PLEASE HELP
Which of the following best describes the existence of undecidable problems?

Answer:

1. Multistage database.

2. Stationary database.

3. Virtual database.

4. Distributed database.

Explanation:

A database management system (DBMS) can be defined as a collection of software applications that typically enables computer users to create, store, modify, retrieve and manage data or informations in a database. Generally, it allows computer users to efficiently retrieve and manage their data with an appropriate level of security.

There are four (4) major types of database in a data warehouse and these are;

1. Multistage database: used for concise as well as detailed historical data. It provides summarized data which can be used by an employee for short-term decision making.

2. Stationary database: used where access to data is rare i.e business firms who do not access data frequently. In order to use this database, the users must have an access to metadata store and thus, directly having access to the data on a source system.

3. Virtual database: used for accessing data in diverse applications using middleware. This type of database is dependent on having access to information on various databases.

4. Distributed database: used by an organization that runs several businesses. Therefore, this type of database are usually located or situated in various geographical regions.

Answer:

String longest = "";

Explanation:

The initialization that would allow the method to work as intended would be the following

String longest = "";

This is because the method is looping through the array provided as an argument and comparing each word in the array with the word saved inside the variable called longest. The length of both are compared and if the word in the array is longer than the string saved in the variable longest then it is overwritten with the word in the array.

Answer:

true

Explanation:

trust me lol, I promise it's correct.

Answer:

Answered below

Explanation:

//Program is implemented in Java

public int countInitials(ArrayList<string> words, char letter){

int count = 0;

int i;

for(i = 0; i < words.length; i++){

if ( words[i][0]) == letter){

count++

}

}

return count;

}

//Test class

Class Test{

public static void main (String args[]){

ArrayList<string> words = new ArrayList<string>()

words.add("boy");

words.add("bell");

words.add("cat");

char letter = 'y';

int numWords = countInitials ( words, letter);

System.out.print(numWords);

}

}

Answer:

Condition one - 1 time

Condition two - 2 times

Explanation:

Given

The above code segment

Required

Determine the number of times each print statement is executed

For condition one:

The if condition required to print the statement is:  if (arr[row][col] >= arr[row][col - 1])

For the given data array, this condition is true only once, when

[tex]row = 1[/tex]  and  [tex]col = 2[/tex]

i.e.

if(arr[row][col] >= arr[row][col - 1])

=> arr[1][2] >= arr[1][2 - 1]

=> arr[1][2] >= arr[1][1]

=> 5 >= 3 ---- True

The statement is false for other elements of the array

Hence, Condition one is printed once

For condition two:

The if condition required to print the statement is:  if (arr[row][col] % 2 == 0)

The condition checks if the array element is divisible by 2.

For the given data array, this condition is true only two times, when

[tex]row = 0[/tex]  and  [tex]col = 1[/tex]

[tex]row = 1[/tex]  and  [tex]col = 0[/tex]

i.e.

if (arr[row][col] % 2 == 0)

When [tex]row = 0[/tex]  and  [tex]col = 1[/tex]

=>arr[0][1] % 2 == 0

=>2 % 2 == 0 --- True

When [tex]row = 1[/tex]  and  [tex]col = 0[/tex]

=>arr[1][0] % 2 == 0

=> 4 % 2 == 0 --- True

The statement is false for other elements of the array

Hence, Condition two is printed twice

Answer:

yes its true  :)

Explanation:

Answer:

In Python:

def fib(nterms):

   n1, n2 = 1, 1

   count = 0

   while count < nterms:

       term = n1

       nth = n1 + n2

       n1 = n2

       n2 = nth

       count += 1

   return term

Explanation:

This line defines the function

def fib(nterms):

This line initializes the first and second terms to 1

   n1, n2 = 1, 1

This line initializes the Fibonacci count to 0

   count = 0

The following while loops gets the number at the position of nterms

  while count < nterms:

       term = n1

       nth = n1 + n2

       n1 = n2

       n2 = nth

       count += 1

This returns the Fibonnaci term

   return term

Answer:

Explanation:

The following code is written in Python and creates arrays for the user's numbers and the next chance numbers, it also creates a cost variable and a did_you_win variable. The function takes in the winning numbers as an array parameter. It asks all the necessary questions to generate data for all the variables and then compares the user's numbers to the winning numbers in order to detect if the user has won. Finally, it prints all the necessary information.

import random

def lottery(winning_numbers):

   user_numbers = []

   next_chance_drawing = []

   cost = 0

   did_you_win = "No"

   #print("Would you like to choose your own 5 numbers? Y or N")

   answer = input("Would you like to choose your own 5 numbers? Y or N: ")

   if answer.capitalize() == "Y":

       for x in range(5):

           user_numbers.append(input("Enter number " + str(x+1) + ": "))

   else:

       for x in range(5):

           user_numbers.append(random.randint(0,31))

           cost += 1

   next_chance = input("Would you like to enter a Next Chance drawing for $1.00? Y or N: ")

   if next_chance.capitalize() == "Y":

       for x in range(4):

           next_chance_drawing.append(random.randint(0, 31))

           cost += 1

   if user_numbers == winning_numbers or next_chance_drawing == winning_numbers:

       did_you_win = "Yes"

   print("User Numbers: " + str(user_numbers))

   print("Next Chance Numbers: " + str(next_chance_drawing))

   print("Cost: $" + str(cost))

   print("Did you win: " + did_you_win)

Answer:

a. Packets - Network layer

b. Segments - Transport layer

c. Bits - Physical layer

d. Frames - Data link layer

Explanation:

When TCP/IP protocols are used for communication between two network hosts, there is a process of coding and decoding also called encapsulation and decapsulation.

This ensures the information is not accessible by other parties except the two hosts involved.

Operating Systems Interconnected model (OSI) is used to standardise communication in a computing system.

There are 7 layers used in the OSI model:

1. Session Layer

2. Transport Layer

3. Network Layer

4. Data Link Layer

5. Physical Layer

6. Presentation layer

7. Application layer

The information formats given are matched as

a. Packets - Network layer

b. Segments - Transport layer

c. Bits - Physical layer

d. Frames - Data link layer

Answer:

Follows are the code to this question:

import java.util.*;//import package for user input

public class Main//defining a class Main

{

public static void main(String[] asp)//main method

{

String n;//defining String variable

Scanner oxr=new Scanner(System.in);//creating Scanner class Object

System.out.print("Enter your name: ");//print message

n=oxr.next();//input value

System.out.println("Hello "+n+"!");//print message with value

System.out.println("Your name is "+n.length()+" letters long.");//print message with value

System.out.println("Your name starts with a "+n.charAt(0)+".");//print message with value

System.out.println("Your name ends with a "+n.charAt(n.length()-1)+".");//print message with value

System.out.print("Goodbye!");//print message

}

}

Output:

Please find the attached file.

Explanation:

In the above-given code, A string variable "n" is declared, that uses the Scanner class object for input the value from the user-end.

In the next step, the multiple print method has used, which calculates the length, first and the last latter of the string value, and uses the print method to print the calculated value with the given message.

Answer:

Some of the qualities of the installed memory which HWiNFO can reveal are:

Explanation:

HWiNFO is an open-source systems information app/tool which Windows users can utilize as they best wish. It helps to detect information about the make-up of computers especially hardware.

If you used HWiNFO to diagnose the memory, the following information will be called up:

Cheers

Answer:

isn't it already showing it if not put text box

Explanation:

Answer:

partial

Explanation:

Answer:

divide it into smaller pieces

Explanation:

Usually, the main reason a programmer does not understand a problem fully is that there is too much information. The best way to try and fully understand a problem is to divide it into smaller pieces. Start off by answering the question what is the expected output for an input. Then divide each individual issue within the problem. This will allow you as a programmer/developer to create an individual solution for each individual issue within the problem and then test to make sure that the input gives the correct output.

Answer:

4,294,967,296 (~4.3B)

Explanation:

IPv4 uses 32-bits for representing addresses, thus you can have 2^32 total combinations.

Answer:

Attached please find my solution in JAVA

Explanation:

long hashMap(String[] queryType, int[][] query) {

       long sum = 0;

       Integer currKey = 0;

       Integer currValue = 0;

       Map<Integer, Integer> values = new HashMap<>();

       for (int i = 0; i < queryType.length; i++) {

           String currQuery = queryType[i];

           switch (currQuery) {

           case "insert":

               HashMap<Integer, Integer> copiedValues = new HashMap<>();

               if (currKey != 0 || currValue != 0) {

                   Set<Integer> keys = values.keySet();

                   for (Integer key : keys) {

                       copiedValues.put(key + currKey, values.get(key) + currValue);

                   }

                   values.clear();

                   values.putAll(copiedValues);

                   currValue = 0;

                   currKey = 0;

               }

               values.put(query[i][0], query[i][1]);

               break;

           case "addToValue":

               currValue += values.isEmpty() ? 0 : query[i][0];

               break;

           case "addToKey":

               currKey += values.isEmpty() ? 0 : query[i][0];

               break;

           case "get":

               copiedValues = new HashMap<>();

               if (currKey != 0 || currValue != 0) {

                   Set<Integer> keys = values.keySet();

                   for (Integer key : keys) {

                       copiedValues.put(key + currKey, values.get(key) + currValue);

                   }

                   values.clear();

                   values.putAll(copiedValues);

                   currValue = 0;

                   currKey = 0;

               }

               sum += values.get(query[i][0]);

           }

       }

       return sum;

   }

Answer:

Publication 5140.

Explanation:

The acronym VITA stands for Volunteer Income Tax Assistance and TCE stands for Tax Counseling for the Elderly. VITA/TCE is a certification gotten from the Internal Revenue Service in which the holders of such certification are trained on how to help people that have disabilities or that their incomes earners that are low. These volunteers help these set of people to prepare for their tax return.

In order to make the volunteers to be able to perform their work with high accuracy, the Department of Treasury, Internal Revenue Service gave out some aids for Quality Site. One of the aids which is the one contains information about the new security requirements at sites is given in the Publication 5140.

Answer:

D. It requires that each item of stock is counted and recorded to determine stock levels

Explanation:

A perpetual system of inventory can be defined as a method of financial accounting, which involves the updating informations about an inventory on a continuous basis (in real-time) as the sales or purchases are being made by the customers, through the use of enterprise management software applications and a digitized point-of-sale (POS) equipment.

Under a perpetual system of inventory, updates of the journal entry for cost of goods sold or received would include debiting accounts receivable and crediting sales immediately as it is being made or happening.

Hence, an advantage of the perpetual system of inventory over the periodic system of inventory is that, it ensures the inventory account balance is always accurate provided there are no spoilage, theft etc.

The following are the characteristic of a perpetual inventory system;

I. It is the most popular choice for modern business.

II. Inventory is updated in near real-time.

III. It provides up-to-date balance information and requires fewer physical counts.

Answer:

SaaS is the cloud service in which virtual machines are provisioned

ok sorry i cant help u with this

Answer:

The term Stored Program Control Concept refers to the storage of instructions in computer memory to enable it to perform a variety of tasks in sequence or intermittently.

Answer:

Answered below

Explanation:

Pseudocode is a language that program designers use to write the logic of the program or algorithms, which can later be implemented using any programming language of choice. It helps programmers focus on the logic of the program and not syntax.

Flowcharts are used to represent the flow of an algorithm, diagrammatically. It shows the sequence and steps an algorithm takes.

Hierarchy charts give a bird-eye view of the components of a program, from its modules, to classes to methods etc.

Answer:

Explanation:

From the given information:

[tex]a_{n-1} , a_{n-2}...a_o[/tex] in binary is:

[tex]a_{n-1}\times 2^{n-1} + a_{n-2}}\times 2^{n-2}+ ...+a_o[/tex]

So, the largest number posses all [tex]a_{n-1} , a_{n-2}...a_o[/tex]  nonzero, however, the smallest number has [tex]a_{n-2} , a_{n-3}...a_o[/tex] all zero.

∴

The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times

i.e.

[tex](11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}[/tex]

[tex]= \dfrac{1(2^n-1)}{2-1}[/tex]

[tex]\mathbf{=2^n -1}[/tex]

[tex](1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}[/tex]

[tex]\mathbf {= 2 ^{n-1}}[/tex]

Hence, the smallest value is [tex]\mathbf{2^{n-1}}[/tex] and the largest value is [tex]\mathbf{2^{n}-1}[/tex]

Answer:

Linux operating system is suitable for the operation of the automated system because it is more secure with a free open-source codebase to acquire and create new applications on the platform.

Explanation:

Linux operating system is open-source software for managing the applications and network functionalities of a computer system and its networks. It has a general public license and its code is available to users to upgrade and share with other users.

The OS allows user to configure their system however they chose to and provides a sense of security based on user privacy.

Answer:

The Selection tool will always select the object as a whole. Use this tool when you want to manipulate the entire object. The Direct Selection tool will always select the points or segments that make up a frame

Explanation:

Answer:

An array.

Explanation:

An array can be defined as a structure that organizes data in a list that is commonly 1-dimensional or 2-dimensional.

Simply stated, an array refers to a set of memory locations (data structure) that comprises of a group of elements with each memory location sharing the same name. Therefore, the elements contained in array are all of the same data type e.g strings or integers.

Basically, in computer programming, arrays are typically used by software developers to organize data, in order to search or sort them.

Binary search is an efficient algorithm used to find an item from a sorted list of items by using the run-time complexity of Ο(log n), where n is total number of elements. Binary search applies the principles of divide and conquer.

In order to do a binary search on an array, the array must first be sorted in an ascending order.

Hence, array elements are mainly stored in contiguous memory locations on computer.

Answer: text import wizard

Explanation:

Answer:

Grace Hopper.

Explanation:

Grace Hopper was a US Naval Rear Admiral and an American computer scientist who was born on the 9th of December, 1906 in New York city, United States of America. She worked on the first commercial computer known as universal automatic computer (UNIVAC), after the second World War II.

In 1953 at the Remington Rand, Grace Hopper invented the first high-level programming language for UNIVAC 1 by using words and expressions.

Additionally, the high-level programming language known as FLOW-MATIC that she invented in 1953 paved the way for the development of common business-oriented language (COBOL).

Hence, Grace Hopper developed the first compiler and conducted work that led to the development of COBOL.

Answer:

d. 0x1a

Explanation:

Answer:

D. Refrigerants

Explanation:

In the United States of America, the agency which was established by US Congress and saddled with the responsibility of overseeing all aspects of pollution, environmental clean up, pesticide use, contamination, and hazardous waste spills is the Environmental Protection Agency (EPA). Also, EPA research solutions, policy development, and enforcement of regulations through the resource Conservation and Recovery Act .

The Clean Air Act Amendments of 1990 prohibit service-related releases of all refrigerants such as R-12 and R-134a. This ban became effective on the 1st of January, 1993.

Refrigerants refers to any chemical substance that undergoes a phase change (liquid and gas) so as to enable the cooling and freezing of materials. They are typically used in air conditioners, refrigerators, water dispensers, etc.

Answer:

D

Explanation: