Answer:
4,294,967,296 (~4.3B)
Explanation:
IPv4 uses 32-bits for representing addresses, thus you can have 2^32 total combinations.
let m be a positive integer with n bit binary representation an-1 an-2 ... a1a0 with an-1=1 what are the smallest and largest values that m could have
Answer:
Explanation:
From the given information:
[tex]a_{n-1} , a_{n-2}...a_o[/tex] in binary is:
[tex]a_{n-1}\times 2^{n-1} + a_{n-2}}\times 2^{n-2}+ ...+a_o[/tex]
So, the largest number posses all [tex]a_{n-1} , a_{n-2}...a_o[/tex] nonzero, however, the smallest number has [tex]a_{n-2} , a_{n-3}...a_o[/tex] all zero.
∴
The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times
i.e.
[tex](11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}[/tex]
[tex]= \dfrac{1(2^n-1)}{2-1}[/tex]
[tex]\mathbf{=2^n -1}[/tex]
[tex](1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}[/tex]
[tex]\mathbf {= 2 ^{n-1}}[/tex]
Hence, the smallest value is [tex]\mathbf{2^{n-1}}[/tex] and the largest value is [tex]\mathbf{2^{n}-1}[/tex]
Given that the variable named Boy = "Joey" and the variable named Age = 6, create statements that will output the following message:
Congratulations, Joey! Today you are 6 years old.
First, write one statement that will use a variable named Message to store the message. (You will need to concatenate all of the strings and variables together into the one variable named Message. If you don't know what that means, read the section in Chapter 1 about concatenation.)
Then write a second statement that will simply output the Message variable.
Answer:
isn't it already showing it if not put text box
Explanation:
