Answer:
A, B, C, E
Explanation:
Inhibiting the enzyme acetylcholinesterase can lead to which of the following?
Answer:
all of the above is correct
Explanation:
Environment: Polluted Forest Moths Released G1 G2 G3 G4 G5 Typica 125 88 83 76 29 Carbonaria 510 735 885 1042 1406 Total 635 823 968 1118 1435 Phenotype Frequency Color Initial Frequency Frequency G5 Typica Light 9 Carbonaria Dark Allele Frequency Allele Initial Allele Frequency G5 Allele Frequency q d p D Genotype Frequency Moths Genotype Color Moths Released Initial Frequency Frequency G5 Number of Moths G5 q2 Typica dd Light 2pq Carbonaria Dd Dark p2 Carbonaria DD Dark
The recessive allele frequency decreased (q = 0.14) and the dominant one increased (p = 0.86). Genotypic frequencies followed this tendency too (q² =0.02, 2pq = 0.24 and p² = 0.74). The Carbonaria phenotype increased to 0.98, while Typica showed a frequency of 0.02.
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Available data:
Some moths were released in the forest (N=1000). 250 were white, and 750 were black.
The color is defined by a single diallelic gene. The dominant allele -D- codes for black color (carbonaria), while the recessive allele -d- codes for white (Typica).
These individuals produced five new generations since they were released, G1, G2, G3, G4, G5.
Moths realesed G1 G2 G3 G4 G5
Typica 250 125 88 83 76 29
Carbonaria 750 510 735 885 1042 1406
Total 1000 635 823 968 1118 1435
Phenotype frequencies
Color Initial Frequency G5 Frequency
Typica white 0.25
Carbonaria Black 0.75
Allele Frequencies
Allele Initial Allele Frequency G5 Allele Frequency
q d 0.5
p D 0.5
Genotype Frequency
Moths Genotype Color Released Initi.Freq. G5 Freq. Nº F5 moths
q² Typica dd White 250 0.25
2pq Carbon. Dd Black 500 0.50
p² Carbon. DD Black 250 0.25
This information is guiding you to know how to calculate frequencies and total numbers. Information about released individuals is an example of how you need to proceed.
Firts, we will assume that this population is under Hardy-Weinberg equilibrium. So let us review some theoretical framework.
The allelic frequencies in a locus ⇒ p and q ⇒ dominant and
recessive alleles.
The genotypic frequencies after one generation are p² (H0m0zyg0us dominant), 2pq (Heterozyg0us), q² (H0m0zyg0us recessive).
If a populations is in H-W equilibrium, it will get the same allelic frequencies generation after generation.
The sum of allelic frequencies equals 1 ⇒ p + q = 1. The sum of genotypic frequencies equals 1 ⇒ p² + 2pq + q² = 1Now let us analyze the problem.
We need to get information on G5 generation. We will do it step by step.
1) Phenotype frequencies
To get the Phenotype frequencies, we just need to divide the number of individuals with each phenotype by the total number of individuals in this generation. So,
Total number of individuals in G5 → 1435 White = Typica = 29 individuals Black = Carbonaria = 1406 individuals
⇒ F(Typica) = 29 / 1435 = 0.02
⇒ F(Carbonaria) = 1406 / 1435 = 0.979 ≅ 0.98
2) Allelic Frequencies
We can use the phenotypic frequencies to get the allelic frequencies.
Remember that carbonaria (black) moths include h0m0zyg0us dominant (DD) and heter0zyg0us (Dd) individuals. So we can not get the allelic frequencies from this data.
We can only use the allelic frequency of Typica (White) individuals. Typica phenotypic frequency only includes h0m0zyg0us recessive individuals, dd.
We know that,
H0m0zyg0us recessive genotype → dd
Genotypic frequency → F(dd) → Represented as q²
F(Typica) = F(dd) = q² = 0.02
Recessive allele → d
Recessive allelic frequency → f(d) → Represented as q
f(d) = q = ??
q² = 0.02
q = √ 0.02
q = 0.1414 ≅ 0.14
0.14 is the recessive allelic frequency. Now we should calculate the dominant allelic frequency. To do this, we will clear the following formula,
p + q = 1
p + 0.14 = 1
p = 1 - 0.14
p = 0.86
So, now we also know that
⇒ f(D) = p = 0.86
⇒ f(d) = q = 0.14
3) Genotypic Frequencies
Now, we need to get the genotypic frequencies, F(xx)
⇒ F(DD) = p² = 0.86² = 0.7396 ≅ 0.74
⇒ F(Dd) = 2pq = 2 x 0.86 x 0.14 = 0.24
⇒ F(dd) = q² = 0.14² = 0.0196 ≅ 0.02
4) Number of individuals
Finally, we need to tell the number of individuals with each genotype. We just need to multiply each frequency by the total number of individuals in G5.
F(DD) = p² = 0.74
F(Dd) = 2pq = 0.24
F(dd) = q² = 0.02
Total number of individuals = 1435
⇒ DD Black -Carbonaria- individuals → 0.74 x 1435 = 1,061.9 ≅ 1062
⇒ Dd Black -Carbonaria- individuals → 0.24 x 1435 = 344.4 ≅ 344
⇒ dd White -Typica- individuals → 0.02 x 1435 = 28.7 ≅ 29
From this results, we can conclude that the moths population is not in H-W equilibrium, because their allelic and genotypic frequencies changed through generations.
It seems that Natural selection is favoring the dominant phenotype by increasing the frequency of the dominant allele over the recessive one. Probably directional selection is acting on this population.
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Related link: brainly.com/question/12724120?referrer=searchResults
Which of the following statements is TRUE during depolarization?
Answer:
a is correct
Explanation:
Fungi have chlorophyll.
True
False
False- unlike plants fungi to not have chlorophyl.
Why- Fungi do not need the sun to make food instead they break down their own food.
Hope this helped
if you can may I have brainlist
Platelets helps us in fighting against diseases. ______.
Answer:
True
Explanation:
THere are two types of platelets which are; lymphocytes and phagocytes
Lymphocytes swallow bacteria while phagocytes kill them
Articulations are classified by their function or structure. Which of the following is an example of functional classification?
Answer:
d. Synarthrotic joints
Explanation: is correct for the choices offered.
answe rir plssssessSSSSSS
Which of the following is true about cells?
A. A cell’s components are all identical and perform the same function.
B. Cells have specialized components that all perform the same functions.
C. A cell has a single component that performs all of the cell’s different, specific functions.
D. Cells have specialized components that perform different, specific functions.
Answer:
D
Explanation:
Hope this helps
How is Wallace's view scientific
chromosomes are duplicated during what portion of the cell cycle?
Answer:
S phase
Explanation:
during interphase (called the S phase), the cell duplicates its chromosomes and ensures its systems are ready for cell division.
Question 3
2 pts
The genetic code found on
gives cells instructions for building specific
which are machine-like molecules that can carry out specific functions in a cell..
O DNA, proteins
O cells, mitochondria
O chromosomes, genes
O genes, liposomes
Answer:
im pretty sure it is DNA,proteins
Explanation:
HELP ME MAKE THIS ESSAY BETTERStructure and Function of MicroscopesA microscope is a laboratory instrument used to examine objects that are too small to be seen by the naked eye. There are several types of microscopes but in this essay, we will be discussing the compound light microscope, the transmission electron microscope, and the scanning electron microscope. And we will be comparing its structure and function.From its name compound light microscope uses light as its radiation source with a wavelength that reaches from 400 to 700 nm though the Transmission electron microscope uses electrons as its radiation source, the scanning electron microscope uses electrons as well which wavelength reaches 0.005 nm.For the lens, the compound light microscope uses glass that is have its maximum resolution of 200 nm and can view colored images with an eyepiece powered 10x and 3 or 4 objective lenses that are power can be (4x, 10x, 40x) power. both transmission electron microscope and scanning electron microscope uses Electromagnetic as their lens although transmission electron microscope lens maximum resolution is 1 nm, and its maximum magnification power is 250 000x with a monogram view and scanning electron microscope lens maximum resolution is 10 nm and its maximum magnification power is 100 000x with a monogram view as well.For the specimen, the compound light microscope supports both living and non-living specimens. The transmission electron microscope and the scanning electron microscope both support only non-living specimens although the transmission electron microscope supports it on a small copper grid in a vacuum, and the scanning electron microscope supports it on in a metal disc in a vacuum.In the end, all microscopes are useful without microscopes no medicines would be found because scientists would not know how to treat the micro viruses and bacteria, and we could not explore and discover micro-organisms around us that we cannot see with our naked eye.
Answer:
After the period, make sure to add a capital letter. Also after the period, add a space. Other then that, it looks terrific! pretty impressed...
Explanation:
Share three ways you would take to reduce water pollution.
Does sugar free red bull have energy for cellular respiration and if so what kind?
Answer: yes my man
Explanation:
Answer:
Red Bull Zero and Red Bull Sugarfree contain the same main ingredients – caffeine, taurine and some B-group vitamins. Both are made without sugar, instead using different low calorie sweeteners.
Explanation:
Describe the two types of speciation (in your own way) pleaseee thank you
Many scientists consider genetic engineering to be simply an efficient method of selective breeding. Is it?
True or False: A positive ion and a negative ion will repel each other.
Answer:
FALSE is correct
Explanation: Questions protected!
What are some examples of non-native species that have been Introduced to and thrive in Los Angeles increasing the overall "biodiversity" because of human activity?
The House Sparrow was introduced to North America from Europe. It is not really a sparrow but a European weaver-finch. It is highly successful, tends to follow human habitation, thrives in agricultural areas, and does not damage the local ecosystem. I would rate it a neutral. Bird of the Day: A Sparrow that's not a Sparrow, and a Successful Immigrant
The reintroduction of wolves into Yellowstone has had a positive effect on the ecosystem there. Wolf Reintroduction Changes Ecosystem
Horses were also introduced from Europe to North America and seem to have been neutral toward the ecosystem (unless you are a cattle rancher). They could be considered a reintroduction since they did evolve in North America also but just died out in the past.
Wild turkeys were introduced to the Western states from its native location in the Eastern US. They have been successful and effect on the ecosystem seems at worst neutral.
Two introductions that we regard as very beneficial animals, the earthworm and the European honeybee had negative effects on the native North American ecosystem, but very positive effects on those plants that the settling Europeans were trying to grow. The earthworm had been killed off the ice age in the Northeast and was introduced via the ballast from ships. Earthworms ground through leaf litter that the trees depended on and resulted in sparser forests. Honeybees were deliberate introductions. The native bees were few and favored only a few plants. The European honeybee was enormously fertile and liked pretty much all flowering plants making it a major league pollinator. My source for this information earthworms and honeybees is America, Found and Lost
If the water concentration inside a cell is higher than the water concentration outside the cell, water flows out of the cell. This method of molecular transport is called
A.
osmosis.
B.
endocytosis.
C.
a sodium pump.
D.
exocytosis.
Answer:
a
Explanation:
Which weather conditions will most likely cause heavy rain and cooler temperatures? (A. Cold front) (B. Seabreeze) (c. warm front) (D. Land breeze)
Answer:
a. cold front
Explanation:
Many fronts cause weather events such as rain, thunderstorms, gusty winds, and tornadoes. At a cold front, there may be dramatic thunderstorms.
hope this helps
One of the following statements is correct about glycolysis:
A.Net gain of only 2 ATP.
B.Glycolysis in fermentation reaction requires more oxygen than glycolysis in aerobic respiration
C.Carbon dioxide is used during glycolysis to form ATP.
D.Only animals can carry on glycolysis.
Answer:
A.
Explanation:
Glycolysis produces 4 ATP molecules in total, however 2 ATP molecules are used to convert a glucose molecule into a new 6 carbon compound with 2 phosphates attached to it. So, the net yield of ATP is 2 molecules.
Answer:
A net gain of only 2 ATP
Explanation:
What is the role of knowing the Earth's history to mankind?
Answer:
Earth history enables us to understand those changes which no human being has ever seen (or if they have, they didn't record it) and to relate them to modern changes. Such events include: The rise and extinction of the dinosaurs. The formation of the Grand Canyon.
Explanation:
Answer:
Earth history enables us to understand those changes which no human being has ever seen (or if they have, they didn't record it) and to relate them to modern changes. Such events include: The rise and extinction of the dinosaurs. The formation of the Grand Canyon.
hope it's helpful
thank you
Helpppppppppdhhdudhdjdjdnndj
Answer:
D
Explanation:
The movement of tectonic plates in two locations is described below:
Location A: Tectonic plates collide and one plate moves over the other while the other plate is pushed deep into the mantle
Location B: Tectonic plates slide past each other
PLS HELP I WILL GIVE BRAIBLIEST AND 100 POINTS
Which statement is most likely correct?
Volcanic eruptions may occur in both locations.
There is no chance of earthquakes in the two locations.
Mountains may form in Location B but not in Location A.
Subduction happens in Location A but not in Location B.
Explanation:
volcanic eruption may occur in both location
Answer: D
Explanation subduction happens when one plate is ontop of another and pushes it into the matel
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In wolves, gray coat color (G) is dominant to black (g) and brown eyes (B) are dominant to blue (b). The genes that control these traits are located on different chromosomes. The alpha male of the pack has the dominant phenotype for both traits and is heterozygous for both traits. The alpha female has brown eyes and a black coat; she is heterozygous for eye color. Which option represents gametes that would be made by the alpha female
The combination of gametes that will be produced by the Alpha female is Bg, Bg, bg and bg.
According to this question, two genes coding for eye color and coat color in wolves are involved. Gray coat color (G) is dominant to black coat color (g) while brown eyes (B) are dominant to blue eyes (b). The alpha female of the pack is said to have a brown eyes and a black coat (gg) but she is heterozygous for eye color (Bb). This means that she posseses the following genotype: Bbgg. According to Mendel in his law of independent assortment, alleles of a gene will segregate into gametes independently of one another. This means that the alpha female with genotype (Bbgg) will segregate into the following combinations of gametes: Bg, Bg, bg and bg.Learn more about gamete formation at: https://brainly.com/question/11523490?referrer=searchResults
What is conditioning?
Answer:
conditioning, in physiology, a behavioral process whereby a response becomes more frequent or more predictable in a given environment as a result of reinforcement, with reinforcement typically being a stimulus or reward for a desired response.
Explanation:
What is the phase shown below?
Prophase
Metaphase
Telophase
Anaphase
Answer:
Telophase
Explanation:
The concept of race is socially constructed,meaning that it is something defined by our society
1.True
2.False
False.
Races are a well-known diversity.
PLSSS HELP! IF CORRECT, WILL MARK BRAINLIEST
Following the fusion of an egg cell and sperm cell, the resulting diploid cell divides by mitosis to create two new daughter cells. Each daughter cell contains pairs of chromosomes, with one set inherited from each parent.
Which of the following best describes the pairs of chromosomes that are present in each newly formed daughter cell?
Choose 1 answer:
A) The pairs are homologous chromosomes that have the same set of genes, but likely different variations of those genes.
B) The pairs are non-homologous chromosomes that contain different sets of genes.
C) The pairs are homologous chromosomes that have identical copies of every gene.
Answer: A
i have no idea why
The pairs are homologous chromosomes that have the same set of genes, but likely different variations of those genes. The correct option is A.
What are homologous chromosomes?Among a pair of chromosomes with the very same gene sequence, loci, chromosomal size, and centromere location is referred to as a homologous chromosome.
One paternal and one maternal chromosome make up a homologous pair. In humans, the nucleus of a somatic cell contains 46 chromosomes.
Homologous chromosomes differ from sister chromatids because they are not identical and do not emanates from the same organism.
Sister chromatids are identical, side-by-side duplicates of each other that form as a result of DNA replication.
Homologous chromosomes do not pair together during mitosis. Homologous chromosomes line up end-to-end in mitosis so that when the cells divide, each daughter cell receives a sister chromatid from both members of the homologous pair.
Thus, the correct option is A.
For more details regarding homologous chromosomes, visit:
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What of the following best explains the pace and timing of evolutionary change?
A: Evolutionary change quickly and constantly occurs throughout time.
B: The pace of evolutionary change has slowed down over time, and it only rarely occurs now.
C: Periods during which evolution occurred were always preceded by a catastrophe.
D: Long periods of stability were punctuated with periods of evolutionary change.
Answer:
B: The pace of evolutionary change has slowed down over time, and it only rarely occurs now.
Explanation:
What of the following best explains the pace and timing of evolutionary change The pace of evolutionary change has slowed down over time, and it only rarely occurs now.
Answer:
D: Long periods of stability were punctuated with periods of evolutionary change.
Explanation:
