Answer:
So if x= 1 , y= -20 , z = -5 , we just have to replace those values on the equation
[tex]\frac{\sqrt{yz}}{(z-x)^{2} + y } =[/tex] [tex]\frac{\sqrt{(-20) * (-5)}}{(-5-1)^{2} + (-20) } =[/tex] [tex]\frac{\sqrt{100}}{(-6)^{2} -20 }[/tex] [tex]= \frac{10}{16} =\frac{5}{8}[/tex]
Answer:
√100 / {-5-1}^² +(-20)10/(-6)^² -2010/36-2010/165/8In this activity, you will create an equation for a function represented by a verbal description.
Vicky charged her phone’s battery to 100 percent. Then she took the phone off the charger. When her phone is off the charger, it loses 5 percent of its battery life every hour. What function models the percentage of battery life left in terms of the number of hours since Vicky took it off the charger?
What is the initial value of the function? Is it positive or negative? Explain your answer.
What is the function’s rate of change? Is it positive or negative? Explain your answer.
Answer:
1) The initial value of the function is the y-value when the x-value is zero. The number of hours is the x-value and the percentage of battery life left is the y-value. When the number of hours, x, is 0, the percentage of remaining battery life, y, is 100 percent. So, the initial value of the function is 100. The initial value is positive because the percentage of remaining battery life cannot be negative.
2) The rate of change is the rate at which the y-value changes with respect to a change in the x-value. When off the charger, the phone loses its battery life at a constant rate of 5 percent per hour. So, the function’s rate of change is -5. The rate of change is negative because the rate indicates that the percentage of remaining battery life decreases as the number of hours increases.
Step-by-step explanation: I just did the tutorial right now i hope this helps
Answer:
part a = The number of hours since Vicky took the phone off the charger is the independent quantity, so the variable x should represent it.
part b = The percentage of battery life left in hours is the dependent quantity, so the variable y should represent it.
part c = The initial value of the function is the y-value when the x-value is zero. The number of hours is the x-value and the percentage of battery life left is the y-value. When the number of hours, x, is 0, the percentage of remaining battery life, y, is 100 percent. So, the initial value of the function is 100. The initial value is positive because the percentage of remaining battery life cannot be negative.
part d = The rate of change is the rate at which the y-value changes with respect to a change in the x-value. When off the charger, the phone loses its battery life at a constant rate of 5 percent per hour. So, the function’s rate of change is -5. The rate of change is negative because the rate indicates that the percentage of remaining battery life decreases as the number of hours increases.
part e = The rate of change of the function, m, is -5, and the initial value of the function, b, is 100. Substitute the values of m and b in the equation y = mx + b. The equation of the function that models the phone’s remaining battery life in terms of the number of hours from the time Vicky took it off the charger is y = -5x + 100.
Step-by-step explanation:
All edmentum answers :)
Which statement correctly compares the function shown on this graph with
the function y = 4x + 2?
Answer:
Y=4X+2
Y=4X
4X/2
4*2+2=Y
Y=2
Step-by-step explanation:
Answer:
The answer is c
Step-by-step explanation:
Which inequality is represented by this graph?
OA. y<-1/5x+1
OB. y>= -1/5x+1
OC. y<= -1/5x+
OD. y>-1/5x+1
Answer:
Option A is correct
Step-by-step explanation:
Hope it is helpful....
f(x) = 2x + 7 with domain: x = {2, 3, 5, 9}
Answer:
2(2)+7=11
2(3)+7=13
2(4)+7=15
2(5)+7=17
2(9)+7=25
Step-by-step explanation:
2(2)+7
4+7=11
2(3)+7
6+7=13
2(4)+7
8+7=15
2(5)+7
10+7=17
2(9)+7
18+7=25
Y and x have a proportional relationship, and y=4 when x=12
Answer:
multiply 4 by 12 okay bro
Answer:
y = [tex]\frac{1}{3}[/tex] x
Step-by-step explanation:
Given that y and x are proportional then the equation relating them is
y = kx ← k is the constant of proportion
To find k use the condition y = 4 when x = 12 , then
4 = 12k ( divide both sides by 12 )
k = [tex]\frac{4}{12}[/tex] = [tex]\frac{1}{3}[/tex]
y = [tex]\frac{1}{3}[/tex] x ← equation of proportion
What are the root(s) of the quadratic equation whose related function is graphed below?
Answer:
0 and 4
Step-by-step explanation:
roots are where the graph intersects at x axis
The roots of the quadratic equation whose related function is graphed are 0 and 4, the correct option is C.
What is the quadratic equation?A quadratic equation is a second-order equation written as ax2 + bx + c = 0 where a, b, and c are coefficients of real numbers and a ≠ 0.
If b2 – 4ac > 0 roots are real and different. As the discriminant is >0 then the square root of it will not be imaginary. It has two cases.
If b2 – 4ac is a perfect square then roots are rational. As the discriminant is a perfect square, so we will have an integer as a square root of the discriminant. Hence, the roots are rational numbers.
The shape of the graph is a downward parabola on the positive x-axis therefore the roots of the graph are positive.
From the given option the roots of the equation are 0 and 4 both are positive.
Hence, the roots of the quadratic equation whose related function is graphed are 0 and 4.
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Find m so that the equation msin²x+cos²x=m-1 has a solution on the interval (0;π/4)
msin²x+cos²x=m-1
since the interval are 0 and π/4
Therefore
msin²(0)+cos²(0)=m-1
m(0)+1=m-1
1=m-1
m=2
use π/4 now
msin²(π/4)+cos²(π/4)=m-1
m(1/2)+(1/2)=m-1
m+1=2(m-1)
m+1=2m-2
-m=-3
m=3
Therefore
m=2 or 3
Olivia is fixing her bicycle. She starts fixing it at 9:34 am and finishes at 1 pm. How much
time did she spend fixing her bicycle?
Answer:
3 hours 26 minutes
Step-by-step explanation:
26 minutes(9.34am to 10am)+3 hours(10am to 1pm)=3 hours 26 minutes
The total time that she spend fixing her bicycle is 3 hr 26 minutes
Calculating total timeGiven the following parameters
Time that Olivia starts fixing bicycle= 9:34 am
Time she finishes = 1pm
The total number of hours spent from 9:34am and 12:34pm is 3 hrs. The remaining minutes to 1 pm is 26 minutes.
Hence the total time that she spend fixing her bicycle is 3 hr 26 minutes
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The price of 5 kg of rice is ₹83.75. How many kilograms of rice can you buy for ₹670?
Answer:
40 kg
Step-by-step explanation:
[tex]\frac{5}{83.75} :\frac{y}{670}[/tex]
y · 83.75 = 5 · 670
83.75y = 3350
83.75y ÷ 83.75 = 3350 ÷ 83.75
y = 40
The amount of rice you can buy for ₹670 is given by the equation
A = 40 kilograms
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the amount of rice for ₹670 be A
Now , the equation will be
The amount for 5 kg of rice = ₹ 83.75
So , the amount for 1 kg of rice = amount for 5 kg of rice / 5
The amount for 1 kg of rice = 83.75 / 5
The amount for 1 kg of rice = ₹ 16.75
So , the amount of rice for ₹ 670 = 670 / amount for 1 kg of rice
The amount of rice for ₹ 670 = 670 / 16.75
The amount of rice for ₹ 670 = 40 kilograms
Therefore , the value of A is 40 kilograms
Hence , the amount of rice is 40 kg
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find the radius of a circle for which an arc 6 cm long subtends an angle of 1/3 radians at the center?
plz some one can help to solve the question??
Step-by-step explanation:
Eueydhhdgdgdbdbddbdbhd
Answer:
Hello,
[tex]R=\dfrac{18}{\pi}\ (cm)[/tex]
Step-by-step explanation:
[tex]Formula: \ L=\theta*R\\[/tex]
[tex]R=\dfrac{6}{\dfrac{\pi}{3} } =\dfrac{6*3}{\pi} =\dfrac{18}{\pi}\ (cm)[/tex]
help please help......
Answer:
[tex]{ \sf{( \sec \theta - \csc \theta)(1 + \tan \theta + \cot \theta) }} \\ = { \sf{( \sec \theta + \tan \theta \sec \theta + \cot \theta \sec \theta) - ( \csc \theta - \csc \theta \tan \theta - \csc \theta \cot \theta)}} \\ = { \sf{( \sec \theta + \sec \theta \tan \theta + \csc \theta) - ( \csc \theta - \sec \theta - \csc \theta \cot \theta)}} \\ = { \sf{ \sec \theta \tan \theta + \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}[/tex]
The scores of James in his math test are 75, 78, 89, and 71. What score on the next test will make James’ average at least 80 ?
x > 87
x > 87
x < 87
x < 87
Answer: x ≥ 87
Step-by-step explanation:
Set the minimum score on the next test as x & calculate it:
[tex]\frac{75+78+89+71+x}{5} =80\\\\75+78+89+71+x=80(5)\\\\313+x=400\\\\x=400-313=87[/tex]
So they need at least a score of 87 for the average to be 80+.
Answer:
x ≥ 87
Step-by-step explanation:
Find the length of each side and the
perimeter.
(5n -17) cm
(2n + 1) cm
n cm
7n-16
Step-by-step explanation:
Sry can u give me the picture
find the angle measures given the figure is a rhombus.
Answer:
92
Step-by-step explanation:
180-88
The lengths of the sides of a triangle are 3, 3, 312. Can the tangle be a right triangle?
Answer:
Yes it can be right angle triangle
If the area of a rectangular field is x2 – 3x + 4 units and the width is 2x – 3, then find the length of the rectangular field.
Answer:x²-3 x+4/ 2x-3 units
Step-by-step explanation:
Area = Length * Width sq. units
x^2 - 3x + 4 = Length * 2x - 3
=>Length = x^2- 3 x + 4/ 2 x − 3 units
please help me
its urgent :)
Step-by-step explanation:
i Will help wit Shape A and Next Try to figure out Shape B
shape A Looks the Shape XY coordinate, which Horizontal & Vertical Line
Shape A Coordinate
X = 7, 8.5, 7,5, 7.5,
Y = 7, 7, 6.5 , 5
if you wanna to understand this coordinate between X & Y try plotting with Horizontal or Vertical Line at your Shape And you Would be Understanding about these coordinate meaning
can someone pls help w finding the x and y intercepts of this?
y=x^2-2x
Answer:
y-intercept is 0, x-intercept is 0 and 1
Step-by-step explanation:
For y-intercept, x=0 :
[tex]{ \tt{y = {(0)}^{2} - 2(0) }} \\ { \tt{y = 0}}[/tex]
For x-intercept, y=0 :
[tex]{ \tt{0 = {2x}^{2} - 2x }} \\ { \tt{2x(x - 1) = 0}} \\ { \tt{x = 0 \: \: and \: \: 1}}[/tex]
draw two intersecting line segment AB and CD intersecting O. Measure the size of each pair of vertically opposite angles. Verify each pair of vertically opposite angles are equal.
When two line segments intersects, a set of vertically opposite angles are formed. So that by comparison of angles formed in the attachment, a set of vertically opposite angles formed are: >AOC and >BOD; then >AOD and >BOC.
A pair of vertically opposite angles are formed when two lines meet at a point. And the pair of vertically opposite angles formed are said to have equal size.
From the given question, line segment AB intersecting CD at point O would produce a set of vertically opposite angles. So that each pair has equal size.
From the attached diagram, it can be observed that;
m>AOC = m>BOC = m>AOD = m>BOD = [tex]90^{o}[/tex]
But;
m>AOC ≅ m>BOD = [tex]90^{o}[/tex] (vertically opposite angle property)
also,
m>AOD ≅ m>BOC = [tex]90^{o}[/tex] (vertically opposite angle property)
Therefore it can be verified that each pair of vertically opposite angles are equal.
NB: The required diagram to the question is herewith attached to this question for more clarifications and reference.
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divide 12by8 and 4by3
lvan earned $8 each time he walks his neighbor's dog. he already walked the dog 5 times.
How many more times does her need to walk the dog to earn enough money to buy a game that costs $88
__? more times
What is the value of the expression: 4+42 +22
Answer:
84
Step-by-step explanation:
[tex]4^3+4^2+2^2= 64+16+4=84[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\boxed{\mathsf{4^3 + 4^2 + 2^2}}[/tex]
[tex]\huge\boxed{\mathsf{4^3}}[/tex]
[tex]\huge\boxed{\mathsf{= 4 \times 4 \times 4}}[/tex]
[tex]\huge\boxed{\mathsf{= 16\times 4}}[/tex]
[tex]\huge\boxed{\mathsf{= \bf 64}}[/tex]
[tex]\huge\boxed{\mathsf{4^2}}[/tex]
[tex]\huge\boxed{\mathsf{= 4 \times 4}}[/tex]
[tex]\huge\boxed{\mathsf{= \bf 16}}[/tex]
[tex]\huge\boxed{\mathsf{2^2}}[/tex]
[tex]\huge\boxed{\mathsf{= 2 \times 2}}}[/tex]
[tex]\huge\boxed{\mathsf{= \bf 4}}[/tex]
[tex]\huge\boxed{\mathsf{= 64 + 16 + 4}}[/tex]
[tex]\huge\boxed{\mathsf{= 80 + 4}}[/tex]
[tex]\huge\boxed{\mathsf{= \bf 84}}[/tex]
[tex]\huge\boxed{\mathsf{Answer: 84}}\huge\checkmark[/tex]
[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]
Question choices:
A: I, IV
B: II, III, IV
C: III, IV
D: II, III
0Answer:
A
Step-by-step explanation:
Find the zeros by letting y = 0 , that is
x² - x - 6 = 0 ← in standard form
(x - 3)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 3 = 0 ⇒ x = 3
x + 2 = 0 ⇒ x = - 2
Since the coefficient of the x² term (a) > 0
Then the graph opens upwards and will be positive to the left of x = - 2 and to the right of x = 3 , that is in the intervals
(-∞, - 2) and (3, ∞ ) → option A
take a square of arbitary measure assuming its area is one square unit.divide it in to four equal parts and shade one of them.again take one shaded part of that square and shade one fourth of it.repeat the same process continuously and find the sum area of shaded region
Answer:
In recreational mathematics, a square array of numbers, usually positive integers, is called a magic square if the sums of the numbers in each row, each column, and both main diagonals are the same.[1][2] The order of the magic square is the number of integers along one side (n), and the constant sum is called the magic constant. If the array includes just the positive integers {\displaystyle 1,2,...,n^{2}}{\displaystyle 1,2,...,n^{2}}, the magic square is said to be normal. Some authors take magic square to mean normal magic square.[3]
The smallest (and unique up to rotation and reflection) non-trivial case of a magic square, order 3
Magic squares that include repeated entries do not fall under this definition and are referred to as trivial. Some well-known examples, including the Sagrada Família magic square and the Parker square are trivial in this sense. When all the rows and columns but not both diagonals sum to the magic constant we have semimagic squares (sometimes called orthomagic squares).
The mathematical study of magic squares typically deals with its construction, classification, and enumeration. Although completely general methods for producing all the magic squares of all orders do not exist, historically three general techniques have been discovered: by bordering method, by making composite magic squares, and by adding two preliminary squares. There are also more specific strategies like the continuous enumeration method that reproduces specific patterns. Magic squares are generally classified according to their order n as: odd if n is odd, evenly even (also referred to as "doubly even") if n is a multiple of 4, oddly even (also known as "singly even") if n is any other even number. This classification is based on different techniques required to construct odd, evenly even, and oddly even squares. Beside this, depending on further properties, magic squares are also classified as associative magic squares, pandiagonal magic squares, most-perfect magic squares, and so on. More challengingly, attempts have also been made to classify all the magic squares of a given order as transformations of a smaller set of squares. Except for n ≤ 5, the enumeration of higher order magic squares is still an open challenge. The enumeration of most-perfect magic squares of any order was only accomplished in the late 20th century.
Magic squares have a long history, dating back to at least 190 BCE in China. At various times they have acquired occult or mythical significance, and have appeared as symbols in works of art. In modern times they have been generalized a number of ways, including using extra or different constraints, multiplying instead of adding cells, using alternate shapes or more than two dimensions, and replacing numbers with shapes and addition with geometric operations.
The sum area of shaded region is [tex]\frac{1}{3}[/tex].
Summation formula for geometric progressionThe formula to find the sum of infinite geometric progression is
[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]
Given
S = [tex]\frac{1}{4} +\frac{1}{16} +\frac{1}{64} +.........[/tex]
Using geometric progression
S = [tex]\lim_{h \to \infty} [\frac{1}{4} +(\frac{1}{4} )^{2} +(\frac{1}{4} )^{3} +.........+(\frac{1}{4} )^{n}][/tex]
Using summation formula for geometric progression
[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]
= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-(\frac{1}{4} )^{n} }{1-\frac{1}{4} }[/tex]
= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-\frac{1}{4^{n} }) }{\frac{3}{4} }[/tex]
= [tex]\lim_{h\to \infty} \frac{1}{3}(1-\frac{1}{4^{n} } )[/tex]
[tex]\lim_{h\to \infty} \frac{1}{4^{n} }[/tex] = 0
S = [tex]\frac{1}{3}(1-0) = \frac{1}{3}[/tex]
The sum area of shaded region is [tex]\frac{1}{3}[/tex].
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Help please and thank you
Answer:
x = y² - 7
Step-by-step explanation:
the inverse function is simply an exchange of x and y (and then the simplification happens to transform the whole expression back into a form y = ....)
The estimate obtained from a sample of which of the following sizes would most likely be closest to the actual parameter value of a population?
To obtain an estimate of a parameter of a population, we use confidence intervals.
Confidence intervals:
The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.
Thus, you should select the highest sample size in the options.
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HELP ME WITH THIS PLS IM FAILING REALLY BAD ITS PYTHAGOREAN THEOREM
Answer:
50 km
Step-by-step explanation:
c = √a^2+b^2
=√30^2+40^2
= √900 + 1600
=√2500
= 50 km
Answer:
50km
Step-by-step explanation:
One of the legs of a right triangle measures 12 cm and its hypotenuse measures 20
cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
Answer:
cm
Submit Answer
attempt 1 out of 2
PLS HELP
Answer:
16
Step-by-step explanation:
First use the Pythagorean theorem a^2+b^2=c^2.
12^2+b^2=20^2. Solve the exponents: 144+b^2=400. Then, subtract the 144 from 400. That would be 256. Therefore b^2=256. Then you find the square root of 256=16.
Step-by-step explanation:
using pythogoras theory
hyp^2=opp^2+adj^2
you have been given the hyp and the opp so lets make the unknown x
20^2=12^2+x^2
400 =144+x^2
make x the subject of the formula
400-144=x^2
266=x^2
x=the square root of 266
what value of x is in the solution set of -5-15>10+20x
Answer:
-3/2 >x
Step-by-step explanation:
-5-15>10+20x
Combine like terms
-20 > 10 +20x
Subtract 20 from each side
-20 -10 > 10+20x-10
-30> 20x
Divide by 20
-30/20 >20x/20
-3/2 >x
Answer:
-3/2 > x
Step-by-step explanation:
-5 - 15 > 10 + 20x
^ ^
-20
-20 > 10 + 20x
-10 -10
---------------------
-30 > 20x
----- -------
20 20
-3/2 > x
Hope this helped.
what does the rational form of the ratio a:b look like
Answer:
a/b
Step-by-step explanation:
The rational form of a:b or simply a/b is in the simplest form.
Answer:
Step-by-step explanation:
the answer is option 2 from the above sheet