outcomes = 8 * 4 = 32

Now, we will find out the cases where the number of heads is more when coin A is tossed three times.

HHH HHT HTH HTT THH THT TTH TTT HHT HTT THT TTT TTH TTT HTT TTT THT TTT TTT TTT

Therefore, the number of times when more heads are obtained when coin A is tossed three times is 10. (We have to exclude the case when there is an equal number of heads.)

Therefore, the required probability is: P = Number of favorable outcomes/ Total number of possible outcomes

P = 10/32P = 5/16

Therefore, the probability that more heads are tossed using coin A than coin B is 5/16.

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Answer:

Choice 2
∠1 and ∠7, ∠2 and ∠8

Step-by-step explanation:

This is a good example of a problem that can be solved by POE(process of elimination)

First choice: ∠2 and ∠3 are on the same straight line so they cannot be congruent. They are supplementary in that they add up to 180°

The same applies for ∠3 and ∠4 (third choice)

The same applies for ∠1 and ∠4 (fourth choice)

That leaves choice 2

We can prove ∠1 ≅ ∠7 as follows:

∠1 ≅ ∠3 since they are vertically opposite angles

∠3 ≅ ∠7 since they are exterior angles

So ∠1 ≅ ∠7

By similar reasoning,
∠2 ≅ ∠8

So correct choice is Choice 2

Answer:

0% (0/40)

Step-by-step explanation:

I feel like this is a trick question. since chicken is not indicated on the graph, I believe chicken is nobodies favorite food

The zeroes of the function are -12 and 5.

Zeros of a function are the values of the input variables that make the output of the function equal to zero. The zeros are the solutions of equation f(x) = 0.

According to the question:

To find the zeros of the function

f(x) = x² + 7x - 60, we must set f(x) equal to zero and solve for x.

So we start with the equation:

x² + 7x - 60 = 0

Next, we need to factor the left side of the equation. We are looking for two numbers that multiply to -60 and add to 7. After some trial and error, we find that the numbers are 12 and -5:

x² + 7x - 60 = (x + 12)(x - 5) = 0

Now we can apply the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, we set each factor equal to zero and solve for x:

x + 12 = 0 or x - 5 = 0

Solving for x, we get:

x = -12 or x = 5

The zeros of the function f(x) = x² + 7x - 60 are therefore x = -12 and x = 5.

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The total volume of the sample is 0.0067 m³ and the density of the sample is 2753.73 kg/m³.

An ore sample weighs 18.5 N in air. When the sample is suspended by a light cord and totally immersed in water, the tension in the cord is 11.8 N. When the ore sample is immersed in water, the tension in the cord is given as 11.8 N.

Thus, the buoyancy force experienced by the ore sample is given by the difference between the weight of the sample in the air and the tension in the cord.

Buoyancy force experienced by the ore sample = Weight of the sample in the air - Tension in the cord

Buoyancy force experienced by the ore sample = (18.5 N) - (11.8 N)

Buoyancy force experienced by the ore sample = 6.7 N

Also, we know that the weight of the ore sample in air is equal to the weight of the ore sample when immersed in water.

Weight of the ore sample = Weight of the displaced water

Weight of the ore sample = Buoyancy force experienced by the ore sample

Weight of the ore sample = 6.7 N

The density of the ore sample

Density is given by the formula Density = Mass/Volume

Where Density is measured in kg/m³

Mass is measured in kg

Volume is measured in m³

Also, the density of water is given as 1000 kg/m³.

The density of the ore sample = Mass/Volume

Mass = Density x Volume

Volume of the ore sample can be obtained from volume of the displaced water.

Volume of the displaced water = Weight of the ore sample/Density of water

Volume of the displaced water = (6.7 N)/(1000 kg/m³)

Volume of the displaced water = 0.0067 m³

Density of the ore sample = (18.5 N)/(0.0067 m³)

Density of the ore sample = 2753.73 kg/m³

Therefore, 0.0067 m³ is the sample's total volume and 2753.73 kg/m³ is the density of the sample.

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The integers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 have been written on a chalkboard by Dayna. She then erased the integers from 1 through 6, as well as their multiplicative inverse $\mod{13}$.

We can find the multiplicative inverse of an integer { a modulo 13 } by using the extended Euclidean algorithm.The integers from 1 to 6 are 1, 2, 3, 4, 5, and 6.The multiplicative inverse of : 1 modulo 13 is 1, 2 modulo 13 is 7,  3 modulo 13 is 9, 4 modulo 13 is 10, 5 modulo 13 is 8, and 6 modulo 13 is 11.The only integer that Dayna does not erase is 12.

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The order of events from least likely to most likely are as follows:

The reason for this order is because of the chances of each event occurring. Event D has the least chance of occurring because no numbers in the set have a value less than or equal to 0. Event A is the next least likely because only one number in the set is greater than 0, which is the number 1. Event C is the next least likely because only two numbers in the set are at least 2 (2 and 3). Event B is the next least likely, as there are only five even numbers in the set (2, 4, 6, 8, and 10). Events E, F, G, and H are the most likely to occur, because of the number of numbers that are divisible by 3, and 5, and are prime numbers.

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Tο shift the graph tο the right, we can simply add a pοsitive cοnstant tο the x values οf each pοint befοre plοtting them. Fοr example, if we want tο shift the graph tο the right by 2 units.

The intersectiοn οf twο number lines creates a twο-dimensiοnal plane knοwn as a cοοrdinate plane. The x-axis, a hοrizοntal number line, and the y-axis, a vertical number line, are twο examples οf these number lines.

Tο graph the equatiοn 5x - 3y = 18 οn a cοοrdinate plane, we can fοllοw these steps:

1. Sοlve fοr y in terms οf x:

5x - 3y = 18

-3y = -5x + 18

y = (5/3)x - 6

2. Chοοse sοme values fοr x and use the equatiοn tο find the cοrrespοnding y values. Fοr example, we can chοοse x = 0, 3, and 6:

When x = 0: y = (5/3)(0) - 6 = -6

When x = 3: y = (5/3)(3) - 6 = -3

When x = 6: y = (5/3)(6) - 6 = 2

3. Plοt the pοints (0, -6), (3, -3), and (6, 2) οn the cοοrdinate plane.

4. Draw a straight line passing thrοugh these three pοints. This line represents the graph οf the equatiοn 5x - 3y = 18.

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The equation of the circle is [tex]x^2 + y^2 + 6x - 18y + 65 = 0[/tex].

Given:

Equation of the circle is [tex](x+3)^2+(y-9)^2=5^2[/tex]

Expand the equation

[tex](x+3)^2 = (x+3)(x+3) = x^2 + 3x + 3x + 9 = x^2 + 6x + 9[/tex]

[tex](y-9)^2 = (y-9)(y-9) = y^2 - 9y - 9y + 81 = y^2 - 18y + 81[/tex]

[tex]5^2 = 25[/tex]

Then, substitute the expanded expressions into the equation

[tex](x+3)^2+(y-9)^2=5^2\\(x^2 + 6x + 9) + (y^2 - 18y + 81) = 25\\[/tex]

Simplify and combine like terms

[tex](x^2 + 6x + 9) + (y^2 - 18y + 81) = 25\\x^2 + y^2 + 6x - 18y + 90 = 25[/tex]

Rearrange the equation so that one side is 0

[tex]x^2 + y^2 + 6x - 18y + 90 = 25\\x^2 + y^2 + 6x - 18y + 90 - 25 = 0\\x^2 + y^2 + 6x - 18y + 65 = 0[/tex]
Thus, the equation of a circle [tex](x+3)^2+(y-9)^2=5^2[/tex] can be rearranged using the distributive property to form [tex]x^2 + y^2 + 6x - 18y + 65 = 0[/tex], with one side equaling 0.

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Answer:

the test does not provide convincing evidence that the proportion is greater than 90%

The centripetal force is 7384.80 N.

For the centripetal force in N on the end of a 52 m (radius) wind turbine blade that is rotating at 0.3 rev/s and assuming the mass is 2 kg.

Use the following formula:

Centripetal force = (mass x velocity²) / radius

Where; mass = 2 kg

In this case, the radius of the wind turbine blade is 52 m, and it is rotating at 0.3 rev/s, which means that the angular velocity is:

ω = 2π * f = 2π * 0.3 = 1.884 rad/s

where f is the frequency or revolutions per second.

The linear velocity at the end of the blade can be calculated as:

v = r * ω ⇒ 52 * 1.884 ⇒ 98.088 m/s

radius = 52 m

Centripetal force = (2 x 98.088²) / 52

Centripetal force  = 7384.80 N

Therefore, the centripetal force on the end of a 52 m wind turbine blade rotating at 0.3 rev/s with a mass of 2 kg is 7384.80 N.

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The value of x that makes the average between 3.15 and x equal to 40 is 76.85.

In this problem, we are given two numbers, 3.15 and x, and told that the average between them is 40. We can set up an equation to solve for x as follows:

(3.15 + x) / 2 = 40

To find the average between 3.15 and x, we add the two numbers together and divide by 2, which gives us the equation above.

To solve for x, we can start by multiplying both sides of the equation by 2:

3.15 + x = 80

Next, we can subtract 3.15 from both sides of the equation:

x = 76.85

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In conclusion, we can prove that[tex](A -B) U (A C)[/tex] is a superset of[tex]A - (B nC)[/tex] using both the choose-an-element method and the algebra of sets.

To answer this question, let's first draw two Venn diagrams to represent the sets A, B, and C. In the first Venn diagram, shade the region that represents[tex]A - (B nC)[/tex].

This is the region outside of the intersection of B and C and inside of A. In the second Venn diagram, shade the region that represents [tex](A -B) U (A C).[/tex] This is the union of the region outside of B and the region outside of C, both of which are inside of A. Based on these diagrams, we can make the conjecture that (A -B) U (A C) is a superset of A - (B nC).

To prove this conjecture, we can use the choose-an-element method. Let a be an element of A - (B nC). This means that a is in A, but not in B or C. Since a is in A, it is also in (A -B) U (A C), and therefore (A -B) U (A C) is a superset of A - (B n C).

We can also use the algebra of sets to prove this conjecture.[tex]A - (B n C) = (A -B) U (A -C) since A - (B n C)[/tex]is the union of the regions outside of B and outside of C, both of which are inside of A. This implies that (A -B) U (A C) is a superset of A - (B nC).

for such more questions on Venn diagram

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