(Physics) Help !! I’ll give brainliest if you answer both the question in the picture and this question :

The loudness or intensity of a sound is related to its…
A. Amplitude
B. Frequency
C. Pitch
D. Wavelength

Answer:

-1.6

Explanation:

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The Height of an Image for a Convex Mirror is calculated by using magnification equation

m = h(i) / h(o)  = − d(i) / d(o) ,where  

the magnification index of the mirror, m

the height of the object, h(o)

the height of the image, h(i)

the distance between the object and the mirror, d(o)

the distance between the image and the mirror, d(i)

h(i)/ 2 = -8 / 10

h(i) = -1.6 cm.

"Convex Mirror is a curved mirror where the reflective surface bulges out towards the light source. This bulging out surface reflect light outwards and are not used to focus light."

"The formula for magnification is m=h(i)/h(o)=-d(i)/d(o). m is the total magnification; h(i) is the height of the image; h(o) is the height of an object; d(i) is the distance from the lens to the in focus projected image; d(o) is the distance of the object to the lens. The negative sign represents that the image is inverted."

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Answer:

Explanation:

the Abu Dhabi Petroleum Company

The first commercially viable oil discovery was made at Bab in 1960. In 1962, the company was renamed the Abu Dhabi Petroleum Company. Exports began to flow from the Jebel Dhanna terminal on December 14, 1963.

Answer:

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Answer:

190 kg m/s

Explanation:

Momentum = Velocity × Mass

→ Substitute in values

2 × 95 = 190 kg m/s

The momentum of the boat of mass 95 Kg moving at 2 m/s will be 190 Kg m/s.

Momentum is defined as the product of mass of velocity. Momentum is a vector quantity. Mathematically, we can write momentum as -

p = mv

It is also the measure of the impact force imparted by any moving object, when it comes in contact with some other body.

Given is a boat with a mass of 95 Kg moving at 2 m/s.

Mass [m] = 95 Kg

Velocity [v] = 2m/s

We can write the momentum as -

p = mv

Substituting values, we get -

Momentum [p] = 95 x 2 = 190 Kg m/s

p = 190 Kg m/s

Therefore, the momentum of the boat of mass 95 Kg moving at 2 m/s will be 190 Kg m/s.

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Answer:

Explanation:

Using the below formula

Speed of sound = ( distance between observers) *2/(total time taken)

Now putt the given values ,

time taken = 0.80 sec

distance = 256 m

hence

V of sound= 256*2/0.80

V of sound = 640 m/sec

Answer:

c - the frequency of the waves decreases

Answer:

ACDE

Explanation:

Energy is generally described as the ability to do work by a body. There are two main forms of energy which are the kinetic energy and the potential energy.

Other energy forms stems from these two energy types.

             Potential energy  = mass x acceleration due to gravity x height

These description satisfies options A, C

             Kinetic energy  = [tex]\frac{1}{2}[/tex] x mass x velocity²

The description satisfies DE

Explanation:  

In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. Common types of potential energy include the gravitational potential energy of an object that depends on its mass and its distance from the center of mass of another object, the elastic potential energy of an extended spring, and the electric potential energy of an electric charge in an electric field. The battery is storing the energy but give it something to power and it'll give its energy to the object and a violin strings are like ruber band and if you play the violin it releases a new type of energy sound energy.

[tex] \sf• \: Current \: (I) = 100 \: Amps.[/tex]

[tex] \sf• \: Resistance \: (R) = 50 \: ohms[/tex]

[tex] \\ [/tex]

[tex] \sf• \: Voltage \: (V)[/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{Solution:- }}[/tex]

[tex] \bf \red{ \bigstar{ \: The \: formula \: of \: Voltage \: (V) = IR}}[/tex]

[tex] \rightarrow \sf V = 100 \times 50[/tex]

[tex] \rightarrow \sf V = 5000[/tex]

[tex] \\ [/tex]

[tex] \bf \purple{Therefore, \: Volatage \: is \: 5000 \: v.}[/tex]