Answer:
See edit
A 20 km / hour
Step-by-step explanation:
The exact answer is 30 km / 172 which is less than 1 km / hr. Since that answer isn't offered, I suspect there is something wrong with the question. If there is a decimal after the 1 in 172 you would get 17.44 km / hr. That's roughly A.
If the decimal is not there, I think you should either resubmit the question or answer A.
Edit
The note said (below) that the ship went 30 km in 1 1/2 hours.
Rate = distance / time
distance = 30 km
time = 1 1/2 hours = 1.5 hours
rate = 30 / 1.5 = 20 km / hr
If this fish tank is filled halfway, how much water will it hold?
96 cubic inches
768 cubic inches
48 cubic inches
384 cubic inches
Answer:
384 cubic inches
Step-by-step explanation:
first find the volume of the fish tank by multipying the length, width, and height.
v=lwh
=(16in)(4in)(12in)
= 768 cubic inches (This answer is equal to the volume of the entire fish tank, however we need to find how much water half the tank can hold. To figure this out, we need to divide 768 by 2. And you should get 384 cubic inches)
Answer:
384
Step-by-step explanation:
took the quiz
Point-Slope Form of a Line
Find the arc length of the 3/4 of a circle with a radius of 5
Answer:
7.5 pi
Step-by-step explanation:
The formula for arc length of a sector is denoted as
[tex]\frac{x}{360}2\pi r[/tex], where x is the central angle of the sector.
Since the sector is 3/4 of a circle, the central angle will be 3/4 of 360 degrees.
3/4 of 360 is 270, so we have our central angle. We also have our radius which we can plug into the formula.
[tex]\frac{270}{360}2(5)\pi[/tex]
2 times 5 is equal to 10, and 270/360 simplifies to 3/4. 3/4 times 10 is equal to 7.5, so the answer is 7.5 pi
The quotient of three times a number and 4 is at least -16.
If anyone can help me I need to Define the variable and write an inequality, then solve.
Answer:
3x4≥−16
3x≥−64
x≥−643
x≥−2113
The answer is x≥−2113
(x2 + 3x + 1) + (2x2 + 2x)
HINT
Answer:
3x^2+5x+1
Step-by-step explanation:
(x^2 + 3x + 1) + (2x^2 + 2x)
Combine like terms
x^2 + 2x^2 + 3x +2x +1
3x^2+5x+1
Answer:
[tex]3x^{2} + 5x + 1[/tex]
Step-by-step explanation:
Step 1: Combine like terms
[tex](x^{2} + 3x + 1) + (2x^{2} + 2x)[/tex]
[tex](x^{2} + 2x^{2} + (3x + 2x) + (1)[/tex]
[tex]3x^{2} + 5x + 1[/tex]
Answer: [tex]3x^{2} + 5x + 1[/tex]
A tortoise is walking in the desert. It walks 7.5 meters in 3 minutes. What is its speed?
meters per minute
9514 1404 393
Answer:
2.5 m/min
Step-by-step explanation:
To find meters per minute, divide meters by minutes:
(7.5 m)/(3 min) = 2.5 m/min
The speed of the tortoise is 2.5 meters per minute.
VG¯¯¯¯¯¯¯¯=12.2 in. PG¯¯¯¯¯¯¯¯=13.1 in. Find the radius of the circle.
Answer:iiii
Step-by-step explanation:iiiii
Answer:
17.9
Step-by-step explanation:
In the data set shown below, what is the value of the quartiles?
{4.3, 4.5, 4.7, 5, 5.5, 5.7, 5.9, 6, 6.1}
A. Q1 = 4.6; Q2 = 5.5; Q3 = 5.95
B. Q1 = 4.7; Q2 = 5.5; Q3 = 6
C. Q1 = 4.7; Q2 = 5.5; Q3 = 5.9
D. Q1 = 4.6; Q2 = 5.5; Q3 = 5.92
Answer:
A. Q1 = 4.6; Q2 = 5.5; Q3 = 5.95Step-by-step explanation:
Q2 is the median of the data set:
Q2 = 5.5Q1 is the median of lower half:
Q1 = (4.5 + 4.7)/2 = 4.6Q3 is the median of upper half:
Q3 = (5.9 + 6)/2 = 5.95Correct choice is A
Answer:
A.Q1 = 4.6;Q2 = 5.5;Q3 = 5.95
Step-by-step explanation:
I hope this helps
Are the two triangles below similar?
U
ВО
56
No because there are not to pairs of congruent corresponding angles
Yes because there are two pairs of congruent corresponding angles
No because the corresponding sides are not proportional
Yes because the corresponding sides are proportional
Answer:
Yes, because there are two pairs of congruent corresponding angles
Step-by-step explanation:
Two triangles are similar if they have the same angles. For triangle UVT on the left, we know that the sum of angles in a triangle is 180 degrees. There is one missing angle there, so the sum of angles is
80 + 55 + missing angle = 180
subtract 80+55 = 135 from both sides
45 = missing angle
Therefore, the angles in UVT are 45, 55, and 80
Similar, for XWY,
missing angle + 45 + 55 = 180
subtract 45 + 55= 100 from both sides
missing angle = 80
The angles for XWY are 45, 55, and 80. The angles are the same for both triangles, and there are three pairs of congruent corresponding angles (45, 55, and 80). Therefore, the triangles are similar
In a closed box there are 7 blue balls and 5 red balls. Randomly pick one from the box one at a time until the ball is green, then stop. Find the probability that the person stops after the 4th time
Answer:
1/7 is the probabiltiy
Step-by-step explanation:
Please find the answer
Answer:
0.3 is the right answer.
Step-by-step explanation:
hope this helps
A factory makes twenty-three million, five hundred fifty candies each month. This number in standard form is
Answer:
23,000,550
Step-by-step explanation:
A million has six zeroes, so twenty three million is
23,000,000
Since five hundred fifty is not in the thousands, it replaces the last trio of zeroes.
We have the number in standard form as
23,000,550
Answer:
23000550
Step-by-step explanation:
In four years,George saved $540. His twin sister, Georgette, saved 10 times as much. How much did Georgette saved?
5400 dollars
540x10= 5400
what is the uniqueness of comeplex integration from line integaration?
Complete the pattern ___ 8,579 ____85.7 8.57____
Answer:
the next one is .857 I hope this helps you :)
Solve for x.
A. 37
B. 27
C. 30
D. 31
Answer:
B
Step-by-step explanation:
The formula for finding the relationship between a secant and a tangent is
tangent length ^2 = external segment secant/full length of secant
In this case
60^2 = 48*(x + 48) Expand
3600 = 48*(x + 48) Remove the brackets/
3600 = 48x + 48^2 Expand
3600 = 48x + 2304 Subtract 2304 from both sides
3600 - 2304 = 48x
1296 = 48x Divide both sides by 48
1296 / 48 = x
x = 27
forty-five percent of the students in a dorm are business majors and fifty-five percent are non-business majors. business majors are twice as likely to do their studying at the library as non-business majors are. half of the business majors study at the library. if a randomly slected student from the dorm studies at the library, what is the probability the student is a business major
Solution :
Defining the following events as :
B : Being a Business major
α : Studying at the library
∴ Given that :
[tex]$P(B) = \frac{45}{100}$[/tex]
= 0.45
Again, P [ Studying at the library | Being a Business major ] = 2 P [ Studying at the library | Being a non business major ]
[tex]$P[ \alpha | B] = 2 P[\alpha | B^C]$[/tex] .......(1)
Again,
[tex]$P[\text{Studying at the library } | \text{ Being a business major}] = \frac{1}{2} = 0.50$[/tex]
[tex]$P(\alpha | B) = 0.50$[/tex]
From (1), we get
[tex]$P(\alpha | B^C) = \frac{1}{2} . P(\alpha | B)$[/tex]
[tex]$=\frac{1}{2} \times 0.50$[/tex]
= 0.25
Therefore, we need,
= P[ The students is a Business major | The student studies at the library ]
[tex]$=P(B | \alpha)$[/tex]
By Bayes theorem
[tex]$=\frac{P(B). P(\alpha | B)}{P(B).P(\alpha | B) + P(B^C). P(\alpha | B^C)}$[/tex]
[tex]$=\frac{0.45 \times 0.50}{0.45 \times 0.50 + 0.55 \times 0.25}$[/tex]
= 0.6207
*20 points*
What is the probability of drawing yellow marble followed by a red marble from a bag containing 12 yellow marbles, 14 red marbles, and 15 green marbles if the first marble is not replaced?
a. 192/1,849
b. 18/43
c. 21/205
Answer:
c: 21/205
Step-by-step explanation:
The probability of choosing a yellow marble first is 12/41 bc there are 12 yellow marbles and 41 marbles to choose from.
The probability of choosing a red marble is 14/40 bc there are 14 red marbles and 40 marbles to choose from( since you have removed the marble you first chose so there are 40 marbles left).
Multiplying these two together, 12/41 * 14/40 = 168/1640, simplified it's 21/205.
At the end of March, Jerry bought a plant that was $16.2 inches tall. During April, the plant grew 2] inches,
and during May, the plant grew another 2 inches. How tall was the plant at the beginning of June?
O 18.2 inches
O 19 inches
0 21 inches
21 inches
Answer:
20.2 inches
Step-by-step explanation:
The plant starts at 16.2 inches
The first month it grows 2 inches
16.2+2 =18.2 inches
Then the next month it grows 2 inches
18.2+2 = 20.2 inches
45%of the total population of a village are males and there are 22000 females Find the male population of the village.
Answer:
18000
Step-by-step explanation:
The 22000 females make up 55% of the population. So, we divide 22000 by 0.55 to get the total population.
22000 ÷ 0.55 = 40000
Now we take our total population and subtract 22000 to get the number of males in the population.
40000 - 22000 = 18000
The male population of the village is 18000.
What is the value of x?
Enter your answer in the box.
__units.
Please help click the picture to see the problem!
Using basic proportionality theorem
[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{42}{15}[/tex]
[tex]\\ \sf\longmapsto 15x=42(10)[/tex]
[tex]\\ \sf\longmapsto 15x=420[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{420}{15}[/tex]
[tex]\\ \sf\longmapsto x=28[/tex]
Please help, question attached.
9514 1404 393
Answer:
TrueFalseStep-by-step explanation:
Dilation has no effect on angle measures, so ∠A = ∠A'.
Point A is the center of dilation, so doesn't move. Any line through point A will still go through point A after dilation. Lines AD and A'D' are not distinct.
help it will really hep with summer school.
Answer:
10 + 5 + 6 × 5 - 2 × 4Step-by-step explanation:
Do MDAS:10 + 5 + 6 × 5 - 2 × 4=10 + 5 + 30 - 2 × 4= 10 + 5 + 30 - 8= 15 + 30 - 8= 45 - 8= 37[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
The method of tree-ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution.
1,2851,1871,2221,1941,2681,3161,2751,3171,275
Required:
a. Use a calculator with mean and standard deviation keys to find the sample mean year x and sample standard deviations.
b. Find a 90% confidence interval for the mean of all tree-ring dates from this archaeological site. (Round your answers to the nearest whole number.)
Answer:
a) The sample mean is 1260 and the standard deviation is 48.
b) The 90% confidence interval for the mean of all tree-ring dates from this archaeological site is (1230, 1290).
Step-by-step explanation:
Question a:
Mean is the sum of all values divided by the number of values. So
[tex]\overline{x} = \frac{1285 + 1187 + 1222 + 1194 + 1268 + 1316 + 1275 + 1317 + 1275}{9} = 1260[/tex]
Standard deviation is the square root of the sum of the differences squared between each value and the mean, divided by the one less than the sample size. So
[tex]s = \sqrt{\frac{(1285-1260)^2 + (1187-1260)^2 + (1222-1260)^2 + (1194-1260)^2 + (1268-1260)^2 + ...}{8}} = 48[/tex]
The sample mean is 1260 and the standard deviation is 48.
Question b:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So
df = 9 - 1 = 8
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.8595
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 1.8595\frac{48}{\sqrt{9}} = 30[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1260 - 30 = 1230
The upper end of the interval is the sample mean added to M. So it is 1260 + 30 = 1290
The 90% confidence interval for the mean of all tree-ring dates from this archaeological site is (1230, 1290).
There are 1000 students in a college.Out of 20000 in the whole university in a study of 200 were found to be smokers in the college and 1000 in whole university. Is there any significant difference between the proportion of smokers in college and university
Answer:
1000 students in college
2000 students in University
200 out of 2000 are smokers
200 out 1000 are smokers
200 : 2000
1 :10
200 : 1000
1 : 5
Can someone do #8 #9 & #10 for me please?!❤️
Answer:
8. 72% × 850
= 72/100 × 850
= 72 × 8,5
= 612 ( b )
9. Poin B = 4 ( b )
Answer:
8. B
9. B
10. C
Step-by-step explanation:
8. To find 72% of 850, you would multiply 0.72 x 850. When you do that, it gives you 612.
9. B is on the number 4.
10. The expression is asking, "What is the absolute value of 28?". Absolute value means that the number inside will always be positive. For example, if it was -28, the absolute value would turn to 28. Since the question has 28 already positive, there is no change, so the answer would be 28.
linear equation 7x+25=9
Answer:
x = -16/7
Step-by-step explanation:
7x+25=9
Subtract 25 from each side
7x+25-25=9-25
7x = -16
Divide each side by 7
7x/7 = -16/7
x = -16/7
Answer:
[tex]7x + 25 = 9 \\ 7x = 9 - 25 \\ 7x = - 16 \\ x = \frac{ - 16}{7} \\ x = - 2.29[/tex]
Step-by-step explanation:
I hope it helped U
stay safe stay happy
A car is advertised with a price of $16336. The payment plan to own a car is $474 per month for 8 years. What is the
amount of interest paid?
Find hypotenuse,perpendicular and base
Answer:
Consider the angle Ф.
the line opposite to Ф is the perpendicular -> PQ = 5cm
The base is the line with whom the perpendicular has 90° angle -> PR = 12cm
Finally, hypotenuse is the line opposite to the 90° which is QR= 13cm
Answer:
hypotenuse = QR = 13 cm
Perpendicular = PQ = 5 cm
Base = PR = 12 cm
The side-by-side stemplot below displays the arm spans, in centimeters, for two classes.
A stemplot titled Arm Span (centimeters). For Class A, the values are 148, 151, 153, 155, 156, 159, 161, 162, 164, 165, 169, 169, 170, 171, 175, 176, 179, 179, 180, 182, 183, 186, 186, 190. For Class B, the values are 153, 155, 16, 160, 162, 162, 162, 163, 163, 165, 166, 167, 170, 173, 180, 181, 182, 189, 192, 202.
Which statement correctly compares the variability of the arm spans for Class A to that of Class B?
The arm spans for Class A have more variability than the arm spans for Class B.
The arm spans for Class B have less variability than the arm spans for Class A.
The arm spans for Class A have less variability than the arm spans for Class B.
The arm spans for Class B have about the same variability as the arm spans for Class A.
Answer:
The answer is in the picture below
Step-by-step explanation:
Sorry just realised the answers were different ;-;
Answer:
The arm spans for Class A are roughly symmetric, while those for Class B are skewed left.
Step-by-step explanation:
