Parallelogram A B C D is shown. Line segment X Y goes from point X on side A B to point Y on side C D to form 2 trapezoids.
Figure ABCD is a parallelogram. Two trapezoids are created using line segment XY such that AX ≅ CY.

What is true about the areas of the trapezoids?

Each area is equal to half of the area of ABCD.
The area of AXYD is less than the area of BXYC.
The area of AXYD is greater than the area of BXYC.
Each area is equal to the area of ABCD.

Hi there!

[tex]\large\boxed{73m^2}}[/tex]

Once again, divide the figure into 3 rectangles:

Top rectangle:

3m × 5m = 15m²

Long rectangle (subtract 5m from 9m to get the width):

12m × 4m = 48m²

Bottom rectangle:

2m × 5m = 10m²

Add up areas:

15m² + 48m² + 10m² = 73m²

Answer:

you should make the picture more clear, i cant see the answer choices

Answer:

use pythogoream theorem that is,

Step-by-step explanation:

c*2=a*2+b*2

so in order to find a*2;

a*2=c*2-b*2

Hello!

4/18 = 6/27 ?

4 × 27 = 18 × 6

108 = 18 × 6

108 = 108 => 4/18 = 6/27

4/6 = 16/36 ?

4 × 36 = 6 × 16

144 = 6 × 16

144 ≠ 96 => 4/6 ≠ 16/36

3/4 = 9/12 ?

3 × 12 = 4 × 9

36 = 4 × 9

36 = 36 => 3/4 = 9/12

5/9 = 8/12 ?

5 × 12 = 9 × 8

60 = 9 × 8

60 ≠ 72 => 5/9 ≠ 8/12

Good luck! :)

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

Number of days Adya took to complete the work = 20

Work done by Adya in 1 day = [tex]\frac{1}{20}[/tex]

Number of days Ashley took to complete the work = 25

Work done by Ashley in 1 day = [tex]\frac{1}{25}[/tex]

So,

Total work by Adya & Ashley in 1 day =

[tex] \frac{1}{20} + \frac{1}{20} \\ = \frac{5 + 4}{100} \\ = \frac{9}{100} [/tex]

•°• Their total work in 10 days =

[tex] \frac{9 \times 10}{100} \\ = \frac{90}{100} \\ = \frac{9}{10} [/tex]

Now,

The work left to be completed =

[tex]1 - \frac{9}{10} \\ = \frac{10}{10} - \frac{9}{10} \\ = \frac{1}{10} [/tex]

From this we know that,

Amber completes [tex]\frac{1}{10}[/tex] of the work in 3 days.

So,

Time taken by Amber to complete the whole work =

[tex]3 \times 10 \\ = 30 \: \: days[/tex]

↦ If Amber alone would do the whole work, he would take [tex]\boxed{30 \ \ days}[/tex] to complete it.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

C. $516

Step-by-step explanation:

His regular rate is $8 per hour.

Since it's 40 hours a week, it means from Monday to Friday his regular work time is 8 hours per day.

Thus, for the regular week work, he is to be paid;

40 × 8 = $320

Now, we are told he worked 9 hours each day from Monday through Friday.

This means that;

He worked 1 hour each day.

That is 5 hours extra from Monday to Friday.

He is paid one and one-half times the regular hourly rate.

Thus, for this 5 extra hours, he will be paid 1½ × 5 × 8 = $60

He works 6 hours on Saturday, and 4 hours on Sunday.

Thus;

For Saturday, he is also paid one and one-half of regular pay. Thus, he is due for;

1½ × 8 × 6 = $72

He is paid double the regular hourly pay for Sundays.

Thus, for 4 hours on Sunday, he is paid;

2 × 8 × 4 = $64

Total he is due = $320 + $60 + $72 + $64 = $516

Answer:

C. 40

Step-by-step explanation:

The smallest factor of 119 (other than 1) is 7.

28/7 = 4,

35/7 = 5,

40/7 = 5 5/7

63/7 = 9

So it is 40

Answer:

832.5

A unit rate is a rate with 1 in the denominator.

Answer:

ok ok ok ok ok ok ok

Step-by-step explanation:

Answer: $11,808

Step-by-step explanation:

5000 - 2048 = 2952

By subtracting the total number of buttons by the number of buttons left, it can be calculated that the tailor used a total of 2952 buttons.

Each shirt has 9 buttons, therefore the number of shirts can be calculated as:

2952 ÷ 9 = 328.

Since the shirts sold at $36 each and there are 328 shirts made, the total amount can be calculated as $36 · 328 = $11,808

(I hope this is right :\)

The total amount collected by the tailor  $11,808.

Division is the process of splitting a number or an amount into equal parts.

Division is one of the four basic operations of arithmetic, the ways that numbers are combined to make new numbers. The other operations are addition, subtraction, and multiplication.

here, we have,

A tailor had 5000 buttons.

He sawed 9 buttons on each shirt and had 2048 buttons left.

Then, he sold all shirts at $36 each.

now,

5000 - 2048 = 2952

By subtracting the total number of buttons by the number of buttons left, it can be calculated that the tailor used a total of 2952 buttons.

Each shirt has 9 buttons, therefore the number of shirts can be calculated as:

2952 ÷ 9 = 328.

Since the shirts sold at $36 each and there are 328 shirts made,

the total amount can be calculated as $36 · 328

                                                             = $11,808

Hence,  the total amount collected by the tailor  $11,808.

To learn more on division click:

brainly.com/question/21416852

#SPJ2

Answer:

G

Step-by-step explanation:

I did this on edge and it was right

Answer:

O  Point G

Step-by-step explanation:

A = -6

B = 8

To find the midpoint, calculate how much would it take for both points to have a value of zero.

-6 + ? = 0

-6 + 6 = 0

8 - ? = 0

8 - 8 = 0

so the midpoint will be about 7 (between 6 & 8)

Now which of the points best shows 7 units apart of AB

Answer: point G

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, [tex]\overline{CP}[/tex] ⊥ [tex]\overline{AM}[/tex], AP = 9, and PM = 16

[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = [tex]\overline{AM}[/tex]²

[tex]\overline{AM}[/tex] = [tex]\overline{AP}[/tex] + PM = 9 + 16 = 25

[tex]\overline{AM}[/tex] = 25

[tex]\overline{AC}[/tex]² = [tex]\overline{AP}[/tex]² + [tex]\overline{CP}[/tex]² = 9² +  [tex]\overline{CP}[/tex]²

∴ [tex]\overline{AC}[/tex]² = 9² +  [tex]\overline{CP}[/tex]²

Similarly we get;

[tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]²

Therefore, we get;

[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = 9² +  [tex]\overline{CP}[/tex]² + 16² + [tex]\overline{CP}[/tex]² = [tex]\overline{AM}[/tex]² = 25²

2·[tex]\overline{CP}[/tex]² = 25² - (9² + 16²) = 288

[tex]\overline{CP}[/tex]² = 288/2 = 144

[tex]\overline{CP}[/tex] = √144 = 12

From [tex]\overline{AC}[/tex]² = 9² +  [tex]\overline{CP}[/tex]², we get

[tex]\overline{AC}[/tex] = √(9² +  12²) = 15

[tex]\overline{AC}[/tex] = 15

From, [tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]², we get;

[tex]\overline{CM}[/tex] = √(16² + 12²) = 20

[tex]\overline{CM}[/tex] = 20.

Answer:

444

Step-by-step explanation:

3 [ ( 15 - 3 )^2 + 4 ]

= 3 [ ( 15 - 3 )^2 + 4 ]

= 3 [ ( 12 )^2 + 4 ]

= 3 [ 144 + 4 ]

= 3 [ 148 ]

= 444

Step-by-step explanation:

3(15-3)²+4

3(12)²+4

3×144+4

432+4

436 Answer

Answer:

A' = (-3, 0)

Step-by-step explanation:

The coordinates of point A are (-6, 2).

The translation adds 3 to x and subtracts 2 from y.

A'(-6 + 3, 2 - 2) = A'(-3, 0)

Answer: A' = (-3, 0)

Answer:

2 : 1

Step-by-step explanation:

Supplementary angles are two angles whose measures add up to 180°

If one of the angle = 120°

The other angle = sum of supplementary angle - one of the angle

= 180° - 120°

= 60°

The other angle = 60°

ratio of pair of supplementary aangle = 120° : 60°

= 120° / 60°

= 2/1

= 2 : 1

ratio of pair of supplementary aangle = 2 : 1

Answer:

[tex]x=7\text{ and } m\angle KLM = 34^\circ[/tex]

Step-by-step explanation:

We are given ethat KM and JN are parallel.

And we want to find the value of x.

Notice that ∠JKM and ∠LKM form a linear pair. Linear pairs total 180°. Therefore:

[tex]m\angle JKM + m\angle LKM = 180[/tex]

We know that ∠JKM measures (14x + 8). Substitute:

[tex](14x+8)+m\angle LKM =180[/tex]

Solve for ∠LKM:

[tex]m\angle LKM = 172-14x[/tex]

Next, since KM and JN are parallel, by the Corresponding Angles Theorem:

[tex]\angle JNM \cong \angle KML[/tex]

Since we know that ∠JNM measure (10x + 2), we can conclude that:

[tex]m\angle KML = 10x+2[/tex]

Next, recall that the three interior angles of a triangle must total 180°. Therefore:

[tex]m\angle KLM + m\angle LKM + m\angle KML = 180[/tex]

Substitute:

[tex](5x-1)+(172-14x)+(10x+2)=180[/tex]

Solve for x. Rewrite:

[tex](5x-14x+10x)+(-1+172+2)=180[/tex]

Combine like terms:

[tex](1x)+(173)=180[/tex]

Therefore:

[tex]x=7[/tex]

To find ∠KLM, substitute in 7 for x and evaluate. So:

[tex]m\angle KLM = 5(7) - 1 =34^\circ[/tex]

Answer:

It's C

Step-by-step explanation:

Answer:

B. (4,2)

Step-by-step explanation:

Answer:

B(4,2)

Step-by-step explanation:

as you can see that if want to find coordinates u should know that the position of x and y is (x,y). So u can that c on the x is lower than 5 so that u can say it is 4 and y is too far away from 5 also u it will be 2.

Answer:

x - 2y + 8 = 0

Step-by-step explanation:

that is the procedure above

Answer:

Step-by-step explanation:

radius of base=8/2=4 ft

l²=4²+9²=16+81=97

l=√97 ft

Answer:

4x^4+3x^2y^2+9y^2

(2x^2)^2 + 2×2x^2×3y^2 + (3y^2)^2 - 9

(2x^2 + 3y^2)^2 - (3)^2

(2x^2 +3y^2+3)(2x^2+3y^3-3)

9514 1404 393

Answer:

  A. subtraction

  B. division

  C. multiplication

  D. addition

Step-by-step explanation:

Observe what is done to the variable. Choose the operation that turns the unwanted value into the appropriate identity element.

A. 3.75 is added. To make that value be 0, we subtract 3.75.

B. -3 is multiplied. To make that value be 1, we divide by -3.

C. m is divided by 5. To make that 1/5 multiplier be 1, we multiply by 5.

D. 4 is subtracted. To make that value be zero, we add 4.

_____

Additional comment

Since subtraction is the same as addition of the opposite, and division is the same as multiplication by the reciprocal, the only two properties we really need are the addition property and multiplication property. Your grader may disagree.

Answer:

Other dude is right.

Step-by-step explanation:

Be safe, have an amazing day. :)

Answer:

[tex]10[/tex].

Step-by-step explanation:

See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".

Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:

[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.

Sum of these digits:

[tex]\text{A} + 9\, x= 2021[/tex].

Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].

Therefore:

[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].

[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].

[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].

Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].

Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Proof:

The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".

For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.

Either of the following must be true:

If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.

Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.

let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].

The coordinates that describe the point D are: Option C: (0, 4)

The graph shows that the vertical axis is labelled as the y-axis while the horizontal axis is labelled as the x -axis.

Normally, the coordinate system of writing the given points of the graph is (x, y)

Thus, the point D on the graph is seem to be 4 units on the positive y-axis and 0 units on the positive x-axis and as such, we can say that the coordinates of point D are:

D(0, 4)

Read more about Graph Coordinates at: https://brainly.com/question/11337174

Complete question is:

Which of the following describes point D?

(-4, 0)

(0, -4)

(0, 4)

(4, 0)

Answer:

(0,3) ; (2,3) ; (0,0) ; (3.5,0)

Step-by-step explanation:

Firstly, we have to plot all the giving inequalities as constraints

Not to forget, f(x) can be written as y

Kindly find the plot as an attachment

Upon plotting, we have the following vertices;

(0,3) ; (2,3) ; (0,0) ; (3.5,0)

Answer:

C

Step-by-step explanation:

The nth term of an AP is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 5 and d = a₂ - a₁ = - 10 - (- 5) = - 10 + 5 = - 5 , then

a₁₀ = - 5 + (9 × - 5) = - 5 - 45 = - 50 → C

Given:

The number of ribbons it can sell each week, x, is related to the price p per ribbon by the equation:

[tex]x=1000-100p[/tex]

To find:

The selling price if the company wants the weekly revenue to be $1,600.

Solution:

We know that the revenue is the product of quantity and price.

[tex]R=xp[/tex]

[tex]R=(1000-100p)p[/tex]

[tex]R=1000p-100p^2[/tex]

We need to find the value of p when the value of R is $1600.

[tex]1600=1000p-100p^2[/tex]

[tex]1600-1000p+100p^2=0[/tex]

[tex]100(16-10p+p^2)=0[/tex]

Divide both sides by 100.

[tex]p^2-10p+16=0[/tex]

Splitting the middle term, we get

[tex]p^2-8p-2p+16=0[/tex]

[tex]p(p-8)-2(p-8)=0[/tex]

[tex](p-8)(p-2)=0[/tex]

Using zero product property, we get

[tex]p-8=0[/tex] or [tex]p-2=0[/tex]

[tex]p=8[/tex] or [tex]p=2[/tex]

Therefore, the smaller value of p is $2 and the larger value of p is $8.

Answer:

the answer is true

Step-by-step explanation:

the ratio is less than 1